Take This Easiest Chemical Bonding Trivia Questions!
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How many non-bonding electrons are present in compound A? Assume all atoms are neutral.
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10
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12
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7
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6
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Take This Easiest Chemical Bonding Trivia Questions if you are looking for a chance to test out just how much you understand about the different types of chemical bonds that exist in a compound. If you have not studied enough, the quiz will tell you which parts of the topic you need to consider more on. Do give it a See moretry and all the best!
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- 2.
What functional groups are present in the molecule?
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An amide and an ester
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A ketone and a nitrile
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An amide and an ether
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An amine and an alcohol
Correct Answer
A. An amide and an etherExplanation
The molecule contains an amide functional group, which is characterized by a carbonyl group (C=O) bonded to a nitrogen atom. Additionally, it contains an ether functional group, which is characterized by an oxygen atom bonded to two alkyl or aryl groups.Rate this question:
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- 3.
Which of the structures contains an aldehyde functional group?
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A only
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D only
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B and D only
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E only
Correct Answer
A. A onlyExplanation
Structure A contains an aldehyde functional group. An aldehyde is characterized by a carbonyl group (C=O) bonded to a hydrogen atom (H). In Structure A, there is a carbonyl group bonded to a hydrogen atom, indicating the presence of an aldehyde functional group. Structures D and E do not have a carbonyl group bonded to a hydrogen atom, so they do not contain an aldehyde functional group. Structure B does not have a carbonyl group at all, so it also does not contain an aldehyde functional group.Rate this question:
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- 4.
What functional groups are present in this molecule?
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An aldehyde and a amine
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An amine and an ester
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An amide and an ether
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An ester and an ether
Correct Answer
A. An amide and an etherExplanation
The correct answer is an amide and an ether. This can be determined by analyzing the functional groups present in the molecule. An amide is characterized by the presence of a carbonyl group (C=O) bonded to a nitrogen atom, while an ether is characterized by the presence of an oxygen atom bonded to two carbon atoms.Rate this question:
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- 5.
Which of the following structures contains a ketone functional group?
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A only
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A, B, and E only
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B and D only
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A and E only
Correct Answer
A. A and E onlyExplanation
Structures A and E both contain a ketone functional group. A ketone functional group consists of a carbon double bonded to an oxygen atom, with two additional carbon groups bonded to the same carbon atom. In structure A, the carbon atom in the middle has a double bond with the oxygen atom and two additional carbon groups bonded to it, making it a ketone. In structure E, the carbon atom in the middle also has a double bond with the oxygen atom and two additional carbon groups bonded to it, making it another example of a ketone. Therefore, the correct answer is A and E only.Rate this question:
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- 6.
What is the molecular formula for compound A?
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C6 H12 O2
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C6 H12 O
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C5 H10 O2
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C6 H10 O
Correct Answer
A. C6 H12 O2Explanation
The molecular formula for compound A is C6 H12 O2 because it indicates that the compound contains 6 carbon atoms, 12 hydrogen atoms, and 2 oxygen atoms. This formula provides the exact number and types of atoms present in the compound, allowing for accurate identification and representation.Rate this question:
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- 7.
Specify the number of secondary carbons in compound A.
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2
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4
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1
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3
Correct Answer
A. 2Explanation
Compound A has 2 secondary carbons. This means that there are 2 carbon atoms in the compound that are bonded to two other carbon atoms. The other carbons in the compound are either bonded to only one carbon atom (primary carbons) or three or more carbon atoms (tertiary carbons).Rate this question:
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- 8.
Which of the following represents the IUPAC name for compound A?
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4-propyl-2-methylhexane
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4-propyl-5-methylhexane
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4-ethyl-2-methylheptane
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3-propyl-2-methyloctane
Correct Answer
A. 4-ethyl-2-methylheptaneExplanation
The IUPAC name for compound A is 4-ethyl-2-methylheptane. This is because the compound has a propyl group (3 carbon chain) attached to the fourth carbon atom of the main chain, an ethyl group (2 carbon chain) attached to the second carbon atom of the main chain, and a methyl group attached to the second carbon atom of the main chain. The main chain has a total of seven carbon atoms, making it a heptane.Rate this question:
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- 9.
Specify the number of primary carbons in compound A.
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1
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2
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3
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4
Correct Answer
A. 3Explanation
Compound A has 3 primary carbons. Primary carbons are those carbons that are directly bonded to only one other carbon atom. Looking at the structure of Compound A, we can see that there are three carbons that are directly bonded to only one other carbon atom. Therefore, the correct answer is 3.Rate this question:
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- 10.
Which of the stick drawings above represents a possible structure for C5H12?
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E only
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A, B, and E only
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A and E only
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All of them
Correct Answer
A. A, B, and E onlyExplanation
The correct answer is A, B, and E only. This is because C5H12 represents a molecule with 5 carbon atoms and 12 hydrogen atoms. The stick drawings A, B, and E all show a structure with 5 carbon atoms and 12 hydrogen atoms, making them possible structures for C5H12.Rate this question:
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- 11.
Rank the above molecules in order of increasing preference for an equatorial placement of the non-hydrogen substituent.
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A, B, D, E
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D, E, A, B
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E, B, A, D
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B, A, D, E
Correct Answer
A. E, B, A, DExplanation
The correct answer is E, B, A, D. This means that molecule E has the highest preference for an equatorial placement of the non-hydrogen substituent, followed by molecule B, then A, and finally D. This ranking is determined by considering factors such as steric hindrance and the stability of the molecule. Molecule E likely has the least steric hindrance and is the most stable when the substituent is in an equatorial position, while molecule D likely has the most steric hindrance and is the least stable in this conformation.Rate this question:
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- 12.
Assign an R/S designation to each of the molecules below.
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A = R, B = S
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A = S, B = R
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A = R, B = R
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A = S, B = S
Correct Answer
A. A = R, B = RExplanation
The given answer states that molecule A has an R configuration and molecule B also has an R configuration. In organic chemistry, R and S designations are used to describe the absolute configuration of chiral molecules. The R configuration means that the molecule's substituents are arranged in a clockwise direction, while the S configuration means they are arranged in a counterclockwise direction. Therefore, in this case, both molecules A and B have the same arrangement of substituents in a clockwise direction, leading to the conclusion that both have an R configuration.Rate this question:
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- 13.
Specify the number of Chiral Centers in the molecule below.
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4
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2
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3
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1
Correct Answer
A. 2Explanation
The molecule shown in the question contains two chiral centers. Chiral centers are carbon atoms that are bonded to four different groups. In this molecule, there are two carbon atoms that meet this criteria, indicated by the red circles in the diagram. These two carbon atoms have four different substituents attached to them, therefore they are chiral centers.Rate this question:
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- 14.
Which of these are meso compounds?
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D and E only
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D only
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All of the above
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A, B, and D only
Correct Answer
A. D onlyExplanation
Meso compounds are optically inactive compounds that possess chiral centers but have an internal plane of symmetry, which cancels out the optical activity. In this question, option D only is the correct answer because it indicates that only compound D is a meso compound. The other options either include compounds that are not meso compounds or exclude compound D, which is the only meso compound in this case.Rate this question:
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- 15.
Which of the following reactions would have a positive ∆S?
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A only
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Neither A nor B
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B only
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Both A and B
Correct Answer
A. B onlyExplanation
∆S is entropy, and a positive ∆S means the products have higher disorder. There's one reactant in B and 3 products, meaning there is increased disorder, and thus a positive ∆S. In A, there is two reactants and only one product, so ∆S is negative and there's lowered disorder.Rate this question:
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- 16.
Which of the following represent(s) a substitution reaction?
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A and D only
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A and B only
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A only
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B only
Correct Answer
A. A and D onlyExplanation
A substitution reaction is a type of chemical reaction where one atom or group of atoms is replaced by another atom or group of atoms. In this case, the correct answer is A and D only, which means that both A and D represent substitution reactions.Rate this question:
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- 17.
Ozonolysis of molecule A would result in the formation of what two functional groups?
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Two ketones
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A ketone and an aldehyde
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Two aldehydes
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Two carboxylic acids
Correct Answer
A. A ketone and an aldehydeExplanation
Ozonolysis is a chemical reaction that involves the cleavage of carbon-carbon double bonds using ozone. In this case, molecule A undergoes ozonolysis, resulting in the formation of two functional groups: a ketone and an aldehyde. This is because one of the carbon-carbon double bonds is cleaved, producing a ketone group, while the other carbon-carbon double bond is cleaved, producing an aldehyde group. Therefore, the correct answer is "A ketone and an aldehyde".Rate this question:
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- 18.
Which of the following products would be obtained in the highest yield from the reaction below?
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D
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E
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A
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B
Correct Answer
A. BExplanation
CHCl3/KOH of a double bond results in a dichlorocyclopropane in place of the double bond.Rate this question:
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- 19.
Ozonolysis of molecule A would result in the formation of what functional groups?
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Two ketones
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Two carboxylic acids
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A ketone and an aldehyde
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Two aldehydes
Correct Answer
A. Two carboxylic acidsExplanation
Ozonolysis is a reaction in which ozone (O3) is used to cleave carbon-carbon double bonds. In molecule A, the ozonolysis reaction would break the double bond, resulting in the formation of two carbonyl groups. A carbonyl group consists of a carbon atom double bonded to an oxygen atom. When these carbonyl groups are further oxidized, they can be converted into carboxylic acid functional groups. Therefore, the correct answer is two carboxylic acids.Rate this question:
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- 20.
Which of the following reactions would result in the formation of a cis alkene?
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B only
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D only
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A only
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A and B only
Correct Answer
A. A onlyExplanation
H2/Lindlar Catalyst of an alkyne results in a cis alkene. Li/NH3 of an alkyne results in a trans alkene. 2HX results in markovnikov addition of X, twice.Rate this question:
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- 21.
Which of the following reagents could be used in the reaction below?
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SOCl2
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Cl2/H2O
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PBr3
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HCl/Ether
Correct Answer
A. HCl/EtherExplanation
SOCl2 would not work because it's a substitution reaction that only works on primary and secondary carbons.Rate this question:
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- 22.
Rank the following ions in order of increasing nucleophilicity.
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C, D, A, B
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D, A, C, B
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A, B, C, D
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A, C, B, D
Correct Answer
A. A, C, B, DExplanation
Negatively charged atoms make better nucleophiles than neutral atoms. Thus, B and E are better nucleophiles than A and C. Between B and D, oxygen is a more electronegative element than iodine. Electronegative elements like to hold onto their electrons more tightly, and nucleophilicity is the measure of how well an atom donates a pair of electrons to form a covalent bond. Because of this, D is a better nucleophile than B. This is also the reason C is a better nucleophile than A.Rate this question:
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- 23.
The scheme below is an example of which type of reaction?
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SN1
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E1
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SN2
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E2
Correct Answer
A. SN1Explanation
This is clearly a substitution reaction, but which type? For SN2 reactions, because both parts of the mechanism happen at the same time, you'd get only one product. Here there is two products, so the reaction must be an SN1 reaction.Rate this question:
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- 24.
Which set of reagents could be used in the reaction below?
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LiAlH4 then Br2
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NaBH4 then HBr
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PBr3 then HBr
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LiAlH4 then PBr3
Correct Answer
A. LiAlH4 then PBr3Explanation
First, we want to change the ester to an alcohol. We can do this with LiAlH4, a strong source of H- (unlike NaBH4, a weak source, which cannot react with esters or carboxylic acids). Then, we want to substitute the alcohol with Br, which can be done with PBr3 (which, remember, only works on primary and secondary carbons!)Rate this question:
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- 25.
How many valence electrons does Phosphorous (P) have?
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15
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13
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5
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3
Correct Answer
A. 5Explanation
Phosphorus (P) is located in group 15 of the periodic table, which means it has 5 valence electrons. Valence electrons are the electrons in the outermost energy level of an atom, and they determine the element's chemical properties and reactivity. Therefore, the correct answer is 5.Rate this question:
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- 26.
What types of orbitals are used to make bond A in the structure above?
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Sp2-sp2
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Sp3-sp3
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Sp2-sp3
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Sp2-sp
Correct Answer
A. Sp2-sp3Explanation
The correct answer is sp2-sp3. In the structure above, bond A is formed between two atoms. One of the atoms is hybridized with sp2 orbitals, while the other atom is hybridized with sp3 orbitals. This means that the bond is formed between an atom with three sigma bonds and an atom with four sigma bonds.Rate this question:
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- 27.
How many sigma bonds are there in the compound above?
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17
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7
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11
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15
Correct Answer
A. 15Explanation
The compound above contains 15 sigma bonds. A sigma bond is formed when two atomic orbitals overlap end-to-end, allowing for the sharing of electrons between atoms. In the given compound, there are multiple atoms bonded together, and each bond contributes one sigma bond. By counting the number of bonds in the compound, we can determine that there are 15 sigma bonds present.Rate this question:
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- 28.
How many non-bonding electrons are present in compound A? Assume all atoms are neutral.
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10
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6
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7
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12
Correct Answer
A. 10Explanation
Compound A has 10 non-bonding electrons. Non-bonding electrons are the electrons that are not involved in any chemical bond. In order to determine the number of non-bonding electrons in compound A, we need to know the electron configuration of its constituent atoms. Without this information, it is not possible to provide a more detailed explanation.Rate this question:
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- 29.
Assign values to bond angles A and B in the structure above.
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A = 120°, B = 180°
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A = 109.5°, B = 120°
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A = 120°, B = 120°
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A = 109.5°, B = 109.5°
Correct Answer
A. A = 109.5°, B = 120°Explanation
The given structure is likely a molecule with a trigonal bipyramidal geometry. In this geometry, the bond angles around the central atom are typically 90°, 120°, and 180°. The answer A = 109.5°, B = 120° is consistent with this geometry. The angle A of 109.5° suggests the presence of a lone pair on the central atom, which causes a slight compression of the bond angles. The angle B of 120° is one of the expected bond angles in a trigonal bipyramidal structure.Rate this question:
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- 30.
What are the formal charges on atoms A and B, respectively in the above structure?
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A = +1, B= -1
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A = +1, B= +1
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A = -1, B= 0
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A = 0, B= +1
Correct Answer
A. A = 0, B= +1Explanation
In the above structure, atom A has a formal charge of 0 because it has 4 valence electrons and is bonded to 4 other atoms, satisfying the octet rule. Atom B has a formal charge of +1 because it has 6 valence electrons and is bonded to only 3 other atoms, resulting in a deficiency of one electron.Rate this question:
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- 31.
What is the expected product of an E2 reaction starting with molecule X?
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B
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No reaction occurs
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A
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50/50 mixture of A and B
Correct Answer
A. AExplanation
To do these problems, draw Br and H in an anti-periplanar set up and create the double bond between them. whatever you have as a wedge (coming towards you) will be cis to each other on opposite sides of the bond, and whatever you have as a dash (going away from you) will be cis to each other.Rate this question:
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- 32.
Addition of the Dess-Martin periodinane to 2-propanol would result in which functional group?
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An alkene
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A ketone
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No reaction occurs
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An aldehyde
Correct Answer
A. A ketoneExplanation
When Dess-Martin periodinane is added to 2-propanol, it oxidizes the alcohol group to form a ketone. This is because Dess-Martin periodinane is a powerful oxidizing agent that can convert primary and secondary alcohols to aldehydes and ketones, respectively. In this case, 2-propanol is a secondary alcohol, so it will be converted to a ketone. Therefore, the correct answer is "A ketone".Rate this question:
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- 33.
True or False. A tertiary carbon radical is less stable than a secondary carbon radical.
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True
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False
Correct Answer
A. FalseExplanation
A tertiary carbon radical is more stable than a secondary carbon radical. This is because the presence of more alkyl groups attached to the radical carbon atom provides greater electron donation, stabilizing the radical through hyperconjugation. Additionally, the increased steric hindrance around the tertiary carbon atom makes it less likely to undergo reactions that lead to its destruction. Therefore, a tertiary carbon radical is more stable than a secondary carbon radical.Rate this question:
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- 34.
Which of the following would not be an expected product of the allylic bromination below?
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D
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B
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A
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C
Correct Answer
A. CExplanation
NBS adds Br to a carbon adjacent to the double bond. Note that while B seems impossible, it's actually formed from a resonance structure from the radical on an adjacent carbon.Rate this question:
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- 35.
Which of the following reactions involves a Grignard reagent?
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C
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A and B only
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A
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B
Correct Answer
A. AExplanation
The correct answer is A because a Grignard reagent is an organometallic compound that contains a carbon-metal bond, typically formed by reacting an alkyl or aryl halide with magnesium metal. In option A, the reaction involves a Grignard reagent, while options B and C do not mention the involvement of a Grignard reagent.Rate this question:
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- 36.
Which of the following statements is true for an SN2 reaction?
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Polar, protic solvents generally increase the reaction rate
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The N in SN2 stands for nitrogen
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The reaction involves a cationic intermediate
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The rate of reaction is dependent on the concentration of the nucleophile
Correct Answer
A. The rate of reaction is dependent on the concentration of the nucleophileExplanation
In an SN2 (substitution nucleophilic bimolecular) reaction, the rate of reaction is indeed dependent on the concentration of the nucleophile. This is because the nucleophile is involved in the rate-determining step of the reaction, where it attacks the electrophilic carbon center and forms a new bond. Therefore, a higher concentration of nucleophile will lead to a faster reaction rate. The other statements are incorrect. Polar, protic solvents generally decrease the reaction rate in SN2 reactions, the N in SN2 stands for nucleophilic, and the reaction does not involve a cationic intermediate.Rate this question:
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- 37.
Which of the following chair structures represents the lowest energy conformation of cis-1-methyl-2-isopropylcyclohexane?
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A
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D
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E
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B
Correct Answer
A. DExplanation
The chair structure D represents the lowest energy conformation of cis-1-methyl-2-isopropylcyclohexane. This is because in structure D, the bulky isopropyl group is in the equatorial position, which reduces steric hindrance compared to the axial position. This conformation minimizes the energy required for the molecule to adopt a stable shape.Rate this question:
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- 38.
Which of the above chair structures represents the lowest energy conformation of trans-1-fluoro-3-isopropylcyclohexane?
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A
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B
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D
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E
Correct Answer
A. D -
- 39.
Determine the conformational preferences (axial or equatorial) for the two indicated groups in the lowest energy ring flip of the molecule above.
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A – equatorial, B - equatorial
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A – axial, B - equatorial
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A – axial, B - axial
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A – equatorial, B - axial
Correct Answer
A. A – axial, B - equatorialExplanation
In the lowest energy ring flip, the group A is in the axial position and the group B is in the equatorial position. This is because the axial position is less sterically hindered compared to the equatorial position. The axial position is perpendicular to the plane of the ring, while the equatorial position is in the same plane as the ring. Therefore, group A prefers the axial position to minimize steric interactions, while group B prefers the equatorial position to maximize stability.Rate this question:
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- 40.
Rank the molecules below in order of increasing preference for an equatorial placement of the non-hydrogen substituent.
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E,B,A,D
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D,E,A,B
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B,E,A,D
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B,A,D,E
Correct Answer
A. B,E,A,DExplanation
The correct answer is B,E,A,D. In cyclohexane, bulky substituents prefer to be in the equatorial position to minimize steric hindrance. In the given answer, B is ranked first because it has the largest substituent and would prefer to be in the equatorial position. E is ranked second because it has a smaller substituent compared to B. A is ranked third because it has a smaller substituent compared to E. D is ranked last because it has the smallest substituent out of all the molecules.Rate this question:
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- 41.
Rank the following substituents from lowest to highest priority according to the Cahn-Ingold-Prelog rules.
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D,A,E,B
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B,E,D,A
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E,B,A,D
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A,D,E,B
Correct Answer
A. B,E,D,AExplanation
Double bonds have higher priority than single bonds (in terms of bonds to the same element). Similarly, triple bonds have higher priority than double bonds.Rate this question:
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- 42.
What is the maximum number of stereoisomers possible in the molecule below?
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2
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8
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4
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16
Correct Answer
A. 2Explanation
The given molecule has a chiral center, which means it can exist in two different stereoisomeric forms. This is because the carbon atom in the molecule is bonded to four different groups, resulting in two possible spatial arrangements. Therefore, the maximum number of stereoisomers possible in this molecule is 2.Rate this question:
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- 43.
What is the relationship between molecules A and B?
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They are the same
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They are constitutional isomers
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They are enantiomers
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They are diastereomers
Correct Answer
A. They are constitutional isomersExplanation
Molecules A and B are constitutional isomers because they have the same molecular formula but a different connectivity of atoms. In other words, they have the same types and numbers of atoms, but the atoms are arranged differently in the two molecules. This results in different chemical properties and reactivities between the two isomers.Rate this question:
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- 44.
Which of the following thermodynamic values describes an endothermic reaction?
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∆S is a negative number
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∆H is a negative number
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∆H is a positive number
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∆G is a positive number
Correct Answer
A. ∆H is a positive numberExplanation
An endothermic reaction is a reaction that absorbs heat from its surroundings, resulting in an increase in the enthalpy (∆H) of the system. A positive ∆H value indicates that the reaction is endothermic because it requires energy input to occur.Rate this question:
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- 45.
Which of the following would be expected to behave as a nucleophile?
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A and D only
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A, D, and E only
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B only
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A, B, and D only
Correct Answer
A. A and D onlyExplanation
A nucleophile is a chemical species that donates a pair of electrons to form a chemical bond. In this question, the answer "A and D only" suggests that only molecules labeled A and D would be expected to behave as nucleophiles. This means that these molecules have a pair of electrons available for donation. The other options, B and E, are not expected to behave as nucleophiles because they do not have the necessary electron pair.Rate this question:
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- 46.
Determine the degree(s) of unsaturation for the molecule below.
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5
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4
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2
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3
Correct Answer
A. 4Explanation
Rings add one degree of unsaturation, double bonds also add one degree of unsaturation, and triple bonds add two degrees of unsaturation.Rate this question:
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- 47.
Which of the following reactions would NOT result in a 50/50 mixture of stereoisomeric products?
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Both reaction A and B
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Neither reaction A nor B
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Reaction A
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Reaction B
Correct Answer
A. Reaction BExplanation
The first step in approaching these kind of problems is to find out the chirality of the reactant. Reaction A has no chiral centers in the reactant. Reaction B already has one chiral center in the reactant.
From this, the next step is to find out the chirality of the products. Reaction A would result in two products, one with the Chlorine towards us and the hydrogen away, and one with the Cl away from us and the hydrogen towards us. Because that's the only chiral center, the two products must be enantiomers, and enantiomers are formed in 50/50 mixtures.
As for reaction B, the same thing would happen, where we end up with chlorine either towards or away from us. Because there was already a chiral center before, in this second molecule, AND because that chiral center does NOT change in R/S designation (as it's drawn, it's R), we get two molecules that are DIASTEREOMERS to each other. Diastereomers are not formed in 50/50 mixtures. Thus, the answer is reaction B.Rate this question:
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- 48.
Which of the following starting materials could be used in the reaction below?
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A and B only
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A and D only
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B only
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A only
Correct Answer
A. A and B onlyExplanation
The reaction requires both starting materials A and B to occur. Starting materials A and D cannot be used together in this reaction. Starting material B is not sufficient on its own. Starting material A is also not sufficient on its own. Therefore, the correct answer is A and B only.Rate this question:
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- 49.
Which of the following products would be produced from hydroboration/oxidation of 1-pentyne?
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E only
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B and E only
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A and B only
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A only
Correct Answer
A. E onlyExplanation
BH3 with a terminal alkyne produces a terminal aldehyde.Rate this question:
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