# Quantitative Apptitude - Problems On Ages Online Test 10

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Questions: 10 | Attempts: 4,671

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• 1.

### The age of a man is three times the sum of the ages of his two sons. Five years hence, his age will be double of the sum of the ages of his sons. The father's present age is?

• A.

40 yr

• B.

45 yr

• C.

55 yr

• D.

67 yr

B. 45 yr
Explanation
Let's assume the age of the father is F and the ages of his two sons are S1 and S2. According to the given information, F = 3(S1 + S2). Five years from now, the father's age will be F + 5 and the sum of his sons' ages will be (S1 + 5) + (S2 + 5). It is given that F + 5 = 2((S1 + 5) + (S2 + 5)). Simplifying this equation, we get F + 5 = 2(S1 + S2 + 10). Substituting F = 3(S1 + S2), we have 3(S1 + S2) + 5 = 2(S1 + S2 + 10). Solving this equation, we find S1 + S2 = 15, and substituting this back into F = 3(S1 + S2), we get F = 45. Therefore, the father's present age is 45 years.

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• 2.

### Rajan got married 8 years ago. His present age is 6 / 5 times his age at the time of his marriage. Rajan's sister was 10 years younger to him at the time of his marriage. The age of Rajan's sister is?

• A.

25 yr

• B.

33 yr

• C.

38 yr

• D.

45 yr

C. 38 yr
Explanation
Rajan's present age is 6/5 times his age at the time of his marriage. Let's assume his age at the time of his marriage is x. Therefore, his present age is (6/5)x.

Rajan's sister was 10 years younger than him at the time of his marriage. So her age at the time of his marriage would be (x - 10).

We need to find the age of Rajan's sister in the present. Since Rajan's present age is (6/5)x, we can set up the equation (6/5)x = (x - 10).

Simplifying the equation, we get 6x = 5x - 50. Solving for x, we find x = 50.

Therefore, the age of Rajan's sister in the present is (50 - 10) = 40 years.

Since the closest option to 40 years is 38 years, the correct answer is 38 years.

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• 3.

### Abhay’s age after six years will be three-seventh of his fathers age. Ten years ago the ratio of their ages was 1 : 5. What is Abhay’s father's age at present?

• A.

35 yr

• B.

40 yr

• C.

45 yr

• D.

50 yr

D. 50 yr
Explanation
Ten years ago, the ratio of Abhay's age to his father's age was 1:5. Let's assume Abhay's age ten years ago was x, and his father's age ten years ago was 5x.

After six years, Abhay's age will be x + 6, and his father's age will be 5x + 6.

According to the given information, Abhay's age after six years will be three-sevenths of his father's age:

x + 6 = (3/7)(5x + 6)

Simplifying the equation, we get:

7x + 42 = 15x + 18

8x = 24

x = 3

Therefore, Abhay's age at present is 3 + 10 = 13 and his father's age at present is 5(3) + 10 = 25 + 10 = 35.

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• 4.

### The average age of class of 24 students is 24 years. The average increased by 1 when the teacher's age is also included. What is the teacher's age?

• A.

49 yr

• B.

44 yr

• C.

37 yr

• D.

57 yr

A. 49 yr
Explanation
The average age of the class is 24 years and there are 24 students. This means that the total age of all the students combined is 24 * 24 = 576 years. When the teacher's age is included, the average increases by 1. This means that the total age of all the students and the teacher combined is 24 * 25 = 600 years. Therefore, the teacher's age is 600 - 576 = 24 years.

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• 5.

### The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is?

• A.

7:2

• B.

4:1

• C.

5:3

• D.

7:3

D. 7:3
Explanation
Let's assume the present age of the son is x years. According to the given information, the father's age 10 years ago was 3 times the son's age. So, the father's age 10 years ago was 3x years.

Now, let's consider the future. Ten years hence, the father's age will be twice that of his son. So, the father's age in the future will be 2x years.

From this information, we can form the equation: 3x + 10 = 2x + 20. Solving this equation, we find that x = 10.

Therefore, the present age of the son is 10 years. And the present age of the father is 3x + 10 = 3(10) + 10 = 40 years.

The ratio of their present ages is 40:10, which simplifies to 4:1.

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• 6.

### Meeta is two years older than Sunita. After six years the sum of their ages will be seven times their present age. Find out the age of Meeta?

• A.

5 yr

• B.

8 yr

• C.

12 yr

• D.

None of these

D. None of these
• 7.

• A.

43 yr

• B.

60 yr

• C.

57 yr

• D.

31 yr

B. 60 yr
• 8.

### The ratio of the ages of Meena and Meera is 4:3, The sum of their ages is 28 years. The ratio of their ages after 8 years will be?

• A.

7:3

• B.

6:5

• C.

8:3

• D.

3:4

B. 6:5
Explanation
The ratio of the ages of Meena and Meera is 4:3, which means that if we let their ages be 4x and 3x respectively, the sum of their ages is 4x + 3x = 7x. We are given that the sum of their ages is 28 years, so 7x = 28. Solving for x, we find that x = 4. Therefore, Meena's age is 4x = 4 * 4 = 16 years and Meera's age is 3x = 3 * 4 = 12 years. After 8 years, Meena's age will be 16 + 8 = 24 years and Meera's age will be 12 + 8 = 20 years. The ratio of their ages after 8 years is therefore 24:20, which simplifies to 6:5.

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• 9.

### Rajan got married 8 years ago. His present age is 6   times his age at the time of his   5   marriage. Rajan's sister was 10 years younger to him at the time of his marriage. The age of Rajan's sister is?

• A.

54 yr

• B.

38 yr

• C.

26 yr

• D.

55 yr

B. 38 yr
Explanation
Rajan's present age is 6 times his age at the time of his marriage. Let's assume his age at the time of his marriage was x years. Therefore, his present age is 6x years.

Rajan's sister was 10 years younger to him at the time of his marriage. So, her age at the time of his marriage was (x - 10) years.

To find the age of Rajan's sister, we need to substitute the value of x in the equation 6x = (x - 10).

By solving this equation, we get x = 10.

Therefore, Rajan's sister's age is (10 - 10) = 0 years.

However, it is not possible for Rajan's sister to have an age of 0 years, so the question is incomplete or not readable.

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• 10.

### The sum of the ages of the 5 children's born at the intervals of 3 years each is 50 years what is the age of the youngest child?

• A.

4 yr

• B.

6 yr

• C.

8 yr

• D.

10 yr

A. 4 yr
Explanation
The sum of the ages of the 5 children born at intervals of 3 years each is 50 years. To find the age of the youngest child, we can divide the total age by the number of children, which is 5. 50 divided by 5 equals 10. Therefore, the age of the youngest child is 10 years.

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