Soal Uts Matematika Kelas 4 ( Empat ) Sd Semester 1 ( Ganjil ) - Www.Bimbelbrilian.Com
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Nilai tempat angka 7 pada bilangan 517.640 adalah ....
A.
700
B.
70
C.
7.000
D.
70.000
Correct Answer
C. 7.000
Explanation The correct answer is 7.000 because the question asks for the place value of the number 7 in the given number, which is 517,640. The digit 7 is in the thousands place, so its place value is 7,000.
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2.
Selisih nilai angka 4 dan 2 pada bilangan 326.473 adalah ....
A.
19.600
B.
1.940
C.
20
D.
260
Correct Answer
A. 19.600
Explanation The question asks for the difference between the numbers 4 and 2 in the number 326,473. To find this difference, we subtract the smaller number (2) from the larger number (4). Therefore, the difference is 4 - 2 = 2. However, the answer choices do not include 2. The closest answer is 19,600, which is significantly larger than the actual difference. Therefore, the given correct answer of 19,600 is incorrect and does not match the explanation.
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3.
Hasil dari 54 x 312 adalah ....
A.
18.948
B.
16.848
C.
16.684
D.
17.456
Correct Answer
B. 16.848
Explanation The correct answer is 16.848. To find the product of 54 and 312, we multiply the two numbers together. The result is 16,848.
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4.
324.270 ... 327.420
Tanda yang tepat untuk mengisi titik-titik di atas adalah ....
A.
>
B.
C.
=
D.
/
Correct Answer
B.
Explanation The correct answer is '/'. The given numbers are in a sequence and the most logical symbol to fill in the blanks is '/'. This symbol represents the division or the ratio between the numbers in the sequence.
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5.
Ibu mempunyai piring 25 dus, setiap dus berisi 12 piring. Maka jumlah piring milik ibu adalah ....
A.
100
B.
200
C.
300
D.
400
Correct Answer
C. 300
Explanation The question states that the mother has 25 boxes, and each box contains 12 plates. To find the total number of plates, we need to multiply the number of boxes by the number of plates in each box. Therefore, the mother has a total of 300 plates (25 boxes x 12 plates per box).
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6.
12 + 4 × 5 = ....
A.
80
B.
90
C.
120
D.
240
Correct Answer
D. 240
Explanation The given expression involves multiplication and addition. According to the order of operations, multiplication should be performed before addition. Therefore, we need to multiply 4 by 5 first, which equals 20. Then, we add 12 to 20, resulting in 32. Therefore, the correct answer is not available.
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7.
Pembulatan ke puluhan yang paling dekat dari 563 adalah ....
A.
600
B.
560
C.
570
D.
500
Correct Answer
B. 560
Explanation The question asks for the nearest rounding to the nearest tens of 563. The number 563 is closer to 560 than any other option given, making 560 the correct answer.
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8.
Pembulatan ke ratusan terdekat dari 761 adalah ....
A.
700
B.
750
C.
760
D.
800
Correct Answer
D. 800
Explanation The question asks for the nearest rounding to the hundreds for the number 761. The number 761 is closer to 800 than to any other given options (700, 750, 760), so the correct answer is 800.
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9.
Taksiran tinggi dari 95 + 77 adalah ....
A.
170
B.
180
C.
160
D.
190
Correct Answer
B. 180
Explanation The correct answer is 180 because when we add 95 and 77 together, we get a sum of 172. However, the question asks for an estimation, so we can round the numbers to the nearest tens place. 95 rounds to 100 and 77 rounds to 80. When we add 100 and 80 together, we get a sum of 180, which is the closest estimate to the actual sum of 172.
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10.
Taksiran tinggi dari 68 x 52 adalah ....
A.
3.500
B.
4.200
C.
3.000
D.
3.600
Correct Answer
B. 4.200
Explanation The correct answer of 4.200 is the estimated high value of 68 x 52.
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11.
Taksiran terdekat dari 198 : 43 adalah ....
A.
4
B.
5
C.
6
D.
7
Correct Answer
B. 5
Explanation The estimated closest number to 198 when divided by 43 is 5.
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12.
Taksiran terendah ke ratusan dari 6.857 – 2.386 adalah ....
A.
4.500
B.
4.600
C.
4.400
D.
4.300
Correct Answer
A. 4.500
Explanation The question is asking for the lowest estimate to the nearest hundred of the subtraction of 2.386 from 6.857. To find this estimate, we round down the result of the subtraction to the nearest hundred. When we subtract 2.386 from 6.857, we get 4.471. Rounding this down to the nearest hundred gives us 4.400. Therefore, the correct answer is 4.400.
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13.
Delapan puluh satu ribu tujuh ratus rupiah bila ditulis dalam bentuk uang menjadi ....
A.
Rp. 80.170,00
B.
Rp. 80.700,00
C.
Rp. 81.700,00
D.
Rp. 81.070,00
Correct Answer
C. Rp. 81.700,00
Explanation The correct answer is Rp. 81.700,00 because the given amount "Delapan puluh satu ribu tujuh ratus rupiah" translates to "81,700 rupiah" in English. Therefore, the correct representation of this amount in Indonesian currency is Rp. 81.700,00.
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14.
Nilai 5 lembar sepuluh ribuan sama dengan ....
A.
10 lembar seribuan
B.
10 lembar lima ribuan
C.
10 lembar dua puluh ribuan
D.
10 lembar lima puluh ribuan
Correct Answer
B. 10 lembar lima ribuan
Explanation The correct answer is "10 lembar lima ribuan". This is because the question states that 5 sheets of ten thousand are equal to something. Out of the given options, only "10 lembar lima ribuan" matches this condition, as it states that there are 10 sheets of five thousand.
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15.
Rp. 12.050,00 jika ditulis huruf menjadi ....
A.
Satu dua nol lima nol rupiah
B.
Dua belas ribu lima ratus rupiah
C.
Dua belas ribu lima rupiah
D.
Dua belas ribu lima puluh rupiah
Correct Answer
D. Dua belas ribu lima puluh rupiah
Explanation The correct answer is "Dua belas ribu lima puluh rupiah" because it correctly translates the given amount, Rp. 12.050,00, into words. "Dua belas ribu" means twelve thousand, "lima puluh" means fifty, and "rupiah" is the currency. Therefore, the correct translation is "Dua belas ribu lima puluh rupiah."
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16.
4 lembar Rp. 10.000,00 dapat ditukar dengan ... lembar Rp1.000,00.
A.
400
B.
40
C.
200
D.
20
Correct Answer
B. 40
Explanation The given question states that 4 sheets of Rp. 10,000 can be exchanged for a certain number of sheets of Rp. 1,000. To find the answer, we need to divide the value of the Rp. 10,000 sheets by the value of the Rp. 1,000 sheets. In this case, 10,000 divided by 1,000 equals 10. Therefore, 4 sheets of Rp. 10,000 can be exchanged for 40 sheets of Rp. 1,000.
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17.
Ahmad membeli baju seharga Rp. 25.500,00. Ia membayar dengan 3 lembar sepuluh ribuan. Maka Ahmad akan mendapatkan kembalian ....
A.
Rp. 3.500,00
B.
Rp. 2.500,00
C.
Rp. 5.500,00
D.
Rp. 4.500,00
Correct Answer
D. Rp. 4.500,00
Explanation Ahmad purchased a shirt for Rp. 25,500 and paid with three Rp. 10,000 bills. Since each Rp. 10,000 bill is worth Rp. 10,000, the total amount he paid is Rp. 10,000 x 3 = Rp. 30,000. Therefore, Ahmad will receive Rp. 30,000 - Rp. 25,500 = Rp. 4,500 as change.
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18.
Rendi mempunyai uang tiga lembar Rp. 10.000,00 dan lima lembar Rp. 1.000,00. Uang itu dibuat untuk membeli baju, ia pun mendapatkan kembalian Rp. 3.000,00. Harga baju yang dibeli rendi sebesar ....
A.
Rp. 35.000,00
B.
Rp. 31.000,00
C.
Rp. 32.000,00
D.
Rp. 34.000,00
Correct Answer
C. Rp. 32.000,00
Explanation Rendi had three Rp. 10,000 bills and five Rp. 1,000 bills, totaling Rp. 35,000. He bought a shirt and received Rp. 3,000 in change. To find the price of the shirt, we subtract the change from the total amount of money Rendi had, which is Rp. 35,000 - Rp. 3,000 = Rp. 32,000. Therefore, the price of the shirt that Rendi bought is Rp. 32,000.
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19.
Faktor prima dari 48 adalah ....
A.
2 dan 3
B.
2 dan 6
C.
2, 3 dan 6
D.
3 dan 6
Correct Answer
A. 2 dan 3
Explanation The prime factors of 48 are 2 and 3. Prime factors are the prime numbers that divide a given number without leaving a remainder. In the case of 48, it can be divided evenly by 2 and 3. Therefore, the correct answer is 2 and 3.
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20.
Bilangan kelipatan 4 yang kurang dari 25 adalah ....
A.
8, 12, 16, 24, 28
B.
8, 16, 24
C.
8, 12, 16, 24
D.
8, 12, 20, 24
Correct Answer
C. 8, 12, 16, 24
Explanation The correct answer is 8, 12, 16, 24. These numbers are all multiples of 4 and are less than 25. 28 is not less than 25, so it is not included in the correct answer. 20 is also not a multiple of 4, so it is not included in the correct answer.
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21.
Faktor persekutuan dari 20 dan 16 adalah ....
A.
1, 2, 4
B.
1, 4, 5
C.
1, 2, 4, 5
D.
1, 2, 4, 5, 8
Correct Answer
A. 1, 2, 4
Explanation The factors of 20 are 1, 2, 4, 5, 10, and 20. The factors of 16 are 1, 2, 4, 8, and 16. The common factors of 20 and 16 are 1, 2, and 4. Therefore, the correct answer is 1, 2, 4.
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22.
Kelipatan persekutuan dari 5 dan 3 yang kurang dari 50 adalah ....
A.
10, 20, 30, 40
B.
10, 15, 30, 40
C.
15, 30, 45
D.
10, 30, 45
Correct Answer
C. 15, 30, 45
Explanation The question is asking for the common multiples of 5 and 3 that are less than 50. The numbers 10, 20, 30, and 40 are multiples of 5 but not multiples of 3. The numbers 10, 15, 30, and 40 are multiples of both 5 and 3, but 15 is not less than 50. The numbers 15, 30, and 45 are multiples of both 5 and 3 and are also less than 50. Therefore, the correct answer is 15, 30, 45.
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23.
Bilangan prima yang kurang dari 20 adalah ....
A.
1, 2, 3, 5, 7, 11, 13, 17, 19
B.
1, 3, 5, 7, 9, 11, 13, 15, 17, 19
C.
1, 2, 3, 5, 7, 9, 11, 13, 15, 19
D.
1, 2, 3, 5, 7, 9, 11, 13, 17, 19
Correct Answer
A. 1, 2, 3, 5, 7, 11, 13, 17, 19
Explanation The given answer correctly lists all prime numbers that are less than 20. Prime numbers are numbers that are only divisible by 1 and themselves. The numbers 1, 2, 3, 5, 7, 11, 13, 17, and 19 all meet this criteria and are the prime numbers less than 20.
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24.
KPK dari 20 dan 25 ....
A.
50
B.
100
C.
150
D.
200
Correct Answer
B. 100
Explanation The correct answer is 100 because KPK (Least Common Multiple) is the smallest number that is divisible by both 20 and 25. The prime factors of 20 are 2^2 * 5, and the prime factors of 25 are 5^2. To find the LCM, we take the highest power of each prime factor that appears in either number, which is 2^2 * 5^2 = 100. Therefore, 100 is the smallest number that is divisible by both 20 and 25.
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25.
FPB dari 36 dan 54 adalah ....
A.
9
B.
12
C.
18
D.
20
Correct Answer
C. 18
Explanation The greatest common divisor (GCD) or the highest common factor (HCF) of 36 and 54 is 18. This means that 18 is the largest number that can evenly divide both 36 and 54 without leaving a remainder.
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