Show your truth tables as solutions in a separate sheet.
¬p ∨ ¬q
P ∨ ¬q
¬p ∨ q
¬p ∧ q
¬q → ¬p
Q → p
¬p → ¬q
¬p → q
Q↔p
P↔¬q
¬p↔¬q
¬q↔¬p
¬ (p → ¬q)
(p → ¬q)
(¬p → ¬q)
(¬p → q)
P ∨ q ≡ q ∨ p
¬(p ∧ q) ≡ ¬p ∨ ¬q
(p ∨ q) ∨ r ≡ p ∨ (q ∨ r)
All options are correct
(p → q) → (q → p)
(p → q) ∨ (q → p)
(p → q) ∧ (q → p)
(p ∧ q) → (q ∧ p)
P → (q ∧ r)
P → (q ∨ r)
P ∧ (q ∨ r)
P ∨ (q ∧ r)
(p ∧ q) ∨ r
(p ∨ q) → r
(p ∧ q) → r
(p → q) → r
P ↔ ¬q
¬p ↔ q
¬p ↔ ¬q
¬q ↔ ¬p
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