Spongebob Genetics Worksheets I

If SpongeBob is heterozygous for his square shape, it means that he carries one dominant allele for square shape and one recessive allele for round shape. SpongeBarbara, on the other hand, is round, which means she carries two recessive alleles for round shape. When these two individuals have children, there is a 50% chance that the child will inherit the dominant allele from SpongeBob and have a square shape, and a 50% chance that the child will inherit the recessive alleles from both parents and have a round shape. Therefore, the chances of a child with square shape are 50%.

Based on the given information, the genotype [SS] represents a dominant square body type. This means that if an organism has two copies of the dominant allele (S), it will have a square body shape.

The chances of a child with a round shape would be 50%. This is because SpongeBob is heterozygous for his square shape, meaning he carries one dominant allele for square shape and one recessive allele for round shape. SpongeBarbara, on the other hand, is round, which means she carries two recessive alleles for round shape. When they have children, there is a 50% chance that the child will inherit SpongeBob's recessive allele for round shape, resulting in a round-shaped child.

The genotypes [Dd], [Bb], and [Ff] are considered hybrids because they contain a combination of two different alleles for a particular trait. In each of these genotypes, one allele is dominant (represented by the capital letter) and the other allele is recessive (represented by the lowercase letter). This combination of dominant and recessive alleles in the genotype results in a hybrid individual with a mixed expression of the trait.

The given question is asking to determine the phenotype for the genotype [Yy]. Based on the information provided, yellow body color is dominant to recessive blue body color. Since the genotype [Yy] has one dominant allele (Y) and one recessive allele (y), the phenotype would be yellow body color.

The correct answer is Square body type. This is because the question states that square body shape is dominant, while round body type is recessive. Since the genotype given is [Ss], with "S" representing the dominant allele for square body shape and "s" representing the recessive allele for round body type, the phenotype would be square body type.

The given answer [Dd], [Bb], [Bb] identifies the genotypes that are in a heterozygous condition. In genetics, heterozygous refers to having two different alleles for a particular gene. In this case, the genotypes [Dd] and [Bb] have a combination of two different alleles, while [DD] and [dd] have two identical alleles. Therefore, [Dd] and [Bb] are the heterozygous genotypes in the given list.

Based on the information given, SpongeBob is heterozygous for his square shape. In genetics, the term "heterozygous" refers to having two different alleles for a particular trait. Since SpongeBob's shape is square, it can be represented by the allele "S." Therefore, his genotype would be [Ss], with "S" representing the square shape and "s" representing the round shape.

The given genotype [YY] corresponds to the yellow body color phenotype. This is because yellow body color is dominant over blue body color, and since the genotype has two dominant alleles (Y), the phenotype will exhibit the dominant trait, which is yellow body color.

The given question states that square body shape is dominant and round body type is recessive. Since the genotype is [ss], where both alleles are recessive, the phenotype would be round body type.

Patti's genotype is [Pp]. This means that she has one dominant allele (P) for pink body color and one recessive allele (p) for yellow body color. Since Patrick and Patti are both heterozygous (Pp), they can pass on either the dominant or recessive allele to their children.

Based on the given information, Patrick and Patti are both heterozygous for the pink body color gene, which means they each have one dominant allele (P) and one recessive allele (p). The Punnett square shows the possible combinations of alleles that their children could inherit. The genotype [Pp] represents one possibility where the child inherits one dominant allele from Patrick (P) and one recessive allele from Patti (p).

Based on the information given, SpongeBob is heterozygous for his square shape, meaning he has one dominant allele (S) and one recessive allele (s). Since SpongeBarbara is round, it can be inferred that she does not have the dominant allele (S) for the square shape. Therefore, her genotype must be homozygous recessive (ss).

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If both Patrick and Patti are heterozygous for the pink body color (Pp), there is a 25% chance that their child will have a yellow body color. This is because when two heterozygous individuals mate, there is a 25% chance of their child inheriting two recessive alleles (pp) for the yellow body color. The other possibilities include the child inheriting two dominant alleles (PP) for the pink body color or being heterozygous (Pp) like the parents.

The phenotype for the given genotype [ss] is Roundpants. This means that SpongeBob has a roundpants body shape.

The phenotype for the given genotype - - [yy] is blue body color.

If both Patrick and Patti are heterozygous for the pink body color (Pp), there is a 75% chance of their child having a pink body. This is because there are four possible combinations in the Punnett square: PP, Pp, pP, and pp. Out of these four combinations, three of them (PP, Pp, and pP) result in a pink body color, while only one combination (pp) results in a yellow body color. Therefore, the chances of a child with a pink body are 75%.

Squidward's genotype is [BB]. This is because all members of his family have the dominant trait for body color, which is light blue (B). Since his family claims to be a "purebred" line, it can be inferred that they are homozygous for the trait, meaning they have two copies of the dominant allele (BB). Since Squidward's genotype is not specified in the question, it can be assumed that he also has the same genotype as his family members.

Since light green skin color is a recessive trait (b), and all members of Squidward's family have the dominant trait (B) for light blue skin color, it means that Squidward does not carry the recessive trait for light green skin. Therefore, the chances of Squidward and his bride having a child with light green skin are 0%.

Mrs. Krabby's genotype is [Tt]. This means that she has one allele for tall eyeballs (T) and one allele for short eyeballs (t). Since she has tall eyeballs, it means that the allele for tall eyeballs (T) is dominant over the allele for short eyeballs (t). Therefore, even though she has one allele for short eyeballs, she still expresses the trait for tall eyeballs.

The genotypes [TT], [dd], [DD], and [FF] are considered purebred because they consist of two of the same alleles for a specific trait. In other words, they are homozygous for that trait.

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Squidward's family has a dominant trait for light blue skin, while his wife has a recessive trait for light green skin. Since light blue skin is dominant, all of their children will inherit the light blue skin trait. Therefore, the chances of a child with light blue skin are 100%.

The chances of Squidward and his bride having children that are purebred light green body color is 25%. This can be determined by creating a Punnett square. Since Squidward is heterozygous (Bb) for the light blue body color trait and his bride is also heterozygous (Bb), there is a 25% chance that they will have children with the genotype bb, which represents the recessive trait for light green body color.

Mr. Krabby's genotype is [TT]. This means that he has two copies of the tall eyeball allele. Since he is homozygous, he does not carry the short eyeball allele. This explains why all of their children have tall eyeballs, as they would have inherited one tall allele from Mr. Krabby and one tall allele from Mrs. Krabby.

If Squidward is heterozygous for the light blue body color (Bb) and his bride is also heterozygous (Bb), then there is a 25% chance that they will have children with the purebred blue body color (BB). This is because in a Punnett square, there are four possible combinations of alleles: BB, Bb, bB, and bb. Only one of these combinations (BB) results in the purebred blue body color. Therefore, the chances of having purebred blue body color children is 25%.

The genotypes [DD], [bb], [FF], and [ff] are homozygous conditions because they consist of two identical alleles for a specific trait. In each of these genotypes, both alleles are the same, either dominant (D) or recessive (b or F or f). This means that these individuals will express the traits associated with the dominant alleles (D or F) or the recessive alleles (b or f) exclusively.

Based on the information given, Mr. Krabbs is homozygous for tall eyeballs while Mrs. Krabby is heterozygous. This means that Mr. Krabbs can only pass on the allele for tall eyeballs, while Mrs. Krabby can pass on either the allele for tall or short eyeballs. Since 100 of the children have short eyeballs, it suggests that Mrs. Krabby did not pass on the allele for tall eyeballs to those children. Therefore, 50% of the children did not inherit the allele from Mrs. Krabby, indicating that there may have been a mistake at the hospital.

The answer [TT],[Tt] suggests that some of Mr. and Mrs. Krabbs' children will have the genotype TT (homozygous tall eyeballs) and some will have the genotype Tt (heterozygous tall eyeballs). This is because Mr. Krabbs is homozygous for tall eyeballs (TT) and Mrs. Krabby is heterozygous for tall eyeballs (Tt). The presence of the recessive allele (t) in Mrs. Krabby's genotype allows for the possibility of some of their children inheriting the recessive allele and having the heterozygous genotype (Tt).