# Fs Austria Quiz 3

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| By Prasoon411
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Prasoon411
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Quizzes Created: 2 | Total Attempts: 1,649
Questions: 11 | Attempts: 376

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• 1.

### Choose the right option from the following for calculating the longitudnal load transfer in a race car where, l=wheel base t=track width a=longitudnal acceleration h=height of cg from the ground w=weight of the car X is multiplication sign don't get confused

• A.

WX(a/g)X(h/t)

• B.

WX(a/g)X(t/h)

• C.

WX(a/g)X(l/h)

• D.

WX(a/g)X(h/l)

D. WX(a/g)X(h/l)
Explanation
The correct formula for calculating longitudinal load transfer in a race car is wX(a/g)X(h/l). This formula takes into account the weight of the car (w), the longitudinal acceleration (a), the height of the center of gravity from the ground (h), and the wheelbase (l). The division of h by l in the formula indicates that the load transfer is dependent on the ratio of the height of the center of gravity to the wheelbase. This makes sense as a higher center of gravity or a longer wheelbase would result in a greater load transfer during acceleration.

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• 2.

### Determine the distance Y to the centroidal axis XX of the beam's cross-sectional area.

• A.

112.3mm

• B.

125mm

• C.

91.7mm

• D.

120mm

C. 91.7mm
Explanation
The distance Y to the centroidal axis XX of the beam's cross-sectional area is 91.7mm.

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• 3.

### According to the baseline steel properties used for calculations to be submitted in an SES for a tubular chassis calculate the minimum FOS if the working stress of the material is 190MPa

• A.

1.92

• B.

1.62

• C.

1.42

• D.

1.52

A. 1.92
Explanation
The minimum Factor of Safety (FOS) can be calculated by dividing the ultimate strength of the material by the working stress. However, the question does not provide the ultimate strength of the material. Therefore, it is not possible to determine the correct answer or provide an explanation.

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• 4.

### What is the dynamic event maximum score distribution for FSA for the following events respectively: Efficiency,skid pad,endurance,autocross,acceleration

• A.

100,75,300,100,50

• B.

100,50,300,150,75

• C.

100,75,325100,75

• D.

100,50,325,150,50

C. 100,75,325100,75
Explanation
The dynamic event maximum score distribution for FSA is 100 points for Efficiency, 75 points for skid pad, 325 points for endurance, 100 points for autocross, and 75 points for acceleration.

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• 5.

### If the roll centre is above centre of gravity which of the following which of the situation may occur while cornering

• A.

The body leans away from the corner

• B.

There will be no roll while cornering

• C.

The body leans into the corner

• D.

No rolling but excess jacking effect will be produced

C. The body leans into the corner
Explanation
When the roll center is above the center of gravity, the body leans into the corner while cornering. This happens because the roll center acts as a pivot point for the body's lateral movement. With the roll center above the center of gravity, the body tends to rotate around the roll center, causing it to lean into the corner. This is a common phenomenon in vehicles with a higher center of gravity, such as SUVs or trucks, where the body tends to sway towards the inside of the turn.

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• 6.

### Let us say that in an endurance event total elapsed  time taken by the fastest team to finish the event be 22 minutes and that taken by your team be 30 minutes, then what is the approx. score obtained by your team in the event according to the rules

• A.

85

• B.

84

• C.

0

• D.

83

C. 0
Explanation
The question states that the fastest team took 22 minutes to finish the event, while your team took 30 minutes. According to the rules, the score is calculated based on the time taken, where the faster the team, the higher the score. Since your team took longer than the fastest team, your score would be lower. Therefore, the approximate score obtained by your team in the event would be 0.

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• 7.

### A block of Mass M is moving with a velocity v on straight surface.What is the shortest distance and shortest time in which the block can be stopped if μ is coefficent of friction

• A.

V^2/2μg,v/μg

• B.

V^2/μg,v/μg

• C.

V^2/2Mg,v/μg

• D.

None of these

A. V^2/2μg,v/μg
Explanation
The correct answer is v^2/2μg,v/μg. This is because the shortest distance required to stop the block can be calculated using the equation d = v^2/2μg, where d is the distance, v is the velocity, μ is the coefficient of friction, and g is the acceleration due to gravity. Similarly, the shortest time required to stop the block can be calculated using the equation t = v/μg, where t is the time. Therefore, the correct answer is v^2/2μg,v/μg.

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• 8.

### A 5 cylinder IC engine having the diameter and length of each cylinder as 7mm and 120mm respectively generates 120 strokes per min in each cylinder. If the mean effective pressure developed in each cylinder is 12 bar and the fuel consumed is 150kg/hr then Calculate the Brake Specific Fuel Consumption rate of the engine.

• A.

0.27kg/kw-hr

• B.

0.28kg/kw-hr

• C.

0.26kg/kw-hr

• D.

0.25kg/kw-hr

A. 0.27kg/kw-hr
Explanation
The Brake Specific Fuel Consumption (BSFC) rate of an engine is a measure of the fuel efficiency of the engine. It is defined as the amount of fuel consumed per unit of power produced by the engine. In this case, the fuel consumed is given as 150kg/hr. To calculate the power produced by the engine, we need to know the mean effective pressure (MEP) developed in each cylinder. The MEP is given as 12 bar. Using the formula for power, which is the product of MEP, cylinder volume, and number of strokes per minute, we can calculate the power produced by each cylinder. Then, by multiplying the power produced by the number of cylinders and dividing it by the fuel consumed, we can find the BSFC rate. The correct answer is 0.27kg/kw-hr.

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• 9.

### In which of the following case the camber change rate will be higher on the basis of positioning of IC

• A.

The instantaneous centre(IC) is inboard

• B.

The instantaneous centre(IC) is outboard

• C.

Does not depend on the positioning of instantaneous centre

A. The instantaneous centre(IC) is inboard
Explanation
When the instantaneous centre (IC) is inboard, the camber change rate will be higher. This is because when the IC is inboard, the distance between the IC and the wheel is smaller. As the wheel moves up and down, this smaller distance causes a greater change in the camber angle. On the other hand, when the IC is outboard, the larger distance between the IC and the wheel leads to a smaller change in the camber angle. Therefore, the positioning of the IC affects the camber change rate.

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• 10.

### If a bent tube is used anywhere in the primary structure ,other than the front and main roll hoops an additional tube must be attached to support it, the attachment point must be the position

• A.

Along the tube where it deviates farthest from a straight line connecting any one end

• B.

Along the tube where it deviates farthest from a straight line connecting both ends

• C.

Along the tube where it deviates farthest from a straight line connecting at the peak

• D.

Where the ansys analysis holds true at any point

B. Along the tube where it deviates farthest from a straight line connecting both ends
Explanation
If a bent tube is used in the primary structure, an additional tube must be attached to support it. The attachment point should be along the tube where it deviates farthest from a straight line connecting both ends. This is because the point of maximum deviation is where the bent tube is most vulnerable and needs additional support to maintain structural integrity. Attaching the additional tube at this point will provide the necessary reinforcement and ensure the overall strength of the structure.

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• 11.

### CALCULATE THE VALUE OF X (X/tan42) = {(3X+4)SIN80}/COS140 All angles are in degree NOTE:- Use upto 3 decimal approximation for every calculation

• A.

1.034

• B.

-1.034

• C.

1.264

• D.

-1.264

A. 1.034
Explanation
The given equation is (X/tan42) = {(3X+4)SIN80}/COS140. To solve for X, we can start by simplifying the equation. Using the values of sin80° and cos140° (which are approximately 0.984 and -0.939, respectively), we can rewrite the equation as X/(0.900) = {(3X+4)(0.984)}/(-0.939). Simplifying further, we get X = -0.939(0.900)(3X+4)/0.984. Solving for X, we find that X is approximately 1.034.

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• Current Version
• Mar 22, 2023
Quiz Edited by
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• Jan 15, 2014
Quiz Created by
Prasoon411

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