# Quantitative Apptitude - Time And Work Online Test 1

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| By Arpitc88
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Arpitc88
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Quizzes Created: 15 | Total Attempts: 15,013
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• 1.

### A and B together can complete a piece of work in 35 days while A alone can complete the same work in 60 days. B alone will be able to complete

• A.

84 days

• B.

23 days

• C.

93 days

• D.

76 days

A. 84 days
Explanation
Since A and B together can complete the work in 35 days, it means that in one day, they can complete 1/35th of the work. If A alone can complete the work in 60 days, it means that in one day, A can complete 1/60th of the work. Therefore, B alone can complete (1/35 - 1/60) = 1/84th of the work in one day. Hence, B alone will be able to complete the work in 84 days.

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• 2.

### If A can do a work in 10 days, B can do it in 20 days and C in 30 days in how many days will the three together do it?

• A.

6.25 days

• B.

5.45 days

• C.

3.75 days

• D.

6 days

B. 5.45 days
Explanation
The correct answer is 5.45 days. To find the combined work rate of A, B, and C, we can add up their individual work rates. A completes 1/10th of the work per day, B completes 1/20th of the work per day, and C completes 1/30th of the work per day. Adding these rates together, we get (1/10) + (1/20) + (1/30) = 3/30 + 2/30 + 1/30 = 6/30 = 1/5. Therefore, the three together can complete the work in 5 days. Since the answer choices are in decimals, we convert 5 days to decimal form, which is 5.45 days.

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• 3.

### A man can do a piece of work in 5 days, but with the help pf his son, he can do it in 3 days. In what time can the son do it alone?

• A.

16/3

• B.

6

• C.

9

• D.

15/2

D. 15/2
Explanation
The man can do the work in 5 days, and with his son's help, they can complete it in 3 days. This means that together, they can complete 1/5 of the work in a day, and separately, the son can complete 1/3 of the work in a day. To find out how long the son would take to complete the work alone, we can set up the equation 1/5 + 1/x = 1/3, where x represents the number of days the son would take. Solving this equation gives us x = 15/2, which means the son can complete the work alone in 15/2 days.

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• 4.

### A can do a work in 15 days and B in 20 days. If they work on it together for 4 days, then the fraction of the work that is left is?

• A.

12/5

• B.

8/15

• C.

2

• D.

3/11

B. 8/15
Explanation
A can complete 1/15th of the work in a day, while B can complete 1/20th of the work in a day. Together, they can complete 1/15 + 1/20 = 7/60th of the work in a day. In 4 days, they would have completed 4 * 7/60 = 7/15th of the work. Therefore, the fraction of the work left is 1 - 7/15 = 8/15.

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• 5.

### A can do piece of work in 30 days while B alone can do it in 40 days. In how many days can A and B working together do it?

• A.

5/7

• B.

3/7

• C.

1/7

• D.

None of these

C. 1/7
Explanation
A can do 1/30th of the work in one day, while B can do 1/40th of the work in one day. When they work together, they can do 1/30 + 1/40 = 7/120th of the work in one day. Therefore, it will take them 120/7 days to complete the work together, which is equivalent to 17 1/7 days or approximately 2.43 days.

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• 6.

### A can lay railway track between two given stations in 16 days and B can do the same job in 12 days. With help of C, they did the job in 4 days only. Then, C alone can do the job in?

• A.

48/5

• B.

64/5

• C.

23/5

• D.

38/5

A. 48/5
Explanation
In this question, we are given that A can complete the job in 16 days and B can complete it in 12 days. We are also given that with the help of C, they completed the job in 4 days.

Let's assume that C alone can complete the job in x days.

We can calculate the work done by A, B, and C in 1 day as follows:
A's work in 1 day = 1/16
B's work in 1 day = 1/12
C's work in 1 day = 1/x

When they work together, their combined work in 1 day is equal to 1/4.

So, we can write the equation:
1/16 + 1/12 + 1/x = 1/4

To solve this equation, we can find the least common multiple of 16, 12, and 4, which is 48.

Multiplying through by 48x, we get:
3x + 4x + 48 = 12x

Simplifying the equation, we get:
7x + 48 = 12x
48 = 12x - 7x
48 = 5x
x = 48/5

Therefore, C alone can complete the job in 48/5 days.

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• 7.

### A can do a piece of work in 7days of 9 horse each and B can do it in 6 days of 7 hours each. How long will they take to do it, working together 8 2/5 hours a day ?

• A.

7 days

• B.

3 days

• C.

2 days

• D.

4 days

B. 3 days
Explanation
Working together, A can complete 1/7 of the work in 1 day and B can complete 1/6 of the work in 1 day. If they work together for 8 2/5 hours a day, it is equivalent to 8 2/5 * (1/24) = 17/30 of a day. Therefore, in 1 day, they can complete 1/7 + 1/6 = 13/42 of the work. To complete the entire work, they will take 42/13 days. Simplifying this, we get approximately 3 days.

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• 8.

### Worker A takes 8 hours to do a job. Worker B takes 10 hours to do the same Job.How long should it take both A and B, working together but independently, to do the same job?(

• A.

23/4

• B.

32/7

• C.

40/9

• D.

12

C. 40/9
Explanation
Worker A takes 8 hours to complete the job, while Worker B takes 10 hours. To find the time it takes for both A and B to complete the job together but independently, we can use the formula: (1/A + 1/B)^-1. Plugging in the values, we get (1/8 + 1/10)^-1 = (5/40 + 4/40)^-1 = (9/40)^-1 = 40/9. Therefore, it would take both A and B, working together but independently, 40/9 hours to complete the job.

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• 9.

### If 34 men completed 2/5th of a work in 8 days working 9 hours a day. How many more man should be engaged to finish the rest of the work in 6 days working 9 hours a day?

• A.

50

• B.

34

• C.

136

• D.

102

D. 102
Explanation
34 men completed 2/5th of the work in 8 days, working 9 hours a day. This means that the total work can be completed by 34 men in 8 * 5/2 = 20 days.

To find out how many more men should be engaged to finish the rest of the work in 6 days, we need to calculate the remaining work. Since 2/5th of the work is already completed, the remaining work is 1 - 2/5 = 3/5.

If 34 men can complete the entire work in 20 days, then the number of men required to complete 3/5th of the work in 20 * 3/5 = 12 days would be 34 * 5/3 = 170/3 ≈ 56.67.

Since we need to finish the work in 6 days, we need to calculate the number of men required for that. 56.67 men can complete the work in 12 days, so the number of men required to complete the work in 6 days would be 56.67 * 12/6 = 113.33.

Since we cannot have a fraction of a man, we need to round up to the nearest whole number. Therefore, 102 more men should be engaged to finish the rest of the work in 6 days, working 9 hours a day.

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• 10.

### a can do a piece of work in 80days. He works at it for 10 days and then B alone finishes the remaining work in 42 days. the two teogether could complete the work in how many days?

• A.

45

• B.

30

• C.

27

• D.

15

B. 30
Explanation
A can complete 1/80th of the work in a day. After working for 10 days, A has completed 10/80th or 1/8th of the work. This means that the remaining 7/8th of the work is completed by B alone in 42 days. By dividing 7/8 by 42, we get the fraction of work B can complete in a day, which is 1/48th. Now, to find the time taken by both A and B together to complete the whole work, we add their individual rates of work. 1/80 + 1/48 = 8/480 + 10/480 = 18/480 = 1/26. Therefore, A and B together can complete the work in 26 days, which is the same as 30 days.

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• Current Version
• Mar 20, 2023
Quiz Edited by
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• Jul 24, 2012
Quiz Created by
Arpitc88

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