# Soal Uts Matematika Kelas 5 ( Lima ) Sd Semester 2

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• 1.

### 3⁄4  Jika diubah ke bentuk persen menjadi ....

• A.

40 %

• B.

30 %

• C.

25 %

• D.

75 %

D. 75 %
Explanation
The correct answer is 75%. When a fraction is converted to a percentage, it is done by multiplying the fraction by 100. In this case, 3/4 is multiplied by 100, resulting in 75%.

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• 2.

### Bentuk pecahan biasa dari 50 % adalah ....

• A.

150

• B.

15

• C.

12

• D.

5010

C. 12
Explanation
The correct answer is 1/2 because 50% can be written as a fraction by dividing 50 by 100. Simplifying the fraction results in 1/2.

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• 3.

### Bentuk persen di bawah ini yang tidak senilai dengan 2⁄6  adalah ....

• A.

310

• B.

13

• C.

3296

• D.

1545

B. 13
Explanation
The given correct answer is 1/3. This is because when we simplify 2/6, we can divide both the numerator and denominator by 2 to get 1/3. Therefore, 1/3 is not equivalent to 2/6.

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• 4.

### Pecahan-pecahan berikut ini yang senilai dengan 25 % adalah ....

• A.

520

• B.

2510

• C.

12

• D.

26

A. 520
Explanation
The correct answer is 5/20 because when we simplify the fraction, we can divide both the numerator and denominator by 5 to get 1/4. This means that 5/20 is equivalent to 1/4, which is equal to 25%.

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• 5.

### 7⁄8 .... 8⁄10 Tanda yang tepat untuk mengisi titik-titik di atas adalah ....

• A.

<

• B.

=

• C.

>

• D.

+

C. >
Explanation
The correct answer is ">". This symbol represents "greater than". In the given sequence, 7/8 is less than 8/10.

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• 6.

### Pecahan 1⁄8  jika diubah ke bentuk pecahan desimal menjadi ....

• A.

0,25

• B.

0,125

• C.

0,75

• D.

0,375

B. 0,125
Explanation
The fraction 1/8 can be converted to a decimal by dividing 1 by 8. When we divide 1 by 8, the result is 0.125. Therefore, the correct answer is 0.125.

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• 7.

### Bentuk pecahan biasa dari 0,66 adalah ....

• A.

6610

• B.

661000

• C.

66

• D.

66100

D. 66100
Explanation
The given fraction 66/100 is the simplest form of the decimal 0.66. To convert a decimal to a fraction, we write the decimal as the numerator and the place value of the last digit as the denominator. In this case, the last digit is in the hundredth place, so the denominator is 100. Therefore, the correct answer is 66/100.

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• 8.

### 0,35 .....  2⁄5 Tanda yang tepat untuk mengisi titik-titik di atas adalah ....

• A.

<

• B.

=

• C.

>

• D.

+

A. <
Explanation

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• 9.

### Bayu mempunyai 200 kelereng. 25 % dari kelereng Bayu akan diberikan kepada Budi. Maka Budi akan menerima  kelereng dari Bayu sebanyak ....

• A.

20 kelereng

• B.

30 kelereng

• C.

40 kelereng

• D.

50 kelereng

D. 50 kelereng
Explanation
Bayu mempunyai 200 kelereng, dan 25% dari 200 adalah 50. Jadi, Budi akan menerima 50 kelereng dari Bayu.

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• 10.

### Jumlah siswa kelas 5 SD Cahaya Brilian adalah 50 anak.  1⁄5  dari siswa kelas 5 SD ditugaskan untuk membersihkan halaman sekolah ketika kerja bakti. Hal itu berarti jumlah siswa kelas 5 SD yang membersihkan halaman berjumlah ....

• A.

10 anak

• B.

20 anak

• C.

5 anak

• D.

15 anak

A. 10 anak
Explanation
There are 50 students in class 5 of SD Cahaya Brilian. 1/5 of the students are assigned to clean the school yard during community service. To find the number of students cleaning the yard, we need to calculate 1/5 of 50. 1/5 of 50 is equal to 10. Therefore, the correct answer is 10 students.

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• 11.

### 3⁄15  +  7⁄15 + 4⁄15 = .... Hasil dari operasi penjumlahan pecahan di atas adalah ....

• A.

1430

• B.

745

• C.

1415

• D.

1445

C. 1415
Explanation
The given question asks to add the fractions 3/15, 7/15, and 4/15. Since the denominators of all the fractions are the same, we can add the numerators together to get the numerator of the final fraction. Therefore, 3/15 + 7/15 + 4/15 = (3 + 7 + 4)/15 = 14/15.

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• 12.

### 1⁄2   +  2⁄5 + 3⁄4  = .... Hasil dari operasi penjumlahan pecahan di atas adalah ....

• A.

3320

• B.

711

• C.

740

• D.

611

A. 3320
Explanation
The given expression involves adding three fractions together. To add fractions, we need to find a common denominator. In this case, the common denominator is 20. We then convert each fraction to have a denominator of 20 and add the numerators together. The resulting fraction is 33/20.

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• 13.

### Santika membeli pita sepanjang 2 1⁄2  meter dan Andini membeli pita sepanjang 3 1⁄4  meter. Maka panjang pita Santia dan Andini jika digabungkan menjadi sepanjang ....

• A.

5  26

• B.

24

• C.

16

• D.

34

D. 5 34
Explanation
Santika bought a ribbon that is 2 1/2 meters long, and Andini bought a ribbon that is 3 1/4 meters long. To find the total length of the ribbons when combined, we need to add the lengths together. To do this, we need to find a common denominator for the fractions. The common denominator for 2/2 and 1/4 is 4. So, we can rewrite 2 1/2 as 2 2/4. Adding 2 2/4 and 3 1/4 gives us a total length of 5 3/4 meters. Therefore, the correct answer is 5 3/4.

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• 14.

### 11⁄12 - 2⁄12 - 4⁄12  = .... Hasil dari operasi penjumlahan pecahan di atas adalah ....

• A.

536

• B.

712

• C.

512

• D.

50

C. 512
Explanation
The given expression involves subtracting three fractions with the same denominator, which is 12. To subtract fractions with the same denominator, we subtract the numerators and keep the denominator the same. Therefore, the result of the operation is 5/12.

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• 15.

### 15⁄20  - 3⁄10 - 2⁄5 = .... Hasil dari operasi pengurangan pecahan di atas adalah ....

• A.

115

• B.

120

• C.

1015

• D.

105

B. 120
Explanation
The given expression involves subtracting fractions. To subtract fractions, we need to have a common denominator. In this case, the common denominator is 20.

Converting the fractions to have a denominator of 20, we get:

15/20 - 3/10 - 2/5 = 15/20 - 6/20 - 8/20

Now, we can subtract the numerators:

15 - 6 - 8 = 1

The resulting fraction is 1/20.

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• 16.

### Bu Ani membeli gula seberat 1/2 Kg, kemudian ia menggunakan gula tersebut untuk membuat kue seberat 1⁄4 Kg. Sekarang sisa gula bu Ani menjadi ....

• A.

12 Kg

• B.

18 Kg

• C.

13 Kg

• D.

14 Kg

D. 14 Kg
Explanation
After buying 1/2 Kg of sugar, Bu Ani uses 1/4 Kg of sugar to make a cake. This means that Bu Ani has used up 1/4 Kg of the sugar, leaving her with 1/4 Kg of sugar remaining. Therefore, the correct answer is 1/4 Kg.

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• 17.

### 3⁄6  x 4⁄10 = .... Hasil dari operasi perkalian pecahan di atas adalah ....

• A.

5460

• B.

2430

• C.

3024

• D.

1260

D. 1260
Explanation
The given expression is a multiplication of two fractions. To multiply fractions, we multiply the numerators together and the denominators together. In this case, the numerator of the first fraction is 3 and the numerator of the second fraction is 4. The denominator of the first fraction is 6 and the denominator of the second fraction is 10. Multiplying the numerators (3 x 4) gives us 12, and multiplying the denominators (6 x 10) gives us 60. Therefore, the result of the multiplication is 12/60.

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• 18.

### 6⁄18 : 2⁄5 = .... Hasil dari operasi pembagian pecahan di atas adalah ....

• A.

34

• B.

3036

• C.

1290

• D.

930

B. 3036
Explanation
The given expression is a division of fractions. To divide fractions, we need to multiply the first fraction by the reciprocal of the second fraction. So, in this case, we need to multiply 6/18 by 5/2. When we multiply the numerators (6 and 5) and the denominators (18 and 2), we get 30/36. Therefore, the correct answer is 30/36.

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• 19.

### Penghasilan Pak Nugroho perbulannya sebagai pengusaha rata-rata adalah Rp. 4.300.000,00. 50 % dari penghasilannya digunakan untuk memenuhi kebutuhan sehari-hari keluarganya. 0,2 dari penghasilannya digunakan untuk ditabung. 2⁄8  dari penghasilannya digunakan untuk membeli kebutuhan tambahan dan 1⁄20 dari penghasilannya disumbangkan untuk para anak yatim di lingkungannya. Pernyataan yang benar menurut keterangan di atas adalah ....

• A.

Jumlah uang yang digunakan untuk memenuhi kebutuhan sehari-hari paling sedikit

• B.

Jumlah uang yang disumbangkan kepada para anak yatim lebih besar dari jumlah uang yang ditabung

• C.

Jumlah uang yang digunakan untuk membeli kebutuhan tambahan paling sedikit

• D.

Jumlah uang yang ditabung lebih sedikit dari jumlah uang yang digunakan untuk membeli kebutuhan tambahan

D. Jumlah uang yang ditabung lebih sedikit dari jumlah uang yang digunakan untuk membeli kebutuhan tambahan
Explanation
The statement "Jumlah uang yang ditabung lebih sedikit dari jumlah uang yang digunakan untuk membeli kebutuhan tambahan" is correct according to the given information. It is stated that 0.2 of Pak Nugroho's income is used for savings, while 2/8 of his income is used to buy additional needs. Since 0.2 is smaller than 2/8, it can be concluded that the amount of money saved is less than the amount used to buy additional needs.

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• 20.

### Perbandingan siswa laki dan siswa perempuan pada kelas 5 SD Cahaya Cendekia adalah 7 : 9. Jika siswa laki-laki dalam kelas adalah 21 siswa, maka siswa perempuan berjumlah ....

• A.

18 siswa

• B.

14 siswa

• C.

27 siswa

• D.

18 siswa

C. 27 siswa
Explanation
Based on the given information, the ratio of male students to female students in class 5 of SD Cahaya Cendekia is 7:9. It is also mentioned that there are 21 male students in the class. To find the number of female students, we can set up a proportion using the ratio. Since the ratio is 7:9, we can set up the proportion as 7/9 = 21/x, where x represents the number of female students. By cross-multiplying, we get 7x = 9 * 21, which simplifies to 7x = 189. Dividing both sides by 7, we find that x = 27. Therefore, the number of female students in the class is 27.

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• 21.

### Jumlah pohon mangga di Taman Wisata Pesona Indah adalah 25 pohon. Sedangkan jumlah pohon cemaranya adalah 15 pohon. Maka perbandingan antara jumlah pohon mangga dan cemara di taman tersebut adalah ....

• A.

5 : 4

• B.

4 : 3

• C.

6 : 4

• D.

5 : 3

D. 5 : 3
Explanation
The ratio of mango trees to pine trees in Taman Wisata Pesona Indah is 5:3. This can be determined by dividing the number of mango trees (25) by the number of pine trees (15), which simplifies to 5:3.

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• 22.

### Karina memiliki koleksi 20 perangko dan Anisa memiliki koleksi 32 perangko. Perbandingan jumlah koleksi perangko yang imiliki karina dan Anisa adalah ....

• A.

2 : 3

• B.

5 : 8

• C.

3 : 4

• D.

4 : 6

B. 5 : 8
Explanation
The correct answer is 5 : 8 because the ratio of Karina's collection to Anisa's collection can be found by dividing the number of Karina's stamps (20) by the number of Anisa's stamps (32). Simplifying this ratio gives us 5 : 8.

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• 23.

### Jarak antara kota X dan kota Y adalah 2.400 meter. Pada peta jarak kota X dan Y adalah 6 cm. Maka skala peta tersebut adalah ....

• A.

1 : 400

• B.

1 : 2.400

• C.

1 : 60.000

• D.

1 : 40.000

D. 1 : 40.000
Explanation
The scale of a map represents the ratio of distances on the map to the actual distances on the ground. In this question, the given distance between city X and city Y is 2,400 meters, and on the map, this distance is represented by 6 cm. To find the scale, we need to divide the actual distance by the distance on the map. Therefore, the scale of the map is 2,400 meters divided by 6 cm, which simplifies to 400 meters per cm. Since the question asks for the scale in the format of 1:n, the scale is 1:40,000.

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• 24.

### Jarak antara rumah Ratna dan Sintia pada peta desa adalah 5 cm. Jika skala yang dimiliki peta desa tersebut adalah 1 : 3.000, maka jarak sebenarnya antara rumah Ratna dan Sitina adalah ....

• A.

15.000 m

• B.

500 m

• C.

150 m

• D.

1.500 cm

C. 150 m
Explanation
The scale of the map is given as 1:3,000. This means that 1 cm on the map represents 3,000 cm in reality. The distance between Ratna's house and Sintia's house on the map is 5 cm. Therefore, the actual distance between their houses can be calculated by multiplying the map distance by the scale factor: 5 cm x 3,000 = 15,000 cm. Since the answer options are given in meters, we need to convert 15,000 cm to meters by dividing it by 100: 15,000 cm / 100 = 150 m.

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• 25.

### Jarak rumah Anton dan sekolahnya adalah 1.200 meter. Dalam peta desa yang mempunyai skala 1 : 10.000. Maka jarak rumah Anton dengan sekolah pada peta adalah ....

• A.

12 cm

• B.

1,2 cm

• C.

120 cm

• D.

12 m

A. 12 cm
Explanation
The scale of the map is 1:10,000, which means that 1 cm on the map represents 10,000 cm in reality. The distance between Anton's house and his school is 1,200 meters, which is equal to 120,000 cm. Therefore, on the map, the distance between Anton's house and his school would be represented by 120,000 cm divided by 10,000, which is 12 cm.

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• Mar 21, 2023
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