Trigonometric Derivatives Quiz

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  • 1/12 Questions

    What is the derivative of y=sin(x)?

    • Y'= sin(x)
    • Y'= cos(x)
    • Y'= tan(x)
    • Y'=1/(1+x^2)
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About This Quiz

Are you ready to test your calculus skills and deepen your understanding of trigonometric functions? Dive into our Trigonometric Derivatives Quiz, specifically designed to challenge and enhance your knowledge of derivatives involving sine, cosine, tangent, and more. This quiz is perfect for students, educators, and math enthusiasts who want to solidify their grasp on trigonometric derivatives in a fun and engaging way.

The Trigonometric Derivatives Quiz covers a variety of questions ranging from basic to advanced levels, ensuring a comprehensive assessment of your calculus abilities. Each question is carefully crafted to reflect real-world applications and theoretical problems, helping you think critically and apply your knowledge effectively. Whether you are preparing for an exam, looking to improve your math skills, or simply enjoy a good challenge, this quiz is an excellent resource.

With instant feedback and detailed explanations for each answer, you will gain valuable insights into your strengths and areas for improvement. Sharpen your calculus skills, boost your confidence, and master trigonometric derivatives. Start the Trigonometric Derivatives Quiz now and take your math proficiency to the next level!

Trigonometric Derivatives Quiz - Quiz

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  • 2. 

    What is the derivative of y= cos (x)?

    • Y'= sin(x)

    • Y'= -sin(x)

    • Y'= cot (x)

    • Y'= sec (x)

    Correct Answer
    A. Y'= -sin(x)
    Explanation
    The derivative of the cosine function, y = cos(x), is equal to the negative sine function, y' = -sin(x). This can be derived using the chain rule of differentiation.

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  • 3. 

    What is the derivative of y= tan(x)?

    • Y'= csc(x)

    • Y'= cot(x)

    • Y'= sec^2(x)

    • Y'= -cscxCotx

    Correct Answer
    A. Y'= sec^2(x)
    Explanation
    The derivative of y = tan(x) is y' = sec^2(x). This is because the derivative of tan(x) is equal to the derivative of sin(x)/cos(x), which can be rewritten as 1/cos^2(x). Since 1/cos^2(x) is equivalent to sec^2(x), the correct answer is y' = sec^2(x).

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  • 4. 

    What is the derivative of y= sec(x)?

    • Y'= 1/(1+x^2)

    • Y'= -csc^2(x)

    • Y'= -cos(x)

    • Y'= Sec(x)Tan(x)

    Correct Answer
    A. Y'= Sec(x)Tan(x)
    Explanation
    The derivative of y = sec(x) is y' = sec(x)tan(x). This can be derived using the quotient rule, where the derivative of sec(x) is sec(x)tan(x) and the derivative of tan(x) is sec^2(x). Therefore, the correct answer is y' = sec(x)tan(x).

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  • 5. 

    What is the derivative of y= cot(x)?

    • Y'=-csc^2(x)

    • Y'= -cos(x)

    • Y'= -sin(x)

    • Y'= sec(x)tan(x)

    Correct Answer
    A. Y'=-csc^2(x)
    Explanation
    The derivative of y=cot(x) is y'=-csc^2(x). This is because the derivative of cot(x) can be found using the quotient rule, where the derivative of the numerator is -csc^2(x) and the derivative of the denominator is 1. Therefore, the derivative of cot(x) is -csc^2(x).

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  • 6. 

    What is the derivative of y= cosec(x)?

    • Y'= Cosec(x)

    • Y'=-Cosec(x)Cot(x)

    • Y'= cot(x)tan(x)

    • Y'= Sec(x)Tan(x)

    Correct Answer
    A. Y'=-Cosec(x)Cot(x)
    Explanation
    The correct answer is y'=-Csc(x)Cot(x). The derivative of y = csc(x) can be found using the chain rule. The derivative of csc(x) is -csc(x)cot(x), where -csc(x) represents the derivative of the outer function and cot(x) represents the derivative of the inner function. Therefore, the correct answer is y'=-Csc(x)Cot(x).

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  • 7. 

    What is the derivative of y= Sin^-1(x)?

    • Y'=1/√(1-x^2)

    • Y'=-1/√(1-x^2)

    Correct Answer
    A. Y'=1/√(1-x^2)
    Explanation
    The given function is y = sin^(-1)(x), which represents the inverse sine function. To find the derivative of this function, we can use the chain rule. The derivative of sin^(-1)(x) is 1/√(1-x^2). Therefore, the correct answer is y' = 1/√(1-x^2).

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  • 8. 

    What is the derivative of y= Tan^-1(x)?

    • Y'=1/√(1-x^2)

    • Y'= 1/(1+x^2)

    • Y'= -1/(1+x^2)

    • Y'=1/√(1-x^2)

    Correct Answer
    A. Y'= 1/(1+x^2)
    Explanation
    The given function is y = Tan^-1(x), which represents the inverse tangent of x. The derivative of the inverse tangent function is 1/(1+x^2). This can be derived using the chain rule and the derivative of the tangent function. Therefore, the correct answer is y' = 1/(1+x^2).

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  • 9. 

    What is the derivative of y= Cos^-1(x)?

    • Y'= 1/√(1-x^2)

    • Y'= 1/(1+x^2)

    • Y'= -1/(1+x^2)

    • Y'= -1/√(1-x^2)

    Correct Answer
    A. Y'= -1/√(1-x^2)
    Explanation
    The given correct answer is y' = -1/√(1-x^2). This can be derived using the chain rule of differentiation. The derivative of y = Cos^-1(x) with respect to x can be found by differentiating the inverse cosine function. Applying the chain rule, we have y' = -1/√(1-x^2), which matches the given correct answer.

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  • 10. 

    What is the derivative of y= cot^-1(x)?

    • Y'= -1/(1+x^2)

    • Y'= 1/(1+x^2)

    • Y'= -1/√(1-x^2)

    • Y'= 1/√(1-x^2)

    Correct Answer
    A. Y'= -1/(1+x^2)
    Explanation
    The given correct answer is y' = -1/(1+x^2). This can be derived using the chain rule of differentiation. The derivative of cot^-1(x) can be found by differentiating the inverse cotangent function. The derivative of cot^-1(x) is equal to -1/(1+x^2). Therefore, the correct answer is y' = -1/(1+x^2).

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  • 11. 

    What is the derivative of y= Sec^-1(x)?

    • Y'=1/√(1-x^2)

    • Y'= 1/(1+x^2)

    • Y'= -1/(x√(1-x^2)

    • Y'= 1/(x√(1-x^2)

    Correct Answer
    A. Y'= 1/(x√(1-x^2)
    Explanation
    The given expression is y = Sec^-1(x), which represents the inverse secant function. To find the derivative of this function, we can use the chain rule. The derivative of Sec^-1(x) is equal to 1 divided by the square root of (1 - x^2). Therefore, the correct answer is y' = 1/(x√(1-x^2)).

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  • 12. 

    What is the derivative of y= csc^-1(x)?

    • Y'= -1/(x√(1-x^2)

    • Y'= -1/√(1-x^2)

    • Y'= 1/(1+x^2)

    • Y'= 1/(x√(1-x^2)

    Correct Answer
    A. Y'= -1/(x√(1-x^2)
    Explanation
    The given answer, y' = -1/(x√(1-x^2), is the derivative of the function y = csc^-1(x). This can be determined using the chain rule and the derivative of the inverse cosecant function. The derivative of csc^-1(x) is equal to -1/(x√(1-x^2), which matches the given answer.

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  • Current Version
  • May 15, 2024
    Quiz Edited by
    ProProfs Editorial Team
  • Oct 03, 2011
    Quiz Created by
    KenArrari
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