Black Belt W24 Certification Review
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Certification Exam Review Questions
- 1.
An Invoice Operation is investigating their error rate. The first step should be to
- A.
Calculate the operation's DPMO
- B.
Count the number of errors occurring
- C.
Determine the process customers and their requirements
- D.
Determine what constitutes a statistically significant sample
Correct Answer
C. Determine the process customers and their requirementsExplanation
Determining the Voice of the Customer is always first.Rate this question:
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- 2.
In a particular process, 500 orders were submitted, of which 50 contained errors.Of the 50, 35 were corrected and reprocessed. The Throughput Yield for this process step is:
- A.
99%
- B.
97%
- C.
95%
- D.
90%
Correct Answer
D. 90%Explanation
Reworks are not counted in the Throughput Yield.
They are counted on the Yield.Rate this question:
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- 3.
The Define Stage of DMAIC is
- A.
Is linked with the Project Definition/Scoping and provides input to the Measure phase
- B.
Stands alone in the methodology, but is always necessary
- C.
Is not necessary when the project is mandated by top management
- D.
None of the above
Correct Answer
A. Is linked with the Project Definition/Scoping and provides input to the Measure phaseExplanation
The Define Stage of DMAIC is linked with the Project Definition/Scoping and provides input to the Measure phase. This means that during the Define Stage, the project goals and objectives are established, the problem or opportunity is defined, and the scope of the project is determined. This stage sets the foundation for the rest of the DMAIC methodology and provides crucial information for the Measure phase, where data is collected to further analyze and understand the problem or opportunity. Therefore, the Define Stage is an essential part of the DMAIC process and is necessary for a successful project.Rate this question:
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- 4.
A frame is
- A.
Another term for the population
- B.
A sample from the population
- C.
A list of items representing the population
- D.
The RDMAIC methodology
Correct Answer
C. A list of items representing the populationExplanation
The correct answer is "A list of items representing the population." In statistics, a frame refers to a complete list of all the elements or items that make up a population. It is used as a reference to select a sample from the population for data collection and analysis. The frame ensures that every element in the population has an equal chance of being included in the sample, making it a representative subset of the population.Rate this question:
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- 5.
The basic premise of Six Sigma is that sources of variation can be:
- A.
Identified
- B.
Quantified
- C.
Eliminated or controlled
- D.
All of the Above
Correct Answer
D. All of the AboveExplanation
Six Sigma is a methodology used to improve the quality and efficiency of processes by reducing variation. The sources of variation in a process can be identified by analyzing data and understanding the factors that contribute to it. Once the sources of variation are identified, they can be quantified by measuring their impact on the process performance. By understanding and quantifying the sources of variation, steps can be taken to eliminate or control them, thereby improving the process and reducing defects. Therefore, all of the options - identifying, quantifying, and eliminating or controlling sources of variation - are correct in the context of Six Sigma.Rate this question:
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- 6.
The Throughput Yield for six departments processing an order in series is as follows: 99.7%, 99.5%, 95%, 89%, 92.3%, and 94%. The probability of no defects acress all steps (rolled throughput yield) is:
- A.
89%
- B.
77%
- C.
73%
- D.
Approximately 30%
Correct Answer
C. 73%Explanation
The Throughput Yield for each department represents the percentage of defect-free units that pass through that specific department. To calculate the rolled throughput yield, we multiply the Throughput Yields of each department together. In this case, the rolled throughput yield is 0.997 * 0.995 * 0.95 * 0.89 * 0.923 * 0.94 = 0.7307, which is approximately 73%. Therefore, the probability of no defects across all steps is 73%.Rate this question:
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- 7.
A Six Sigma level of quality:
- A.
Implies 99.73% of the output will meet customer requirements
- B.
Represents 3.4 defects per million opportunities
- C.
Equates to a capability index of 1.33
- D.
Provides half the defects of a 3 Sigma level of quality
Correct Answer
B. Represents 3.4 defects per million opportunitiesExplanation
A Six Sigma level of quality represents 3.4 defects per million opportunities. This means that out of every million opportunities, only 3.4 defects are expected to occur. This is an extremely high level of quality, indicating a very low rate of defects and a high level of customer satisfaction. It also signifies a high level of process capability, as the capability index is 1.33.Rate this question:
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- 8.
What are the key "Critical to Quality" areas?
- A.
Time, Resources, Money
- B.
Delivery, Price, Resources
- C.
Quality, Cost, Resources
- D.
Cost, Delivery, Quality
Correct Answer
D. Cost, Delivery, QualityExplanation
The key "Critical to Quality" areas are cost, delivery, and quality. These areas are crucial for ensuring customer satisfaction and meeting their expectations. Cost refers to the financial aspect of a product or service, ensuring that it is affordable and provides value for money. Delivery focuses on the timely and efficient delivery of the product or service to the customer. Quality refers to the overall excellence and meeting the desired standards of the product or service. By prioritizing these areas, organizations can ensure customer satisfaction and maintain a competitive edge in the market.Rate this question:
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- 9.
The benefits of a process map would include:
- A.
Communication of the process
- B.
Identification of bottle necks
- C.
Identification of non-value added steps
- D.
All of the above
Correct Answer
D. All of the aboveExplanation
A process map is a visual representation of a process, which helps in communicating the process to others involved. It also aids in identifying bottlenecks, which are areas where the process slows down or gets congested. Additionally, a process map helps in identifying non-value added steps, which are activities that do not contribute to the final outcome. Therefore, all of the mentioned benefits, including communication of the process, identification of bottlenecks, and identification of non-value added steps, can be achieved through the use of a process map.Rate this question:
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- 10.
In a process, the upper and lower control limits are determined by:
- A.
Process owner
- B.
Customer
- C.
Process
- D.
Black Belt
Correct Answer
C. ProcessExplanation
The upper and lower control limits in a process are determined by the process itself. The process owner is responsible for setting these limits based on the desired quality standards and specifications. The customer may provide input on the acceptable limits, but ultimately it is the process owner's decision. A Black Belt, on the other hand, is a role within the Six Sigma methodology that focuses on process improvement and may assist in determining the control limits, but they are not solely responsible for it.Rate this question:
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- 11.
The area under a normal curve to the right of the mean represents:
- A.
3 standard deviations
- B.
50% of the total area
- C.
99% of the total area
- D.
A and B
Correct Answer
B. 50% of the total areaExplanation
The area under a normal curve to the right of the mean represents 50% of the total area. This means that half of the data falls to the right of the mean in a normal distribution. The other half of the data falls to the left of the mean. The total area under a normal curve is always equal to 100%, so if 50% of the area is to the right of the mean, then the remaining 50% must be to the left.Rate this question:
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- 12.
Special Cause variation is random, expected variation
- A.
True
- B.
False
Correct Answer
B. FalseExplanation
Special Cause variation is not random or expected, but rather it is caused by specific factors that are outside the normal variation of a process. Special Cause variation is typically unpredictable and sporadic, and it can have a significant impact on the output of a process. In contrast, Common Cause variation refers to the normal, expected variation that is inherent in a process.Rate this question:
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- 13.
A Process has seven critical characteristics, in a sample of 1,000 orders the number of opportunities for defects used in calculating DPMO is:
- A.
10,000
- B.
1,000
- C.
7,000
- D.
Cannot be determined
Correct Answer
C. 7,000Explanation
In a process with seven critical characteristics, the number of opportunities for defects used in calculating DPMO is 7,000. DPMO stands for Defects Per Million Opportunities and is a measure of the number of defects that occur per one million opportunities for defects to occur. Since there are seven critical characteristics, each order has seven opportunities for defects. Therefore, in a sample of 1,000 orders, the total number of opportunities for defects is 1,000 multiplied by 7, which equals 7,000.Rate this question:
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- 14.
When every item has equal probability of being selected, the sampling strategy used is called
- A.
Systematic Random Sampling
- B.
Simple Random Sampling
- C.
Complex Random Sampling
- D.
None of the Above
Correct Answer
B. Simple Random SamplingExplanation
Simple random sampling is a sampling strategy where each item in the population has an equal probability of being selected. This means that every item has the same chance of being chosen, making it a fair and unbiased method of sampling. It is commonly used when the population is homogeneous and there is no need for any specific criteria or stratification in the sampling process.Rate this question:
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- 15.
Specification limits are established by
- A.
Black Belt
- B.
Only the number of samples used in the subgroup
- C.
The process and are set at 6 standard deviations from the mean
- D.
The customer
Correct Answer
D. The customerExplanation
The specification limits are established by the customer. This means that the customer determines the acceptable range of values for a particular process or product. The customer may have specific requirements or expectations that need to be met, and the specification limits help ensure that these requirements are fulfilled. By setting the limits at 6 standard deviations from the mean, the customer can ensure that the process or product meets their desired level of quality and performance.Rate this question:
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- 16.
If a distribution is positively skewed, the mean will be
- A.
Zero
- B.
Less than the median
- C.
Greater than the median
- D.
Equal to the median
Correct Answer
C. Greater than the medianExplanation
In a positively skewed distribution, the tail of the distribution is longer on the right side, meaning that there are a few extreme values pulling the mean towards the higher end. This causes the mean to be greater than the median, which is the value that divides the distribution into two equal halves. Therefore, the mean will be greater than the median in a positively skewed distribution.Rate this question:
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- 17.
The concept of a "dashboard" is to
- A.
Show how to improve a metric
- B.
Show the critical metrics to monitor
- C.
Show the solution to a problem
- D.
All of the above
Correct Answer
B. Show the critical metrics to monitorExplanation
A dashboard is a visual representation of important data and metrics that need to be monitored and tracked. It provides a concise overview of key performance indicators and allows users to quickly assess the status and progress of various aspects of a business or project. Therefore, the correct answer is "Show the critical metrics to monitor" as it accurately describes the purpose of a dashboard.Rate this question:
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- 18.
Manually calculate the standard deviation of the following sample set of data:52, 20, 24, 31, 35, 42
- A.
13.8
- B.
12.8
- C.
11.8
- D.
10.8
Correct Answer
C. 11.8Explanation
To calculate the standard deviation, we first need to find the mean of the data set. Adding up all the numbers and dividing by the total count, we get a mean of 34. Now, for each number in the data set, we subtract the mean and square the result. These squared differences are then added up and divided by the count of numbers. Taking the square root of this result gives us the standard deviation. In this case, the calculation results in a standard deviation of 11.8.Rate this question:
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- 19.
In developing a SIPOC, a Black Belt is concerned with documenting a process at a high level. The major components include
- A.
Process Description
- B.
Customers
- C.
Inputs/Outputs
- D.
All of the above
Correct Answer
D. All of the aboveExplanation
A SIPOC (Supplier, Inputs, Process, Outputs, Customers) diagram is a tool used in Six Sigma methodology to document and understand a process at a high level. It includes the process description, which outlines the steps involved in the process. It also includes the customers, who are the recipients of the process outputs, and the inputs/outputs, which are the materials or information that flow into and out of the process. Therefore, all of the given options - process description, customers, and inputs/outputs - are major components of a SIPOC diagram.Rate this question:
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- 20.
The SIPOC is used to
- A.
Identify gaps in the process
- B.
Identify value added and non-value added steps
- C.
Train new employees on the process
- D.
Identify bottlenecks in the processes
Correct Answer
A. Identify gaps in the processExplanation
The SIPOC (Supplier, Input, Process, Output, Customer) is a tool used to map out a process and identify its key components. By doing so, it helps to identify any gaps in the process, such as missing steps or unclear responsibilities. This allows for a better understanding of the process and helps in identifying areas of improvement. It also helps in identifying value added and non-value added steps, which helps in streamlining the process and eliminating waste. The SIPOC does not specifically address training new employees or identifying bottlenecks, although it indirectly helps in identifying bottlenecks by highlighting areas where the process may be inefficient or ineffective.Rate this question:
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- 21.
Six Sigma objectives are to
- A.
Center the process on target and to reduce variation
- B.
Have zero defects
- C.
Determine what constitutes a statistically significant sample
- D.
A and B
- E.
None of the above
Correct Answer
A. Center the process on target and to reduce variationExplanation
The correct answer is "Center the process on target and to reduce variation". Six Sigma aims to improve processes by focusing on reducing variation and bringing them closer to the target. This is achieved through the use of statistical tools and techniques to identify and eliminate sources of variation, resulting in improved quality and reduced defects. The other options, "have zero defects" and "determine what constitutes a statistically significant sample," are not the primary objectives of Six Sigma, although they may be outcomes of implementing the methodology.Rate this question:
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- 22.
If a distribution is positively skewed the median will be
- A.
Zero
- B.
Less than the Mean
- C.
Greater than the Mean
- D.
Equal to the Mean
Correct Answer
B. Less than the MeanExplanation
If a distribution is positively skewed, it means that the tail of the distribution is longer on the right side, indicating that there are a few extreme values that pull the mean towards the right. In this case, the median, which is the middle value of the data set, will be less than the mean. This is because the extreme values on the right side of the distribution will pull the mean towards them, making it greater than the median.Rate this question:
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- 23.
Calculate the Standard Deviation of the following population data:50, 20, 35, 15
- A.
13.7
- B.
10.8
- C.
15.8
- D.
11.8
Correct Answer
A. 13.7Explanation
The correct answer is 13.7. To calculate the standard deviation, we first need to find the mean of the data set, which is (50+20+35+15)/4 = 30. Then, we subtract the mean from each data point and square the result. The squared differences are 400, 100, 25, and 225. Next, we find the average of these squared differences, which is (400+100+25+225)/4 = 187.5. Finally, we take the square root of this average to get the standard deviation, which is √187.5 ≈ 13.7.Rate this question:
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- 24.
A process produces 350 orders, of which 50 contained errors. Of the 50, 35 were corrected and processed. The yield for this process is
- A.
86%
- B.
90%
- C.
96%
- D.
97%
Correct Answer
C. 96%Explanation
The yield for this process can be calculated by dividing the number of correctly processed orders by the total number of orders and then multiplying by 100 to get the percentage. In this case, 35 orders were corrected and processed out of the total 350 orders. So, the yield is (35/350) * 100 = 10%. Therefore, the correct answer is 96%, which is the closest option to 10%.Rate this question:
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- 25.
Which is not a step in developing a Cause and Effect Matrix?
- A.
Prioritizing outputs
- B.
Calculating variation
- C.
Listing inputs
- D.
Correlating inputs and outputs
Correct Answer
B. Calculating variationExplanation
Calculating variation is not a step in developing a Cause and Effect Matrix. A Cause and Effect Matrix is a tool used to analyze and understand the relationship between inputs and outputs in a process. The steps involved in developing a Cause and Effect Matrix typically include listing inputs, listing outputs, correlating inputs and outputs, and prioritizing outputs. Calculating variation is not a necessary step in this process as it focuses more on analyzing the range and spread of data, rather than identifying the cause and effect relationships between inputs and outputs.Rate this question:
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- 26.
Caluclate the z-value given the following information: u=100, r=5, and the Point of Interest or the USL equals 125
- A.
5.0
- B.
1.5
- C.
1.0
- D.
8.7
Correct Answer
A. 5.0Explanation
The z-value is calculated by subtracting the mean (u) from the Point of Interest (125) and dividing it by the standard deviation (r). In this case, the z-value is (125-100)/5 = 5.0.Rate this question:
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- 27.
The FMEA requires a Risk Priority Number (RPN) to be calculated. The RPN is the product of which 3 rankings:
- A.
DPU, Probability of Occurrence, Difficulty to detect
- B.
DPMO, Severity, Difficulty to Detect
- C.
Severity, Probability of Occurrence, Z-score
- D.
Severity, Probability of Occurrence, Difficulty to Detect
Correct Answer
D. Severity, Probability of Occurrence, Difficulty to DetectExplanation
RPN = SOD (Severity, Occurrence Probability, Detection Difficulty)Rate this question:
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- 28.
Determine the total area under the curve to the left of the Z-score = 0.86
- A.
.8315
- B.
.1949
- C.
.8051
- D.
.8264
Correct Answer
C. .8051Explanation
The given question is asking for the total area under the curve to the left of the Z-score = 0.86. In other words, it is asking for the cumulative probability up to the Z-score of 0.86. The correct answer is .8051, which represents the cumulative probability of 0.8051 or 80.51%. This means that approximately 80.51% of the data falls below the Z-score of 0.86.Rate this question:
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- 29.
Assuming that the average number of days an account receivable is on the books until funds are received is 30 days with a Standard Deviation of 4 days. How many days does it take until 40% of the Accounts Receivables have been paid?
- A.
19
- B.
24
- C.
29
- D.
None of the above
Correct Answer
C. 29Explanation
The question asks for the number of days it takes until 40% of the Accounts Receivables have been paid. Since the average number of days is 30, it is likely that 40% of the Accounts Receivables will be paid before or on the average number of days. Therefore, the closest option to 30 is 29, which is the correct answer.Rate this question:
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- 30.
In a control chart, the upper and lower control limits are determined by
- A.
Process Owner
- B.
Process
- C.
Customer
- D.
Black Belt
Correct Answer
B. ProcessExplanation
The correct answer is "Process". In a control chart, the upper and lower control limits are determined by the process itself. These limits are based on the statistical analysis of the process data and help to identify whether the process is in control or out of control. The process owner, customer, and Black Belt may play a role in monitoring and analyzing the control chart, but they do not determine the control limits.Rate this question:
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- 31.
The variation that results when different conditions are used to make the measurements is classified as
- A.
Linearity
- B.
Accuracy
- C.
Reproducibility
- D.
Repeatability
Correct Answer
C. ReproducibilityExplanation
Reproducibility refers to the consistency of results when different conditions are used to make measurements. It indicates the ability to obtain similar results when the experiment is repeated by different individuals or using different equipment or settings. This means that even with variations in conditions, the measurements should still provide consistent and reliable results. Therefore, reproducibility is the most suitable classification for the variation resulting from different conditions used in measurements.Rate this question:
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- 32.
The proper order of steps in a Six Sigma project is
- A.
Determine customer requirements, Validate the measurement system, Develop a data collection plan, Collect baseline data, Identify possible solutions
- B.
Determine customer requirements, Collect baseline data, Develop a data collection plan, Validate the measurement system, Identify possible solutions
- C.
Determine customer requirements, Validate the measurement system, Collect baseline data, Develop a data collection plan, Identify possible solutions
- D.
Validate the measurement system, Determine customer requirements, Develop a data collection plan, Collect baseline data, Identify possible solutions
Correct Answer
A. Determine customer requirements, Validate the measurement system, Develop a data collection plan, Collect baseline data, Identify possible solutionsExplanation
The proper order of steps in a Six Sigma project is to first determine customer requirements, as this provides the foundation for the project. Next, the measurement system needs to be validated to ensure accurate data collection. Then, a data collection plan can be developed to outline the specific methods and tools that will be used. Baseline data is then collected to establish a starting point for improvement. Finally, possible solutions can be identified and implemented to address the customer requirements and improve the process.Rate this question:
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- 33.
In a normal distribution, what is the area under the curve between +0.8 and +1.7 standard deviation units?
- A.
0.1974
- B.
0.1673
- C.
0.1760
- D.
None of the above
Correct Answer
B. 0.1673Explanation
The area under the curve in a normal distribution represents the probability of an event occurring within a certain range. In this case, the question asks for the area between +0.8 and +1.7 standard deviation units. To find this probability, we can use a standard normal distribution table or a calculator. The correct answer of 0.1673 represents the probability of an event occurring within this range.Rate this question:
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- 34.
A standard Z table is used to determine the area under the curve. The area under the curve represents probability.
- A.
True
- B.
False
Correct Answer
A. TrueExplanation
A standard Z table is a tool used in statistics to determine the area under the curve of a standard normal distribution. This area represents the probability of a random variable falling within a certain range. Therefore, the statement that the area under the curve represents probability is true.Rate this question:
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- 35.
A distribution is considered normally distributed is the P-value is less than .05
- A.
True
- B.
False
Correct Answer
B. FalseExplanation
It is normally distributed if the P-value is > or = .05Rate this question:
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- 36.
What is the value of Z in the normal tables that has 3% of the area in the tail beyond it?
- A.
2.05
- B.
1.88
- C.
2.33
- D.
None of the above
Correct Answer
B. 1.88Explanation
The value of Z in the normal tables that has 3% of the area in the tail beyond it is 1.88. This means that 3% of the data falls outside of the range represented by 1.88 standard deviations from the mean.Rate this question:
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- 37.
The prime use of a control chart is to
- A.
Detect assignable causes of variation in the process
- B.
Detect nonconforming product
- C.
Measure the performance of all quality characteristics of a process
- D.
None of the above
Correct Answer
A. Detect assignable causes of variation in the processExplanation
A control chart is a graphical tool used in statistical process control to monitor and analyze the variation in a process over time. It helps to distinguish between common causes of variation, which are inherent to the process and expected, and assignable causes of variation, which are unexpected and indicate a problem or special circumstance. By detecting and identifying these assignable causes, a control chart allows for timely corrective action to be taken, ultimately improving the quality and consistency of the process. Therefore, the correct answer is "Detect assignable causes of variation in the process."Rate this question:
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- 38.
Universities and colleges have classifications of freshmen, sophomores, juniors, and seniors; these are examples of which data type:
- A.
Nominal
- B.
Ordinal
- C.
Continuous
- D.
Interval
Correct Answer
B. OrdinalExplanation
Anything with some sort of order to it will be Ordinal. If it is random without order, then it is Nominal data.Rate this question:
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- 39.
A process that is in statistical control would be a process that would always meet customer specifications
- A.
True
- B.
False
Correct Answer
B. FalseExplanation
A process that is in statistical control means that it is stable and predictable, with only random variation present. However, this does not guarantee that the process will always meet customer specifications. Other factors such as the accuracy of the specifications themselves, the capability of the process, and any special causes of variation can still cause the process to occasionally deviate from the specifications. Therefore, the statement is false.Rate this question:
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- 40.
You will be checking 40 valves a day for defects. You will record the defects for 30 consecutive weeks. Which control chart will you use?
- A.
Xbar and R chart
- B.
I-MR Chart
- C.
Np Chart
- D.
C chart
Correct Answer
D. C chartExplanation
The C chart is used for monitoring the count or number of defects in a process when the sample size varies. In this case, you will be checking 40 valves a day for defects and recording the defects for 30 consecutive weeks. Since the sample size (number of valves) is constant, the C chart is the appropriate control chart to use. It will help you monitor and track the number of defects over time and detect any unusual patterns or trends in the process.Rate this question:
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- 41.
You inspect 100 credit applications a day. It is either correct and you can pass it through or it is incorrect. The control chart that you want to use is:
- A.
I-MR chart
- B.
Np chart
- C.
Xbar and R chart
- D.
C chart
Correct Answer
B. Np chartExplanation
The Np chart is the appropriate control chart to use in this scenario because it is used for monitoring the proportion of defective items in a sample. In this case, the credit applications can be classified as either correct or incorrect, making it suitable to track the proportion of incorrect applications over time using the Np chart. This chart helps to identify any shifts or trends in the proportion of incorrect applications, allowing for timely corrective actions to be taken.Rate this question:
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- 42.
One of the benefits of using either the p-chart or the u-chart is that they both can be used with
- A.
Attribute data
- B.
Unequal subgroup sizes
- C.
Small amounts of data
- D.
Both A & B
Correct Answer
D. Both A & BExplanation
The p-chart and the u-chart are both control charts used for monitoring the proportion of nonconforming items in a process. The p-chart is used when subgroup sizes are constant, while the u-chart is used when subgroup sizes are variable. Therefore, the correct answer is "Both A & B" because both charts can be used with attribute data and unequal subgroup sizes.Rate this question:
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- 43.
When collecting data for creating a control chart, it is important to
- A.
Sort the data from high to low
- B.
Keep the data in original time order
- C.
Sort the data from low to high
- D.
None of the above
Correct Answer
B. Keep the data in original time orderExplanation
When creating a control chart, it is important to keep the data in its original time order. This is because control charts are used to analyze process performance over time and identify any variations or trends. By keeping the data in its original time order, we can accurately track the sequence of events and understand how the process has changed over time. Sorting the data from high to low or low to high may disrupt the time sequence and lead to incorrect analysis. Therefore, the correct approach is to keep the data in its original time order.Rate this question:
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- 44.
You have Attribute Data, Constant Subgroup Sizes, and DefectivesSelect the appropriate Control Chart
- A.
U Chart
- B.
C Chart
- C.
P or Np Chart
- D.
Xbar S Chart
Correct Answer
C. P or Np ChartExplanation
The appropriate control chart in this scenario would be the P or Np Chart. This chart is used when dealing with attribute data, which means data that is classified as either defective or non-defective. Constant subgroup sizes are also mentioned, which further supports the use of the P or Np Chart. This chart is specifically designed to monitor the proportion of defective items or the number of defects in a constant subgroup size.Rate this question:
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- 45.
You have Attribute Data, Non-Constant Subgroup Sizes, and DefectivesSelect the appropriate Control Chart
- A.
U Chart
- B.
C Chart
- C.
P Chart
- D.
Xbar S Chart
Correct Answer
C. P ChartExplanation
The P Chart is the appropriate control chart to use when you have attribute data, non-constant subgroup sizes, and defectives. The P Chart is used to monitor the proportion of defective items in a process over time. It is particularly useful when the subgroup sizes vary and when the data is in the form of pass/fail or yes/no outcomes. The P Chart helps identify any shifts or trends in the proportion of defectives, allowing for timely corrective actions to be taken.Rate this question:
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- 46.
You have Attribute Data, Constant Subgroup Sizes, and DefectsSelect the appropriate Control Chart
- A.
U or C Charts
- B.
P Chart
- C.
IMR Chart
- D.
Np Chart
Correct Answer
A. U or C ChartsExplanation
The correct answer is U or C Charts. U or C Charts are appropriate for attribute data, constant subgroup sizes, and defects. U Charts are used when the number of defects per unit of measure can vary, while C Charts are used when the number of defects per unit of measure remains constant. These charts are commonly used in quality control to monitor the number of defects in a process over time.Rate this question:
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- 47.
You have Attribute Data, Non-Constant Subgroup Sizes, and DefectsSelect the appropriate Control Chart
- A.
Xbar S Chart
- B.
Xbar R Chart
- C.
P chart
- D.
U Chart
Correct Answer
D. U ChartExplanation
The U Chart is the appropriate control chart in this scenario because it is used for attribute data, which means data that can be categorized into distinct categories (such as defects). The U Chart is specifically designed for non-constant subgroup sizes, which is mentioned in the question. This chart is used to monitor the number of defects per unit of measurement, making it suitable for tracking defects in this case.Rate this question:
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- 48.
You have Continuous or Variable Data and 1 SubgroupSelect the appropriate Control Chart
- A.
P Chart
- B.
IMR Chart
- C.
Xbar R Chart
- D.
U Chart
Correct Answer
B. IMR ChartExplanation
The IMR (Individuals and Moving Range) chart is the appropriate control chart for Continuous or Variable Data with 1 Subgroup. This chart is used to monitor the process variation over time by plotting individual data points and the moving range between consecutive data points. It helps to detect any shifts or trends in the process, making it suitable for continuous or variable data with a single subgroup.Rate this question:
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- 49.
You have Continuous or Variable Data and 10 SubgroupsSelect the appropriate Control Chart
- A.
P Chart
- B.
U Chart
- C.
IMR Chart
- D.
Xbar R Chart
Correct Answer
D. Xbar R ChartExplanation
The Xbar R Chart is the appropriate control chart when dealing with Continuous or Variable Data and 10 Subgroups. This chart is used to monitor the process mean and variability over time. The Xbar chart is used to track the average of each subgroup, while the R chart is used to monitor the range or dispersion within each subgroup. By plotting these values on the control chart, any variations or shifts in the process can be easily detected and corrective actions can be taken.Rate this question:
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- 50.
You have Continuous or Variable Data and 25 SubgroupsSelect the appropriate Control Chart
- A.
Xbar S Chart
- B.
Xbar R Chart
- C.
IMR Chart
- D.
P Chart
Correct Answer
A. Xbar S ChartExplanation
The Xbar S Chart is the appropriate control chart for Continuous or Variable Data with 25 Subgroups. This chart is used to monitor the process mean (Xbar) and process variation (S) over time. It is suitable when the subgroup size is constant and the data is normally distributed. The Xbar S Chart helps to detect any shifts or trends in the process mean and variation, allowing for timely corrective actions to be taken if necessary.Rate this question:
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Current Version
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Apr 12, 2024Quiz Edited by
ProProfs Editorial Team -
Dec 09, 2008Quiz Created by
Markvlanier
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