Grade 9 Algebra. (Canada)

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| By Robertmclellan03
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Robertmclellan03
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1. Developpe the follweing equation:

3(z-7+6y)

Explanation

The given equation is developed by distributing the 3 to each term inside the parentheses. This results in 3z - 21 + 18y, which is the correct answer.

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Grade 9 Algebra. (Canada) - Quiz

This quiz will test you if you really know algebra

2. Subtract the following trinomes: (2y+3zx-4)-(5zx+3-6y)  

Explanation

To subtract the trinomials (2y + 3zx - 4) and (5zx + 3 - 6y), distribute the negative sign across the terms inside the second set of parentheses. This involves changing the sign of each term within the parentheses. After that, combine like terms by grouping similar variables together and simplifying the constants. The final result is 8y - 2zx - 7.

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3. Multiply the following:

(-2jrl)(-3yuh)(-4asd)

Explanation

The given expression involves multiplying three terms: (-2jrl), (-3yuh), and (-4asd). When multiplying three negative numbers, the result is positive. Therefore, the correct answer is 24jrlyuhasd, without the negative sign.

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4. Developp the following, then simplify:

(x+10)(x+2)

Explanation

The given expression is a product of two binomials. To simplify it, we can use the distributive property. Multiplying the first terms of each binomial gives x^2. Multiplying the outer terms gives 2x, and multiplying the inner terms gives 10x. Finally, multiplying the last terms gives 20. Combining like terms, we have x^2 + 12x + 20, which is the simplified form of the expression.

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Developpe the follweing equation:3(z-7+6y)
Subtract the following trinomes: ...
Multiply the following:(-2jrl)(-3yuh)(-4asd)
Developp the following, then simplify:(x+10)(x+2)
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