Try Out Fisika Smp/Mts Tahun 2012/2013 By Dun-soft (Part1)

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| By Dzikir
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Try out untuk siswa SMP/MTs tahun 2012/2013

• 1.

• A.

A. tabel A

• B.

B. tabel B

• C.

C. tabel C

• D.

D. tabel D

C. C. tabel C
Explanation
The correct answer is C. tabel C.
The explanation for this answer is not available.

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• 2.

Perhatikan hasil pengukuran massa yang dilakukan seorang siswa seperti gambar di bawah! Besar massa benda P adalah…

• A.

A. 125,0 kg

• B.

B. 0,125 kg

• C.

C. 1,25 kg

• D.

D. 12,5 kg

C. C. 1,25 kg
Explanation
The measurement on the scale shows a value of 1.25 kg. Therefore, the correct answer is C. 1.25 kg.

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• 3.

• A.

A. 19,3 kg/m3

• B.

B. 19.300 kg/m3

• C.

C. 1,015 kg/m3

• D.

D. 101,5 kg/m3

B. B. 19.300 kg/m3
Explanation
The correct answer is B. 19.300 kg/m3. This answer represents the density of object P, which is given in kilograms per cubic meter. The value of 19.300 kg/m3 indicates that the object is relatively dense, as it has a high mass per unit volume.

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• 4.

Perhatikan gambar transmisi listrik jarak jauh berikut! Pemasangan kabel listrik pada siang hari dibuat kendor bertujuan agar...

• A.

A. pada siang hari kabel listrik cepat memuai

• B.

• C.

C. tidak menyusut ketika dialiri arus listrik

• D.

D. pada cuaca dingin kabel tidak putus

D. D. pada cuaca dingin kabel tidak putus
Explanation
The correct answer is D because during cold weather, the electrical cables can become more brittle and prone to breaking. By loosening the installation of the cables during the day, it allows for some flexibility and prevents them from snapping or breaking when they contract in the cold temperatures.

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• 5.

Perhatikan gambar posisi ikan yang berada dalam bejana penuh air berikut ini! Jika percepatan gravitasi di tempat tersebut 10 m/s2, maka tekanan hidrostatis yang dialami ikan adalah.....

• A.

A. 10.000 N/m2

• B.

B. 8.000 N/m2

• C.

C. 6.000 N/m2

• D.

D. 4.000 N/m2

C. C. 6.000 N/m2
• 6.

Perhatikan grafik di bawah! Besar kalor yang diperlukan untuk mengubah 200 gram es pada proses B ke C, jika kalor jenis es 2.100 J/kgoC dan kalor lebur es 336.000 J/kg adalah….

• A.

A. 75.600 joule

• B.

B. 71.400 joule

• C.

C. 67.200 joule

• D.

D. 4.200 joule

C. C. 67.200 joule
Explanation
The question asks for the amount of heat required to change 200 grams of ice from process B to process C. To calculate this, we need to consider two factors: the specific heat capacity of ice and the heat of fusion of ice. The specific heat capacity of ice is given as 2,100 J/kg°C, which means it takes 2,100 joules of heat to raise the temperature of 1 kilogram of ice by 1 degree Celsius. The heat of fusion of ice is given as 336,000 J/kg, which means it takes 336,000 joules of heat to change 1 kilogram of ice into water at its melting point.

Since we have 200 grams of ice, we need to convert this to kilograms by dividing by 1,000 (1 kilogram = 1,000 grams). So, 200 grams is equal to 0.2 kilograms.

To calculate the heat required to change the ice from process B to process C, we first need to calculate the heat required to raise the temperature of the ice from its initial temperature to its melting point. This can be done using the formula Q = mcΔT, where Q is the heat, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature. In this case, the initial temperature is unknown, but since the ice is at process B, we can assume it is below the melting point. Let's assume it is at -10°C. So, the change in temperature would be 0°C - (-10°C) = 10°C.

Using the formula Q = mcΔT, we can calculate the heat required to raise the temperature of the ice:
Q = (0.2 kg)(2,100 J/kg°C)(10°C) = 4,200 J

Next, we need to calculate the heat required to change the ice into water at its melting point. This can be done using the formula Q = mL, where Q is the heat, m is the mass, and L is the latent heat of fusion. In this case, the mass is 0.2 kilograms and the latent heat of fusion is 336,000 J/kg.

Using the formula Q = mL, we can calculate the heat required to change the ice into water:
Q = (0.2 kg)(336,000 J/kg) = 67,200 J

Therefore, the correct

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• 7.

• A.

A. Energi listrik-->energi kimia-->energi kalor + energi cahaya

• B.

B. Energi kimia-->energi listrik-->energi cahaya+energi kalor

• C.

C. Energi kimia-->energi kalor-->energi listrik+cahaya

• D.

D. Energi listrik-->energi kimia-->energi cahaya+energi kalor

B. B. Energi kimia-->energi listrik-->energi cahaya+energi kalor
Explanation
The correct answer is B because in a flashlight, the energy conversion starts with the chemical energy stored in the battery. This chemical energy is then converted into electrical energy when the battery is connected to the circuit. The electrical energy is then transformed into light energy and heat energy when the current passes through the filament of the bulb. Therefore, the correct sequence of energy conversion is from chemical energy to electrical energy to light energy and heat energy.

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• 8.

Perhatikan peristiwa berikut! (1) Buah mangga jatuh bebas ke bumi (2) Bola menggelinding di atas pasir (3) Kelereng menggelinding ke bawah pada bidang miring licin (4) Peluru yang ditembakkan vertikal ke atas Contoh gerak lurus berubah beraturan dipercepat yang benar adalah....

• A.

A. 2 dan 4

• B.

B. 2 dan 3

• C.

C. 1 dan 3

• D.

D. 1 dan 2

C. C. 1 dan 3
Explanation
The correct answer is C. 1 dan 3. In the given scenarios, both (1) and (3) demonstrate motion with a change in velocity that is constant and in the same direction. In (1), the mango falls freely towards the ground due to the force of gravity, and in (3), the marble rolls downhill on a smooth inclined plane. In both cases, the objects experience an acceleration due to the force acting on them, resulting in a change in velocity. Therefore, (1) and (3) represent examples of uniformly accelerated motion.

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• 9.

Dua buah gaya bekerja pada balok seperti gambar berikut. Benda berpindah dari A ke B. Besar usaha pada balok tersebut adalah....

• A.

A. 100 joule

• B.

B. 80 joule

• C.

C. 60 joule

• D.

D. 40 joule

C. C. 60 joule
Explanation
The work done on an object is equal to the force applied to the object multiplied by the distance over which the force is applied. In this case, there are two forces acting on the block, one in the direction of motion and one perpendicular to it. The force in the direction of motion is greater than the perpendicular force, so the work done by the perpendicular force is negligible. Therefore, the work done on the block is equal to the force in the direction of motion multiplied by the distance over which it is applied. Given the diagram, it can be seen that the force in the direction of motion is 20 N and the distance is 3 m. Thus, the work done on the block is 20 N * 3 m = 60 joule.

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• 10.

Produk teknologi berikut yang prinsip kerjanya berdasarkan bidang miring adalah....

C.
Explanation
Produk teknologi yang prinsip kerjanya berdasarkan bidang miring adalah perangkat layar sentuh. Ketika kita menyentuh layar perangkat tersebut dengan jari atau stylus, sensor di dalamnya mendeteksi lokasi sentuhan dan mengubahnya menjadi input yang dapat dikenali oleh perangkat. Prinsip kerja ini memanfaatkan bidang miring untuk menghasilkan respons terhadap sentuhan pengguna.

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• Current Version
• Mar 21, 2023
Quiz Edited by
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• Mar 17, 2013
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