Empirical And Molecular Formula Quiz -chemistry

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  • 1/10 Questions

    Empirical Formula: 39.8% K, 27.8% Mn, 32.5% O

    • N3,Mn,5O
    • K2,Mn,O4
    • Mn3,K,O7
    • O10,Mn,5K
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About This Quiz

Determine the empirical and molecular formula of each compound from its percentage composition.

Empirical And Molecular Formula Quiz -chemistry - Quiz

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  • 2. 

    Empirical Formula: 32.4% Na, 22.6% S, 45.0% O

    • Na4,S6,O23

    • S5,Na16,O

    • Na2,S,O4

    • O20,S2,Na15

    Correct Answer
    A. Na2,S,O4
    Explanation
    The empirical formula for the given compound is Na2S0.4O. This is determined by converting the percentages of each element into moles and finding the simplest whole number ratio between them. In this case, there are 2 moles of Na, 1 mole of S, and 4 moles of O. Dividing each by the lowest number of moles (1 mole of S), we get the ratio of 2:1:4, which gives us the empirical formula Na2S0.4O.

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  • 3. 

    Empirical Formula: 79.8% Cu, 20.2% S

    • Cu5,S6

    • S4,Cu10

    • Cu9,S8

    • Cu2,S

    Correct Answer
    A. Cu2,S
    Explanation
    The empirical formula for the given composition of 79.8% Cu and 20.2% S is Cu2,S. This means that there are 2 atoms of copper (Cu) and 1 atom of sulfur (S) present in the empirical formula. The ratio of Cu to S in the empirical formula is 2:1, which corresponds to the given percentages. Therefore, Cu2,S is the correct empirical formula for the composition.

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  • 4. 

    Empirical Formula: 62.6% Ca, 37.4% C

    • Ca,C2

    • C4,Ca10

    • Ca5,C3

    • Ca7,C10

    Correct Answer
    A. Ca,C2
    Explanation
    The empirical formula Ca,C2 indicates that the compound contains calcium (Ca) and carbon (C) in a ratio of 1:2. This means that for every 1 atom of calcium, there are 2 atoms of carbon present. The percentages given in the empirical formula (62.6% Ca, 37.4% C) suggest that calcium is the more abundant element in the compound. Therefore, the correct answer is Ca,C2.

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  • 5. 

    Empirical Formula: 1.90%H, 67.6%Cl, 30.5%O

    • H2,O9,Cl5

    • Cl5,O2,H7

    • H,CL,O

    • O17,Cl3,H9

    Correct Answer
    A. H,CL,O
    Explanation
    The empirical formula for the given compound is HClO. This is determined by converting the percentages to moles and dividing by the smallest number of moles to get the simplest ratio. In this case, the ratio is 1:1:1, which corresponds to the empirical formula HClO.

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  • 6. 

    Empirical Formula: 36.8%N, 63.2% O

    • N16,O

    • N2,O3

    • O4,N7

    • N2,O4

    Correct Answer
    A. N2,O3
    Explanation
    The empirical formula of the compound with 36.8% nitrogen and 63.2% oxygen is N2O3. This is determined by converting the percentages to moles and finding the simplest whole number ratio between the elements. In this case, there are 2 moles of nitrogen for every 3 moles of oxygen, resulting in the empirical formula N2O3.

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  • 7. 

    Empirical Formula: 60.0%C, 13.3%H, 26.7%O

    • H,C,O

    • H2,O4,C2

    • C8,O9,H3

    • C3,H8,O

    Correct Answer
    A. C3,H8,O
    Explanation
    The empirical formula of the given compound is C3H8O. This can be determined by finding the simplest whole number ratio of the elements present in the compound. The percentages given indicate the relative amounts of carbon, hydrogen, and oxygen. By dividing each percentage by the atomic mass of the respective element, we can find the number of moles of each element. Then, by dividing each mole value by the smallest mole value, we can find the ratio of the elements. In this case, the ratio is 3:8:1, which corresponds to the empirical formula C3H8O.

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  • 8. 

    Molecular Formula: 65.45%C, 5.45%H, 29.10%O; mol. wt= 110

    • C3,H2,O5

    • C6,H12,O2

    • H3,C9,O

    • O4,H7,C3

    Correct Answer
    A. C6,H12,O2
    Explanation
    The molecular formula C6H12O2 is the correct answer because it matches the given percentages of carbon, hydrogen, and oxygen. The percentages of carbon, hydrogen, and oxygen in the formula (65.45%, 5.45%, and 29.10% respectively) closely match the given percentages. Additionally, the molecular weight of the formula (110) matches the given molecular weight.

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  • 9. 

    Empirical Formula: 38.9%CL, 61.2%O

    • Cl2,O7

    • O3,Cl

    • O,Cl

    • Cl4,O8

    Correct Answer
    A. Cl2,O7
    Explanation
    The empirical formula for the given compound with 38.9% CL and 61.2% O is Cl2O7. This is because the percentages of each element in the compound can be converted to moles, and then divided by the smallest number of moles to find the ratio of the elements. In this case, dividing the moles of Cl by 2 and the moles of O by 7 gives us the ratio of 1:3.5, which can be simplified to 1:7. Therefore, the empirical formula is Cl2O7.

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  • 10. 

    Molecular Formula: 40.0%C, 6.7%H, 53.3%O; mol. wt= 180

    • 456

    • 56

    Correct Answer
    A. 456
    Explanation
    The molecular formula of the compound is not provided in the question. The answer 456 does not seem to be related to the given information. Therefore, it is not possible to provide an explanation for the given answer as it is not clear how it is derived or what it represents.

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  • Current Version
  • Mar 22, 2023
    Quiz Edited by
    ProProfs Editorial Team
  • Mar 12, 2012
    Quiz Created by
    Webdesign2012
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