1.
āĻ¤ā§āĻāĻ¸ā§āĻā§āĻ°āĻŋāĻ¯āĻŧ āĻŽā§āĻ˛ā§āĻ° āĻ¨āĻŋāĻāĻā§āĻ˛āĻŋāĻ¯āĻŧāĻžāĻ¸ āĻĨā§āĻā§ āĻ¯ā§ āĻāĻ˛ā§āĻāĻā§āĻ°āĻ¨ āĻ¨āĻŋāĻ°ā§āĻāĻ¤ āĻšāĻ¯āĻŧ āĻ¤āĻžāĻā§ āĻŦāĻ˛ā§
Correct Answer
D. āĻŦāĻŋāĻāĻž āĻāĻŖāĻž
Explanation
The question is asking about the electron that is emitted from the nucleus of a radioactive atom. The correct answer is "āĻŦāĻŋāĻāĻž āĻāĻŖāĻž" which refers to the beta particle. Beta particles are high-energy electrons or positrons that are emitted during the radioactive decay of certain atomic nuclei.
2.
āĻ¤ā§āĻāĻ¸ā§āĻā§āĻ°āĻŋāĻ¯āĻŧāĻ¤āĻž āĻšāĻ˛-
Correct Answer
B. āĻĒāĻ°āĻŽāĻžāĻŖā§āĻ° āĻ¨āĻŋāĻāĻā§āĻ˛āĻŋāĻ¯āĻŧāĻžāĻ¸ā§āĻ° āĻ¸ā§āĻŦāĻ¤āĻāĻ¸ā§āĻĢā§āĻ°ā§āĻ¤ āĻāĻžāĻā§āĻāĻ¨
Explanation
Tejascriyata refers to the spontaneous disintegration of the nucleus of an atom. Out of the given options, "āĻĒāĻ°āĻŽāĻžāĻŖā§āĻ° āĻ¨āĻŋāĻāĻā§āĻ˛āĻŋāĻ¯āĻŧāĻžāĻ¸ā§āĻ° āĻ¸ā§āĻŦāĻ¤āĻāĻ¸ā§āĻĢā§āĻ°ā§āĻ¤ āĻāĻžāĻā§āĻāĻ¨" translates to "spontaneous disintegration of the nucleus of an atom", which aligns with the given definition of tejascriyata. Therefore, this is the correct answer.
3.
āĻĒāĻĻāĻžāĻ°ā§āĻĨāĻŦāĻŋāĻā§āĻāĻžāĻ¨ā§ āĻ¸āĻ°ā§āĻŦāĻĒā§āĻ°āĻĨāĻŽ āĻā§āĻ¨ āĻŦāĻŋāĻā§āĻāĻžāĻ¨ā§ āĻ¨ā§āĻŦā§āĻ˛ āĻ˛āĻžāĻ āĻāĻ°ā§āĻ¨?
Correct Answer
D. āĻāĻāĻ˛āĻšā§āĻŽ āĻ°āĻ¨ā§āĻāĻā§āĻ¨
Explanation
Wilhelm RÃļntgen was the first scientist to receive the Nobel Prize in Physics. In 1901, he was awarded the prize for his discovery of X-rays. RÃļntgen's discovery revolutionized the field of medicine and had significant implications for various scientific disciplines. His work laid the foundation for the development of medical imaging techniques and greatly contributed to our understanding of the structure of matter. RÃļntgen's groundbreaking research and its practical applications made him a deserving recipient of the Nobel Prize.
4.
āĻ¨āĻŋāĻā§āĻ° āĻā§āĻ¨ āĻ°āĻļā§āĻŽāĻŋāĻ° āĻāĻžāĻ°ā§āĻ āĻ āĻāĻ° āĻ¨ā§āĻ?
Correct Answer
C. āĻāĻžāĻŽāĻž
5.
āĻĻā§āĻ°ā§āĻ¤āĻāĻ¤āĻŋāĻ¸āĻŽā§āĻĒāĻ¨ā§āĻ¨ āĻā§āĻ¨ āĻāĻŖāĻŋāĻāĻžāĻāĻŋ āĻ§āĻžāĻ¤ā§āĻā§ āĻāĻāĻžāĻ¤ āĻāĻ°āĻ˛ā§ āĻāĻā§āĻ¸āĻ°ā§ āĻā§āĻĒāĻ¨ā§āĻ¨ āĻšāĻ¯āĻŧ?
Correct Answer
A. āĻāĻ˛ā§āĻāĻā§āĻ°āĻ¨
Explanation
When a fast-moving particle collides with a metal, it can cause the ejection of an electron from the metal. This process is known as the photoelectric effect. Therefore, when a fast-moving particle collides with a metal, it is the electron that is emitted.
6.
āĻ¤ā§āĻāĻ¸ā§āĻā§āĻ°āĻŋāĻ¯āĻŧāĻ¤āĻžāĻ° āĻāĻāĻ āĻā§?
Correct Answer
B. āĻā§āĻ°āĻŋ
7.
āĻā§āĻ¨ āĻ
āĻŦāĻ¸ā§āĻĨāĻžāĻ¯āĻŧ āĻ¤ā§āĻāĻ¸ā§āĻā§āĻ°āĻŋāĻ¯āĻŧ āĻĒāĻĻāĻžāĻ°ā§āĻĨ āĻĨā§āĻā§ āĻāĻ˛āĻĢāĻž, āĻŦāĻŋāĻāĻž āĻ āĻāĻžāĻŽāĻž āĻ°āĻļā§āĻŽāĻŋ āĻ¨āĻŋāĻ°ā§āĻāĻ¤ āĻšāĻ¯āĻŧ?
Correct Answer
D. āĻā§āĻ¨ āĻ°āĻāĻŽ āĻĒā§āĻ°āĻāĻžāĻŦ āĻāĻžāĻĄāĻŧāĻž āĻ¸ā§āĻŦāĻ¤āĻāĻ¸ā§āĻĢā§āĻ°ā§āĻ¤āĻāĻžāĻŦā§
Explanation
āĻāĻ āĻĒā§āĻ°āĻļā§āĻ¨ā§ āĻāĻŋāĻā§āĻāĻžāĻ¸āĻž āĻāĻ°āĻž āĻšāĻ¯āĻŧā§āĻā§ āĻ¤ā§āĻāĻ¸ā§āĻā§āĻ°āĻŋāĻ¯āĻŧ āĻĒāĻĻāĻžāĻ°ā§āĻĨ āĻĨā§āĻā§ āĻāĻ˛āĻĢāĻž, āĻŦāĻŋāĻāĻž āĻ āĻāĻžāĻŽāĻž āĻ°āĻļā§āĻŽāĻŋ āĻā§āĻ¨ āĻ¨āĻŋāĻ°ā§āĻāĻ¤ āĻšāĻ¯āĻŧāĨ¤ āĻāĻ¤ā§āĻ¤āĻ°ā§ āĻŦāĻ˛āĻž āĻšāĻ¯āĻŧā§āĻā§ āĻ¯ā§ āĻāĻ āĻ°āĻļā§āĻŽāĻŋ āĻ¸ā§āĻŦāĻ¤āĻāĻ¸ā§āĻĢā§āĻ°ā§āĻ¤āĻāĻžāĻŦā§ āĻ¨āĻŋāĻ°ā§āĻāĻ¤ āĻšāĻ¯āĻŧ āĻāĻ° āĻŽāĻžāĻ¨ā§ āĻāĻ° āĻāĻ¨ā§āĻ¯ āĻā§āĻ¨ āĻĒā§āĻ°āĻāĻžāĻŦ āĻāĻžāĻĄāĻŧāĻž āĻ¨ā§āĻāĨ¤ āĻ
āĻ°ā§āĻĨāĻžā§ āĻāĻ āĻ°āĻļā§āĻŽāĻŋ āĻ¨āĻŋāĻ°ā§āĻāĻ¤ āĻšāĻ¤ā§ āĻ¸ā§āĻŦāĻ¤āĻāĻ¸ā§āĻĢā§āĻ°ā§āĻ¤āĻāĻžāĻŦā§ āĻ¨āĻŋāĻ°ā§āĻāĻŽāĻ¨ āĻāĻ°ā§ āĻāĻŦāĻ āĻā§āĻ¨ āĻĒāĻ°āĻŦāĻ°ā§āĻ¤ā§ āĻĒāĻĻāĻžāĻ°ā§āĻĨā§āĻ° āĻ¸āĻžāĻĨā§ āĻ¸āĻāĻāĻ°ā§āĻˇ āĻŦāĻž āĻĒā§āĻ°āĻāĻžāĻŦ āĻāĻžāĻĄāĻŧāĻž āĻ¨āĻŋāĻā§āĻ āĻ¨āĻŋāĻ°ā§āĻāĻŽāĻ¨ āĻāĻ°ā§āĨ¤
8.
āĻāĻŋāĻāĻŽāĻžāĻ° āĻā§āĻˇ āĻ§ā§āĻŦāĻāĻ¸ āĻāĻ°āĻ¤ā§ āĻā§āĻ¨ āĻŽā§āĻ˛ā§āĻ° āĻ¤ā§āĻāĻ¸ā§āĻā§āĻ°āĻŋāĻ¯āĻŧ āĻāĻāĻ¸ā§āĻā§āĻĒ āĻŦā§āĻ¯āĻŦāĻšāĻžāĻ° āĻāĻ°āĻž āĻšāĻ¯āĻŧ?
Correct Answer
B. āĻā§āĻŦāĻžāĻ˛ā§āĻ
Explanation
Cobalt-60, a radioactive isotope of cobalt, is used in radiation therapy to destroy tumor cells. It emits high-energy gamma rays that can penetrate tissues and target cancer cells, causing damage to their DNA and preventing them from dividing and growing. This makes cobalt a suitable choice for destroying tumor cells.
9.
X-ray āĻā§āĻĒāĻžāĻĻāĻ¨ā§ āĻā§āĻ¨ āĻ°āĻļā§āĻŽāĻŋ āĻŦā§āĻ¯āĻŦāĻšā§āĻ¤ āĻšāĻ¯āĻŧ?
Correct Answer
C. āĻā§āĻ¯āĻžāĻĨā§āĻĄ āĻ°āĻļā§āĻŽāĻŋ
Explanation
X-rays are produced by using cathode rays. When high-speed electrons from a cathode strike a metal target, X-rays are generated. Therefore, the correct answer is "āĻā§āĻ¯āĻžāĻĨā§āĻĄ āĻ°āĻļā§āĻŽāĻŋ" (cathode rays).
10.
āĻāĻ¸āĻ˛ āĻšā§āĻ°āĻž āĻā§āĻ¨āĻžāĻ° āĻāĻĒāĻžāĻ¯āĻŧ āĻāĻŋ?
Correct Answer
D. āĻāĻ° āĻā§āĻ¤āĻ° āĻĻāĻŋāĻ¯āĻŧā§ āĻ°āĻā§āĻāĻ¨ āĻ°āĻļā§āĻŽāĻŋ āĻ¯ā§āĻ¤ā§ āĻĒāĻžāĻ°ā§ āĻ¨āĻž
Explanation
The correct answer states that "āĻāĻ° āĻā§āĻ¤āĻ° āĻĻāĻŋāĻ¯āĻŧā§ āĻ°āĻā§āĻāĻ¨ āĻ°āĻļā§āĻŽāĻŋ āĻ¯ā§āĻ¤ā§ āĻĒāĻžāĻ°ā§ āĻ¨āĻž" which means that the real diamond cannot emit visible light. This explanation is derived from the given options where it is mentioned that "āĻāĻ° āĻāĻŋāĻ¤āĻ° āĻĻāĻŋāĻ¯āĻŧā§ āĻ°āĻā§āĻāĻ¨ āĻ°āĻļā§āĻŽāĻŋ āĻ¯ā§āĻ¤ā§ āĻĒāĻžāĻ°ā§" which means that visible light can pass through it. Therefore, the correct answer is that the real diamond cannot emit visible light.
11.
āĻ¯ā§ āĻĄāĻŋāĻāĻžāĻāĻ¸ āĻāĻ āĻļāĻā§āĻ¤āĻŋāĻā§ āĻ
āĻ¨ā§āĻ¯ āĻļāĻā§āĻ¤āĻŋāĻ¤ā§ āĻ°ā§āĻĒāĻžāĻ¨ā§āĻ¤āĻ° āĻāĻ°ā§ āĻ¤āĻžāĻā§ āĻŦāĻ˛ā§
Correct Answer
B. Transducer
Explanation
A transducer is a device that converts one form of energy into another. In this case, it converts one form of power into another form of power. A transformer, on the other hand, is a device that transfers electrical energy between two or more circuits through electromagnetic induction. A transistor is a semiconductor device that amplifies or switches electronic signals and electrical power. A generator is a device that converts mechanical energy into electrical energy. Therefore, the correct answer is transducer as it best fits the description of converting one form of power into another.
12.
āĻĻāĻŋāĻ āĻĒāĻ°āĻŋāĻŦāĻ°ā§āĻ¤ā§ āĻŦāĻŋāĻĻā§āĻ¯ā§ā§ āĻĒā§āĻ°āĻŦāĻžāĻšāĻā§ āĻāĻāĻŽā§āĻā§ āĻāĻ°āĻžāĻ° āĻāĻ¨ā§āĻ¯ āĻŦā§āĻ¯āĻŦāĻšāĻžāĻ° āĻāĻ°āĻž āĻšāĻ¯āĻŧ
Correct Answer
D. āĻ¸āĻŦāĻā§āĻ˛ā§
Explanation
All of the given options (p-n junction, rectifier, diode) are used to convert alternating current (AC) to direct current (DC) and make the flow of current unidirectional. Therefore, all of these options can be used to make the flow of current unidirectional, which is the requirement for changing the direction of the electric current.
13.
VLSI āĻāĻ° āĻĒā§āĻ°ā§āĻŖāĻ°ā§āĻĒ āĻšāĻ˛
Correct Answer
B. Very Large Scale Integration
Explanation
VLSI stands for Very Large Scale Integration. This term refers to the process of integrating thousands or millions of transistors onto a single chip. VLSI technology has revolutionized the field of electronics by allowing for the creation of smaller, faster, and more complex integrated circuits. With VLSI, it is possible to pack a large number of electronic components onto a small chip, resulting in more efficient and powerful electronic devices.
14.
āĻāĻ˛ā§āĻāĻā§āĻ°āĻ¨āĻŋāĻā§āĻ¸ āĻāĻ° āĻļā§āĻ°ā§ āĻšāĻ¯āĻŧ
Correct Answer
A. āĻā§āĻ¯āĻžāĻā§āĻ¯āĻŧāĻžāĻŽ āĻāĻŋāĻāĻŦ āĻāĻŦāĻŋāĻˇā§āĻāĻžāĻ°ā§āĻ° āĻŽāĻ§ā§āĻ¯ āĻĻāĻŋāĻ¯āĻŧā§
Explanation
The correct answer is "āĻā§āĻ¯āĻžāĻā§āĻ¯āĻŧāĻžāĻŽ āĻāĻŋāĻāĻŦ āĻāĻŦāĻŋāĻˇā§āĻāĻžāĻ°ā§āĻ° āĻŽāĻ§ā§āĻ¯ āĻĻāĻŋāĻ¯āĻŧā§" which means "through the invention of the vacuum tube". This suggests that the beginning of electronics was marked by the invention of the vacuum tube. The vacuum tube was one of the earliest electronic devices that allowed the control and amplification of electrical signals. It played a crucial role in the development of early electronic systems and paved the way for subsequent inventions such as transistors and integrated circuits.
15.
āĻ¸āĻžāĻ§āĻžāĻ°āĻŖāĻ¤ āĻā§āĻ°āĻžāĻ¨āĻāĻŋāĻ¸ā§āĻāĻ° āĻāĻžāĻ āĻāĻ°ā§
Correct Answer
C. āĻāĻāĻ¯āĻŧ āĻšāĻŋāĻ¸ā§āĻŦā§āĻ
Explanation
The correct answer is "āĻāĻāĻ¯āĻŧ āĻšāĻŋāĻ¸ā§āĻŦā§āĻ" (Both as an amplifier and as a switch). Transistors can function as amplifiers by controlling the current or voltage of a signal, allowing it to be amplified. They can also work as switches by either allowing or blocking the flow of current based on the input signal. Therefore, transistors can serve both purposes, making the answer "āĻāĻāĻ¯āĻŧ āĻšāĻŋāĻ¸ā§āĻŦā§āĻ" correct.
16.
āĻāĻāĻāĻŋ āĻā§āĻ°āĻžāĻ¨āĻāĻŋāĻ¸ā§āĻāĻ°ā§āĻ° āĻ¸āĻŦāĻā§āĻ¯āĻŧā§ āĻāĻŽ āĻĄā§āĻĒāĻžāĻ¯āĻŧāĻŋāĻ¤ āĻ
āĻā§āĻāĻ˛ āĻā§āĻ¨āĻāĻŋ?
Correct Answer
B. āĻŦā§āĻ¸
Explanation
The base region of a transistor is the least doped region compared to the emitter and collector regions. The base region is responsible for controlling the flow of current between the emitter and collector regions, and it is the region where the input signal is applied. Therefore, the base region is the least doped region in a transistor.
17.
āĻ°āĻŋāĻŽā§āĻ āĻ¸ā§āĻ¨ā§āĻ¸āĻŋāĻ āĻŦāĻ˛āĻ¤ā§ āĻā§ āĻŦā§āĻāĻžāĻ¯āĻŧ?
Correct Answer
D. āĻāĻĒāĻā§āĻ°āĻšā§āĻ° āĻ¸āĻžāĻšāĻžāĻ¯ā§āĻ¯ā§ āĻĻā§āĻ° āĻĨā§āĻā§ āĻā§āĻŽāĻ¨ā§āĻĄāĻ˛ā§āĻ° āĻ
āĻŦāĻ˛ā§āĻāĻ¨
Explanation
Remote sensing refers to the process of collecting information about an object or area from a distance, without physically being present. In this context, the correct answer states that remote sensing involves the observation of the Earth's atmosphere and surface from space using satellites or other spacecraft. This allows for the remote detection and analysis of various features and phenomena on Earth, including the monitoring of weather patterns, land use, and natural resources.
18.
āĻ¤āĻžāĻĒāĻŽāĻžāĻ¤ā§āĻ°āĻž āĻŦā§āĻĻā§āĻ§āĻŋāĻ° āĻ¸āĻžāĻĨā§ āĻ¸āĻžāĻĨā§ āĻ
āĻ°ā§āĻ§āĻĒāĻ°āĻŋāĻŦāĻžāĻšā§āĻ° āĻĒāĻ°āĻŋāĻŦāĻžāĻšāĻāĻ¤ā§āĻŦ
Correct Answer
B. āĻŦā§āĻĻā§āĻ§āĻŋ āĻĒāĻžāĻ¯āĻŧ
Explanation
As the temperature increases, the conductivity of a semi-conductor also increases. This is because at higher temperatures, more electrons are excited from the valence band to the conduction band, creating more charge carriers and increasing the conductivity of the material. Therefore, the statement "āĻŦā§āĻĻā§āĻ§āĻŋ āĻĒāĻžāĻ¯āĻŧ" (increases) is the correct answer.
19.
P-n āĻāĻāĻļāĻ¨ āĻāĻ° āĻ
āĻĒāĻ° āĻ¨āĻžāĻŽ āĻāĻŋ?
Correct Answer
C. āĻ
āĻ°ā§āĻ§āĻĒāĻ°āĻŋāĻŦāĻžāĻšā§ āĻ°ā§āĻāĻāĻŋāĻĢāĻžāĻ¯āĻŧāĻžāĻ°
Explanation
The correct answer is "āĻ
āĻ°ā§āĻ§āĻĒāĻ°āĻŋāĻŦāĻžāĻšā§ āĻ°ā§āĻāĻāĻŋāĻĢāĻžāĻ¯āĻŧāĻžāĻ°" (half-wave rectifier). A p-n junction can act as a rectifier, allowing current to flow in only one direction. In a half-wave rectifier, only half of the AC input waveform is allowed to pass through, resulting in a pulsating DC output.
20.
IC āĻ¤ā§āĻ°āĻŋāĻ¤ā§ āĻā§āĻ¨āĻāĻŋāĻ° āĻĒā§āĻ°āĻ¯āĻŧā§āĻāĻ¨ āĻĒāĻĄāĻŧā§ āĻ¨āĻž?
Correct Answer
C. āĻāĻ¨ā§āĻĄāĻžāĻā§āĻāĻ°
Explanation
In the given options, the only component that is not required in the construction of an Integrated Circuit (IC) is an inductor (āĻāĻ¨ā§āĻĄāĻžāĻā§āĻāĻ°). ICs are made up of transistors, resistors, and capacitors, but not inductors. Inductors are typically used in circuits that involve the generation or manipulation of magnetic fields, which are not typically required in ICs. Therefore, an inductor is not needed in the construction of an IC.
21.
āĻā§āĻ°āĻžāĻ¨āĻāĻŋāĻ¸ā§āĻāĻ° āĻāĻ¤ āĻ¸āĻžāĻ˛ā§ āĻ¤ā§āĻ°āĻŋ āĻāĻ°āĻž āĻšāĻ¯āĻŧ?
Correct Answer
B. ā§§ā§¯ā§Ēā§
Explanation
Transistors were first invented and created in the year 1947.
22.
Diode āĻāĻ° āĻĻā§'āĻāĻŋ āĻĒā§āĻ°āĻžāĻ¨ā§āĻ¤ āĻšāĻ˛ā§
Correct Answer
D. Anode and Cathode
Explanation
In a diode, the anode is the positive terminal and the cathode is the negative terminal. The anode is where the current enters the diode, while the cathode is where the current exits. Therefore, the correct answer is "Anode and Cathode".
23.
āĻ¨āĻŋāĻā§āĻ° āĻā§āĻ¨āĻāĻŋ āĻāĻā§āĻ¸āĻ°ā§āĻ° āĻŦā§āĻļāĻŋāĻˇā§āĻā§āĻ¯ āĻ¨āĻ¯āĻŧ?
Correct Answer
B. āĻāĻāĻŋ āĻ¸ā§āĻŦāĻ˛ā§āĻĒ āĻāĻ¯āĻŧāĻ¨āĻžāĻ¯āĻŧāĻ¨ āĻā§āĻˇāĻŽāĻ¤āĻž āĻ¸āĻŽā§āĻĒāĻ¨ā§āĻ¨
Explanation
The given options describe the characteristics of X. The first option states that X does not have any charge or mass. The second option states that X has a low refractive index. The third option states that X behaves like a wave. The fourth option states that X is not affected by electric or magnetic fields. Among these options, the correct answer is that X has a low refractive index.
24.
āĻ¤āĻŋāĻ¨ āĻ§āĻ°āĻ¨ā§āĻ° āĻ¤ā§āĻāĻ¸ā§āĻā§āĻ°āĻŋāĻ¯āĻŧ āĻ°āĻļā§āĻŽāĻŋāĻ° āĻ
āĻ¸ā§āĻ¤āĻŋāĻ¤ā§āĻŦ āĻĒā§āĻ°āĻŽāĻžāĻŖ āĻāĻ°ā§āĻ¨ āĻā§?
Correct Answer
B. āĻŽāĻžāĻĻāĻžāĻŽ āĻā§āĻ°āĻŋ
Explanation
Madam Curie discovered the existence of three types of active radiation, namely alpha particles, beta particles, and gamma rays. She conducted extensive research on radioactive materials and made significant contributions to the field of nuclear physics. Her discoveries and experiments were instrumental in shaping our understanding of radiation and its properties. Therefore, Madam Curie is the correct answer for proving the existence of three types of active radiation.
25.
Uranium-235 āĻāĻ° āĻ
āĻ°ā§āĻ§āĻžāĻ¯āĻŧā§ āĻāĻ¤?
Correct Answer
B. ā§ā§Ļ āĻā§āĻāĻŋ āĻŦāĻāĻ°
Explanation
The half-life of Uranium-235 is 70 crore years.
26.
āĻā§āĻ¨ āĻĻā§āĻāĻŋ āĻā§āĻ°ā§āĻĒā§āĻ° āĻŽā§āĻ˛ā§āĻ° āĻ¸āĻŽāĻ¨ā§āĻŦāĻ¯āĻŧā§ n-āĻāĻžāĻāĻĒ āĻ
āĻ°ā§āĻ§āĻĒāĻ°āĻŋāĻŦāĻžāĻšā§ āĻ¤ā§āĻ°āĻŋ āĻāĻ°āĻž āĻšāĻ¯āĻŧ?
Correct Answer
C. āĻā§āĻ°ā§āĻĒ IV + āĻā§āĻ°ā§āĻĒ V
Explanation
An n-type semiconductor is formed by doping a pure semiconductor with impurities that have more valence electrons than the atoms in the pure semiconductor. Group IV elements, such as silicon and germanium, are commonly used as the base material for semiconductors. Group V elements, such as phosphorus and arsenic, have one extra valence electron compared to the atoms in the pure semiconductor, making them suitable dopants for creating n-type semiconductors. Therefore, when we combine a group IV element with a group V element, we can create an n-type semiconductor.
27.
āĻ¨āĻŋāĻā§āĻ° āĻā§āĻ¨āĻāĻŋ āĻ¤ā§āĻāĻ¸ā§āĻā§āĻ°āĻŋāĻ¯āĻŧāĻ¤āĻžāĻ° āĻŦā§āĻļāĻŋāĻˇā§āĻā§āĻ¯ āĻ¨āĻ¯āĻŧ?
Correct Answer
C. āĻ¤ā§āĻāĻ¸ā§āĻā§āĻ°āĻŋāĻ¯āĻŧāĻ¤āĻž āĻ¤āĻĄāĻŧāĻŋā§ āĻŦāĻž āĻā§āĻŽā§āĻŦāĻ āĻā§āĻˇā§āĻ¤ā§āĻ° āĻĻā§āĻŦāĻžāĻ°āĻž āĻĒā§āĻ°āĻāĻžāĻŦāĻŋāĻ¤ āĻšāĻ¯āĻŧ
Explanation
āĻāĻ āĻĒā§āĻ°āĻļā§āĻ¨ā§ āĻāĻŋāĻ¨āĻŋāĻ¸āĻāĻŋ āĻ¯āĻžāĻāĻžāĻ āĻāĻ°āĻžāĻ° āĻāĻ¨ā§āĻ¯ āĻāĻŽāĻžāĻĻā§āĻ°āĻā§ āĻ¤ā§āĻāĻ¸ā§āĻā§āĻ°āĻŋāĻ¯āĻŧāĻ¤āĻžāĻ° āĻŦā§āĻļāĻŋāĻˇā§āĻā§āĻ¯āĻā§āĻ˛āĻŋ āĻĻā§āĻāĻ¤ā§ āĻšāĻŦā§āĨ¤ āĻĒā§āĻ°āĻļā§āĻ¨ā§ āĻĻā§āĻāĻ¯āĻŧāĻž āĻŦā§āĻļāĻŋāĻˇā§āĻā§āĻ¯āĻā§āĻ˛āĻŋāĻ° āĻŽāĻ§ā§āĻ¯ā§ āĻļā§āĻ§ā§āĻŽāĻžāĻ¤ā§āĻ° "āĻ¤ā§āĻāĻ¸ā§āĻā§āĻ°āĻŋāĻ¯āĻŧāĻ¤āĻž āĻ¤āĻĄāĻŧāĻŋā§ āĻŦāĻž āĻā§āĻŽā§āĻŦāĻ āĻā§āĻˇā§āĻ¤ā§āĻ° āĻĻā§āĻŦāĻžāĻ°āĻž āĻĒā§āĻ°āĻāĻžāĻŦāĻŋāĻ¤ āĻšāĻ¯āĻŧ" āĻāĻ āĻŦā§āĻļāĻŋāĻˇā§āĻā§āĻ¯āĻāĻŋ āĻ¤ā§āĻāĻ¸ā§āĻā§āĻ°āĻŋāĻ¯āĻŧāĻ¤āĻžāĻ° āĻŦā§āĻļāĻŋāĻˇā§āĻā§āĻ¯ āĻ¨āĻ¯āĻŧāĨ¤ āĻ¤āĻžāĻ āĻāĻāĻŋ āĻ¸āĻ āĻŋāĻ āĻāĻ¤ā§āĻ¤āĻ° āĻ¨āĻ¯āĻŧāĨ¤
28.
BJT āĻā§āĻ¨ āĻ§āĻ°āĻ¨ā§āĻ° āĻā§āĻ°āĻžāĻ¨āĻāĻŋāĻ¸ā§āĻāĻ°?
Correct Answer
B. āĻŦāĻžāĻāĻĒā§āĻ˛āĻžāĻ°
Explanation
The correct answer is "āĻŦāĻžāĻāĻĒā§āĻ˛āĻžāĻ°" which translates to "bipolar" in English. This answer indicates that BJT (Bipolar Junction Transistor) is a type of transistor that has two types of charge carriers, both electrons and holes, involved in its operation. This distinguishes it from unipolar transistors which only have one type of charge carrier.
29.
āĻĄāĻžāĻ¯āĻŧā§āĻĄ āĻ¸āĻŽā§āĻĒāĻ°ā§āĻāĻŋāĻ¤ āĻā§āĻ¨ āĻ¤āĻĨā§āĻ¯āĻāĻŋ āĻā§āĻ˛?
Correct Answer
B. āĻĄāĻžāĻ¯āĻŧā§āĻĄ āĻā§ āĻ°āĻŋāĻāĻžāĻ°ā§āĻ¸ āĻŦāĻžāĻ¯āĻŧāĻžāĻ¸ āĻāĻ°āĻ˛ā§ āĻāĻ° āĻŽāĻ§ā§āĻ¯ āĻĻāĻŋāĻ¯āĻŧā§ āĻ¤āĻĄāĻŧāĻŋā§ āĻĒā§āĻ°āĻŦāĻžāĻšāĻŋāĻ¤ āĻšāĻ¯āĻŧ
Explanation
When a diode is reverse biased, no current flows through it. The correct information is that "āĻĄāĻžāĻ¯āĻŧā§āĻĄ āĻā§ āĻ°āĻŋāĻāĻžāĻ°ā§āĻ¸ āĻŦāĻžāĻ¯āĻŧāĻžāĻ¸ āĻāĻ°āĻ˛ā§ āĻāĻ° āĻŽāĻ§ā§āĻ¯ āĻĻāĻŋāĻ¯āĻŧā§ āĻ¤āĻĄāĻŧāĻŋā§ āĻĒā§āĻ°āĻŦāĻžāĻšāĻŋāĻ¤ āĻšāĻ¯āĻŧ" (When a diode is reverse biased, current flows through it). This statement is incorrect because when a diode is reverse biased, the depletion region widens and prevents the flow of current.
30.
āĻā§āĻ¨ āĻĻā§āĻāĻŋ āĻā§āĻ°ā§āĻĒā§āĻ° āĻŽā§āĻ˛ā§āĻ° āĻ¸āĻŽāĻ¨ā§āĻŦāĻ¯āĻŧā§ p-āĻāĻžāĻāĻĒ āĻ
āĻ°ā§āĻ§āĻĒāĻ°āĻŋāĻŦāĻžāĻšā§ āĻ¤ā§āĻ°āĻŋ āĻāĻ°āĻž āĻšāĻ¯āĻŧ?
Correct Answer
A. āĻā§āĻ°ā§āĻĒ III + āĻā§āĻ°ā§āĻĒ IV
Explanation
A p-type semiconductor is formed by adding trivalent impurities to a pure semiconductor material. Group III elements in the periodic table are trivalent, meaning they have three valence electrons. Group IV elements have four valence electrons, making them tetravalent. Therefore, when we combine a trivalent element from Group III with a tetravalent element from Group IV, we can create a p-type semiconductor.