Qualitative Analysis Self Test

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Quizzes Created: 4 | Total Attempts: 5,898
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  • 1/5 Questions

    Which of the following ions in solution would form a reddish-brown precipitate when aqueous sodium hydroxide solution is added dropwise to it?

    • Copper(II) ions
    • Iron(II) ions
    • Iron(III) ions
    • Zinc ions
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  • 2. 

    Which of the following ions in solution would form a white precipitate when acidified barium nitrate solution is added to it?

    • Chloride ion

    • Iodide ion

    • Nitrate ion

    • Sulfate ion

    Correct Answer
    A. Sulfate ion
    Explanation
    When acidified barium nitrate solution is added to sulfate ions in solution, a white precipitate of barium sulfate is formed. This is because barium sulfate is insoluble in water and forms a solid precipitate when barium ions react with sulfate ions.

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  • 3. 

    What would be the observations when aqueous ammonia is added to a solution of zinc nitrate (until in excess) and heated?

    • White precipitate formed. On heating, a colourless, pungent gas evolved.

    • White precipitate formed which dissolved in excess aqeous ammonia to form a colourless solution.

    • White precipitate formed which dissolved in excess aqeous ammonia to form a colourless solution. On heating, a colourless, pungent gas evolved.

    • Blue precipitate formed which dissolved in excess aqeous ammonia to form a dark blue solution. On heating, a colourless, pungent gas evolved.

    Correct Answer
    A. White precipitate formed which dissolved in excess aqeous ammonia to form a colourless solution. On heating, a colourless, pungent gas evolved.
    Explanation
    When aqueous ammonia is added to a solution of zinc nitrate until in excess and heated, a white precipitate is formed. This white precipitate is zinc hydroxide, which is insoluble in water. However, when excess aqueous ammonia is added, it dissolves the white precipitate to form a colorless solution. This is because zinc hydroxide reacts with excess aqueous ammonia to form a complex ion called tetraamminezinc(II) ion, which is soluble in water. On heating, a colorless and pungent gas, which is ammonia gas, is evolved due to the decomposition of the tetraamminezinc(II) ion.

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  • 4. 

    Which of the following ions in solution would form a white precipitate that is soluble in excess sodium hydroxide solution is added to it?

    • Aluminium ions

    • Calcium ions

    • Lead(II) ions

    • Zinc ions

    Correct Answer(s)
    A. Aluminium ions
    A. Lead(II) ions
    A. Zinc ions
    Explanation
    Aluminium ions, Lead(II) ions, and Zinc ions would form a white precipitate that is soluble in excess sodium hydroxide solution. This is because these ions can react with sodium hydroxide to form their respective hydroxide compounds, which are white precipitates. However, these precipitates are soluble in excess sodium hydroxide solution due to the formation of soluble complex ions.

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  • 5. 

    Which of the following gases fits the following description?"The gas is colourless, pungent and turns moist blue litmus paper pink and bleaches it."

    • Ammonia

    • Chlorine

    • Oxygen

    • Sulfur dioxide

    Correct Answer(s)
    A. Chlorine
    A. Sulfur dioxide
    Explanation
    Chlorine and sulfur dioxide are the correct answers because both gases are colorless and have a pungent odor. Additionally, they both have the ability to turn moist blue litmus paper pink and bleach it.

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  • Mar 21, 2023
    Quiz Edited by
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  • Feb 26, 2010
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