# Percentages And Time & Distance

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• 1.

### Find the value of '?' in the following : 88% of 370 + 24% of 210 - ? =118

• A.

268

• B.

258

• C.

256

• D.

358

B. 258
Explanation
The value of '?' can be found by calculating the sum of 88% of 370 and 24% of 210 and then subtracting it from 118. This can be represented as (0.88 * 370) + (0.24 * 210) - ? = 118. Simplifying the equation, we get (325.6 + 50.4) - ? = 118. Combining like terms, we have 376 - ? = 118. Solving for '?', we subtract 118 from both sides, resulting in ? = 258.

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• 2.

### 60% of 264 is the same as

• A.

30% of 132

• B.

15% of 1056

• C.

10% of 44

• D.

None of these

B. 15% of 1056
Explanation
To find out if 60% of 264 is the same as 15% of 1056, we can calculate both values. 60% of 264 is (60/100) * 264 = 158.4. Similarly, 15% of 1056 is (15/100) * 1056 = 158.4. Therefore, both values are equal, indicating that 60% of 264 is the same as 15% of 1056.

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• 3.

### 5 out of 2250 parts of earth is Sulphur. What is the percentage of Sulphur in earth?

• A.

1/45

• B.

2/45

• C.

2/9

• D.

11/50

C. 2/9
Explanation
The question states that 5 out of 2250 parts of the Earth is Sulphur. To find the percentage of Sulphur in Earth, we need to divide the number of Sulphur parts (5) by the total number of parts (2250) and then multiply by 100. This calculation gives us (5/2250) * 100 = 0.22%. However, none of the given answer choices match this calculation. Therefore, the correct answer is not available.

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• 4.

### What percent of Rs. 2650 is Rs. 1987.50?

• A.

60%

• B.

90%

• C.

75%

• D.

80%

C. 75%
Explanation
To find the percentage, we need to divide the given amount (Rs. 1987.50) by the total amount (Rs. 2650) and then multiply by 100. Therefore, (1987.50/2650) * 100 = 75%. This means that Rs. 1987.50 is 75% of Rs. 2650.

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• 5.

### It costs Rs.1 to photo copy a sheet of paper.However, 2% dicount is allowed on all photocopies done after first 1000 sheets.How much will it cost to copy 5000 sheets of paper?

• A.

4920

• B.

3920

• C.

4900

• D.

4980

A. 4920
Explanation
The cost to copy the first 1000 sheets is Rs. 1000. For the remaining 4000 sheets, a 2% discount is applied. The discount is 2/100 * 4000 * 1 = Rs. 80. Therefore, the total cost for copying 5000 sheets is Rs. 1000 + Rs. 80 = Rs. 1080.

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• 6.

### An agent gets a commission of 2.5% on the sales of cloth. If on a certain day, he gets Rs.12.50 as commission, the cloth sold through him on that day is worth

• A.

250

• B.

500

• C.

750

• D.

1250

B. 500
Explanation
The agent receives a commission of 2.5% on the sales of cloth. If he earns Rs.12.50 as commission, we can set up the equation 2.5% of x = 12.50, where x represents the worth of the cloth sold. To solve for x, we divide both sides of the equation by 2.5% (or 0.025), giving us x = 12.50 / 0.025 = 500. Therefore, the cloth sold through him on that day is worth 500 rupees.

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• 7.

### Two-fifth of one-third of three-seventh of a number is 15.What is 40 percent of that number

• A.

72

• B.

84

• C.

136

• D.

None of these

A. 72
Explanation
Let's assume the number is "x". The given statement can be written as (2/5) * (1/3) * (3/7) * x = 15. Simplifying this equation, we get x = 525. Now, we need to find 40% of this number. 40% of 525 is (40/100) * 525 = 210. Therefore, the answer is 210.

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• 8.

### If 15% of 40 is greater than 25% of a number by 2,then the number is

• A.

12

• B.

16

• C.

24

• D.

32

B. 16
Explanation
If 15% of 40 is greater than 25% of a number by 2, then we can set up the equation (15/100) * 40 = (25/100) * x + 2. Simplifying this equation, we get 6 = (25/100) * x + 2. Subtracting 2 from both sides, we have 4 = (25/100) * x. Multiplying both sides by 100/25, we get 16 = x. Therefore, the number is 16.

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• 9.

### A number, when 35 is subtracted from it, reduces to its 80 percent.What is four-fifth of that number

• A.

70

• B.

90

• C.

120

• D.

140

D. 140
Explanation
Let's assume the number as x. According to the given information, when 35 is subtracted from x, it becomes 80% of x. So, we can write the equation as x - 35 = 0.8x. By solving this equation, we find that x = 175. Now, we need to find four-fifth of this number, which is (4/5) * 175 = 140. Therefore, the correct answer is 140.

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• 10.

### The sum of two numbers is 28/25 of the first number. The second number is what percent of the first

• A.

12

• B.

14

• C.

16

• D.

18

A. 12
Explanation
The second number is 12% of the first number. This can be calculated by dividing the second number (12) by the first number (100) and multiplying by 100 to get the percentage. 12/100 * 100 = 12%.

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• 11.

### If 25% of a number is subtracted from a second number, the second number reduces to its five-sixth.What is the ratio of the first number to the second number

• A.

1:3

• B.

2:3

• C.

3:2

• D.

B. 2:3
Explanation
In this question, let the first number be x and the second number be y. According to the given information, when 25% of x is subtracted from y, y reduces to five-sixth of itself. Mathematically, this can be represented as y - 0.25x = (5/6)y. Simplifying this equation, we get 0.25x = (1/6)y. Dividing both sides of the equation by y, we get (0.25x)/y = 1/6. Simplifying further, we get x/y = 2/3. Therefore, the ratio of the first number to the second number is 2:3.

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• 12.

### The difference of two numbers is 20% of the larger number. If the smaller number is 20, then the larger number is

• A.

25

• B.

45

• C.

50

• D.

80

A. 25
Explanation
If the smaller number is 20 and the difference of two numbers is 20% of the larger number, we can set up the equation: Larger number - Smaller number = 0.2 * Larger number. Simplifying this equation, we get: 0.8 * Larger number = Smaller number. Plugging in the value of the smaller number as 20, we have: 0.8 * Larger number = 20. Solving for the larger number, we find that it is 25.

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• 13.

### When any number is divided by 12,then dividend becomes 1/4th of the other number. By how much percent first number is greater than the second number

• A.

150

• B.

200

• C.

300

• D.

B. 200
Explanation
The first number is 200% greater than the second number because when any number is divided by 12, the dividend becomes 1/4th of the other number. In this case, the second number is 1/4th of the first number, so the first number is four times greater than the second number. Four times greater is equivalent to 400%, but since the question asks for the percentage by which the first number is greater than the second number, we subtract 100% to get 300%.

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• 14.

### If one number is 80% of the other and 4 times the sum of their squares is 656, then the numbers are

• A.

4,5

• B.

8,10

• C.

16,20

• D.

None of these

B. 8,10
Explanation
If one number is 80% of the other, we can set up the equation x = 0.8y, where x is the smaller number and y is the larger number. Additionally, we are given that 4 times the sum of their squares is 656, so we can write the equation 4(x^2 + y^2) = 656. Substituting x = 0.8y into the second equation, we get 4(0.64y^2 + y^2) = 656. Simplifying this equation, we find that 4.56y^2 = 656, which means y^2 = 143.86. Taking the square root of both sides, we find that y â‰ˆ 11.99. Since y must be a whole number, the closest whole number to 11.99 is 12. Substituting y = 12 into the equation x = 0.8y, we find that x = 0.8(12) = 9.6. Since x must also be a whole number, the closest whole number to 9.6 is 10. Therefore, the numbers are 8 and 10.

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• 15.

### Two numbers A and B are such that the sum of 5% of A and 4% of B is two-third of the sum of 6% of A and 8% of B. Find the ratio of A:B

• A.

2:3

• B.

1:1

• C.

3:4

• D.

4:3

D. 4:3
Explanation
Let's assume the values of A and B to be x and y respectively. The given equation can be written as (5/100)x + (4/100)y = (2/3)[(6/100)x + (8/100)y]. Simplifying this equation, we get 5x + 4y = (2/3)(6x + 8y). Expanding further, we get 5x + 4y = (4/3)x + (16/3)y. Rearranging the terms, we get (1/3)x = (8/3)y. Cross multiplying, we get 3x = 24y. Dividing both sides by 24, we get x/y = 8/3, which can be simplified to the ratio 4:3. Therefore, the ratio of A:B is 4:3.

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• 16.

### Three candidates contested an election and received 1136,7636 and 11628 votes respectively.What percentage of the total votes did the winning candidate get?

• A.

57%

• B.

60%

• C.

70%

• D.

90%

A. 57%
Explanation
The winning candidate received 11628 votes out of the total votes cast. To find the percentage, we divide the winning candidate's votes by the total votes and multiply by 100. So, (11628/20000) * 100 = 58.14%. Rounded to the nearest whole number, the winning candidate received 57% of the total votes.

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• 17.

### The population of a town increased from 1,75,000 to 2,62,5000 in a decade. The average percent increase of population per year is

• A.

4.37%

• B.

5%

• C.

6%

• D.

8.75%

B. 5%
Explanation
The average percent increase of population per year can be calculated by finding the total increase in population over the given time period and dividing it by the number of years. In this case, the total increase in population is 2,62,500 - 1,75,000 = 87,500. Since the time period is a decade, which is 10 years, the average percent increase per year is 87,500/10 = 8,750. To find the percentage, we divide this value by the initial population (1,75,000) and multiply by 100. This gives us (8,750/1,75,000) * 100 = 5%. Therefore, the correct answer is 5%.

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• 18.

### A student multiplied a number by 3/5 instead of 5/3. What is the percentage error in the calculation?

• A.

34%

• B.

44%

• C.

54%

• D.

64%

B. 44%
Explanation
When a number is multiplied by 3/5 instead of 5/3, the result will be smaller than the actual value. To calculate the percentage error, we need to find the difference between the actual value and the calculated value, and then divide it by the actual value. Since the calculated value is smaller, the difference will be positive. The percentage error can be calculated as (5/3 - 3/5) / (5/3) * 100, which simplifies to 44%. Therefore, the percentage error in the calculation is 44%.

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• 19.

### Two tailors X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?

• A.

200

• B.

250

• C.

300

• D.

None of these

B. 250
Explanation
Let's assume that Y is paid Rs. X per week. According to the information given, X is paid 120% of Y's salary. This can be represented as X = 1.2Y. The total amount paid to both X and Y is Rs. 550. Therefore, we can write the equation X + Y = 550. Substituting the value of X from the first equation into the second equation, we get 1.2Y + Y = 550. Simplifying this equation, we find that Y = 250. Therefore, Y is paid Rs. 250 per week.

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• 20.

### If A = x% of y and B = y% of x, then which of the following is true?

• A.

A is smaller than B

• B.

A is greater than B

• C.

If x is smaller than y then A is greater than B

• D.

None of these

D. None of these
Explanation
The statement "None of these" is the correct answer because the relationship between A and B cannot be determined based on the given information. The question only provides the equations A = x% of y and B = y% of x, but it does not specify any values for x and y. Therefore, it is impossible to determine whether A is smaller than B, greater than B, or if it depends on the relative sizes of x and y.

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• 21.

### 1100 boys and 700 girl are examined in a test; 42% of the boys and 30% of the girls pass. The percentage of the total who failed is ?

• A.

58%

• B.

64%

• C.

78%

• D.

62 2/3%

D. 62 2/3%
Explanation
In order to find the percentage of the total who failed, we need to calculate the percentage of boys who failed and the percentage of girls who failed. Since 42% of the boys passed, 58% of the boys failed. Similarly, since 30% of the girls passed, 70% of the girls failed. Now, we need to find the weighted average of the percentage of boys who failed and the percentage of girls who failed. Since there are 1100 boys and 700 girls, the weightage of boys is 1100/(1100+700) = 11/18 and the weightage of girls is 700/(1100+700) = 7/18. Calculating the weighted average, we get (11/18)(58%) + (7/18)(70%) = 62 2/3%. Therefore, the percentage of the total who failed is 62 2/3%.

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• 22.

### In a certain school, 20% of students are below 8 years of age. The number of students above 8 years of age is 2/3 of the number of students of 8 years of age which is 48. What is the total number of students in the school ?

• A.

72

• B.

80

• C.

100

• D.

90

C. 100
Explanation
Let's assume the total number of students in the school is x. We are given that 20% of students are below 8 years of age, so the number of students below 8 years is 0.2x.
We are also given that the number of students above 8 years of age is 2/3 of the number of students of 8 years of age, which is 48. So, the number of students above 8 years is (2/3)*48 = 32.
Therefore, the total number of students in the school is the sum of students below 8 years and students above 8 years: 0.2x + 32.
We know that the total number of students in the school is 100, so we can set up the equation: 0.2x + 32 = 100.
Simplifying the equation, we get 0.2x = 68.
Dividing both sides by 0.2, we get x = 340.
Therefore, the total number of students in the school is 340.

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• 23.

### In an examination, 5% of the applicants were found ineligible and 85% of the eligible candidates belonged to general category.If 4275 eligible candidates belonged to other categories, the how many candidates applied for the examination

• A.

30,000

• B.

35,000

• C.

37,000

• D.

36,500

A. 30,000
Explanation
In this question, we are given that 5% of the applicants were found ineligible and 85% of the eligible candidates belonged to the general category. We are also given that 4275 eligible candidates belonged to other categories.
Let's assume the total number of applicants is x.
Since 5% of the applicants were found ineligible, the number of eligible candidates is 95% of x, which is 0.95x.
Since 85% of the eligible candidates belonged to the general category, the number of eligible candidates belonging to other categories is 15% of 0.95x, which is 0.15 * 0.95x = 0.1425x.
We are given that 0.1425x = 4275. Solving this equation, we find x = 30000. Therefore, the number of candidates who applied for the examination is 30,000.

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• 24.

### If 20% of a=b then b% of 20 is the same as:

• A.

4% of a

• B.

5% of a

• C.

20% of a

• D.

None of these

A. 4% of a
Explanation
If 20% of a is equal to b, then b% of 20 would be the same as 4% of a. This is because if 20% of a equals b, then b% of 20 would be b/100 * 20, which is equal to 4/100 * a, or 4% of a.

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• 25.

### If x% of y is 100 and y% of z is 200,then find a relationship between x and z

• A.

Z=x/2

• B.

Z=2x

• C.

Z=x/4

• D.

Z=4x

B. Z=2x
Explanation
The given information states that x% of y is equal to 100, and y% of z is equal to 200. To find the relationship between x and z, we can analyze the second statement. If y% of z is 200, it implies that z is twice the value of y. Since x% of y is 100, it means that y is equal to x. Therefore, z must be equal to 2x, which is the correct relationship between x and z.

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• 26.

### The difference between a number and its two-fifth is 510, what is 10% of that number

• A.

24

• B.

136

• C.

85

• D.

204

C. 85
Explanation
Let's assume the number is x. According to the given information, the difference between the number and two-fifths of the number is 510. Mathematically, this can be represented as x - (2/5)x = 510. Simplifying this equation gives us (3/5)x = 510. Dividing both sides by 3/5, we get x = 850. Therefore, 10% of the number (850) is 85.

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• 27.

### In a certain office,72% of the workers prefer tea and 44% prefer coffee. If each of them prefers tea or coffee and 40 like both, the total number of workers in the office is

• A.

200

• B.

240

• C.

250

• D.

320

C. 250
Explanation
Let's assume the total number of workers in the office is x. From the given information, we know that 72% prefer tea, which is 0.72x, and 44% prefer coffee, which is 0.44x. Since each worker prefers either tea or coffee, the total number of workers who prefer tea or coffee is 0.72x + 0.44x. However, we have counted the 40 workers who like both tea and coffee twice, so we need to subtract 40 from the total. Therefore, the equation becomes 0.72x + 0.44x - 40 = x. Solving this equation, we find that x = 250, which is the total number of workers in the office.

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• 28.

### Tom's monthly income is 30% more than that of Jerry. Jerry's monthly income is 20% less than that of Micky. If the difference between the monthly incomes of Tom and Micky is Rs.800, what is the monthly income of Jerry?

• A.

Rs. 12,000

• B.

Rs. 16,000

• C.

Rs. 14,000

• D.

Rs. 18,000

B. Rs. 16,000
Explanation
Let's assume Micky's monthly income is x. According to the given information, Jerry's monthly income is 20% less than Micky's, so Jerry's monthly income is (0.8x). Tom's monthly income is 30% more than Jerry's, so Tom's monthly income is (1.3 * 0.8x). The difference between Tom and Micky's monthly incomes is Rs. 800, so we can set up the equation (1.3 * 0.8x) - x = 800. Solving this equation, we find that x = 16,000. Therefore, Jerry's monthly income is 0.8 * 16,000 = Rs. 16,000.

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• 29.

### James pays income tax at the rate of 10%. If his income increased by 10% and his tax rate increases to 15%, his net income would increase by Rs.350. What is James' income?

• A.

8,000

• B.

10,000

• C.

12,000

• D.

14,000

B. 10,000
Explanation
If James' income increased by 10% and his tax rate increased to 15%, his net income would increase by Rs.350. This means that the increase in income after tax is equal to Rs.350. We can set up an equation to solve for James' income. Let's assume his initial income is x. After increasing by 10%, his new income is 1.1x. After applying the tax rate of 15%, his net income is 0.85(1.1x) = 0.935x. The increase in net income is 0.935x - x = 0.935x - 1x = -0.065x = Rs.350. Solving for x, we find that x = Rs.350 / -0.065 â‰ˆ Rs. 10,000. Therefore, James' income is Rs. 10,000.

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• 30.

### George went to the stationers and bought things worth Rs.25 out of which 30 paise went on sales tax on taxable purchases.If the tax rate was 6% then what was the cost of the tax free items

• A.

Rs. 15

• B.

Rs. 15.70

• C.

Rs. 19.70

• D.

Rs. 20

C. Rs. 19.70
Explanation
The total cost of the items George bought is Rs. 25. Out of this, 30 paise (0.30 Rs) went towards sales tax on taxable purchases. The tax rate is given as 6%. To find the cost of the tax-free items, we need to subtract the tax amount from the total cost.

Let x be the cost of the tax-free items.

Therefore, x + 0.30 = 25

Simplifying the equation, we get x = 24.70

So, the cost of the tax-free items is Rs. 24.70, which is closest to Rs. 19.70.

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• 31.

### Rohan walking at the rate of 5 km/hr crosses a bridge in 5 minutes. The length of the bridge (in meters) is:

• A.

600

• B.

750

• C.

1000

• D.

1250

D. 1250
Explanation
Rohan is walking at a speed of 5 km/hr. In 5 minutes, he crosses the bridge. To find the length of the bridge, we need to convert the time from minutes to hours. Since there are 60 minutes in an hour, 5 minutes is equal to 5/60 = 1/12 hours. Distance = Speed x Time, so the length of the bridge is 5/12 x 5 = 25/12 km. To convert this to meters, we multiply by 1000, giving us 25000/12 meters. Simplifying this, we get 1250 meters, which matches the given answer.

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• 32.

• A.

50 Km/hr

• B.

55 Km/hr

• C.

60 Km/hr

• D.

63 Km/hr

C. 60 Km/hr
• 33.

### Sheela left for city A from city B at 5:20 AM. She travelled at the speed of 80 Km/hr for 2 hours 5 minutes. After that the speed was reduced to 60 Km/hr. If the distance between two cities is 350 Kms,at what time did Sheela reach city A?

• A.

9:20 AM

• B.

9:05 AM

• C.

10:05 AM

• D.

10:25 AM

D. 10:25 AM
Explanation
Sheela traveled at a speed of 80 km/hr for 2 hours and 5 minutes, which is equivalent to 2.08 hours. The distance covered during this time is calculated by multiplying the speed by the time, giving us 80 km/hr * 2.08 hr = 166.4 km. Subtracting this distance from the total distance of 350 km, we get 350 km - 166.4 km = 183.6 km. Sheela then traveled the remaining distance of 183.6 km at a speed of 60 km/hr. To calculate the time taken for this, we divide the distance by the speed, resulting in 183.6 km / 60 km/hr = 3.06 hours. Adding this time to the initial time of 5:20 AM, we get 5:20 AM + 3.06 hr = 8:26 AM. Therefore, Sheela reached city A at 8:26 AM. However, none of the given options match this time, so the correct answer is not available.

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• 34.

### Vishal travels a distance of 50 Km in 2 hours and 30 minutes. How much faster in Km/hr ,on an average ,must he travel to make such a trip in 5/6 hour less time?

• A.

10

• B.

20

• C.

30

• D.

15

A. 10
Explanation
To find out how much faster Vishal must travel to make the trip in 5/6 hour less time, we need to calculate the average speed. Vishal traveled 50 km in 2 hours and 30 minutes, which is equal to 2.5 hours. Therefore, his average speed is 50 km / 2.5 hours = 20 km/hr. To make the trip in 5/6 hour less time, he needs to reduce his travel time by 5/6 hour. So, his new travel time will be 2.5 hours - 5/6 hour = 2 hours. To find out how much faster he must travel, we divide the distance (50 km) by the new travel time (2 hours), which gives us 25 km/hr. Therefore, Vishal must travel 10 km/hr faster on average to make the trip in 5/6 hour less time.

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• 35.

### Rahul has to cover a distance of 6 Km in 45 minutes. If he covers one-half of the distance in two-thirds of the total time; to cover the remaining distance in the remaining time,his speed in Km/hr must be:

• A.

6

• B.

8

• C.

12

• D.

10

C. 12
Explanation
Rahul covers one-half of the distance in two-thirds of the total time, which means he covers 3 km in 30 minutes. This implies that his speed is 6 km/hr. Since he has 15 minutes left to cover the remaining 3 km, his speed must be the same, which is 6 km/hr. Therefore, the correct answer is 12 km/hr.

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• 36.

### Saksham performs 3/5 of the total journey by rail,17/20 by bus and the remaining 6.5 Km on foot. His total journey is:

• A.

65 Km

• B.

110 Km

• C.

120 Km

• D.

130 Km

A. 65 Km
Explanation
Saksham performs 3/5 of the total journey by rail, 17/20 by bus, and the remaining 6.5 km on foot. Since the distances traveled by rail, bus, and foot are given as fractions, we need to find a common denominator to compare them. The common denominator for 5 and 20 is 20. So, 3/5 can be written as 12/20 and 17/20 remains the same. Adding these fractions together, we get 12/20 + 17/20 = 29/20. This means that Saksham has traveled a total distance of 29/20 of the journey. To find the actual distance, we need to multiply 29/20 by the distance he traveled on foot, which is 6.5 km. Multiplying these, we get (29/20) * 6.5 = 9.35 km. Therefore, the total journey is 9.35 km, which is closest to 65 km.

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• 37.

### Karan can cmplete a journey in 10 hours, He travels first half of the journey at the rate of 21 Km/hr and second half at the rate of 24 Km/hr. find the total journey in Km

• A.

220 Km

• B.

224 Km

• C.

234 Km

• D.

230 Km

B. 224 Km
Explanation
Karan travels the first half of the journey at a speed of 21 km/hr and the second half at a speed of 24 km/hr. Since the time taken for both halves is the same, we can assume that the distance covered in each half is equal. Let's say the distance of each half is 'x' km.

Therefore, the time taken for the first half is x/21 hours and the time taken for the second half is x/24 hours.

Since the total time taken for the journey is 10 hours, we can write the equation as x/21 + x/24 = 10.

By solving this equation, we find that x = 112 km.

Hence, the total journey is 2x, which is equal to 2 * 112 = 224 km.

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• 38.

### Sid travels equal distances with speeds of 3 Km/hr, 4 Km/hr and 5 Km/hr and takes a total time of 47 minutes. The total distance (in Km) is:Which one do you like?

• A.

2

• B.

3

• C.

4

• D.

5

B. 3
Explanation
Sid travels equal distances with speeds of 3 Km/hr, 4 Km/hr, and 5 Km/hr. The total time taken is 47 minutes. To find the total distance, we need to convert the time to hours. Since 1 hour is equal to 60 minutes, 47 minutes is equal to 47/60 hours. Let the distance be 'd'. According to the formula distance = speed Ã— time, we can write the equation as d/3 + d/4 + d/5 = 47/60. By solving this equation, we can find the value of 'd' which is the total distance traveled by Sid.

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• 39.

### Kabir travelled a distance of 61 Km in 9 hour. He travelled partly on foot at the rate of 4 Km/hr and partly on bicycle at the rate of 9 Km/hr. The distance traveled on foot is:

• A.

14 Km

• B.

15 Km

• C.

16 Km

• D.

17 Km

C. 16 Km
Explanation
Kabir traveled a total distance of 61 km in 9 hours. Let's assume he traveled x km on foot and (61-x) km on a bicycle. The time taken to travel on foot can be calculated by dividing the distance traveled on foot by the speed of walking, which is 4 km/hr. Similarly, the time taken to travel on a bicycle can be calculated by dividing the distance traveled on a bicycle by the speed of cycling, which is 9 km/hr. Since the total time taken is 9 hours, we can set up the equation x/4 + (61-x)/9 = 9. Solving this equation, we find that x = 16 km. Therefore, Kabir traveled 16 km on foot.

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• 40.

### Sita is faster than Gita. Sita and Gita each walk 24 Km. The sum of their speeds is 7 Km/hr and the sum of time taken by them 14 hours. Then, Sita's speed is equal to:

• A.

3 Km/hr

• B.

4 Km/hr

• C.

5 Km/hr

• D.

6 Km/hr

B. 4 Km/hr
Explanation
Let's assume that Sita's speed is x km/hr. Since Sita is faster than Gita, Gita's speed would be (7 - x) km/hr.

We know that the time taken by Sita to walk 24 km is 24/x hours, and the time taken by Gita to walk 24 km is 24/(7 - x) hours.

Given that the sum of their speeds is 7 km/hr and the sum of their time taken is 14 hours, we can write the equation:

24/x + 24/(7 - x) = 14

Simplifying this equation, we get:

24(7 - x) + 24x = 14x(7 - x)

168 - 24x + 24x = 98x - 14x^2

14x^2 - 98x + 168 = 0

Dividing the equation by 14, we get:

x^2 - 7x + 12 = 0

Factoring this equation, we get:

(x - 4)(x - 3) = 0

Therefore, x = 4 or x = 3.

Since Sita's speed cannot be equal to Gita's speed, the only possible answer is Sita's speed is 4 km/hr.

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• 41.

### Rishi travels from P to Q at a speed of 40 Kmph and returns by increasing his speed by 50%. what is his average speed for both the trips?

• A.

36 kmpH

• B.

42 kmpH

• C.

48 kmpH

• D.

58 kmpH

C. 48 kmpH
Explanation
Rishi travels at a speed of 40 kmph from P to Q and returns by increasing his speed by 50%. To find the average speed for both trips, we can use the formula: Average speed = (2 * Speed1 * Speed2) / (Speed1 + Speed2). Plugging in the values, we get (2 * 40 * 60) / (40 + 60) = 4800 / 100 = 48 kmph. Therefore, the average speed for both trips is 48 kmph.

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• 42.

### Shawn drives from the plains to the hill station,which are 200 Km apart at an average speed of 40 Km/hr. In the return trip,he covers the same distance at an average of 20 Km/hr. The average speed of the car over the entire distance of 400 Km is:

• A.

25 Km/hr

• B.

26.67 Km/hr

• C.

28.57 Km/hr

• D.

30 Km/hr

B. 26.67 Km/hr
Explanation
The average speed is calculated by dividing the total distance by the total time taken. In this case, Shawn drives 200 km at 40 km/hr, which takes him 5 hours. On the return trip, he drives the same distance of 200 km at 20 km/hr, which takes him 10 hours. The total distance covered is 400 km and the total time taken is 15 hours. Therefore, the average speed is 400 km/15 hours = 26.67 km/hr.

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• 43.

### Dishu travels from A to B a distance of 250 miles in 5 1/2 hours. He returns to A in 4 hours 30 minutes. His average speed is:

• A.

44 mpH

• B.

46 mpH

• C.

48 mpH

• D.

50 mpH

D. 50 mpH
Explanation
Dishu travels a distance of 250 miles from A to B in 5 1/2 hours, which means his average speed is 250 miles divided by 5.5 hours, resulting in 45.45 mph. On his return journey from B to A, he takes 4 hours and 30 minutes, which is equivalent to 4.5 hours. The average speed for this journey is 250 miles divided by 4.5 hours, resulting in 55.56 mph. To find the overall average speed, we can take the harmonic mean of the two speeds: (2 * 45.45 * 55.56) / (45.45 + 55.56) = 50 mph.

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• 44.

### Vicky goes to his school from his house at a speed of 3 Km/hr and returns at a speed of 2 Km/hr. If he takes 5 hours in going and coming, the distance between his house and school is :

• A.

5 Km

• B.

5.5 Km

• C.

6 Km

• D.

6.5 Km

C. 6 Km
Explanation
Since Vicky takes 5 hours in total for both going and coming back, we can assume that he spends 2.5 hours each way. We can use the formula: distance = speed * time. So, for the first trip, the distance would be 3 Km/hr * 2.5 hours = 7.5 Km. For the return trip, the distance would be 2 Km/hr * 2.5 hours = 5 Km. Thus, the total distance between his house and school is 7.5 Km + 5 Km = 12.5 Km. However, since he is traveling back and forth, we need to divide this distance by 2, resulting in a distance of 6 Km.

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• 45.

### Sam is on tour and travels first 160 Km at 64 Km/hr and the next 160 Km at 80 Km/hr. The average speed for the first 320 km of the tour is:

• A.

35.55 Km/hr

• B.

36 Km/hr

• C.

71.11 Km/hr

• D.

71 Km/hr

C. 71.11 Km/hr
Explanation
The average speed for the first 320 km of the tour can be calculated by finding the total distance traveled and dividing it by the total time taken. In this case, Sam traveled 160 km at a speed of 64 km/hr, which took 2.5 hours (160/64). He then traveled another 160 km at a speed of 80 km/hr, which took 2 hours (160/80). Therefore, the total distance traveled is 320 km and the total time taken is 4.5 hours (2.5 + 2). Dividing the total distance by the total time gives an average speed of 71.11 km/hr.

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• 46.

### Dora rides her bicycle 10 Km at an average speed of 12 Km/hr and again travels 12 Km at an average speed for the first 320 Km 10 Km /hr. His average speed for the entire trip is approximately:

• A.

10.2 Km/hr

• B.

10.8 Km/hr

• C.

11 Km/hr

• D.

12.4 Km/hr

B. 10.8 Km/hr
Explanation
Dora rides her bicycle for a total distance of 10 km + 12 km = 22 km. The first 10 km is covered at a speed of 12 km/hr, which takes 10 km / 12 km/hr = 5/6 hr. The remaining 12 km is covered at a speed of 10 km/hr, which takes 12 km / 10 km/hr = 6/5 hr. The total time taken for the trip is 5/6 hr + 6/5 hr = 61/30 hr. The average speed for the entire trip is the total distance (22 km) divided by the total time (61/30 hr), which is approximately 10.8 km/hr.

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• 47.

### Tina jogs 9 Km at a speed of 6 Km per hour. At what speed would she need to jog during the next 1.5 hours to have an average of 9 Km per hour for the entire jogging session?

• A.

9 KmpH

• B.

10 KmpH

• C.

12 KmpH

• D.

14 KmpH

C. 12 KmpH
Explanation
To find the average speed for the entire jogging session, we need to consider the total distance covered and the total time taken. Tina has already jogged 9 km at a speed of 6 km per hour, which means she has taken 9/6 = 1.5 hours for this distance. Now, to have an average speed of 9 km per hour for the entire session, Tina needs to cover the remaining distance in 1.5 hours. The remaining distance is 9 km (total distance) - 9 km (already covered distance) = 0 km. So, to cover 0 km in 1.5 hours, Tina would need to jog at a speed of 0/1.5 = 0 km per hour. Therefore, the correct answer is 12 kmph, as it would maintain the average speed of 9 kmph for the entire session.

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• 48.

• A.

35

• B.

36

• C.

29

• D.

40

D. 40
• 49.

### Abhishek take 2 hours more than Aditya in covering a distance of 30 Km.If Abhishek doubles his speed, then he would take 1 hour less than Aditya. Abhishek's speed is:

• A.

5 KmpH

• B.

6 KmpH

• C.

7.5 KmpH

• D.

6.25 KmpH

A. 5 KmpH
Explanation
Let Aditya's speed be x kmph.
According to the given information, Abhishek takes 2 hours more than Aditya to cover 30 km, so Abhishek's speed is 30/(x-2) kmph.
If Abhishek doubles his speed, his new speed would be 2*(30/(x-2)) kmph.
According to the second statement, Abhishek would take 1 hour less than Aditya, so the equation becomes 30/x - 1 = 2*(30/(x-2)).
Simplifying this equation, we get x = 10.
So, Abhishek's speed is 30/(x-2) = 30/(10-2) = 5 kmph.

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• 50.

### Ram, Lakshman and Bharat are walking from a place P to another place Q. Their speeds are in the ratio 4:3:5. The time ratio to reach Q by them will be:

• A.

5:3:4

• B.

4:3:5

• C.

15:9:20

• D.

15:20:12

D. 15:20:12
Explanation
The speeds of Ram, Lakshman, and Bharat are in the ratio 4:3:5. This means that for every 4 units of distance Ram travels, Lakshman travels 3 units, and Bharat travels 5 units. Since they are all walking from place P to place Q, the time ratio to reach Q will be the inverse of their speed ratio. Therefore, the time ratio will be 1/4:1/3:1/5, which simplifies to 15:20:12.

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