TEAS Practice Test #2
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24.018
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15.185
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49.089
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32.156
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Are you a student who is taking mathematics in any place in the globe? If you have an upcoming quiz or test and you need practice then try out this quiz. It will gauge how much knowledge you really have.
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- 2.
Martin and Mary are brother and sister. Martin is two times as old as Mary. There is 27 years between their ages. How old is Martin?
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27
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54
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24
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12
Correct Answer
A. 54Explanation
Mary's age is X
Martin's age is 2X
2X - X = 27
X = 27
2X = 54
So, Martin is 54 years oldRate this question:
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- 3.
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13
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17
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16
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2
Correct Answer
A. 13 -
- 4.
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![TEAS Practice Test #2 - Quiz]()
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![TEAS Practice Test #2 - Quiz]()
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![TEAS Practice Test #2 - Quiz]()
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1
Correct Answer
A. -
- 5.
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5
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12
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13
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12.8
Correct Answer
A. 12.8 -
- 6.
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0.75
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3
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-3
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0.10
Correct Answer
A. -3 -
- 7.
In Math 141, students need to achieve at least 90% to get A in class. If the total point of the course is 1800 points, how many points must the students earn to get A in this class?
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1620 pts
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2000 pts
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1600 pts
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162 pts
Correct Answer
A. 1620 pts -
- 8.
A doctor gives a patient a prescription that instructs the patient to take 2 tablets every 4 hours. The prescription orders 120 tablets to be issued. how long will the prescription last if the tablets are taken as ordered?
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10 days
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20 days
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5 days
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40 days
Correct Answer
A. 10 days -
- 9.
Martha is considering purchasing a life insurance policy. The annual premium rate on $10,000 worth of life insurance is $25 per $1,000. What is the annual cost of Martha's premium?
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$250
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$10,000
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$2,500
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$1,000
Correct Answer
A. $250Explanation
Martha is considering purchasing a life insurance policy with an annual premium rate of $25 per $1,000 worth of life insurance. Since she is purchasing $10,000 worth of life insurance, we can calculate the annual cost of her premium by multiplying the premium rate by the value of the insurance. Therefore, the annual cost of Martha's premium is $25 * $10,000 = $250.Rate this question:
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- 10.
Determine the perimeter of the following triangle.
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27"
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53"
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43"
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45"
Correct Answer
A. 45" -
- 11.
Determine x for a right triangle where the hypotenuse is equal to 5 and one leg is equal to 4.
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3
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9
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1
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5
Correct Answer
A. 3 -
- 12.
Order the following rational numbers from least to greatest:
Correct Answer
A. -
- 13.
55% of 18 yards =
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19 ft
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29.7 ft
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32.7 ft
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0.98 ft
Correct Answer
A. 29.7 ft -
- 14.
Convert 89 to Roman numerals.
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XCIX
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LXXXIX
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XIC
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LIXXXX
Correct Answer
A. LXXXIX -
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Correct Answer
A. -
- 16.
Two long-distance runners are 50 miles apart. they start running toward each other at 7:00 A.M. Runner One runs an average 4 miles per hour, and Runner Two runs an average of 1.5 miles per ten minutes. what time will the runners meet?
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10:48 A.M
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8:00 A.M
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10:08 A.M
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9:00 A.M
Correct Answer
A. 10:48 A.MExplanation
The runners are 50 miles apart and are running towards each other. Runner One runs at an average speed of 4 miles per hour, while Runner Two runs at an average speed of 1.5 miles per ten minutes. To find out when they will meet, we need to calculate the time it takes for them to cover a total distance of 50 miles.
Runner One's speed is given in miles per hour, so we can calculate the time it takes for Runner One to cover 50 miles by dividing the distance by the speed: 50 miles / 4 miles per hour = 12.5 hours.
Runner Two's speed is given in miles per ten minutes, so we need to convert it to miles per hour. There are 6 ten-minute intervals in an hour, so Runner Two's speed in miles per hour is 1.5 miles per ten minutes * 6 = 9 miles per hour.
Now, we can calculate the time it takes for Runner Two to cover 50 miles by dividing the distance by the speed: 50 miles / 9 miles per hour = 5.56 hours.
To find out the total time it takes for them to meet, we add the times it takes for each runner to cover the distance: 12.5 hours + 5.56 hours = 18.06 hours.
Since they start running at 7:00 A.M., we add 18.06 hours to 7:00 A.M. to find out the time they will meet: 7:00 A.M. + 18.06 hours = 1:48 A.M.
Therefore, the runners will meet at 10:48 A.M.Rate this question:
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- 17.
If the number of candidates qualified in 1998 was 21200, what was the number of candidates appeared in 1998?
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32000
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26500
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28500
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25000
Correct Answer
A. 26500Explanation
The number of candidates appeared in 1998 was 26500.Rate this question:
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- 18.
A cosmetic company provide 5 different products. The sales of these five products during 1995 and 2000 are shown in the following bar graph: WHAT IS THE APPROXIMATE RATIO OF THE SALES OF NAIL ENAMELS IN 2000 TO THE SALES OF TALCUM POWDER IN 1995?
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7:2
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4:3
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5:2
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2:1
Correct Answer
A. 5:2Explanation
The approximate ratio of the sales of nail enamels in 2000 to the sales of talcum powder in 1995 is 5:2. This can be determined by comparing the lengths of the bars representing the sales of nail enamels in 2000 and talcum powder in 1995 on the bar graph. The length of the nail enamels bar is approximately 5 times longer than the length of the talcum powder bar, indicating a ratio of 5:2.Rate this question:
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- 19.
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![TEAS Practice Test #2 - Quiz]()
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![TEAS Practice Test #2 - Quiz]()
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This equation has no solution
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![TEAS Practice Test #2 - Quiz]()
Correct Answer
A. This equation has no solution -
- 20.
Correct Answer
A. -
.JPG "If the number of candidates qualified in 1998 was 21200, what was the number of candidates appeared in 1998?")
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Current Version
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Mar 21, 2023Quiz Edited by
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May 23, 2013Quiz Created by
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