Quick Test On Time & Work

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Time Quizzes & Trivia

Time and Work is one of the important topics in Quantitative Aptitude. In all competitive exams, we can expect a minimum of two questions from this topic. Practice this test and also share with your friends.


Questions and Answers
  • 1. 

    8 children and 10 men complete a certain piece of work in 29 days. If each child takes twice the time taken by a man to finish the work, then in how many days will 15men and 86 boys finish the same work?

    • A.

      15 days

    • B.

      10 days

    • C.

      7 days

    • D.

      6 days

    • E.

      None

    Correct Answer
    C. 7 days
    Explanation
    2 children = 1 man
    ∴ 8 children and 10 men = 4 + 10 = 14 men
    15 men + 86 boys = 15 men + 43 men = 58 men
    58 men finish the work in 14X29/58 = 7 days.

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  • 2. 

    A contractor undertook to do a certain work in 75 days and employed 48 men to do it. After 55 days he found that only 2/3 of the work was done. How many more men must be employed so that the work may finished in time?

    • A.

      18 men

    • B.

      22 men

    • C.

      15 men

    • D.

      20 men

    • E.

      None

    Correct Answer
    A. 18 men
    Explanation
    M1D2/W2 = M2 D2/W2
    48 X 55/ 2/3 = M X 20/ 1/3
    ∴ M = 66 men
    Required more men = 66 - 48 = 18 men.

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  • 3. 

    A, B and C each working alone, can finish a project in 42 days, 28 days and 48 days respectively. A started the project by working alone for 7 days and then B took over from A. B worked alone for 7 days, and then C took over from B. In how many days will C finish the remaining work?

    • A.

      30 days

    • B.

      28 days

    • C.

      20 days

    • D.

      40 days

    • E.

      None

    Correct Answer
    B. 28 days
    Explanation
    Let the total work be 336 units (LCM of 42, 28 and 48 = 336 units)
    ∴ A's one day's work = 336/42 = 8 units
    Similarly, B's one day's work = 336/28 = 12 units
    C's one day's work = 336/48 = 7 units
    ∴ A's 7 day's work = 7 X 8 = 56 units
    B's 7 day's work = 7 X 12 = 84 units
    ∴ Remaining work = 336 - (56 + 84) = 196
    ∴ C can do the remaining work in 196/7 = 28 days.

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  • 4. 

    24 women take 14 days to complete a piece of work which can be completed by 14 men in 12 days. 18 men started working and after 5 days, 10 men left and 8 women joined them. How many days will it take them to complete the remaining work?

    • A.

      15 1/4 days

    • B.

      10 1/3 days

    • C.

      6 1/2 days

    • D.

      5 1/3 days

    • E.

      None

    Correct Answer
    C. 6 1/2 days
    Explanation
    Work done by 24 women in 14 days = work done by 14 men in 12 days
    (24 X 14) women = (14 X 12) men
    ∴ 2 women = 1 man
    Now, work done by 14 men in one day = 1/12
    1 man's 1 day's work = 1/12 X 14 = 1/168
    ∴ 18 men's 5 days work = 18 X 5/168 = 15/28
    ∴ Remaining work = 1 - 15/28 = 13/28
    Now, 13/28 work is done by 8 men and 8 women
    8 men + 8 women = (8 men + 4 men) = 12 men
    Applying formula, M1D1/W1 = M2D2/W2
    14 X 12/1 = 12 X D2/ 13/28
    ∴ D2 = 14 X 12 X 13/12 X 28 = 13/2 = 6 1/2 days.

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  • 5. 

    2 boys and 3 girls can do a piece of work in 8 days while 3 boys and 2 girls can do the same piece of work in 7 days. How much time will be taken by 5 boys and 4 girls to do the same piece of work?

    • A.

      16 days

    • B.

      4 days

    • C.

      6 days

    • D.

      10 days

    • E.

      None

    Correct Answer
    A. 16 days
    Explanation
    According to the question,
    2b + 3g = 1/8
    3b + 2g = 1/7
    After solving both the equations,
    We have b = 1/28 and g = 1/56
    5b + 4g = 5/28 + 4/56 = 14/56 = 1/4
    So, 5 boys and 4 girls can finish the work in 4 days.

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  • 6. 

    A certain number of men can complete a piece of work in 70 days. Had there been 12 men less, it would have taken 10 days more. How many men were there initially?

    • A.

      100 men

    • B.

      80 men

    • C.

      36 men

    • D.

      96 men

    • E.

      None

    Correct Answer
    D. 96 men
    Explanation
    Let initially the number of men be x
    Then x men do the work in 70 days
    Now, (x – 12) men do the work in (70 + 10) = 80 days
    Thus, 70x = (x – 12) X 80
    70x = 80x – 960
    10x = 960
    ∴ x = 96 men.

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  • 7. 

    If 21 men can do a piece of work in 25 days working 10 hours a day, then how many men are required to complete the work in 15 days by working 7 hours per day?

    • A.

      50 men

    • B.

      55 men

    • C.

      40 men

    • D.

      25 men

    • E.

      None

    Correct Answer
    A. 50 men
    Explanation
    M1 X D1 X H1 = M2 X D2 X H2
    M2 = M1 X D1 X H1/H2 X D2 = 21 X 25 X 10/15 X 7 = 50 men.

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  • 8. 

    M can do a piece of work in 24 days. He works at it alone for 4 days and N alone finishes the remaining work in 25 days. Both of them together can complete the work in?

    • A.

      15 1/3 days

    • B.

      10 1/7 days

    • C.

      13 1/3 days

    • D.

      20 1/7 days

    • E.

      None

    Correct Answer
    C. 13 1/3 days
    Explanation
    M can do the work in 24 days
    ∴ M can do in 4 days = 4/24 = 1/6 part
    ∴ Remaining work = 1 – 1/6 = 5/6
    Since 5/6 is completed by N in 25 days
    ∴ 1 work is completed by N in 6/5 X 25 = 30 days
    ∴ Both together can do in 1 day = 1/24 + 1/30
    = 5 + 4/120
    = 9/120
    ∴ Hence both M and N can do the work in 120/9 = 13 3/9 = 13 1/3 days.

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  • 9. 

    A can do a piece of work in 8 days which B can destroy in 3 days. A has worked for 6 days, during the last 2 days of which has been destroying. How many days must A now work alone to complete the work?

    • A.

      7 1/3 days

    • B.

      11 1/5 days

    • C.

      10 1/3 days

    • D.

      8 1/3 days

    • E.

      None

    Correct Answer
    A. 7 1/3 days
    Explanation
    A can do the work in 8 days
    B can destroy it in 3 days
    LCM of 8 and 3 is 24
    So, A can do the work in 1 day = 3 units
    B can destroy the work in 1 day = 8 units
    Now, A has done the work in 6 days = 6 X 3 = 18 units
    But B has been destroyed the work in 2 days
    = 2 X 8 = 16 units
    ∴ In 8 days the work completed = 18 – 16 = 2 units
    ∴ Remaining work = 24 – 2 = 22 units
    ∴ 22 units of work is done by A in 22/3 = 7 1/3 days.

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  • 10. 

    A can build up a structure in 8 days and B can break it in 3 days. A has worked for 4 days and then B joined to work with A for another 2 days. In how many days will A alone build up the remaining part of the structure?

    • A.

      8 1/3 days

    • B.

      10 days

    • C.

      13 1/2 days

    • D.

      7 1/3 days

    • E.

      None

    Correct Answer
    D. 7 1/3 days
    Explanation
    A can build the structure in 8 days
    ∴ A can build the structure in a day = 1/8 part
    Similarly, B can break the structure in 3 days
    ∴ B can break 1/3 part of structure in 1 day
    Amount of work done by A in 4 days = 4/8 = 1/2
    Again, both A and B together work for 2 days
    So, the part of work done in these 2 days
    = 2 (1/8 – 1/3) = - 5/12
    ∴ Remaining work = 1 – 1/2 + 5/12
    = 12 – 6 + 5/12 = 11/12 work
    So, 11/12 work will be done by A in (11/12 X 8) days
    = 22/3 days = 7 1/3 days

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  • 11. 

    8 men and 4 women together can complete a piece of work in 8 days. The work done by a man in one day is twice the work done by a woman in one day. If 8 men and 4 women started working and after 2 days, 4 men left and 4 new women joined, in how many more days will the work be completed?

    • A.

      11 1/3 days

    • B.

      7 1/2 days

    • C.

      5 1/2 days

    • D.

      7 1/3 days

    • E.

      None

    Correct Answer
    B. 7 1/2 days
    Explanation
    According to the question,
    1 man = 2 women
    ∴ 8 men = 2 X 8 = 16 women
    ∴ 8 men + 4 women = 16 + 4 = 20 women
    4 men + 8 women = 8 + 8 = 16 women
    20 women’s 2 days work = 2/8 = ¼ part
    ∴ Remaining work = 1 – ¼ = ¾
    20 women complete 1 work in 8 days
    ∴ 16 women complete 1 work in 20 X 8/16 X 3/4
    = 15/2 = 7 ½ days.

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  • 12. 

    A and B can do a piece of work in 20 days while B and C can do the same piece of work in 30 days and C and A in 24 days. They all worked together for 10 days when C and A left the job. How many more days will B take to finish the work?

    • A.

      20 days

    • B.

      50 days

    • C.

      18 days

    • D.

      25 days

    • E.

      None

    Correct Answer
    C. 18 days
    Explanation
    2 (A + B + C)’s 1 day’s work = 1/20 + 1/30 + 1/24 = 15/120 = 1/8
    ∴ (A + B + C)’s 1 day’s work = 1/16
    Work done by A, B and C in 10 days = 10/16 = 5/8
    Remaining work = 1 – 5/8 = 3/8 part of work
    ∴ B’s 1 day’s work = 1/16 – 1/24 = 1/48
    So, 3/8 part of the work will be done by B in 48 X 3/8 = 18 days.

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  • 13. 

    A alone can finish a piece of work in 36 days. B is 20% more efficient than A. C is 50% more efficient than B. In how many days can A and C working together finish the same piece of work? (in days)

    • A.

      12 6/7 days

    • B.

      21 1/3 days

    • C.

      15 2/3 days

    • D.

      15 2/7 days

    • E.

      None

    Correct Answer
    A. 12 6/7 days
    Explanation
    A can alone finish the work in 36 days
    B is 20% more efficient than A
    Then B can alone finish the work in 36 X 100/120
    = 36 X 5/6 = 30 days
    ∴ C can alone finish the work in 30 X 100/150
    = 30 X 4/6 = 20 days
    ∴ (A + C) can do it one day = 1/36 + 1/20
    = 5 + 9/180
    = 14/180 = 7/90
    ∴ A and C can finish the work in 90/7 = 12 6/7 days.

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  • 14. 

    Aman alone can complete a piece of work in 8 days. The work done by Bihubati alone in one day is half of the work done by Aman alone in one day. In how many days can the work be completed if Aman and Bihubati work together?

    • A.

      15 1/2 days

    • B.

      4 1/3 days

    • C.

      8 1/3 days

    • D.

      5 1/3 days

    • E.

      None

    Correct Answer
    D. 5 1/3 days
    Explanation
    X does the work in 8 days
    Y does the work in 16 days
    ∴ X + Y do the work in 8 X 16/8 +16 = 5 1/3 days.

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  • 15. 

    If 20 men or 40 women or 80 children can do a piece of work in 11 days, then 5 men, 10 women and 15 children together can do the double of the work in __________

    • A.

      20 days

    • B.

      16 days

    • C.

      30 days

    • D.

      10 days

    • E.

      None

    Correct Answer
    B. 16 days
    Explanation
    20 men = 40 women = 80 children
    ∴ 1 man = 2 women = 4 children
    ∴ 1 woman = 2 children
    ∴ 5 men + 10 women + 15 children = 20 + 20 + 15 = 55 children
    Now, M1D1 = M2D2
    80 X 11 = 55 X D2
    ∴ D2 = 80 X 11/55
    ∴ D2 = 16 days.

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  • 16. 

    Two workers A and B working together completed a job in 12 days. Had A worked 4 times as efficiently as he actually did and B worked 2/3 as efficiently as he actually did, the work would have been completed in 7 days. To complete the job alone A would require?

    • A.

      43 1/11 days

    • B.

      8 1/3 days

    • C.

      38 2/11 days

    • D.

      5 4/3 days

    • E.

      None

    Correct Answer
    C. 38 2/11 days
    Explanation
    If A alone does the work in x days and B alone does the work in y days
    Then, 1/x + 1/y = 1/12 ---------- > (i)
    Again, 4/x + 2/3y = 1/7 ---------- > (ii)
    Subtracting equation (i) from equation (ii) X 3/2 , we get
    6/x + 1/y – 1/x – 1/y = 3/14 – 1/12
    6/x – 1/x = 11/84
    5/x = 11/84
    ∴ x = 84 X 5/11 = 38 2/11 days.

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  • 17. 

    A can complete a given task in 24 days, while B is twice as efficient as he. A started on the work initially, and was joined by B after a few days. If the whole work was completed in 10 days, after how many days, from the time A started working, did B join A?

    • A.

      3 days

    • B.

      6 days

    • C.

      10 days

    • D.

      15 days

    • E.

      None

    Correct Answer
    A. 3 days
    Explanation
    A can complete the work in 24 days
    Efficiency of B is twice that of A
    ∴ B can complete the work in 24 X ½ = 12 days
    According to the question, the work is completed in 10 days.
    LCM of 24 and 12 = 24 units
    Let the total work be 24 units
    ∴ A can do in one day 24/24 = 1 unit
    A and B can do in one day = 24/12 = 2 units
    Now, A works for 10 days
    ∴ Total work done by A in 10 days = 10 X 1 = 10 units’
    ∴ Remaining work = 24 – 10 = 14 units
    Now, 14 units of work is done by B in 14/2 = 7 days
    Hence B joined the work after (10 – 7) = 3 days.

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  • 18. 

    6 men and 6 women together can complete a piece of work in 6 days. In how many days can 15 men alone complete the same work if 9 women alone can complete it in 10 days?

    • A.

      6 days

    • B.

      5 days

    • C.

      8 days

    • D.

      4 days

    • E.

      None

    Correct Answer
    D. 4 days
    Explanation
    Since, 9 women can complete the work in 10 days
    ∴ 6 women can complete the work in 10 X 9/6 = 15 days
    6 women in 6 days complete 6/15 = 2/5 part
    ∴ The remaining (1 – 2/5) = 3/5 part will be completed by 6 men in 6 days
    So, 6 men’s work in 1 day = 3/5 X 6 = 1/10 part
    Since, 6 men can complete the work in 10 days
    ∴ 15 men can complete the work in 6 X 10/15 = 4 days.

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  • 19. 

    36 men can complete a work in 24 days. How many persons will be required to complete the work in 18 days?

    • A.

      14 persons

    • B.

      48 persons

    • C.

      28 persons

    • D.

      58 persons

    • E.

      None

    Correct Answer
    B. 48 persons
    Explanation
    Required no. of persons = 36 X 24/18 = 48 persons.

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  • 20. 

    12 persons can complete a piece of work in 84 days. How many persons will be required to complete the work in 36 days?

    • A.

      30 persons

    • B.

      14 persons

    • C.

      28 persons

    • D.

      15 persons

    • E.

      None

    Correct Answer
    C. 28 persons
    Explanation
    Required no. of persons = 12 X 84/36 = 28 persons.

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  • 21. 

    18 men and 24 women can complete a piece of work in 16 days. All of them started working together but after 12 working days, the women stopped working together. 12 men completed the work in 9 days. How many days will it take to complete the entire job if only 24 women have to complete the job?

    • A.

      48 days

    • B.

      50 days

    • C.

      53 days

    • D.

      46 days

    • E.

      None

    Correct Answer
    A. 48 days
    Explanation
    Amount of work done by 18 men and 24 women in 12 days = 12/16 = 3/4
    ∴ Remaining work = 1 – 3/4 = 1/4
    Now, 12 men complete ¼ work in 9 days
    ∴ 18 men can complete the entire work in 9 x 4 X 12/18 = 24 days
    Now, 1/16 – 1/24 = 1/48
    ∴ 24 women together can do the job = 48 days.

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  • 22. 

    Priyanka can do a piece of work in 4 hours. Priya and Pritam together can do it in 3 3/7 hours, while Priyanka and Pritam together can do it in 2 2/3 hours. How long will Priya alone take to do it?

    • A.

      5 hours

    • B.

      10 hours

    • C.

      9 hours

    • D.

      6 hours

    • E.

      None

    Correct Answer
    D. 6 hours
    Explanation
    Priya + Pritam = 3 3/7 = 24/7 ------- > (i)
    Priyanka + Pritam = 2 2/3 = 8/3 ------ > (ii)
    Now, from (ii), we get
    Pritam’s work = 3/8 – 1/4 = 3 – 2/8 = 1/8
    Again from (i),
    Priya’s work = 7/24 – 1/8 = 7 – 3/24 = 4/24 = 1/6
    Hence Priya alone does it in 6 hours.

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  • 23. 

    Priyanka can do 3/4 of a job in 12 days. Muskan is twice as efficient as Priyanka. In how many days can Muskan finish the job?

    • A.

      10 days

    • B.

      8 days

    • C.

      15 days

    • D.

      20 days

    • E.

      None

    Correct Answer
    B. 8 days
    Explanation
    Priyanka can do the whole job in 12 X 4/3 = 16 days
    ∴ Muskan can do it in 16/2 = 8 days.

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  • 24. 

    When 24 men work for only 3 days, 5/6 of the work remains unfinished. How much work will remain unfinished if 27 men work for only 2 days?

    • A.

      1/3 work

    • B.

      2/3 work

    • C.

      7/8 work

    • D.

      8/3 work

    • E.

      None

    Correct Answer
    C. 7/8 work
    Explanation
    M1D1/W1 = M2D2/W2
    Here M1 = 24, D1= 3 days, W1 = 1 – 5/6 = 1/6 work finished
    M2 = 27, D2 = 2 days, W2 = ?
    ∴ W2 = M2D2 X W1/M1D1 = 27 X 2 X 1/6 / 24 X 3 = 9/24 X 3 = 1/8 work finished
    ∴ Unfinished work = 1 – 1/8 = 7/8.

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  • 25. 

    4 men can complete a piece of work in 7 days. 7 children can complete the work in 16 days. In how many days can 3 men and 2 children together complete the work?

    • A.

      6 days

    • B.

      8 days

    • C.

      9 days

    • D.

      12 days

    • E.

      None

    Correct Answer
    B. 8 days
    Explanation
    According to the question,
    The work completed by one man and one child.
    (4 X 7) men = (16 X 7) children
    28 men = 112 children
    ∴ 1 man = 4 children
    ∴ 3 men = 3 X 4 = 12 children
    Since, 7 children complete the work in 16 days.
    ∴ 12 + 2 = 14 children complete the work in 16 X 7/14 = 112/14 = 8 days.

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Our quizzes are rigorously reviewed, monitored and continuously updated by our expert board to maintain accuracy, relevance, and timeliness.

  • Current Version
  • Mar 19, 2023
    Quiz Edited by
    ProProfs Editorial Team
  • Mar 28, 2017
    Quiz Created by
    Divyanaidu94
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