To determine the number of admissible values of x, we need to find the values of x for which the area of the triangle is an integer. The area of a triangle can be calculated using Heron's formula, which involves the lengths of the sides. The formula is: 
Area = sqrt(s * (s - a) * (s - b) * (s - c)), 
where s is the semi-perimeter of the triangle and a, b, and c are the lengths of its sides. 
In this case, the lengths of the sides are 9x+1, 6x+2, and 3x+3. 
We can calculate the semi-perimeter as: 
s = (9x+1 + 6x+2 + 3x+3) / 2 = 9x + 3. 
Substituting the values of the sides and the semi-perimeter into the area formula, we get: 
Area = sqrt((9x+3) * (9x+3 - (9x+1)) * (9x+3 - (6x+2)) * (9x+3 - (3x+3))) 
Simplifying this expression, we get: 
Area = sqrt((9x+3) * 4 * 3 * (6x)) 
Area = sqrt(216x^2 + 216x + 36) 
For the area to be an integer, the expression inside the square root must be a perfect square. 
216x^2 + 216x + 36 = k^2, where k is an integer. 
Simplifying this equation, we get: 
54x^2 + 54x + 9 = (3x + 1)^2 = k^2 
This is a quadratic equation in terms of x. By factoring, we can rewrite it as: 
(3x + 1 - k)(3x + 1 + k) = 9 
The factors on the left-hand side must be divisors of 9. The divisors of 9 are 1, 3, and 9. 
We can set up three separate equations and solve for x: 
1) 3x + 1 - k = 1 and 3x + 1 + k = 9 
2) 3x + 1 - k =