Matematika Smp Klas 9 Materi Kesebangunan

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| By Joko_Subiyanto
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Matematika Smp Klas 9 Materi Kesebangunan - Quiz

SMP Negeri 2 Godean Kerjakan Soal-soal  berikut  a. Dengan klik pada jawaban yang kamu anggap paling tepat  pada soal pilihan ganda b. isikan dengan singkat jawaban anda pada soal isian singkat


Questions and Answers
  • 1. 

    Setiap bangun berikut pasti sebangun, kecuali .....

    • A.

      A. Dua bangun Lingkaran

    • B.

      B. Dua bangun Persegi

    • C.

      C. Dua bangun Belah ketupat

    • D.

      D. Dua bangun Segitiga sama sisi

    Correct Answer
    C. C. Dua bangun Belah ketupat
    Explanation
    Silahkan lanjutkan ke Soal Berikut

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  • 2. 

    Segitiga ABC dan Segitga DEF kongruen, pernyataan berikut yang benar adalah ... .

    • A.

      A. AB = DE

    • B.

      B. BC = EF

    • C.

      C. BC = DF

    • D.

      D. AC = EF

    Correct Answer
    D. D. AC = EF
    Explanation
    The statement "AC = EF" is correct because in congruent triangles, corresponding sides are equal in length. Therefore, if triangle ABC is congruent to triangle DEF, it means that side AC is equal in length to side EF.

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  • 3. 

    Bangun- bangun berikut  sebangun dengan ubin yang berukuruan 30 cmx 30 cm,  kecuali ... .

    • A.

      A. Buku tulis dengan ukuran 20cm x 15 cm

    • B.

      B. Karpet berukuran 4 m x 4m

    • C.

      C. Ring tinju dengan ukuran 5m x 5m

    • D.

      D. Tikar berukuran 2m x 2m

    Correct Answer
    A. A. Buku tulis dengan ukuran 20cm x 15 cm
    Explanation
    The given statement states that all the shapes mentioned are similar to tiles measuring 30 cm x 30 cm, except for the size of a notebook which is 20 cm x 15 cm. This means that the notebook is not proportional to the tiles and does not have the same dimensions. Therefore, the correct answer is A. Buku tulis dengan ukuran 20cm x 15 cm.

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  • 4. 

    Sebuah karton dengan ukuran 30cm x 50cm sebangun dengan  foto   ditempel seperti gambar di samping, jika sisi kanan sisi atas, sisi kanan dan   kiri foto berjarak 5cm, maka lebar foto adalah ....cm

    Correct Answer
    24
    24 cm
    24cm
    Explanation
    The width of the photo can be calculated by subtracting the distances between the sides of the photo and the sides of the cardboard from the width of the cardboard. Since the distances between the sides of the photo and the sides of the cardboard are all 5cm, we can subtract 5cm from both sides of the cardboard. Therefore, the width of the photo is 30cm - 5cm - 5cm = 20cm.

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  • 5. 

     Sebuah fotodengan tinggi 8 cm dan lebar 6 cm, diperbesar hingga lebarnya menjadi 21cm, Luas foto setelah diperbesar   adalah ... .

    Correct Answer
    588
    588cm
    588 cm
    Explanation
    The correct answer is 588 cm². To find the area of the photo after it is enlarged, we need to determine the scale factor of the enlargement. The scale factor is found by dividing the new width (21 cm) by the original width (6 cm), which gives us a scale factor of 3.5. To find the area, we square the scale factor and multiply it by the original area. The original area is 8 cm x 6 cm = 48 cm². Multiplying 48 cm² by 3.5² gives us 588 cm².

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  • 6. 

    Pada siang hari yang cerah, satu regu pramuka mendapat tugas untuk menghitung tinggi sebuah pohon tanpa harus memanjat. Salh seaorang anggota mengambi tongkat yang panjangnya 160 cm, kemudian tongkat tersebut di dirikan tegak lurus di atas tanah rata. Anggota pramuka yang lain mengukur panjang bayangan pohon dan panjang bayangan tongkat. Ternyata, panjang bayangan pohon 375 cm dan panjang bayangan tongkat 80 cm. maka tinggi pohon tersebut adalah … .

    • A.

      8 m

    • B.

      7,5 m

    • C.

      6 m

    • D.

      3,75 m

    Correct Answer
    B. 7,5 m
    Explanation
    The height of the tree can be calculated using the concept of similar triangles. The length of the tree's shadow is proportional to the height of the tree, while the length of the stick's shadow is proportional to the length of the stick. By setting up a proportion, we can find the height of the tree. The length of the tree's shadow is 375 cm and the length of the stick's shadow is 80 cm. Therefore, the height of the tree is (375 cm / 80 cm) * 160 cm = 7.5 m.

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  • 7. 

    Sebuah tower mempunyai banyangan yang panjangnya 6,25 m. JIka sepotong kayu yang panjangnya 70 cm di tancapkan tegak lurus diatas tanah, maka panjang bayangannya 20 cm, Maka tinggi tower adalah ... .

    • A.

      437,5 m

    • B.

      218,7 m

    • C.

      43,75 m

    • D.

      21,87 m

    Correct Answer
    D. 21,87 m
    Explanation
    The given question involves a shadow problem. The length of the shadow of the wooden stick is given as 20 cm, and the actual length of the stick is 70 cm. To find the height of the tower, we can use the concept of similar triangles. The ratio of the height of the tower to the length of the shadow is equal to the ratio of the length of the stick to the length of its shadow. Using this proportion, we can calculate the height of the tower as (70 cm * 6.25 m) / 20 cm = 21.87 m.

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  • 8. 

    Dua bangun berikut pasti sbangun

    • A.

      Dua segitiga siku-siku

    • B.

      Dua segitiga lancip

    • C.

      Dua segitiga sama kaki

    • D.

      Dua segitiga sama sisi

    Correct Answer
    D. Dua segitiga sama sisi
    Explanation
    The given answer states that "dua segitiga sama sisi" (two equilateral triangles) are definitely congruent. This is because equilateral triangles have all sides and angles equal, so if we have two equilateral triangles, they will be congruent to each other. Therefore, the given answer is correct.

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  • Current Version
  • Mar 22, 2023
    Quiz Edited by
    ProProfs Editorial Team
  • Jul 27, 2012
    Quiz Created by
    Joko_Subiyanto
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