Number Magic: Discrete Math Quiz (Counting)
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How many 4-digit counting numbers are multiples of 10?
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10000
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1000
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900
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5040
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Embark on a numerical adventure with our "Number Magic: Discrete Math Quiz (Counting)." Dive into the fascinating realm of discrete mathematics, specifically focusing on counting principles. This quiz challenges your grasp of combinatorics, permutations, and combinations, unraveling the magic behind counting in mathematics.
Explore scenarios where you'll apply fundamental counting principles to solve problems, making this quiz ideal for students, See moremath enthusiasts, and those seeking to enhance their understanding of discrete mathematics. Whether you're intrigued by the permutations of possibilities or the combinations that shape mathematical outcomes, this quiz offers an engaging platform to hone your counting skills.
Unlock the secrets of Number Magic and elevate your appreciation for the intricacies of discrete math through this thought-provoking and educational quiz.
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- 2.
A coin is tossed four times. How many possible outcomes are there?
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16
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8
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6
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32
Correct Answer
A. 16Explanation
When a coin is tossed four times, each toss has two possible outcomes: either heads or tails. Since there are four tosses, the total number of possible outcomes can be calculated by multiplying the number of outcomes for each toss together. In this case, it is 2 x 2 x 2 x 2 = 16. Therefore, there are 16 possible outcomes when a coin is tossed four times.Rate this question:
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- 3.
If you have four shirts and four pairs of trousers and any shirt can be worn with any pair of trousers, in how many ways can you wear your shirts and pairs of pants?
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24
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12
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16
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8
Correct Answer
A. 16Explanation
There are four shirts and four pairs of trousers, and each shirt can be worn with any pair of trousers. Therefore, for each shirt, there are four possible combinations with the trousers. Since there are four shirts, the total number of combinations is 4 multiplied by 4, which equals 16.Rate this question:
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- 4.
A student enrolled in ASC but residing in Bigaan Hinatuan has four ways to go to and from school. He can ride Pafra jeep, Bachelor bus, a van, or via single habalhabal. If he prefers to ride ONLY via van to go home, how many possible ways can he travel to and from school?
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12
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8
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16
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4
Correct Answer
A. 4Explanation
The student has four options for transportation to and from school: Pafra jeep, Bachelor bus, van, or single habalhabal. However, if he prefers to only ride via van to go home, then he can only choose the van as his mode of transportation. Therefore, there is only one possible way for him to travel to and from school, which is by riding the van. Hence, the correct answer is 1.Rate this question:
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- 5.
In how many ways can two vacancies be filled from among four men and 12 women if one job is supplied by a man and the other by a woman?
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4
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16
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48
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12
Correct Answer
A. 48Explanation
There are 4 ways to choose a man for the first vacancy and 12 ways to choose a woman for the second vacancy. Since these choices are independent, the total number of ways to fill the vacancies is 4 * 12 = 48.Rate this question:
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- 6.
In how many ways can two vacancies be filled from among four men and 12 women if one vacancy is filled by a man and the other by either a man or a woman?
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60
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30
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48
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16
Correct Answer
A. 60Explanation
There are 4 ways to fill the first vacancy with a man. For the second vacancy, there are 4 men and 12 women to choose from, so there are 16 possible combinations. However, since the second vacancy can be filled by either a man or a woman, we need to subtract the case where both vacancies are filled by men, which is 4. Therefore, the total number of ways to fill the vacancies is 16 - 4 = 12. Since each combination has 2 different orders (man-woman or woman-man), we multiply 12 by 2 to get 24. Finally, since there are 3 different pairs of vacancies that can be filled, we multiply 24 by 3 to get 72.Rate this question:
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- 7.
How many three-digit numbers greater than 600 can be formed using the digits 1, 2, 5, 6, 8 without repeating the digits?
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2
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24
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60
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125
Correct Answer
A. 24Explanation
To form a three-digit number greater than 600 using the given digits without repeating any digit, we need to consider the hundreds place first. Since the number needs to be greater than 600, the hundreds place can only be 6 or 8. Once we choose the hundreds place, we have 4 options for the tens place (1, 2, 5, or 8) and 3 options for the units place (the remaining digits). Therefore, the total number of three-digit numbers greater than 600 that can be formed is 2 (choices for the hundreds place) multiplied by 4 (choices for the tens place) multiplied by 3 (choices for the units place), which equals 24.Rate this question:
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- 8.
How many four-digit numbers can be formed with digits 1, 2, 3, and 4 and with distinct digits?
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10
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24
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256
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10000
Correct Answer
A. 24Explanation
To form a four-digit number, we have four choices for the first digit (1, 2, 3, or 4). After selecting the first digit, we have three choices left for the second digit, two choices left for the third digit, and only one choice left for the fourth digit. Therefore, the total number of four-digit numbers that can be formed with distinct digits is 4 x 3 x 2 x 1 = 24.Rate this question:
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- 9.
5 students are staying in a dormitory. In how many ways can you allot 5 beds to them?
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10
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25
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120
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3125
Correct Answer
A. 120Explanation
There are 5 students and 5 beds, so each student can be assigned to a specific bed in 5 different ways. Therefore, the total number of ways to allot the beds to the students is 5 x 5 x 5 x 5 x 5 = 125. However, this includes cases where the same bed is assigned to multiple students. Since each bed can only be assigned to one student, we need to divide this total by the number of ways to arrange the students, which is 5! (5 factorial). 125 divided by 5! equals 120.Rate this question:
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- 10.
What is the maximum possible number of 3- letter words in English that do not contain any vowel? (repetition is allowed)
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9261
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7980
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15600
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17576
Correct Answer
A. 9261Explanation
The maximum possible number of 3-letter words in English that do not contain any vowels can be calculated by finding the number of possibilities for each letter position. Since there are 26 letters in the English alphabet, and we are looking for words without vowels, we have 21 consonants to choose from for each position. Therefore, the total number of possibilities is 21 * 21 * 21 = 9261.Rate this question:
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Current Version
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Dec 19, 2023Quiz Edited by
ProProfs Editorial Team -
Mar 16, 2018Quiz Created by
Auabellanosa
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