Black Belt W24 Certification Review

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1. Pearson Correlation Coefficient is a number that gives strength and direction of linear correlation

Explanation

The Pearson Correlation Coefficient is a statistical measure that quantifies the strength and direction of a linear relationship between two variables. It ranges from -1 to 1, where a positive value indicates a positive linear relationship, a negative value indicates a negative linear relationship, and a value of 0 indicates no linear relationship. Therefore, the statement that the Pearson Correlation Coefficient gives the strength and direction of linear correlation is true.

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About This Quiz
Black Belt W24 Certification Review - Quiz

This Black Belt W24 Certification Review assesses knowledge in Six Sigma methodologies, focusing on DMAIC process, error analysis, and process yield calculations.

2. The Define Stage of DMAIC is

Explanation

The Define Stage of DMAIC is linked with the Project Definition/Scoping and provides input to the Measure phase. This means that during the Define Stage, the project goals and objectives are established, the problem or opportunity is defined, and the scope of the project is determined. This stage sets the foundation for the rest of the DMAIC methodology and provides crucial information for the Measure phase, where data is collected to further analyze and understand the problem or opportunity. Therefore, the Define Stage is an essential part of the DMAIC process and is necessary for a successful project.

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3. The residuals should be analyzed when performing a DOE

Explanation

When performing a Design of Experiments (DOE), analyzing the residuals is important. Residuals are the differences between the observed values and the predicted values from the statistical model. By analyzing the residuals, one can assess the adequacy of the model and check for any patterns or trends that may indicate a violation of the assumptions. This helps in identifying any potential issues or outliers in the data, which can affect the validity of the experimental results. Therefore, it is necessary to analyze the residuals when conducting a DOE to ensure the reliability and accuracy of the findings.

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4. Correlation does not imply causation because a third variable may be "lurking" that causes both  X and Y to vary

Explanation

The statement is true because correlation alone cannot establish a cause-and-effect relationship between two variables. It is possible that there is a third variable that is influencing both X and Y, making them appear correlated. This third variable is often referred to as a "lurking" variable. Therefore, correlation does not imply causation as there may be other factors at play.

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5. When collecting data for creating a control chart, it is important to

Explanation

When creating a control chart, it is important to keep the data in its original time order. This is because control charts are used to monitor processes over time and identify any variations or trends. By keeping the data in its original time order, it allows for accurate analysis and detection of any potential issues or changes in the process. Sorting the data from high to low or low to high would disrupt the time order and may lead to incorrect interpretations of the data.

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6. The last step in Hypothesis Testing is

Explanation

The last step in Hypothesis Testing is to compare the p-value to the alpha risk and make the decision. This is because the p-value represents the probability of obtaining a test statistic as extreme as the one observed, assuming the null hypothesis is true. By comparing the p-value to the alpha risk (the predetermined level of significance), we can determine if the result is statistically significant or not. If the p-value is less than the alpha risk, we reject the null hypothesis, otherwise, we fail to reject it. Therefore, this step is crucial in drawing conclusions from the hypothesis test.

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7. In developing a SIPOC, a Black Belt is concerned with documenting a process at a high level.  The major components include

Explanation

A SIPOC (Supplier, Inputs, Process, Outputs, Customers) diagram is a tool used in Six Sigma methodology to document and understand a process at a high level. It includes the process description, which outlines the steps involved in the process. It also includes the customers, who are the recipients of the process outputs, and the inputs/outputs, which are the materials or information that flow into and out of the process. Therefore, all of the given options - process description, customers, and inputs/outputs - are major components of a SIPOC diagram.

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8. When collecting data for creating a control chart, it is important to

Explanation

When creating a control chart, it is important to keep the data in its original time order. This is because control charts are used to analyze process performance over time and identify any variations or trends. By keeping the data in its original time order, we can accurately track the sequence of events and understand how the process has changed over time. Sorting the data from high to low or low to high may disrupt the time sequence and lead to incorrect analysis. Therefore, the correct approach is to keep the data in its original time order.

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9. An assembly process is receiving incorrect pieces for assembly.  To ensure that only the correct pieces are sent, the parts tub is redesigned so that only the correct pieces (and their correct number) can fit into the tub.  This is an application of

Explanation

Also known as Mistake Proofing

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10. RDMAIC stands for

Explanation

The correct answer is "Recognize, Define, Measure, Analyze, Improve, Control." This is the correct acronym for the RDMAIC process, which is a problem-solving methodology used in Six Sigma. It involves recognizing a problem, defining the problem clearly, measuring the current process, analyzing the data to identify the root cause of the problem, improving the process based on the analysis, and implementing control measures to sustain the improvements.

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11. Which is not a step in developing a Cause and Effect Matrix?

Explanation

Calculating variation is not a step in developing a Cause and Effect Matrix. A Cause and Effect Matrix is a tool used to analyze and understand the relationship between inputs and outputs in a process. The steps involved in developing a Cause and Effect Matrix typically include listing inputs, listing outputs, correlating inputs and outputs, and prioritizing outputs. Calculating variation is not a necessary step in this process as it focuses more on analyzing the range and spread of data, rather than identifying the cause and effect relationships between inputs and outputs.

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12. The 5 S's would include which of the following

Explanation

The correct answer is "Sorting, Set in Order, Sweeping, Standardizing, Sustain." These are the 5 S's in the methodology known as 5S, which is used for workplace organization and efficiency. Sorting refers to eliminating unnecessary items, Set in Order involves arranging necessary items in a neat and logical manner, Sweeping refers to cleaning the workspace, Standardizing involves creating and following standardized procedures, and Sustain refers to maintaining the improvements made through the previous steps.

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13. The FMEA requires a Risk Priority Number (RPN) to be calculated.  The RPN is the product of which 3 rankings:

Explanation

RPN = SOD (Severity, Occurrence Probability, Detection Difficulty)

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14. A standard Z table is used to determine the area under the curve.  The area under the curve represents probability.

Explanation

A standard Z table is a tool used in statistics to determine the area under the curve of a standard normal distribution. This area represents the probability of a random variable falling within a certain range. Therefore, the statement that the area under the curve represents probability is true.

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15. A Six Sigma level of quality:

Explanation

A Six Sigma level of quality represents 3.4 defects per million opportunities. This means that out of every million opportunities, only 3.4 defects are expected to occur. This is an extremely high level of quality, indicating a very low rate of defects and a high level of customer satisfaction. It also signifies a high level of process capability, as the capability index is 1.33.

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16. A distribution is considered normally distributed if the P-value is greater than .05

Explanation

It can also be equal to .05. Anything less than .05 is not normally distributed.

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17. In a control chart, the upper and lower control limits are determined by

Explanation

The correct answer is "Process". In a control chart, the upper and lower control limits are determined by the process itself. These limits are based on the statistical analysis of the process data and help to identify whether the process is in control or out of control. The process owner, customer, and Black Belt may play a role in monitoring and analyzing the control chart, but they do not determine the control limits.

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18. If a distribution is negatively skewed, the mean will be

Explanation

Outliers pull the Mean toward it. The Median stays in the middle. Mean is pulled left in a Negatively Skewed distribution.

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19. The basic premise of Six Sigma is that sources of variation can be:

Explanation

Six Sigma is a methodology used to improve the quality and efficiency of processes by reducing variation. The sources of variation in a process can be identified by analyzing data and understanding the factors that contribute to it. Once the sources of variation are identified, they can be quantified by measuring their impact on the process performance. By understanding and quantifying the sources of variation, steps can be taken to eliminate or control them, thereby improving the process and reducing defects. Therefore, all of the options - identifying, quantifying, and eliminating or controlling sources of variation - are correct in the context of Six Sigma.

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20. You have Attribute Data, Constant Subgroup Sizes, and Defects
Select the appropriate Control Chart

Explanation

The correct answer is U or C Charts. U or C Charts are appropriate for attribute data, constant subgroup sizes, and defects. U Charts are used when the number of defects per unit of measure can vary, while C Charts are used when the number of defects per unit of measure remains constant. These charts are commonly used in quality control to monitor the number of defects in a process over time.

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21. The benefits of a process map would include:

Explanation

A process map is a visual representation of a process, which helps in communicating the process to others involved. It also aids in identifying bottlenecks, which are areas where the process slows down or gets congested. Additionally, a process map helps in identifying non-value added steps, which are activities that do not contribute to the final outcome. Therefore, all of the mentioned benefits, including communication of the process, identification of bottlenecks, and identification of non-value added steps, can be achieved through the use of a process map.

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22. Specification limits are established by

Explanation

The specification limits are established by the customer. This means that the customer determines the acceptable range of values for a particular process or product. The customer may have specific requirements or expectations that need to be met, and the specification limits help ensure that these requirements are fulfilled. By setting the limits at 6 standard deviations from the mean, the customer can ensure that the process or product meets their desired level of quality and performance.

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23. Caluclate the z-value given the following information:  u=100, r=5, and the Point of Interest or the USL equals 125

Explanation

The z-value is calculated by subtracting the mean (u) from the Point of Interest (125) and dividing it by the standard deviation (r). In this case, the z-value is (125-100)/5 = 5.0.

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24. You have Continuous or Variable Data and 25 Subgroups
Select the appropriate Control Chart

Explanation

The Xbar S Chart is the appropriate control chart for Continuous or Variable Data with 25 Subgroups. This chart is used to monitor the process mean (Xbar) and process variation (S) over time. It is suitable when the subgroup size is constant and the data is normally distributed. The Xbar S Chart helps to detect any shifts or trends in the process mean and variation, allowing for timely corrective actions to be taken if necessary.

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25. The controls established in a control plan should

Explanation

The controls established in a control plan should be in writing to ensure that they are documented and can be easily referenced. They should also be usable and accepted by the owners/users to ensure that they are practical and can be effectively implemented. Additionally, the controls should try to control all of the process' Key Process Input Variables (KPIVs) to ensure that all relevant factors are considered and managed. Therefore, all of the given options are correct and should be followed when establishing controls in a control plan.

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26. The correlation coefficient lies between -1 and +1.  If the coefficient is 0, this indicates the strongest linear correlation possible.

Explanation

The given statement is false. The correlation coefficient measures the strength and direction of the linear relationship between two variables. A correlation coefficient of 0 indicates no linear correlation between the variables, not the strongest linear correlation possible. The strongest linear correlation possible is indicated by a correlation coefficient of either +1 or -1, depending on the direction of the relationship.

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27. A quality control inspector at a power station inspected 100 metal pins.  Safety laws dictate that the variance of the pins' length must be less than 0.001 inches.  Test the hypothesis at 1% significance level.  Open worksheet QCI.mtw  Is the power station in accordance with safety laws?

Explanation

This is a 1 Variance Test

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28. The variation that results when multiple measurements of the same unit under identical conditions is classified as

Explanation

Same person, multiple times = Repeatability

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29. In regression analysis, the difference between th predicted value and the observed value is

Explanation

The correct answer is "Residual." In regression analysis, the residual is the difference between the predicted value and the observed value. It represents the error or the unexplained portion of the data. By calculating the residuals, we can assess how well the regression model fits the data. A smaller residual indicates a better fit, while a larger residual suggests a poorer fit. Therefore, the residual is an important measure in evaluating the accuracy and effectiveness of a regression model.

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30. The proper order of steps in a Six Sigma project is

Explanation

The proper order of steps in a Six Sigma project is to first determine customer requirements, as this provides the foundation for the project. Next, the measurement system needs to be validated to ensure accurate data collection. Then, a data collection plan can be developed to outline the specific methods and tools that will be used. Baseline data is then collected to establish a starting point for improvement. Finally, possible solutions can be identified and implemented to address the customer requirements and improve the process.

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31. A distribution is considered normally distributed is the P-value is less than .05

Explanation

It is normally distributed if the P-value is > or = .05

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32. You have Continuous or Variable Data and 1 Subgroup
Select the appropriate Control Chart

Explanation

The IMR (Individuals and Moving Range) chart is the appropriate control chart for Continuous or Variable Data with 1 Subgroup. This chart is used to monitor the process variation over time by plotting individual data points and the moving range between consecutive data points. It helps to detect any shifts or trends in the process, making it suitable for continuous or variable data with a single subgroup.

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33. A Process has seven critical characteristics, in a sample of 1,000 orders the number of opportunities for defects used in calculating DPMO is:

Explanation

In a process with seven critical characteristics, the number of opportunities for defects used in calculating DPMO is 7,000. DPMO stands for Defects Per Million Opportunities and is a measure of the number of defects that occur per one million opportunities for defects to occur. Since there are seven critical characteristics, each order has seven opportunities for defects. Therefore, in a sample of 1,000 orders, the total number of opportunities for defects is 1,000 multiplied by 7, which equals 7,000.

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34. You have Continuous or Variable Data and 10 Subgroups
Select the appropriate Control Chart

Explanation

The Xbar R Chart is the appropriate control chart when dealing with Continuous or Variable Data and 10 Subgroups. This chart is used to monitor the process mean and variability over time. The Xbar chart is used to track the average of each subgroup, while the R chart is used to monitor the range or dispersion within each subgroup. By plotting these values on the control chart, any variations or shifts in the process can be easily detected and corrective actions can be taken.

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35. The area under a normal curve to the right of the mean represents:

Explanation

The area under a normal curve to the right of the mean represents 50% of the total area. This means that half of the data falls to the right of the mean in a normal distribution. The other half of the data falls to the left of the mean. The total area under a normal curve is always equal to 100%, so if 50% of the area is to the right of the mean, then the remaining 50% must be to the left.

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36. If we have attribute data, then we should run a Process Capability Analysis to determine our Z-Score.

Explanation

Process Capability Analysis is used to determine the capability of a process to meet customer specifications, not to calculate the Z-Score. The Z-Score is a statistical measure used to determine how far a data point is from the mean of a distribution. Therefore, the statement is false.

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37. Select the Control Chart for Attribute Data, Defects, Non-Constant Subgroup Size

Explanation

The U chart is the correct control chart for attribute data with non-constant subgroup size. The U chart is used to monitor the number of defects per unit or opportunity, and it is suitable when the subgroup size varies. It helps to detect any shifts or trends in the process that may indicate a change in the defect rate. By plotting the number of defects per subgroup on the U chart, any unusual patterns or points outside the control limits can be identified, allowing for timely corrective actions to be taken.

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38. Select the Control Chart for Attribute Data, Defects, Constant Subgroup Size

Explanation

The C or U Chart is the correct control chart for attribute data with defects and a constant subgroup size. This chart is used to monitor the number of defects or nonconformities per unit of a process. The C Chart is used when the subgroup size is constant, while the U Chart is used when the subgroup size varies. These charts help to identify any patterns or trends in the defect rates, allowing for timely corrective actions to be taken.

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39. What are the key "Critical to Quality" areas?

Explanation

The key "Critical to Quality" areas are cost, delivery, and quality. These areas are crucial for ensuring customer satisfaction and meeting their expectations. Cost refers to the financial aspect of a product or service, ensuring that it is affordable and provides value for money. Delivery focuses on the timely and efficient delivery of the product or service to the customer. Quality refers to the overall excellence and meeting the desired standards of the product or service. By prioritizing these areas, organizations can ensure customer satisfaction and maintain a competitive edge in the market.

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40. When every item has equal probability of being selected, the sampling strategy used is called

Explanation

Simple random sampling is a sampling strategy where each item in the population has an equal probability of being selected. This means that every item has the same chance of being chosen, making it a fair and unbiased method of sampling. It is commonly used when the population is homogeneous and there is no need for any specific criteria or stratification in the sampling process.

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41. The concept of a "dashboard" is to

Explanation

A dashboard is a visual representation of important data and metrics that need to be monitored and tracked. It provides a concise overview of key performance indicators and allows users to quickly assess the status and progress of various aspects of a business or project. Therefore, the correct answer is "Show the critical metrics to monitor" as it accurately describes the purpose of a dashboard.

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42. A process that is in statistical control would be a process that would always meet customer specifications

Explanation

A process that is in statistical control means that it is stable and predictable, with only random variation present. However, this does not guarantee that the process will always meet customer specifications. Other factors such as the accuracy of the specifications themselves, the capability of the process, and any special causes of variation can still cause the process to occasionally deviate from the specifications. Therefore, the statement is false.

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43. Special Cause variation is random, expected variation

Explanation

Special Cause variation is not random or expected, but rather it is caused by specific factors that are outside the normal variation of a process. Special Cause variation is typically unpredictable and sporadic, and it can have a significant impact on the output of a process. In contrast, Common Cause variation refers to the normal, expected variation that is inherent in a process.

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44. A 95% confidence interval for the mean is from 13.8067 to 18.1933.  This means that

Explanation

The statement "There is a 95% probability that the true mean lies between 13.8067 and 18.1933" is the correct answer because a 95% confidence interval means that if the sampling process was repeated multiple times, 95% of the intervals formed would contain the true population mean. Therefore, there is a 95% probability that the true mean falls within the given interval.

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45. The SIPOC is used to

Explanation

The SIPOC (Supplier, Input, Process, Output, Customer) is a tool used to map out a process and identify its key components. By doing so, it helps to identify any gaps in the process, such as missing steps or unclear responsibilities. This allows for a better understanding of the process and helps in identifying areas of improvement. It also helps in identifying value added and non-value added steps, which helps in streamlining the process and eliminating waste. The SIPOC does not specifically address training new employees or identifying bottlenecks, although it indirectly helps in identifying bottlenecks by highlighting areas where the process may be inefficient or ineffective.

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46. The prime use of a control chart is to

Explanation

A control chart is a graphical tool used in statistical process control to monitor and analyze the variation in a process over time. It helps to distinguish between common causes of variation, which are inherent to the process and expected, and assignable causes of variation, which are unexpected and indicate a problem or special circumstance. By detecting and identifying these assignable causes, a control chart allows for timely corrective action to be taken, ultimately improving the quality and consistency of the process. Therefore, the correct answer is "Detect assignable causes of variation in the process."

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47. What best describes the document that tells the process team what to do (or try) if something deteriorates of is deteriorating?

Explanation

A reaction plan is a document that outlines the steps and actions to be taken by the process team when something deteriorates or is deteriorating. It provides guidance on how to respond to unexpected situations or issues that may arise during the process. This plan helps the team to quickly and effectively address the problem, minimize the impact, and prevent further deterioration. It ensures that the team has a clear understanding of the actions they need to take in order to resolve the issue and restore the process to its optimal state.

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48. The first step in Hypothesis Testing is

Explanation

The first step in Hypothesis Testing is to state the null and alternative hypotheses. This involves formulating a null hypothesis, which assumes that there is no significant difference or relationship between variables, and an alternative hypothesis, which suggests that there is a significant difference or relationship. By stating these hypotheses, researchers can then proceed with conducting statistical tests to either accept or reject the null hypothesis based on the evidence gathered from the data.

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49. What is the value of Z in the normal tables that has 3% of the area in the tail beyond it?

Explanation

The value of Z in the normal tables that has 3% of the area in the tail beyond it is 1.88. This means that 3% of the data falls outside of the range represented by 1.88 standard deviations from the mean.

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50. Select the Control Chart for Attribute Data, Defective Units, Constant Subgroup Size

Explanation

A P or NP Chart is the appropriate control chart for attribute data, defective units, and a constant subgroup size. The P Chart is used when the subgroup size is constant and the number of defective units is counted within each subgroup. The NP Chart is used when the subgroup size is constant and the number of defective units is counted, but the total number of units in each subgroup is also known. Both charts are used to monitor the proportion of defective units in a process over time.

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51. Assuming the average number of days an account receivable is on the books until funds are received is 25 days, with a standard deviation of 4.6 days.  Approximately how many days does it take until 10% of the accounts receivables have been paid?

Explanation

Z(10%) = -1.28
-1.28 = ( POI - 25 ) / 4.6 = 19.112 which is apprx. 19 days

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52. You have Attribute Data, Non-Constant Subgroup Sizes, and Defectives
Select the appropriate Control Chart

Explanation

The P Chart is the appropriate control chart to use when you have attribute data, non-constant subgroup sizes, and defectives. The P Chart is used to monitor the proportion of defective items in a process over time. It is particularly useful when the subgroup sizes vary and when the data is in the form of pass/fail or yes/no outcomes. The P Chart helps identify any shifts or trends in the proportion of defectives, allowing for timely corrective actions to be taken.

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53. If a distribution is positively skewed, the mean will be

Explanation

In a positively skewed distribution, the tail of the distribution is longer on the right side, meaning that there are a few extreme values pulling the mean towards the higher end. This causes the mean to be greater than the median, which is the value that divides the distribution into two equal halves. Therefore, the mean will be greater than the median in a positively skewed distribution.

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54. You have Attribute Data, Constant Subgroup Sizes, and Defectives
Select the appropriate Control Chart

Explanation

The appropriate control chart in this scenario would be the P or Np Chart. This chart is used when dealing with attribute data, which means data that is classified as either defective or non-defective. Constant subgroup sizes are also mentioned, which further supports the use of the P or Np Chart. This chart is specifically designed to monitor the proportion of defective items or the number of defects in a constant subgroup size.

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55. An Invoice Operation is investigating their error rate.  The first step should be to

Explanation

Determining the Voice of the Customer is always first.

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56. In a particular process, 500 orders were submitted, of which 50 contained errors.
Of the 50, 35 were corrected and reprocessed.  The Throughput Yield for this process step is:

Explanation

Reworks are not counted in the Throughput Yield.
They are counted on the Yield.

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57. The variation that results when different conditions are used to make the measurements is classified as

Explanation

Reproducibility refers to the consistency of results when different conditions are used to make measurements. It indicates the ability to obtain similar results when the experiment is repeated by different individuals or using different equipment or settings. This means that even with variations in conditions, the measurements should still provide consistent and reliable results. Therefore, reproducibility is the most suitable classification for the variation resulting from different conditions used in measurements.

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58. Universities and colleges have classifications of freshmen, sophomores, juniors, and seniors; these are examples of which data type:

Explanation

Anything with some sort of order to it will be Ordinal. If it is random without order, then it is Nominal data.

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59. You have Attribute Data, Non-Constant Subgroup Sizes, and Defects
Select the appropriate Control Chart

Explanation

The U Chart is the appropriate control chart in this scenario because it is used for attribute data, which means data that can be categorized into distinct categories (such as defects). The U Chart is specifically designed for non-constant subgroup sizes, which is mentioned in the question. This chart is used to monitor the number of defects per unit of measurement, making it suitable for tracking defects in this case.

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60. You will be checking 25 fuses a day for defects.  You will record the defects for 30 consecutive weeks.  Which control chart will you use?

Explanation

Attribute Data, Defects, Constant Sample Size, Counts

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61. In a process, the upper and lower control limits are determined by:

Explanation

The upper and lower control limits in a process are determined by the process itself. The process owner is responsible for setting these limits based on the desired quality standards and specifications. The customer may provide input on the acceptable limits, but ultimately it is the process owner's decision. A Black Belt, on the other hand, is a role within the Six Sigma methodology that focuses on process improvement and may assist in determining the control limits, but they are not solely responsible for it.

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62. You will be checking 40 valves a day for defects.  You will record the defects for 30 consecutive weeks.  Which control chart will you use?

Explanation

The C chart is used for monitoring the count or number of defects in a process when the sample size varies. In this case, you will be checking 40 valves a day for defects and recording the defects for 30 consecutive weeks. Since the sample size (number of valves) is constant, the C chart is the appropriate control chart to use. It will help you monitor and track the number of defects over time and detect any unusual patterns or trends in the process.

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63. When finding a confidence interval for mean u based on a sample size n

Explanation

Increasing the sample size, n, decreases the interval of the confidence interval for the mean, u. This is because as the sample size increases, the standard error of the mean decreases, resulting in a narrower interval. A larger sample size provides more information and reduces the uncertainty in estimating the population mean, leading to a more precise estimate. Therefore, increasing n decreases the interval width and increases the precision of the estimate.

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64. Select the Control Chart for Attribute Data, Defective Units, Non-Constant Subgroup Size

Explanation

The P Chart is the correct control chart for attribute data with non-constant subgroup size and defective units. The P Chart is used to monitor the proportion of defective units in a process over time. It is particularly useful when the subgroup sizes vary, as it takes into account the different sample sizes in calculating the control limits. By plotting the proportion of defective units in each subgroup on the chart, it allows for the detection of any shifts or trends in the process, helping to identify and address any potential quality issues.

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65. Manually calculate the standard deviation of the following sample set of data:
52, 20, 24, 31, 35, 42

Explanation

To calculate the standard deviation, we first need to find the mean of the data set. Adding up all the numbers and dividing by the total count, we get a mean of 34. Now, for each number in the data set, we subtract the mean and square the result. These squared differences are then added up and divided by the count of numbers. Taking the square root of this result gives us the standard deviation. In this case, the calculation results in a standard deviation of 11.8.

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66. Six Sigma objectives are to

Explanation

The correct answer is "Center the process on target and to reduce variation". Six Sigma aims to improve processes by focusing on reducing variation and bringing them closer to the target. This is achieved through the use of statistical tools and techniques to identify and eliminate sources of variation, resulting in improved quality and reduced defects. The other options, "have zero defects" and "determine what constitutes a statistically significant sample," are not the primary objectives of Six Sigma, although they may be outcomes of implementing the methodology.

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67. You inspect 100 credit applications a day.  It is either correct and you can pass it through or it is incorrect.  The control chart that you want to use is:

Explanation

The Np chart is the appropriate control chart to use in this scenario because it is used for monitoring the proportion of defective items in a sample. In this case, the credit applications can be classified as either correct or incorrect, making it suitable to track the proportion of incorrect applications over time using the Np chart. This chart helps to identify any shifts or trends in the proportion of incorrect applications, allowing for timely corrective actions to be taken.

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68. The use of main effects plots will help to do all of the following except

Explanation

Main effects plots are used to determine which factors affect the CTQ, determine which direction the CTQ moves when a factor is changed, and show the relative influence each factor has on a CTQ. However, main effects plots do not help in finding combinations or interactions of factors that explain variability in the CTQ. This is because main effects plots only display the individual effects of each factor on the CTQ, not the combined effects or interactions between factors. To find combinations or interactions, other techniques such as interaction plots or factorial experiments need to be used.

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69. The company considers a broken electric insulator nonconforming to standards.  Various numbers of insulators are randomly selected for 25 consecutive days.  The correct control chart is

Explanation

Attribute Data, Non Constant Sample Size, Defectives

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70. One of the benefits of using either the p-chart or the u-chart is that they both can be used with

Explanation

The p-chart and the u-chart are both control charts used for monitoring the proportion of nonconforming items in a process. The p-chart is used when subgroup sizes are constant, while the u-chart is used when subgroup sizes are variable. Therefore, the correct answer is "Both A & B" because both charts can be used with attribute data and unequal subgroup sizes.

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71. 150 meter reads were analyzed and the last digit was recorded.  You want to find out if the frequency of these digits occur by chance or were the meters being estimated?  The expected frequency = 15 for each digit.  There are 10 digits 0 - 9 each with Observed Frequencies.  What test would you use?

Explanation

The Chi Square Goodness of Fit Test would be the appropriate test to use in this scenario. This test is used to determine if observed frequencies differ significantly from expected frequencies. In this case, the expected frequency for each digit is 15, and the observed frequencies for each digit are recorded. By comparing the observed frequencies to the expected frequencies using the Chi Square test, we can determine if the frequency of the digits occurring is due to chance or if the meters were being estimated.

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72. In a normal distribution, what is the area under the curve between +0.8 and +1.7 standard deviation units?

Explanation

The area under the curve in a normal distribution represents the probability of an event occurring within a certain range. In this case, the question asks for the area between +0.8 and +1.7 standard deviation units. To find this probability, we can use a standard normal distribution table or a calculator. The correct answer of 0.1673 represents the probability of an event occurring within this range.

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73. A team is trying to determine if a new machine installed in the process has changed the yield.  A sample of 1966 units prior to the change contained 166 defects.  A sample of 897 after the change contained 247 defects.  With an alpha risk of .05, perform the statistical analysis and determine the power of the test.

Explanation

2 Proportions Test
Stat, Basic Statistics, 2 Proportions
Select "Summarized Data"
Events Trials
First: 166 1966
Second: 247 897
P Value = 0.000
Stat, Power and Sample Size, 2 Proportions
Sample sizes: 1966 897
Proportion 1 value: 0.084435 (determined from 1st test)
Power Values: leave blank for calculation
Proportion 2: 0.275362
Power = 1

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74. A frame is

Explanation

The correct answer is "A list of items representing the population." In statistics, a frame refers to a complete list of all the elements or items that make up a population. It is used as a reference to select a sample from the population for data collection and analysis. The frame ensures that every element in the population has an equal chance of being included in the sample, making it a representative subset of the population.

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75. The Throughput Yield for six departments processing an order in series is as follows: 
99.7%, 99.5%, 95%, 89%, 92.3%, and 94%.  The probability of no defects acress all steps (rolled throughput yield) is:

Explanation

The Throughput Yield for each department represents the percentage of defect-free units that pass through that specific department. To calculate the rolled throughput yield, we multiply the Throughput Yields of each department together. In this case, the rolled throughput yield is 0.997 * 0.995 * 0.95 * 0.89 * 0.923 * 0.94 = 0.7307, which is approximately 73%. Therefore, the probability of no defects across all steps is 73%.

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76. The operating range of factors under study describes which of the following terms

Explanation

The operating range of factors under study refers to the range or scope within which the study's conclusions or inferences can be applied. It represents the space in which the study's findings can be generalized or extended to a larger population or other similar scenarios. It helps to determine the validity and reliability of the study's results and ensures that the conclusions are not limited to a specific set of conditions or variables.

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77. Determine the correct chart for the labor hours of engineering projects using samples of thirteen every day for 25 consecutive days.

Explanation

Continuous Data, 325 Sample Points, 13 Subgroups

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78. Assuming that the average number of days an account receivable is on the books until funds are received is 25 days, with a standard deviation of 4 days.  How many days does it take until 40% of the accounts receivables have been paid?

Explanation

Z = (Point of Interest - Mean) divided by Standard Deviation
Z area = 40%, Mean = 25, Std Dev = 4
Z value for a Z probability area of 40% = -0.25 Look this up on the Z table to determine it.
-0.25 = (POI - 25) / 4
= 24

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79. A team is trying to determine if a new machine installed in the process has changed the yield.  A sample of 1966 units prior to the change contained 166 defects.  A sample of 897 after the change contained 247 defects.  Determine the hypotheses.

Explanation

This is a 2 Proportion Test

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80. If a distribution is positively skewed the median will be

Explanation

If a distribution is positively skewed, it means that the tail of the distribution is longer on the right side, indicating that there are a few extreme values that pull the mean towards the right. In this case, the median, which is the middle value of the data set, will be less than the mean. This is because the extreme values on the right side of the distribution will pull the mean towards them, making it greater than the median.

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81. Invoices are processed in 4 different regions of the country.  We want to know if there is a difference in processing speeds between any of the regions.  We know that the underlying variability of processing speeds has a standard deviation of 30 minutes.  If we want to detect a 10 minute difference, how many samples do we need to collect?  Assume you will use an alpha of .05 and a beta of 20%

Explanation

One-Way ANOVA Sample Size needed
Stat, Power and Sample Size, One-Way ANOVA
Number of Levels = 4
Sample Sizes = leave blank (this is what we are calculating)
Values of Maximum Difference between Means = 10
Power Values = .8 (1 - beta = 1 - 20% = 80% = .8)
Standard Deviation = 30

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82. The alpha risk is

Explanation

Note: Beta Risk would be B and D

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83. Determine the total area under the curve to the left of the Z-score = 0.86

Explanation

The given question is asking for the total area under the curve to the left of the Z-score = 0.86. In other words, it is asking for the cumulative probability up to the Z-score of 0.86. The correct answer is .8051, which represents the cumulative probability of 0.8051 or 80.51%. This means that approximately 80.51% of the data falls below the Z-score of 0.86.

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84. Which of the following cannot be a Null Hypothesis?

Explanation

Hypothesis must always be about the population, not a sample.

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85. Determine the sample size needed to test whether a population has changed from its current value of 56% to a target value of 54%.  Use an alpha of 5% and a beta of 20%

Explanation

This is a 1 proportion test (comparison to a target)
Stat, Power and Sample Size, 1 Proportion
Sample sizes: (leave this blank; this is what is calculated)
Alternative values of p: .56
Power values: .8
Hypothesized p: .54
Sample Size = 4863

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86. Calculate the Standard Deviation of the following population data:
50, 20, 35, 15

Explanation

The correct answer is 13.7. To calculate the standard deviation, we first need to find the mean of the data set, which is (50+20+35+15)/4 = 30. Then, we subtract the mean from each data point and square the result. The squared differences are 400, 100, 25, and 225. Next, we find the average of these squared differences, which is (400+100+25+225)/4 = 187.5. Finally, we take the square root of this average to get the standard deviation, which is √187.5 ≈ 13.7.

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87. A process produces 350 orders, of which 50 contained errors.  Of the 50, 35 were corrected and processed.  The yield for this process is

Explanation

The yield for this process can be calculated by dividing the number of correctly processed orders by the total number of orders and then multiplying by 100 to get the percentage. In this case, 35 orders were corrected and processed out of the total 350 orders. So, the yield is (35/350) * 100 = 10%. Therefore, the correct answer is 96%, which is the closest option to 10%.

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88. Assuming that the average number of days an account receivable is on the books until funds are received is 30 days with a Standard Deviation of 4 days.  How many days does it take until 40% of the Accounts Receivables have been paid?

Explanation

The question asks for the number of days it takes until 40% of the Accounts Receivables have been paid. Since the average number of days is 30, it is likely that 40% of the Accounts Receivables will be paid before or on the average number of days. Therefore, the closest option to 30 is 29, which is the correct answer.

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89. Determine the Sample Size needed to detect a mean shift of 3.2 on a process with a standard deviation of 9.  Use an Alpha of 5% and a Beta of 10%

Explanation

Stat, Power and Sample Size, 1-Sample t
Sample Size = leave blank
Differences = 3.2
Power values = .9
Standard Deviation = 9

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90. Determine the sample size needed to detect a mean shift of 3.2 on a process with a variance of 9.  Use an alpha of 5% and a beta of 10%.

Explanation

In minitab, go to Stat, Power and Sample Size, 1-Sample t
Leave "Sample size" field blank
Enter the following
3.2 in "Differences" field
.9 in the "Power Values" field (1 - beta = 1 -.1 = .9)
3 in the Standard Deviation" field (Square Root of 9 which is the variance)
Confidence Level remains = .05 under options

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