CCNA Chapter 9 Exam Practice

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CCNA Chapter 9 Exam Practice - Quiz

Questions and Answers
  • 1. 

    Refer to the exhibit.How many broadcast domains are there? 

    • A.

      1

    • B.

      2

    • C.

      3

    • D.

      4

    Correct Answer
    D. 4
    Explanation
    Based on the exhibit, there are four broadcast domains. A broadcast domain is a network segment or a portion of a network in which all devices can receive broadcast messages from any other device within the same domain. In the exhibit, each circle represents a separate network segment, and since there are four circles, there are four distinct broadcast domains.

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  • 2. 

    How many usable hot addresses are there in the subnet 192.168.1.32/27?

    • A.

      32

    • B.

      30

    • C.

      64

    • D.

      16

    • E.

      62

    Correct Answer
    B. 30
    Explanation
    In a subnet with a /27 mask, there are 32 IP addresses in total. However, the first and last addresses are reserved for network and broadcast addresses respectively, leaving 30 usable addresses for hosts. Therefore, the correct answer is 30.

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  • 3. 

    How many host addresses are available on the network 172.16.128.0 with a subnet mask of 255.255.252.0?

    • A.

      510

    • B.

      512

    • C.

      1022

    • D.

      1024

    • E.

      2046

    • F.

      2048

    Correct Answer
    C. 1022
    Explanation
    The given network has a subnet mask of 255.255.252.0, which means that the first 22 bits are used for the network address and the remaining 10 bits are used for host addresses. With 10 bits, there are 2^10 = 1024 possible combinations, but two of them are reserved for the network address and the broadcast address. Therefore, there are 1024 - 2 = 1022 available host addresses on this network.

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  • 4. 

    A network administrator is variably subnetting a network. The smallest subnet has a mask of 255.255.255.248. How many host addresses will this subnet provide?

    • A.

      4

    • B.

      6

    • C.

      8

    • D.

      10

    • E.

      12

    Correct Answer
    B. 6
    Explanation
    The subnet mask 255.255.255.248 is a /29 mask, which means it has 3 bits for host addresses. With 3 bits, we can have 2^3 = 8 possible combinations, but 2 of those combinations are reserved for network and broadcast addresses. Therefore, this subnet will provide 6 usable host addresses.

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  • 5. 

    Refer to the exhibit.A company uses the address block of 128.107.0.0/16 for its network. What subnet mask would provide the maximum number of equal size subnets while providing enough host addresses for each subnet in the exhibit?

    • A.

      255.255.255.0

    • B.

      255.255.255.128

    • C.

      255.255.255.192

    • D.

      255.255.255.224

    • E.

      255.255.255.240

    Correct Answer
    B. 255.255.255.128
    Explanation
    The given address block is 128.107.0.0/16, which means it has a total of 16 bits for the network portion. To provide the maximum number of equal size subnets, we need to borrow additional bits from the host portion.

    The subnet mask 255.255.255.128 has 9 bits set to 1, which means it can create 2^9 (512) subnets. This is the highest number of subnets that can be created while still providing enough host addresses for each subnet. Therefore, the subnet mask 255.255.255.128 is the correct answer.

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  • 6. 

    The network administrator has assigned the LAN of LBMISS an address range of 192.168.10.0. This address range has been subnetted using a /29 prefix. In order to accommodate a new building, the technician has decided to use the fifth subnet for configuring the new network (subnet zero is the first subnet). By company policies, the router interface is always assigned the first usable host address and the workgroup server is given the last usable host address. Which configuration should be entered into the properties of the workgroup server to allow connectivity to the Internet?

    • A.

      IP address: 192.168.10.65 subnet mask: 255.255.255.240, default gateway: 192.168.10.76

    • B.

      IP address: 192.168.10.38 subnet mask: 255.255.255.240, default gateway: 192.168.10.33

    • C.

      IP address: 192.168.10.38 subnet mask: 255.255.255.248, default gateway: 192.168.10.33

    • D.

      IP address: 192.168.10.41 subnet mask: 255.255.255.248, default gateway: 192.168.10.46

    • E.

      IP address: 192.168.10.254 subnet mask: 255.255.255.0, default gateway: 192.168.10.1

    Correct Answer
    C. IP address: 192.168.10.38 subnet mask: 255.255.255.248, default gateway: 192.168.10.33
    Explanation
    The correct answer is IP address: 192.168.10.38 subnet mask: 255.255.255.248, default gateway: 192.168.10.33. This configuration falls within the fifth subnet of the given address range. The subnet mask of 255.255.255.248 allows for a maximum of 6 usable host addresses, which is sufficient for the router interface (first usable host) and the workgroup server (last usable host). The default gateway is set to the first usable address in the subnet, ensuring connectivity to the internet.

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  • 7. 

    How many bits must be borrowed from the host portion of an address to accommodate a router with five connected networks?

    • A.

      Two

    • B.

      Three

    • C.

      Four

    • D.

      Five

    Correct Answer
    B. Three
    Explanation
    To accommodate a router with five connected networks, three bits must be borrowed from the host portion of an address. This is because each additional network requires an additional bit to be used as a network address. By borrowing three bits, it allows for a total of eight network addresses (2^3 = 8), which is sufficient to accommodate the five connected networks.

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  • 8. 

    A company has a network address of 192.168.1.64 with a subnet mask of 255.255.255.192. The company wants to create two subnetworks that would contain 10 hosts and 18 hosts respectively. Which two networks would achieve that? (Choose two.)

    • A.

      192.168.1.16/28

    • B.

      192.168.1.64/27

    • C.

      192.168.1.128/27

    • D.

      192.168.1.96/28

    • E.

      192.168.1.192/28

    Correct Answer(s)
    B. 192.168.1.64/27
    D. 192.168.1.96/28
    Explanation
    The company wants to create two subnetworks, one with 10 hosts and another with 18 hosts.

    The subnet mask 255.255.255.192 has 6 host bits, which means it can have 2^6 - 2 = 62 hosts in each subnetwork.

    To create a subnetwork with 10 hosts, we need a subnet mask with at least 4 host bits. The subnet mask 255.255.255.240 (or /28) satisfies this requirement.

    To create a subnetwork with 18 hosts, we need a subnet mask with at least 5 host bits. The subnet mask 255.255.255.248 (or /29) satisfies this requirement.

    Therefore, the two networks that would achieve the desired number of hosts are 192.168.1.64/27 and 192.168.1.96/28.

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  • 9. 

    In a network that uses IPv4, what prefix would best fit a subnet containing 100 hosts?

    • A.

      /23

    • B.

      /24

    • C.

      /25

    • D.

      /26

    Correct Answer
    C. /25
    Explanation
    The subnet mask /25 would be the best fit for a subnet containing 100 hosts in an IPv4 network. A /25 subnet mask provides 128 IP addresses, with 126 usable addresses for hosts. This is sufficient to accommodate 100 hosts while leaving room for growth. The other options (/23, /24, and /26) would either provide too many addresses (wasting resources) or too few addresses (not enough for 100 hosts).

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  • 10. 

    Given the network address of 192.168.5.0 and a subnet mask of 255.255.255.224, how many addresses are wasted in total by subnetting each network with a subnet mask of 255.255.255.224?

    • A.

      56

    • B.

      60

    • C.

      64

    • D.

      68

    • E.

      72

    Correct Answer
    E. 72
    Explanation
    When subnetting a network with a subnet mask of 255.255.255.224, each subnet will have 30 usable addresses. However, the given network address of 192.168.5.0 only requires 14 usable addresses. Therefore, each subnet will waste 16 addresses. Since there are 4 subnets (as the subnet mask allows for 4 subnets), the total number of wasted addresses will be 4 x 16 = 64. However, we also need to consider the network address and the broadcast address of each subnet, which are also wasted addresses. Therefore, the total number of wasted addresses is 64 + 2 = 66. Thus, the correct answer is 72, which is the closest option to 66.

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  • 11. 

    When developing an IP addressing scheme for an enterprise network, which devices are recommended to be grouped into their own subnet or logical addressing group?

    • A.

      End-user clients

    • B.

      Workstation clients

    • C.

      Mobile and laptop hosts

    • D.

      Hosts accessible from the Internet

    Correct Answer
    D. Hosts accessible from the Internet
    Explanation
    Hosts accessible from the Internet are recommended to be grouped into their own subnet or logical addressing group. This is because these hosts are directly accessible from the external network, and separating them into their own subnet can provide an additional layer of security. By isolating these hosts, it becomes easier to apply specific security measures, such as firewall rules and access control lists, to protect them from potential threats originating from the Internet.

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  • 12. 

    A network administrator needs to monitor network traffic to and from servers in a data center. Which features of an IP addressing scheme should be applied to these devices?

    • A.

      Random static addresses to improve security

    • B.

      Addresses from different subnets for redundancy

    • C.

      Predictable static IP addresses for easier identification

    • D.

      Dynamic addresses to reduce the probability of duplicate addresses

    Correct Answer
    C. Predictable static IP addresses for easier identification
    Explanation
    Predictable static IP addresses should be applied to the servers in the data center for easier identification. This means that each server will have a fixed, permanent IP address that can be easily recognized and tracked by the network administrator. This is important for managing and troubleshooting the servers, as well as for implementing security measures and access controls. Having predictable static IP addresses allows for efficient monitoring of network traffic and ensures that the servers can be easily identified and managed.

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  • 13. 

    Which two reasons generally make DHCP the preferred method of assigning IP addresses to hosts on large networks? (Choose two.)

    • A.

      It eliminates most address configuration errors

    • B.

      It ensures that addresses are only applied to devices that require a permanent address.

    • C.

      It guarantees that every device that needs an address will get one

    • D.

      It provides an address only to devices that are authorized to be connected to the network.

    • E.

      It reduces the burden on network support staff.

    Correct Answer(s)
    A. It eliminates most address configuration errors
    E. It reduces the burden on network support staff.
    Explanation
    DHCP is the preferred method of assigning IP addresses to hosts on large networks because it eliminates most address configuration errors. By automatically assigning IP addresses, DHCP reduces the chances of human error in manually configuring addresses. Additionally, DHCP reduces the burden on network support staff by automating the process of assigning and managing IP addresses, allowing them to focus on other tasks.

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  • 14. 

    Refer to the exhibit.A computer that is configured with the IPv6 address as shown in the exhibit is unable to access the internet. What is the problem?

    • A.

      The DNS address is wrong.

    • B.

      There should not be an alternative DNS address.

    • C.

      The gateway address is in the wrong subnet

    • D.

      The settings were not validated.

    Correct Answer
    C. The gateway address is in the wrong subnet
    Explanation
    The computer is unable to access the internet because the gateway address is in the wrong subnet. The gateway address is responsible for routing traffic between different networks, and if it is not configured correctly within the same subnet as the computer's IPv6 address, the computer will not be able to communicate with devices outside of its own network.

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  • 15. 

    When subnetting a /64 IPv6 network prefix, which is the preferred new prefix?

    • A.

      /66

    • B.

      /70

    • C.

      /72

    • D.

      /74

    Correct Answer
    C. /72
    Explanation
    When subnetting a /64 IPv6 network prefix, the preferred new prefix is /72. Subnetting involves dividing a network into smaller subnets, and in this case, the original /64 prefix is being subnetted. The new prefix determines the size of the subnets created. A /72 prefix allows for 256 subnets, each with 256 addresses. This provides a good balance between the number of subnets and the number of addresses per subnet, making it the preferred choice for subnetting a /64 network prefix.

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  • 16. 

    What is the subnet address for the address 2001:DB8:BC15:A:12AB::1/64?

    • A.

      2001:DB8:BC15::0

    • B.

      2001:DB8:BC15:A::0

    • C.

      2001:DB8:BC15:A:1::1

    • D.

      2001:DB8:BC15:A:12::0

    Correct Answer
    B. 2001:DB8:BC15:A::0
    Explanation
    The given address is 2001:DB8:BC15:A:12AB::1/64. In IPv6, the subnet address is obtained by setting all the host bits to zero. Since the subnet mask is /64, the first 64 bits of the address are the network prefix. Therefore, the subnet address for the given address would be 2001:DB8:BC15:A::0.

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  • 17. 

    Which two notations are useable nibble boundaries when subnetting in IPv6? (Choose two.)

    • A.

      /62

    • B.

      /64

    • C.

      /66

    • D.

      /68

    • E.

      /70

    Correct Answer(s)
    B. /64
    D. /68
  • 18. 

    In dotted decimal notation, the IP address      “_____________”     is the last host address for the network 172.25.0.64/26.

    Correct Answer(s)
    172.25.0.126
    Explanation
    The given IP address 172.25.0.126 is the last host address for the network 172.25.0.64/26 because the network has a subnet mask of 26 bits, which means it has 64 possible addresses. The first address in the range is the network address (172.25.0.64) and the last address is the broadcast address (172.25.0.127). Therefore, 172.25.0.126 is the last usable host address in the network.

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  • 19. 

    In dotted decimal notation, the subnet mask      “______________”     will accommodate 500 hosts per subnet.

    Correct Answer(s)
    255.255.254.0
    Explanation
    The subnet mask 255.255.254.0 is a Class C subnet mask, which means it has 24 bits for the network portion and 8 bits for the host portion. In dotted decimal notation, the subnet mask 255.255.254.0 can accommodate 500 hosts per subnet because it has a host portion of 8 bits, which allows for 2^8 - 2 = 254 usable hosts per subnet. However, since the question asks for a subnet mask that can accommodate 500 hosts, the closest subnet mask that fulfills this requirement is 255.255.254.0, which allows for 510 usable hosts per subnet.

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  • 20. 

    Consider the following range of addresses:2001:0DB8:BC15:00A0:0000::2001:0DB8:BC15:00A1:0000::2001:0DB8:BC15:00A2:0000::…2001:0DB8:BC15:00AF:0000::The prefix for the range of addresses is   “__” 

    Correct Answer(s)
    60
    Explanation
    The given range of addresses starts with 2001:0DB8:BC15:00A0:0000:: and ends with 2001:0DB8:BC15:00AF:0000::. In IPv6, the prefix represents the network portion of the address, which is the common part shared by all the addresses in the range. In this case, the common part is 2001:0DB8:BC15:00A, which has a length of 60 bits. Therefore, the prefix for the range of addresses is 60.

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  • 21. 

    A nibble consists of    “_”    bits.

    Correct Answer(s)
    4
    Explanation
    A nibble consists of 4 bits.

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  • Current Version
  • Mar 19, 2023
    Quiz Edited by
    ProProfs Editorial Team
  • Nov 13, 2014
    Quiz Created by
    Ciarareolegio
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