The Bond Energy Quiz! Chemistry Trivia!

The reaction is exothermic because the formation of 2 moles of SO3 releases energy. The enthalpy change (∆H) can be calculated using the formula: ∆H = Σ∆Hf(products) - Σ∆Hf(reactants). Given that ∆H°f(SO2) = -296.8 kJ/mol and ∆H°f(SO3) = -395.7 kJ/mol, we can substitute these values into the formula. ∆H = (2*(-395.7 kJ/mol)) - (-296.8 kJ/mol) = -791.4 kJ/mol + 296.8 kJ/mol = -494.6 kJ/mol. Since the reaction releases energy, the value of ∆H is negative. The correct answer, -197.8 kJ/mol, is obtained by dividing -494.6 kJ/mol by 2, as the reaction involves the formation of 2 moles of SO3.

The question asks for the amount of energy involved in the formation of 5 grams of rust (Fe2O3), given that the ∆H°f for the formation of rust is -826 kJ/mol. To find the energy involved in the formation of 5 grams of rust, we need to convert grams to moles. The molar mass of Fe2O3 is 159.7 g/mol, so 5 grams is equal to 5/159.7 moles. Multiplying this by the ∆H°f (-826 kJ/mol), we get -25.9 kJ. Therefore, the correct answer is 25.9 kJ.

The density of the sample is not needed to calculate the amount of heat absorbed as a substance melts. The heat absorbed during the melting process depends on the mass of the substance, the change in temperature, and the specific heat of the substance. The density of the sample is not directly related to the heat absorbed during melting.

If one energy level diagram shows a much larger fall from the reactants to the products when compared with another energy level diagram, this would indicate that more energy is being released in the reaction. This suggests that the reaction is more exothermic, as a larger fall in energy levels indicates a greater release of energy.

This reaction is exothermic because the energy released when forming the products (CH3Br and HBr) is greater than the energy required to break the bonds in the reactants (CH4 and Br2). The bond energy values provided indicate that breaking the C-H and Br-Br bonds requires more energy than is released when forming the C-Br and H-Br bonds. Therefore, the overall reaction releases energy, making it exothermic.

The molar enthalpy for water vapor can be calculated by subtracting the molar enthalpies of the reactants from the molar enthalpies of the products. In this reaction, the molar enthalpy of CH4 is 75 kj/mol and the molar enthalpy of CH3OH is 239 kj/mol. Since water vapor is a product in the reaction, we can subtract the molar enthalpies of the reactants (CH4 and H2O) from the molar enthalpies of the products (CH3OH and H2) to find the molar enthalpy of water vapor. Therefore, the correct answer is 239 kj/mol.

The enthalpy change for a reaction can be calculated using the equation:

ΔH = q / n

Where ΔH is the enthalpy change, q is the heat absorbed or released by the reaction, and n is the number of moles of the substance involved in the reaction.

In this case, we know that 80g of ammonium nitrate is dissolved in water to form 1L of solution. Using the molar mass of ammonium nitrate (80g/mol), we can calculate the number of moles of ammonium nitrate present in the solution.

n = mass / molar mass
n = 80g / 80g/mol
n = 1 mol

We also know that the temperature decreases from 20°C to 14°C. The heat absorbed or released by the reaction can be calculated using the equation:

q = m * C * ΔT

Where q is the heat absorbed or released, m is the mass of the solution, C is the specific heat capacity of the solution, and ΔT is the change in temperature.

Since we have 1L of solution, we can assume that the mass of the solution is 1000g (since 1g = 1mL for water). The specific heat capacity of water is 4.18 J/g°C.

q = 1000g * 4.18 J/g°C * (14°C - 20°C)
q = -25080 J

Since the temperature decreases, the reaction is exothermic and releases heat. Therefore, the enthalpy change is -25080 J/mol, which is equivalent to -25080 kJ/mol.

The energy change required to produce 3 mol of glucose can be calculated by summing up the bond energies of all the bonds involved in the formation of glucose. The given bond energies are in kilojoules per mole (kJ/mol). By multiplying the bond energies by the number of each type of bond in glucose and adding them up, we can find the total energy change.