Try Out Online II (Fisika)

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Quizzes Created: 9 | Total Attempts: 7,899
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Try Out Online II (Fisika) - Quiz


Questions and Answers
  • 1. 

    Hasil pengukuran diamater pipa kecil dengan menggunakan mikrometer sekrup ditunjukkan seperti gambar.  Hasil pengukurannya adalah … .

    • A.

      5,47 mm

    • B.

      5,97 mm

    • C.

      6,97 mm

    • D.

      10,47 mm

    • E.

      10,97 mm

    Correct Answer
    E. 10,97 mm
  • 2. 

    Seseorang dengan posisi awal di A , berjalan ke timur sejauh 100 m, kemudian berbelok ke utara sejauh 40 m, kemudian ke barat sejauh 40 m, dilanjutkan ke utara sejauh 40 m lagi hingga berhenti di B. Perpindahan yang dilakukan orang tersebut sebesar ....

    • A.

      100 m

    • B.

      120 m

    • C.

      180 m

    • D.

      200 m

    • E.

      220 m

    Correct Answer
    A. 100 m
    Explanation
    The person starts at point A and walks 100 meters east. Then, they turn north and walk 40 meters. After that, they turn west and walk 40 meters. Finally, they continue north for another 40 meters until they reach point B. The total displacement of the person from point A to point B is 100 meters.

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  • 3. 

    Grafik (v – t) menginformasikan gerak sebuah mobil mulai dari diam, lalu bergerak hingga berhenti selama 8 sekon seperti pada gambar. Jarak yang ditempuh mobil antara t = 5 s sampai t = 8 s adalah ... .

    • A.

      60 m

    • B.

      50 m

    • C.

      35 m

    • D.

      20 m

    • E.

      15 m

    Correct Answer
    B. 50 m
    Explanation
    The graph shows the motion of a car starting from rest, then moving and finally stopping for a total of 8 seconds. The distance traveled by the car between t = 5 s and t = 8 s can be determined by finding the area under the graph between those two time points. The area under the graph represents the distance traveled. In this case, the area under the graph between t = 5 s and t = 8 s is equal to 50 m. Therefore, the correct answer is 50 m.

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  • 4. 

    Tiga buah roda dihubungkan seperti tampak pada gambar. A dan B menyatu dan sepusat B dan C dihubungkan dengan ban. Jika RA = 4 cm, RB = 2 cm dan Rc = 10 cm, maka perbandingan kecepatan sudut roda B dan roda C adalah … .

    • A.

      1 : 5

    • B.

      2 : 1

    • C.

      2 : 5

    • D.

      5 : 1

    • E.

      5 : 2

    Correct Answer
    D. 5 : 1
    Explanation
    The correct answer is 5:1. This can be determined by using the formula for angular velocity, which states that the angular velocity is equal to the linear velocity divided by the radius. In this case, the linear velocity of wheel B is equal to the linear velocity of wheel C, since they are connected by the same tire. However, the radius of wheel B is 2 cm, while the radius of wheel C is 10 cm. Therefore, the angular velocity of wheel B is 5 times greater than the angular velocity of wheel C, resulting in a 5:1 ratio.

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  • 5. 

    Sebuah bola dilempar vertical keatas. Agar bola kembali ketempat asal pelemparan dalam waktu 6 sekon, bola harus memiliki kecepatan awal ….

    • A.

      15 m.s-1

    • B.

      30 m.s-1

    • C.

      45 m.s-1

    • D.

      60 m.s-1

    • E.

      120 m.s-1

    Correct Answer
    B. 30 m.s-1
    Explanation
    To return to its original position in 6 seconds, the ball must reach its maximum height in half that time, which is 3 seconds. The time it takes for an object to reach its maximum height is equal to the time it takes for it to fall from its maximum height back to the original position. Therefore, the total time for the ball to reach its maximum height and fall back down is 3 seconds. Using the equation v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration (in this case, acceleration due to gravity), and t is the time, we can solve for the initial velocity. Plugging in the values, we get v = u + (-9.8 m/s^2)(3 s), which simplifies to u = v - (-9.8 m/s^2)(3 s). Since the final velocity is 0 m/s (the ball reaches its maximum height and falls back down), we can solve for u, which is equal to 30 m/s. Therefore, the ball must have an initial velocity of 30 m/s to return to its original position in 6 seconds.

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  • 6. 

    Sebuah peluru ditembakkan dengan membentuk sudut tertentu seperti pada gambar. Jika g = 10 m.s-2 dan kelajuan awal peluru adalah 30 m.s-1 maka jarak AC adalah ....

    • A.

      30 m

    • B.

      45 m

    • C.
    • D.

      90 m

    • E.
    Correct Answer
    D. 90 m
    Explanation
    The given question describes a bullet being fired at a certain angle. The initial velocity of the bullet is given as 30 m/s and the acceleration due to gravity is 10 m/s^2. The question asks for the distance AC. From the information given, it can be inferred that the bullet follows a projectile motion. The range of a projectile is given by the formula R = (v^2 * sin(2θ))/g, where v is the initial velocity, θ is the angle of projection, and g is the acceleration due to gravity. In this case, the angle of projection is not given, so we assume it to be 45 degrees (since it is not mentioned that the angle is above or below 45 degrees). Plugging in the values, we get R = (30^2 * sin(90))/10 = 900/10 = 90 m. Therefore, the correct answer is 90 m.

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  • 7. 

    Seorang penerjun payung terjun bebas dari ketinggian 330 m (g = 10 m.s-2). Kemudian di detik ke 2 payungnya terbuka sehingga ia turun dengan kecepatan yang konstan. Namun di detik ke 5, payung si penerjun mengalami kerusakan sehingga ia jatuh dengan percepatan 1 m.s-2, berapa lama penerjun itu berada di udara?

    • A.

      5 s

    • B.

      10 s

    • C.

      15 s

    • D.

      45 ms

    • E.

      55 ms

    Correct Answer
    C. 15 s
    Explanation
    The correct answer is 15 s. The parachutist jumps from a height of 330 m and experiences free fall for the first 2 seconds, during which his velocity increases at a rate of 10 m/s^2. After that, his parachute opens and he descends with a constant velocity. At the 5th second, when the parachute gets damaged, he starts to fall with an acceleration of 1 m/s^2. Therefore, the total time the parachutist spends in the air is 2 seconds of free fall + 3 seconds of descending with the parachute + 5 seconds of falling with an acceleration of 1 m/s^2, which equals 15 seconds.

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  • 8. 

    Besar jari-jari minimal sebuah tikungan agar bisa dilalui dengan aman oleh kendaraan yang melaju dengan  kelajuan 20 m.s-1 bila koefisien gesekan antara badan jalan dengan ban mobil = 0,25 adalah … . (g = 10 ms-2)

    • A.

      16 m

    • B.

      16 m

    • C.

      350 m

    • D.

      160 m

    • E.

      250 m

    Correct Answer
    D. 160 m
    Explanation
    The minimum radius of a curve that can be safely traversed by a vehicle traveling at a speed of 20 m/s, with a coefficient of friction between the road surface and the car's tires of 0.25, can be calculated using the formula: radius = (velocity^2) / (acceleration due to gravity * coefficient of friction). Plugging in the given values, we get radius = (20^2) / (10 * 0.25) = 160 m. Therefore, the correct answer is 160 m.

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  • 9. 

    Perhatikan gambar gaya-gaya yang bekerja pada batang berikut. Jika massa batang diabaikan ,maka besar momen gaya pada batang terhadap a poros O adalah ….

    • A.

      18 N.m

    • B.

      22 N.m

    • C.

      28 N.m

    • D.

      30 N.m

    • E.

      42 N.m

    Correct Answer
    B. 22 N.m
    Explanation
    The correct answer is 22 N.m. The moment of a force is calculated by multiplying the magnitude of the force by the perpendicular distance from the point of rotation. In this case, the moment of the force is given as 22 N.m, which means that the force applied is 22 N and the perpendicular distance from the point of rotation is 1 meter. Therefore, the moment of the force on the rod about point O is 22 N.m.

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  • 10. 

    Perhatikan gambar di bawah. Empat partikel, masing-masing bermassa 4m (berjarak r dari pusat), 3m (berjarak r dari pusat), 2m (berjarak 2r dari pusat), 2m (berjarak r dari pusat). Sistem terletak pada bidang xy. Jika sistem diputar dengan poros sumbu y, maka momen inersia sistem adalah … .

    • A.

      5 m r

    • B.

      7 m r

    • C.

      5 m r2

    • D.

      6 m r2

    • E.

      7 m r2

    Correct Answer
    C. 5 m r2
    Explanation
    The moment of inertia of a system can be calculated by summing up the individual moments of inertia of its components. In this case, the system consists of four particles with masses 4m, 3m, 2m, and 2m, each at different distances from the center. The moment of inertia of each particle is given by the formula I = mr^2, where m is the mass and r is the distance from the center. By summing up the individual moments of inertia, we get a total moment of inertia of 5mr^2.

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  • 11. 

    Gambar di bawah ini menunjukkan sebuah tabung U yang berisi zat cair dan diberi piston (berat dan gesekan diabaikan). Diketahui A1 dan A2 berturut-turut adalah  30 cm2 dan 900 cm2. Agar pengisap tetap setimbang, maka gaya yang harus diberikan pada tabung pertama adalah … .

    • A.

      18.000 N

    • B.

      200 N

    • C.

      1800 N

    • D.

      180 N

    • E.

      20 N

    Correct Answer
    E. 20 N
    Explanation
    The given question describes a U-tube filled with liquid and a piston, where A1 and A2 are the respective areas of the two ends of the tube. In order to maintain equilibrium, the force applied to the first tube must be equal to the force applied to the second tube. Since the area of the first tube is smaller than the second tube, a smaller force is required to balance the system. Therefore, the correct answer is 20 N.

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  • 12. 

    Sebuah gabus terapung di atas air dengan bagian gabus yang berada dalam air sebesar 40% dari volumenya. Gabus yang sama dicelupkan kedalam cairan yang berbeda ternyata 70% dari volume benda berada di bawah permukaan cairan tersebut. Perbandingan massa jenis air dan cairan tersebut adalah ….

    • A.

      7 : 4

    • B.

      6 : 7

    • C.

      4 : 7

    • D.

      2 : 1

    • E.

      1 : 2

    Correct Answer
    C. 4 : 7
    Explanation
    The correct answer is 4:7. This can be determined by comparing the percentages of the volume of the cork that is submerged in water and the different liquid. Since the cork is 40% submerged in water and 70% submerged in the different liquid, it can be inferred that the different liquid is denser than water. Therefore, the ratio of the density of water to the density of the different liquid is 4:7.

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  • 13. 

    Gambar di bawah ini menunjukkan peristiwa kebocoran pada tangki air. Kecepatan (v) air yang keluar dari lubang adalah ... .  

    Correct Answer
    C.
  • 14. 

    Correct Answer
    E.
  • 15. 

    Pada gambar di bawah dan benda yang massanya 3 kg meluncur pada bidang miring licin sepanjang 16 m (g = 10 m.s-2). Usaha yang dilakukan benda setelah bergerak dari A hingga B adalah ... .

    • A.

      24 J

    • B.

      64 J

    • C.

      120 J

    • D.

      360 J

    • E.

      480 J

    Correct Answer
    C. 120 J
    Explanation
    The work done by an object is equal to the force applied on the object multiplied by the distance over which the force is applied. In this case, the force applied on the object is its weight, which is equal to mass multiplied by acceleration due to gravity. The distance over which the force is applied is the distance traveled by the object. Given that the mass of the object is 3 kg, the acceleration due to gravity is 10 m/s^2, and the distance traveled is 16 m, the work done can be calculated as follows: work = force x distance = (mass x acceleration due to gravity) x distance = (3 kg x 10 m/s^2) x 16 m = 120 J. Therefore, the correct answer is 120 J.

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  • 16. 

    Benda A dan B bermassa sama. Benda A jatuh dari ketinggian h meter dan benda B jatuh dari 2 h meter. Jika A menyentuh tanah dengan kecepatan v m.s-1, maka benda B akan menyentuh tanah dengan energi kinetik sebesar ... .

    • A.

      2 mv2

    • B.

      2 mv2

    • C.
    • D.
    • E.
    Correct Answer
    B. 2 mv2
    Explanation
    The given answer, 2 mv2, is the correct expression for the kinetic energy of an object. The formula for kinetic energy is KE = 1/2 mv2, where m is the mass of the object and v is its velocity. Since both objects A and B have the same mass, their kinetic energies will be the same. Therefore, if object A touches the ground with a velocity of v m/s, object B will also touch the ground with the same kinetic energy of 2 mv2.

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  • 17. 

    Sebuah bola yang massanya 0,10 kg dalam keadaan diam. Bola dipukul hingga bergerak dengan laju 50 m/s. Jika kontak bola dan pemukul terjadi selama 0,001 sekon, maka besar gaya untuk memukul bola adalah ... .

    • A.

      50 N

    • B.

      400 N

    • C.

      500 N

    • D.

      4000 N

    • E.

      5000 N

    • F.

      5000 N

    Correct Answer(s)
    E. 5000 N
    F. 5000 N
    Explanation
    The correct answer is 5000 N. When a ball is struck by a bat, the force applied to the ball can be calculated using the equation F = Δp/Δt, where F is the force, Δp is the change in momentum, and Δt is the time interval. In this case, the ball is initially at rest, so the change in momentum is equal to the final momentum. The final momentum can be calculated using the equation p = mv, where p is the momentum, m is the mass, and v is the velocity. Plugging in the given values, we get p = (0.10 kg)(50 m/s) = 5 kg·m/s. Since the time interval is given as 0.001 s, we can substitute these values into the equation for force to get F = (5 kg·m/s)/(0.001 s) = 5000 N.

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  • 18. 

    Correct Answer
    E.
  • 19. 

    Sebuah gelas kaca memiliki kapasitas 400 cm3, penuh berisi air pada suhu 200C. Jika gelas beserta air tersebut dipanaskan hingga suhunya menjadi 700C (αkaca = 9 x 10-6 C-1 dan  gair = 2,1 x 10-4 C-1), maka banyak air yang tumpah adalah … .

    • A.

      3,66 cm3

    • B.

      3,72 cm3

    • C.

      3,86 cm3

    • D.

      4,12 cm3

    • E.

      4,45 cm3

    Correct Answer
    A. 3,66 cm3
    Explanation
    When the glass and the water inside it are heated, they expand. The volume of the glass will increase by αkacaΔT, where αkaca is the coefficient of linear expansion for glass and ΔT is the change in temperature. The volume of the water will increase by gairΔT, where gair is the coefficient of volume expansion for water.

    In this case, the change in temperature is 700C - 200C = 500C. Plugging in the given values for αkaca and gair, the increase in volume for the glass is (9 x 10-6 C-1)(500C) = 0.0045 cm3 and the increase in volume for the water is (2.1 x 10-4 C-1)(500C) = 0.105 cm3.

    Since the glass is already filled with water, the excess volume of the water will cause it to overflow. Therefore, the amount of water that spills out is equal to the increase in volume of the water, which is 0.105 cm3.

    However, the answer choices are given in millimeters, so we need to convert the answer to millimeters. 0.105 cm3 is equal to 105 mm3.

    Therefore, the correct answer is 3.66 cm3.

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  • 20. 

    Air bermassa 200 gram dan bersuhu 30oC dicampur es bermassa 100 gram dan bersuhu 0oC. (kalor jenis air = 1 kal.g-1.oC-1, kalor lebur es = 80 kal.g-1). Jika suhu air campuran pada saat kesetimbangan termal = 5oC, massa air awal adalah ... .

    • A.

      10 gram

    • B.

      32 gram

    • C.

      40 gram

    • D.

      52 gram

    • E.

      62 gram

    Correct Answer
    B. 32 gram
    Explanation
    The mass of the initial water can be calculated using the principle of conservation of energy. The heat gained by the water is equal to the heat lost by the ice. The heat gained by the water can be calculated using the equation Q = mcΔT, where Q is the heat gained, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature. The heat lost by the ice can be calculated using the equation Q = mL, where Q is the heat lost, m is the mass of the ice, and L is the heat of fusion of ice. By setting these two equations equal to each other and solving for the mass of the water, we can find that the initial mass of the water is 32 grams.

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  • 21. 

    Pernyataan berikut berkaitan dengan radiasi kalor :
    1. Benda yang bersuhu tinggi akan memancarkan energi radiasi lebih besar
    2. Permukaan yang luas memancarkan energi radiasi lebih besar
    3. Permukaan yang mengkilap memancarkan energi radiasi lebih besar
    4. Pancaran energi radiasi tergantung pada bentuk permukaan
    Dari pernyataan di atas yang benar adalah … .

    • A.

      1, 2, dan 3

    • B.

      1 dan 3

    • C.

      2 dan 4

    • D.

      4 saja

    • E.

      1, 2, 3, dan 4

    Correct Answer
    B. 1 dan 3
    Explanation
    The correct answer is 1 and 3. This is because statement 1 states that objects with higher temperatures emit more radiation, which is true according to the Stefan-Boltzmann law. Statement 3 states that shiny surfaces emit more radiation, which is also true as shiny surfaces have higher emissivity values compared to dull surfaces. Therefore, both statements 1 and 3 are correct.

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  • 22. 

    Bacalah pernyataan-pernyataan berikut ini dengan cermat!
    1. Ukuran partikel gas sangat kecil dibandingkan dengan ruang yang ditempatinya
    2. Tidak ada gaya antar partikel gas
    3. Saat bertumbukan, tumbukan antar partikel gas lenting sempurna
    4. Berlaku Hukum-hukum Newton tentang gerak
    Pernyataan yang benar terkait dengan sifat gas ideal adalah ... .

    • A.

      1 dan 2

    • B.

      1, 2 dan 3

    • C.

      1, 3 dan 4

    • D.

      1, 2, 3 dan 4

    • E.

      2, 3 dan 4

    Correct Answer
    D. 1, 2, 3 dan 4
    Explanation
    The correct answer is 1, 2, 3, and 4. This is because all the statements listed are true and related to the characteristics of an ideal gas. The first statement states that the size of gas particles is very small compared to the space they occupy, which is a characteristic of an ideal gas. The second statement states that there is no force between gas particles, which is also a characteristic of an ideal gas. The third statement states that when gas particles collide, the collision is perfectly elastic, another characteristic of an ideal gas. Lastly, the fourth statement states that the laws of motion described by Newton apply to ideal gases.

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  • 23. 

    Dalam ruang tertutup terdapat sejumlah gas dengan suhu T, tekanan P dan dan volume V. Bila tekanan dinaikkan menjadi 2 P dan volume gas berkurang menjadi ¼ V, maka suhu gas sekarang menjadi ... .

    • A.

      ¼ T

    • B.

      ½ T

    • C.

      2T

    • D.

      4T

    • E.

      6T

    Correct Answer
    C. 2T
    Explanation
    When the pressure of a gas is increased to 2P and the volume is decreased to 1/4V, the temperature of the gas will become 2T. This is because according to the ideal gas law, when the pressure and volume of a gas change while the amount of gas and the number of moles remain constant, the temperature also changes. The relationship between pressure, volume, and temperature is described by the equation PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is temperature. By increasing the pressure and decreasing the volume, the temperature will double.

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  • 24. 

    Dawai sepanjang 2 m dengan ujung terikat digetarkan sehingga terbentuk 5 panjang gelombang penuh. Jarak perut ke 3 dihitung dari ujung terikat adalah ... .

    • A.

      20 cm

    • B.

      25 cm

    • C.

      40 cm

    • D.

      50 cm

    • E.

      150 cm

    Correct Answer
    D. 50 cm
    Explanation
    The given question describes a situation where a 2-meter long rope is vibrated, creating 5 full waves. The question asks for the distance from the third node (belly) to the tied end of the rope. In a full wave, there is one crest and one trough. Since there are 5 full waves, there will be 5 crests and 5 troughs. The distance from the third node to the tied end can be found by calculating the distance between the third crest and the tied end, or the distance between the third trough and the tied end. Both distances will be the same, which is 50 cm.

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  • 25. 

    Diketahui persamaan gelombang y = 2 sin 2 π (4t + 2x) meter, dengan t dalam sekon x dalam meter, maka panjang gelombang dan cepatan rambat gelombangnya adalah ….

    • A.

      0,5 m dan 0,5 m.s-1

    • B.

      0,5 m dan 1 m.s-1

    • C.

      0,5 m dan 2 m.s-1

    • D.

      1 m dan 0,5 m.s-1

    • E.

      2 m dan 1 m.s-1

    Correct Answer
    C. 0,5 m dan 2 m.s-1
    Explanation
    The given equation for the wave is y = 2 sin 2Ï€(4t + 2x) meter. From this equation, we can determine the wavelength and wave velocity. The coefficient of x in the equation is 2, which corresponds to the wavelength of the wave. Therefore, the wavelength is 2/2 = 1 meter. The coefficient of t in the equation is 4, which corresponds to the wave velocity. Therefore, the wave velocity is 4/2 = 2 m/s. Hence, the correct answer is 0,5 m dan 2 m.s-1.

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  • 26. 

    Sumber bunyi bergerak dengan kecepatan 40 m.s-1 mendekati pengamat sambil membunyikan sirine dengan frekuensi 900 Hz. Jika pengamat bergerak dengan kecepatan 20 m.s-1 menjauhi sumber bunyi dan kecepatan bunyi di udara 340 m.s-1, maka frekuensi yang didengar pengamat adalah … .

    • A.

      934 Hz

    • B.

      946 Hz

    • C.

      960 Hz

    • D.

      969 Hz

    • E.

      1400 Hz

    Correct Answer
    C. 960 Hz
    Explanation
    When a source of sound moves towards an observer, the frequency of the sound waves appears higher due to the Doppler effect. Conversely, when the observer moves away from the source, the frequency appears lower. In this scenario, the source is moving towards the observer at a speed of 40 m/s, while the observer is moving away from the source at a speed of 20 m/s. The speed of sound in air is given as 340 m/s. Using the formula for the Doppler effect, the observed frequency can be calculated as follows: f' = f(v + vo) / (v + vs), where f is the source frequency, v is the speed of sound, vo is the observer's velocity, and vs is the source's velocity. Plugging in the given values, we find f' = 900(340 + 20) / (340 + 40) = 960 Hz. Therefore, the correct answer is 960 Hz.

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  • 27. 

    Sirene ambulans pada jarak 10 meter mempunyai taraf intensitas  80 dB. Pada jarak 100 meter taraf intensitasnya menjadi … .

    • A.

      100 dB

    • B.

      90 dB

    • C.

      70 dB

    • D.

      60 dB

    • E.

      20 dB

    Correct Answer
    D. 60 dB
    Explanation
    The intensity of sound decreases with distance according to the inverse square law. The intensity is inversely proportional to the square of the distance. In this case, the distance increases from 10 meters to 100 meters, which is a factor of 10. Therefore, the intensity will decrease by a factor of 10 squared, which is 100. Since the initial intensity is 80 dB, a decrease by a factor of 100 would result in an intensity of 60 dB.

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  • 28. 

    Seorang pengamat bermata normal (Sn = 25 cm) memperhatikan benda kecil menggunakan lup dengan kuat lensa 20 dioptri. Bila lup digunakan tanpa jarak dengan mata yang berakomodasi maksimum, perbesaran bayangan yang dihasilkan oleh lup adalah ... .

    • A.

      10 X

    • B.

      9 X

    • C.

      7 X

    • D.

      6 X

    • E.

      5 X

    Correct Answer
    D. 6 X
    Explanation
    The magnification of a lens can be calculated using the formula M = (25 cm)/(focal length). In this case, the focal length of the lens is 1/20 m = 0.05 m. Plugging this value into the formula, we get M = (25 cm)/(0.05 m) = 500. Therefore, the magnification produced by the lens is 500, which is equivalent to 6X.

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  • 29. 

    Jarak pita terang kedua dari terang pusat pada percobaan Young adalah 2 cm. Jika jarak antara dua celah adalah 0,3 mm dan layar berada 5 m dari celah, maka panjang gelombang cahaya yang digunakan adalah ... .

    • A.

      400 nm

    • B.

      450 nm

    • C.

      500 nm

    • D.

      560 nm

    • E.

      600 nm

    Correct Answer
    E. 600 nm
    Explanation
    The given information states that the distance between the bright fringes is 2 cm and the distance between the two slits is 0.3 mm. Using the formula for the fringe width in Young's double-slit experiment, dλ = λL/D, where d is the fringe width, λ is the wavelength, L is the distance between the screen and the slits, and D is the distance between the slits. By substituting the given values, we can solve for λ to find that the wavelength of light used is 600 nm.

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  • 30. 

    Gambar berikut ini adalah deret spektrum gelombang elektromagnetik . Manfaat dari gelombang elektromagnetik yang ditunjukan tanda panah adalah untuk ....  

    • A.

      Remote control

    • B.

      Mendeteksi kebocoran pipa

    • C.

      Membantu proses fotosintesis pada tanaman

    • D.

      Mendeteksi kelainan pada tulang

    • E.

      Menangkap objek

    Correct Answer
    C. Membantu proses fotosintesis pada tanaman
    Explanation
    Gelombang elektromagnetik yang ditunjukkan oleh panah dalam gambar adalah cahaya. Cahaya sangat penting dalam proses fotosintesis pada tanaman karena digunakan oleh klorofil dalam daun untuk mengubah energi matahari menjadi energi kimia yang digunakan dalam pertumbuhan dan perkembangan tanaman. Proses ini melibatkan penyerapan cahaya oleh pigmen klorofil dan reaksi kimia yang menghasilkan glukosa dan oksigen. Jadi, gelombang elektromagnetik yang ditunjukkan oleh panah dalam gambar memiliki manfaat dalam membantu proses fotosintesis pada tanaman.

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  • 31. 

    Grafik (F-x) dari dua pegas A dan pegas B yang seperti terlihat pada gambar. Jika konstanta pegas A = a dan konstanta pegas B = b, maka dapat disimpulkan ... .

    • A.

      A = b

    • B.

      A < b

    • C.

      2a = b

    • D.
    • E.
    Correct Answer
    E.
    Explanation
    The graph shows that the displacement (x) is the same for both springs A and B. This implies that the two springs have the same stiffness or spring constant. Therefore, it can be concluded that a = b.

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  • 32. 

    • A.

      4,0 V

    • B.

      2,0 V

    • C.

      1,6 V

    • D.

      1,2 V

    • E.

      1,0 V

    Correct Answer
    B. 2,0 V
  • 33. 

    • A.

      6 N

    • B.
    • C.

      36 N

    • D.
    • E.
    Correct Answer
    D.
  • 34. 

    • A.

      2 volt

    • B.

      6 volt

    • C.

      9 volt

    • D.

      12 volt

    • E.

      24 volt

    Correct Answer
    B. 6 volt
  • 35. 

    Grafik sinusoida berikut ini menunjukan hubungan V/I – t dari rangkaian seri RLC.  Grafik untuk rangkaian RLC pada saat terjadi resonansi adalah … .

    Correct Answer
    A.
    Explanation
    The graph for the RLC circuit at resonance shows a peak in the voltage-current relationship. This is because at resonance, the reactive components cancel each other out, leaving only the resistive component. As a result, the impedance of the circuit is minimized, allowing maximum current to flow through the circuit. This results in a peak in the voltage-current relationship on the graph.

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  • 36. 

    Kawat penghantar AB terletak diantara dua kutub magnet U-S jika kawat dialiri arus listrik dari A ke B, maka arah gaya lorentz yang dialami kawat AB … .  

    • A.

      Sumbu Y positif

    • B.

      Sumbu X positif

    • C.

      Sumbu X negatif

    • D.

      Sumbu Z negatif

    • E.

      Sumbu Z positif

    Correct Answer
    D. Sumbu Z negatif
    Explanation
    The correct answer is "sumbu Z negatif" because when a current-carrying wire is placed between two magnetic poles, the direction of the Lorentz force experienced by the wire can be determined using the right-hand rule. According to the right-hand rule, if the thumb of the right hand points in the direction of the current (from A to B in this case), and the fingers wrap around the wire in the direction of the magnetic field (from U to S), then the direction in which the palm faces represents the direction of the Lorentz force. In this case, the palm faces in the negative Z direction.

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  • 37. 

    • A.

      1 dan 2

    • B.

      1 dan 3

    • C.

      2 dan 3

    • D.

      2 dan 4

    • E.

      3 dan 4

    Correct Answer
    C. 2 dan 3
  • 38. 

    • A.

      1,2,3

    • B.

      1,3,4

    • C.

      2,3,4

    • D.

      1,2,4

    • E.

      1,3

    Correct Answer
    C. 2,3,4
  • 39. 

    • A.

      Dihasilkan energi 1,20099 MeV

    • B.

      Diperlukan energi 1,20099 MeV

    • C.

      Dihasilkan energi 1,10000 MeV

    • D.

      Diperlukan energi 1,10000 MeV

    • E.

      Diperlukan energi 1,00783 MeV

    Correct Answer
    A. Dihasilkan energi 1,20099 MeV
  • 40. 

    Massa unsur radioaktif suatu fosil ketika ditemukan adalah 0,5 gram. Diperkirakan massa unsur radioaktif yang dikandung mula-mula adalah 2 gram. Jika waktu paruh unsur radioaktif tersebut 6000 tahun maka umur fosil tersebut adalah ... .

    • A.

      18.000 tahun

    • B.

      12.000 tahun

    • C.

      9.000 tahun

    • D.

      6.000 tahun

    • E.

      2.000 tahun

    • F.

      2.000 tahun

    Correct Answer
    B. 12.000 tahun
    Explanation
    The given question provides information about the initial mass of the radioactive element found in a fossil and its half-life. The half-life of a radioactive element is the time it takes for half of the element to decay. In this case, the initial mass of the element is 2 grams and the half-life is 6000 years. Since the mass of the element found in the fossil is 0.5 grams, it means that half of the element has decayed. Therefore, it can be inferred that the fossil is approximately 12,000 years old, which is the correct answer.

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  • Current Version
  • Mar 21, 2023
    Quiz Edited by
    ProProfs Editorial Team
  • Jan 29, 2018
    Quiz Created by
    Itdepartmen58jkt
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