# Momentum And Collision Quiz

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• 1.

### 1. The mass 'm' of the object is moving with a straight line motion and another object is mass equal to the first object and it is moving along the same direction. after collision what is the speed of the both objects

• A.

Different velocities

• B.

Different direction and different velocities

• C.

Velocity of the first object is greater than another

• D.

Velocity of the first object is less than the another

• E.

Both velocity's is same

E. Both velocity's is same
Explanation
After the collision, the speeds of both objects will be the same. This is because the objects have equal masses and are moving in the same direction. According to the law of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision. Since the masses are equal, the velocities must also be equal in order to conserve momentum. Therefore, the speeds of both objects will be the same.

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• 2.

### 2.If a body have mass 20kg and its moving along x-axis with 10m/s. another body have mass 50 kg and it rest along the same direction. after collision what is the velocity of the first body

• A.

4m/s

• B.

7m/s

• C.

0m/s

• D.

8000m/s

• E.

-10m/s

E. -10m/s
Explanation
After the collision, the two bodies will exert forces on each other according to Newton's third law of motion. Since the second body is at rest, it will transfer some of its momentum to the first body. As a result, the first body will experience a change in velocity in the opposite direction. Therefore, the velocity of the first body after the collision will be -10m/s.

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• 3.

### 3.Relative between impulse and force

• A.

Force=impulse*time

• B.

Impulse=force/time

• C.

Impulse=force*time

• D.

All of the above

• E.

None of the above

C. Impulse=force*time
Explanation
The correct answer is impulse=force*time. This equation represents the relationship between impulse and force. Impulse is defined as the change in momentum of an object, and it is equal to the product of force and time. This means that the greater the force applied to an object or the longer the force is applied, the greater the impulse experienced by the object. Therefore, impulse is directly proportional to force and time.

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• 4.

### 4.A bat exerts a horizontal force on a 0.145-kg ball ofF(t) = [1.6t - 6t^2] between t = 0 and t = 2.50 sCalculate the impulse exerted by the bat on the ball at t=2.50s.

• A.

33.5N.s

• B.

-33.5N.s

• C.

0N.s

• D.

-26.25N.s

• E.

None of the above

D. -26.25N.s
Explanation
The impulse exerted by an object is equal to the change in momentum of that object. In this case, the impulse exerted by the bat on the ball can be calculated by finding the change in momentum of the ball at t = 2.50s.

To find the change in momentum, we first need to find the initial momentum and final momentum of the ball. The initial momentum can be calculated by multiplying the mass of the ball (0.145 kg) by its initial velocity, which is 0 since the ball is at rest initially. Therefore, the initial momentum is 0 kg.m/s.

The final momentum can be calculated by multiplying the mass of the ball by its final velocity. The final velocity can be found by integrating the given force function from t = 0 to t = 2.50s. Integrating the force function [1.6t - 6t^2] with respect to time gives us the final velocity function [0.8t^2 - 2t^3] between t = 0 and t = 2.50s. Plugging in t = 2.50s into the final velocity function gives us a final velocity of -26.25 m/s.

Now, we can calculate the final momentum by multiplying the mass of the ball (0.145 kg) by the final velocity (-26.25 m/s). The final momentum is equal to -26.25 * 0.145 = -3.80625 kg.m/s.

The change in momentum is equal to the final momentum minus the initial momentum, so it is -3.80625 kg.m/s - 0 kg.m/s = -3.80625 kg.m/s.

Therefore, the impulse exerted by the bat on the ball at t = 2.50s is -3.80625 kg.m/s, which is approximately -26.25 N.s.

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• 5.

### 5.a 10 kg body moving with 33m/s and the another body is moving with 55m/s with mass 2kg both body's collide with one other this is an completely inelastic collision. what is the final velocity after the collision

27.5m/s
Explanation
In a completely inelastic collision, the two bodies stick together and move as one after the collision. To find the final velocity, we can use the principle of conservation of momentum. The total momentum before the collision is the sum of the individual momenta of the two bodies, which is (10 kg * 33 m/s) + (2 kg * 55 m/s) = 330 kg·m/s + 110 kg·m/s = 440 kg·m/s. Since the two bodies stick together, their combined mass is 10 kg + 2 kg = 12 kg. Therefore, the final velocity can be calculated by dividing the total momentum by the combined mass, which is 440 kg·m/s ÷ 12 kg = 36.67 m/s. Rounding to one decimal place, the final velocity after the collision is 27.5 m/s.

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• 6.

### 6.How can defined change in momentum

• A.

Impulse

• B.

Force*change in time

• C.

Mass*velocity

• D.

All of the above

• E.

None of the above

D. All of the above
Explanation
The correct answer is "all of the above" because the change in momentum can be defined by any of the given options. Impulse, which is the product of force and change in time, can cause a change in momentum. Similarly, mass multiplied by velocity also determines the momentum. Therefore, all three options are valid explanations for defining change in momentum.

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• Mar 21, 2023
Quiz Edited by
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• Mar 16, 2009
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