This quiz, titled 'Catholic Central Ch. 3 Chemistry Review', assesses understanding of fundamental chemical laws through questions on Dalton's atomic theory, laws of conservation of mass, multiple proportions, and definite proportions. It evaluates key concepts crucial for mastering chemistry.
Unable to determine
15 mass units
30 mass units
A ratio of 1:2
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Multiple ratios
Multiple proportions
Conservation of mass
Definite composition
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Ms. Watson
Milikan
Rutherford
Dalton
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Rutherford
Dalton
Niels Bohr
Andy Dalton
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Of the same element are the same in size, mass, and other properties
Of isotopes are the same in size, mass, and other properties
Of different elements are the same in size, mass, and other properties
Are extremely maleable
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Chili mac n cheese
Low pressure Cesium
High pressure gas
Low pressure gas
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The were negatively charged (electrons)
Because like forces attract
The negative plate was radioactive
The cathode rays were positively charged protons
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Nuclide
Nucleon
Nucleus
Nucleolus
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Neutral
Positively charged
Negatively charged
Slimy and a dark
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The strong nuclear forces within the nucleus
The number of protons is equal to the number of electrons
Dalton's atomic theory
Atoms are not neutral
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Nuclear Forces
Changes of state forces
Bonding
Pauli Exclusion forces
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The electron
The atom
I don't know because that was from chapter 1
The proton
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Amount of energy
Different isothermal properties
Atomic numbers
Mass numbers
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Protons and neutrons
Protons and electrons
Neutrons and electrons
Undertermined
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1
2
10
3
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Yttrium
Tritium
Protium
Dueterium
None of them
Protium
Dueterium
Tritium
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Number of electrons
Number of protons
Number of neutrons
Number of times the Bengals have gone to the Superbowl
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Dueterium
Um.... what standard?
The carbon- 12 atom
The carbon-14 atom
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12
6
7
14
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6.022x10^32
6.022x10^23
6.042x10^32
12.022x10^23
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8
9
7
14
30 tiny moles
16g/mol
18g/mol
32g/mol
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The average atomic mass
The atomic number (z)
The isotope mass
The elements telephone number
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Cannot be determined
132.9g
1329g
664.5g
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4
1
2
3
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1
4
3
2
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Multiply 2 moles by the molar mass of water which is 36g/mole
Multiply 3 moles by the molar mass of water which is 18g/mole
Multiply 2 moles by the molar mass of water which is 18g/mole
Ask a crystal ball
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6.022x10^23 x 2
6.022x10^3 x 2
6.022x10^23 x 3
It DEPENDS on the compound
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Take the weighted average of the isotopes and their atomic masses
You add the number of protons and neutrons together
You add together all the isotopes' masses
You take the mass of one mole divided by the molar mass
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