Final Chemistry Quiz - 2019 Batch

Approved & Edited by ProProfs Editorial Team
The editorial team at ProProfs Quizzes consists of a select group of subject experts, trivia writers, and quiz masters who have authored over 10,000 quizzes taken by more than 100 million users. This team includes our in-house seasoned quiz moderators and subject matter experts. Our editorial experts, spread across the world, are rigorously trained using our comprehensive guidelines to ensure that you receive the highest quality quizzes.
Learn about Our Editorial Process
| By Medbatch22019
M
Medbatch22019
Community Contributor
Quizzes Created: 1 | Total Attempts: 164
Questions: 60 | Attempts: 164

SettingsSettingsSettings
Final Chemistry Quiz - 2019 Batch - Quiz



Done by your colleagues: محمد شناعة سدين سمير حسام العمري لينة العبابنة لينة الطيطي حسام اللمع عبد الله أبو اشقير رؤى حكيم ريما المومني سارة بني عامر شهد الجوارنة صهيب القادري علاء دكناش


Questions and Answers
  • 1. 

     دفعتنا العزيزة ⁦⁩ عارفين كمية الضغط الي عليكو بالامتحان وقديش الأشياء المتراكمة عليكو بس تذكرو دايما، براسكو في حلم وقدامكو في مستقبل، وجنبكو أهاليكو بدعولكو بالليل والنهار، ووراكو ناس تسندو عليهم ظهوركو وبستنو منكو ترفعو راسهم دايما بكل مكان، كل هاي الأشياء بتستاهل منكو تتعبو عشانها  ("  ما بحكيلكم الطريق سهلة، الطريق صعبة وكثير كمان، بس ما عمرها الأشياء كانت حلوة إلا بصعوبتها  .تذكرو دايما، براسنا في حلم وقدامنا في مستقبل .لا تنسو لا تنسو !موفقين

  • 2. 

    All of the following are cases that determine where H atom should be placed in unsaturated compounds EXCEPT 

    • A.

      Markovnikv’s Rule

    • B.

      Van der Waals

    • C.

      Symmetrical compounds

    • D.

      Unsymmetrical compounds

    Correct Answer
    B. Van der Waals
    Explanation
    Van der Waals forces are intermolecular forces that exist between all molecules, regardless of whether they are saturated or unsaturated compounds. These forces arise due to temporary fluctuations in electron distribution, causing temporary dipoles. Therefore, Van der Waals forces do not determine where the H atom should be placed in unsaturated compounds.

    Rate this question:

  • 3. 

    Which one of the organic compounds is less stable and more reactive?

    • A.

      Cyclohexane

    • B.

      Cyclopropane

    • C.

      Cyclobutan

    • D.

      Two answers are correct

    Correct Answer
    D. Two answers are correct
    Explanation
    Cyclopropane and cyclobutan are both less stable and more reactive compared to cyclohexane. This is because cyclopropane and cyclobutan have strained ring structures due to the presence of three and four-membered rings respectively. The strain in these small rings causes increased reactivity and makes them less stable compared to cyclohexane, which has a more stable six-membered ring structure. Therefore, both cyclopropane and cyclobutan are correct answers as they are less stable and more reactive organic compounds.

    Rate this question:

  • 4. 

    What is the correct name of the following molecule?

    • A.

      2-Bromo-5-ethyl-6-methyl-3-heptyne

    • B.

      3-iso propyl6-bromo 4-heptyne

    • C.

      2-Bromo-5-iso propyl-3-heptyne

    • D.

      2-Bromo-5-ethyl-6-methyl-3-heptene

    Correct Answer
    A. 2-Bromo-5-ethyl-6-methyl-3-heptyne
    Explanation
    The given molecule is named as 2-Bromo-5-ethyl-6-methyl-3-heptyne. This name accurately describes the structure of the molecule, indicating the positions and types of substituents on the carbon chain. The prefix "2-Bromo" indicates that there is a bromine atom attached to the second carbon atom in the chain. The prefixes "5-ethyl" and "6-methyl" indicate that there are ethyl and methyl groups attached to the fifth and sixth carbon atoms, respectively. The suffix "-yne" indicates that the molecule contains a triple bond between the third and fourth carbon atoms.

    Rate this question:

  • 5. 

    Which Alkene that give this product in the addition of HBr?

    • A.

      Option 1

    • B.

      Option 2

    • C.

      Option 3

    • D.

      Option 4

    Correct Answer
    B. Option 2
  • 6. 

    All the following Alkenes give two major products up on addition of HCL EXCEPT?  

    • A.

      Option 1

    • B.

      Option 2

    • C.

      Option 3

    • D.

      Option 4

    Correct Answer
    A. Option 1
  • 7. 

    Which of the following compounds can exist as cis-trans isomers ?

    • A.

      2-hexene

    • B.

      Cyclohexene

    • C.

      2,3-dimethyl -2-butene

    • D.

      2-methyl -2-pentene

    Correct Answer
    A. 2-hexene
    Explanation
    2-hexene can exist as cis-trans isomers because it contains a carbon-carbon double bond, which allows for rotation around the bond. In the cis isomer, the two substituents on the same side of the double bond, while in the trans isomer, the two substituents are on opposite sides of the double bond. The other compounds listed do not have a carbon-carbon double bond and therefore cannot exhibit cis-trans isomerism.

    Rate this question:

  • 8. 

    Give the IUPAC name for the following compound

    • A.

      Trans -7,8-dimethyl-6-isopropyl-3-nonene

    • B.

      Cis-7,8-dimethyl-6-isopropyl-3-nonene

    • C.

      Cis-6-isopropyl-2,3-dimethyl-6-nonene

    • D.

      Trans-6-isopropyl-7,8-dimethyl-3-nonene

    Correct Answer
    D. Trans-6-isopropyl-7,8-dimethyl-3-nonene
    Explanation
    The compound in question is a nonene, which means it has nine carbon atoms. The "trans" or "cis" prefix indicates the arrangement of substituents on the double bond. In this case, the substituents are the methyl and isopropyl groups. The "trans" prefix indicates that the substituents are on opposite sides of the double bond, while the "cis" prefix indicates that they are on the same side. The correct answer is "Trans-6-isopropyl-7,8-dimethyl-3-nonene" because it accurately describes the arrangement of the substituents on the double bond and the position of the methyl and isopropyl groups on the carbon chain.

    Rate this question:

  • 9. 

    What is the correct name for this compound?

    • A.

      1-Fluoro-3-isopropyl-5-ethylbenzene

    • B.

      1-ethyl-3-isopropyl-5-fluorobenzene

    • C.

      1-ethyl-3-fluoro-5-isopropylbenzene

    • D.

      1-isopropyl-3-fluoro-5-ethylbenzene

    Correct Answer
    C. 1-ethyl-3-fluoro-5-isopropylbenzene
    Explanation
    The correct name for the compound is 1-ethyl-3-fluoro-5-isopropylbenzene because it follows the IUPAC naming rules for organic compounds. The numbers indicate the positions of the substituents on the benzene ring, and the substituents are listed alphabetically. In this case, the ethyl group is at position 1, the fluoro group is at position 3, and the isopropyl group is at position 5.

    Rate this question:

  • 10. 

    Which of the following alcohols yields a carboxylic acid when treated with K2Cr2O7 / H2SO4

    • A.

      2-methyl-2-propanol

    • B.

      Phenol

    • C.

      2,2-dimethyl-1-propanol

    • D.

      Cyclohexanol

    Correct Answer
    C. 2,2-dimethyl-1-propanol
    Explanation
    2,2-dimethyl-1-propanol undergoes oxidation when treated with K2Cr2O7 / H2SO4 to yield a carboxylic acid. This is because the presence of the oxidizing agent (K2Cr2O7) and the acidic medium (H2SO4) promotes the oxidation of the alcohol functional group to a carboxylic acid functional group. The other options, 2-methyl-2-propanol, phenol, and cyclohexanol, do not have the necessary functional groups or conditions to undergo this oxidation reaction.

    Rate this question:

  • 11. 

    Which of the following reagents can be used to reduce aldehyde to alcohol

    • A.

       LiAlH/ H3O+

    • B.

      BH/ H2O2

    • C.

      KMnO4

    • D.

      NH2NH/ OH-

    Correct Answer
    A.  LiAlH/ H3O+
    Explanation
    LiAlH4 is a strong reducing agent that can be used to reduce aldehydes to alcohols. When LiAlH4 is added to an aldehyde, it donates a hydride ion (H-) to the carbonyl carbon, resulting in the formation of an alkoxide intermediate. This intermediate is then protonated by H3O+ to yield the corresponding alcohol. The other reagents listed, BH3/H2O2, KMnO4, and NH2NH2/OH-, do not have the ability to directly reduce aldehydes to alcohols.

    Rate this question:

  • 12. 

    A carboxylic acid is a ---------------- acid than ethanol because upon ionization ........

    • A.

      Stronger, the carboxylate ion is destabilized by resonance

    • B.

      Weaker, the carboxylate ion is stabilized by resonance

    • C.

      Stronger, the ethoxide ion is stabilized by resonance

    • D.

      Stronger, the carboxylate ion is stabilized by resonance

    Correct Answer
    D. Stronger, the carboxylate ion is stabilized by resonance
    Explanation
    A carboxylic acid is a stronger acid than ethanol because upon ionization, the carboxylate ion is stabilized by resonance.

    Rate this question:

  • 13. 

    Which compound undergoes nucleophilic addition reaction?

    • A.

      Cyclohexene

    • B.

      Chlorocyclohexane

    • C.

      Hexanal

    • D.

      Cyclohexanol

    Correct Answer
    C. Hexanal
    Explanation
    Hexanal undergoes nucleophilic addition reaction because it contains a carbonyl group (C=O), which is a strong electrophile. In nucleophilic addition reactions, a nucleophile attacks the electrophilic carbon of the carbonyl group, resulting in the addition of the nucleophile and the formation of a new bond. In the case of hexanal, the carbonyl carbon is susceptible to attack by nucleophiles, making it capable of undergoing nucleophilic addition reactions.

    Rate this question:

  • 14. 

    What is the organic product obtained from the reaction of dimethylamine with acetic acid

    • A.

      N,N-Dimethylacetamide

    • B.

      N-Dimethylformamide

    • C.

      Dimethylammonium acetate

    • D.

      Dimethylamine acetate

    Correct Answer
    A. N,N-Dimethylacetamide
    Explanation
    N,N-Dimethylacetamide is the correct answer because it is the organic product obtained from the reaction of dimethylamine with acetic acid. This is a condensation reaction where the amine group of dimethylamine reacts with the carboxylic acid group of acetic acid to form an amide bond. The resulting compound is N,N-Dimethylacetamide, which is a commonly used solvent in various chemical reactions and industrial processes.

    Rate this question:

  • 15. 

    What type of compound is formed when a primary (1°) alcohol is treated with H2CrO4

    • A.

      Carboxylic acid

    • B.

      Alkyne

    • C.

      Aldehyde

    • D.

      Ketone

    Correct Answer
    A. Carboxylic acid
    Explanation
    When a primary alcohol is treated with H2CrO4, it undergoes oxidation. H2CrO4 is a strong oxidizing agent that converts primary alcohols to carboxylic acids. Therefore, the correct answer is carboxylic acid.

    Rate this question:

  • 16. 

    - What are the product from hydrolysis of ethyl - benzoate in acidic solution

    • A.

      Acetic acid and phenol

    • B.

      Benzoic acid and methanol

    • C.

      Benzoic acid and ethanol

    • D.

      Benzoate and ethanol

    Correct Answer
    D. Benzoate and ethanol
    Explanation
    The correct answer is "Benzoate and ethanol." During hydrolysis of ethyl benzoate in acidic solution, the ester bond between ethyl benzoate is broken, resulting in the formation of benzoic acid and ethanol.

    Rate this question:

  • 17. 

    Which of the following reactions would be the most suitable to convert 2-hexanol to 2- hexanone

    • A.

      LiAlH4

    • B.

      NaBH4

    • C.

      PCC in CH2Cl2

    • D.

      H2 /Ni

    Correct Answer
    C. PCC in CH2Cl2
    Explanation
    PCC (pyridinium chlorochromate) in CH2Cl2 is the most suitable reaction to convert 2-hexanol to 2-hexanone. PCC is a mild oxidizing agent that selectively converts primary alcohols to aldehydes or ketones. In this case, 2-hexanol is a primary alcohol, and PCC will oxidize it to form 2-hexanone. CH2Cl2 is the solvent used for the reaction.

    Rate this question:

  • 18. 

    How many sterogenic carbon in this compound?

    • A.

      Zero

    • B.

      1

    • C.

      2

    • D.

      3

    Correct Answer
    A. Zero
    Explanation
    This compound does not have any stereogenic carbon because stereogenic carbons are carbon atoms that have four different groups attached to them, resulting in the possibility of having two different stereoisomers. Since this compound does not have any such carbon atoms, the answer is zero.

    Rate this question:

  • 19. 

    The angle of rotation for a compound is (+12) what is the angle of rotation for the mirror image of it?

    • A.

      +12

    • B.

      -12

    • C.

      +78

    • D.

      -78

    Correct Answer
    B. -12
    Explanation
    The angle of rotation for the mirror image of a compound is equal to the negative of the original angle of rotation. Therefore, if the angle of rotation for the compound is +12, the angle of rotation for its mirror image would be -12.

    Rate this question:

  • 20. 

    Assign a priority order to each of the following set of group -CH (CH3)2 / -OH / -CH2NH2 / -CH3 / -CCL4

    • A.

      -OH >-CH2NH2 > -CH (CH3)2> -CH3 >-CCL4

    • B.

      -OH >-CCL4> -CH (CH3)2>-CH2NH2>-CH3 

    • C.

      -CCL4>-OH >-CH2NH2 >-CH3> -CH (CH3)2

    • D.

      -OH >-CCL4>-CH3 >-CH2NH2 > -CH (CH3)2

    Correct Answer
    B. -OH >-CCL4> -CH (CH3)2>-CH2NH2>-CH3 
    Explanation
    The priority order is determined by the functional groups present in each compound. The highest priority is given to the -OH group because it is an alcohol, which is a very reactive functional group. Next in priority is -CCL4, which is a haloalkane and also reactive. -CH (CH3)2 is next because it is a tertiary alkyl group, followed by -CH2NH2, which is an amine. Lastly, -CH3 is given the lowest priority because it is a simple alkyl group.

    Rate this question:

  • 21. 

    The configuration around carbons labeled 1 and 2 respectively:

    • A.

      (R, R)

    • B.

      (S, S)

    • C.

      (R, S)

    • D.

      (S, R)

    Correct Answer
    A. (R, R)
    Explanation
    The configuration around carbons labeled 1 and 2 is (R, R) because both carbons have the same substituents in a clockwise direction. According to the Cahn-Ingold-Prelog priority rules, the higher priority groups are on the same side, resulting in an (R) configuration for both carbons.

    Rate this question:

  • 22. 

    What is the O-S-O bond angle in SO3?

    • A.

      Less than 109.5

    • B.

      109.5

    • C.

      120

    • D.

      Greater than 120

    Correct Answer
    C. 120
    Explanation
    The O-S-O bond angle in SO3 is 120 degrees. This is because SO3 has a trigonal planar molecular geometry, where the three oxygen atoms are arranged in a flat triangle around the central sulfur atom. In a trigonal planar geometry, the bond angles between the atoms are all equal and are 120 degrees.

    Rate this question:

  • 23. 

    What is the geometry around the central atom in the following molecular model of PH3?

    • A.

      Linear

    • B.

      Bent

    • C.

      Pyramidal

    • D.

      Tetrahedral

    Correct Answer
    C. Pyramidal
    Explanation
    The geometry around the central atom in the molecular model of PH3 is pyramidal. This is because phosphorus (P) has three bonded hydrogen (H) atoms and one lone pair of electrons, resulting in a trigonal pyramidal shape. The lone pair pushes the bonded atoms away from it, causing the molecule to adopt a pyramidal shape.

    Rate this question:

  • 24. 

    In the drawing of acetic acid CH3CO2H, a partial positive charge occurs on :

    • A.

      Only (a)

    • B.

      Only (b)

    • C.

      (a) and (c)

    • D.

      (b) and (d)

    Correct Answer
    D. (b) and (d)
    Explanation
    In the drawing of acetic acid CH3CO2H, a partial positive charge occurs on the carbon atom (C) and the oxygen atom (O) in the carboxyl group (COOH). The carbon atom in the carboxyl group is electron-deficient due to the presence of the highly electronegative oxygen atom, causing it to have a partial positive charge. Similarly, the oxygen atom in the carboxyl group also has a partial positive charge due to the electron-withdrawing effect of the adjacent carbon atom. Therefore, the correct answer is (b) and (d).

    Rate this question:

  • 25. 

    Which of the following pairs would you expect to form solutions?

    • A.

      CH3CH2COOCH3/CH3OH

    • B.

      CH3CH2CONH2/CH3COOH

    • C.

      C6H14/CH3OCH3

    • D.

      (A+B)

    Correct Answer
    B. CH3CH2CONH2/CH3COOH
    Explanation
    The pair CH3CH2CONH2/CH3COOH would form solutions because both compounds are polar and have the ability to form hydrogen bonds. CH3CH2CONH2 is a primary amide and CH3COOH is acetic acid, which can both participate in hydrogen bonding. This allows them to mix and dissolve in each other, forming a solution.

    Rate this question:

  • 26. 

    Molality is a relationship that connects :

    • A.

      The mass of solute with the volume of solution

    • B.

      The moles of solute with the volume of solution

    • C.

      The mass of solute with the moles of solvent

    • D.

      The moles of solute with the mass of solvent

    Correct Answer
    D. The moles of solute with the mass of solvent
    Explanation
    Molality is a relationship that connects the moles of solute with the mass of solvent. It is a concentration unit that is expressed as the number of moles of solute per kilogram of solvent. This relationship is important in determining the concentration of a solution, as it takes into account the mass of the solvent rather than its volume. By considering the mass of the solvent, molality allows for more accurate calculations and comparisons between different solutions.

    Rate this question:

  • 27. 

    Which of the following statements is correct?

    • A.

      Freezing point is lower for a solution than for a pure solvent

    • B.

      Vapor pressure is higher for a solution than for a pure solvent

    • C.

      Boiling point is lower for a solution than for a pure solvent

    • D.

      None of the above

    Correct Answer
    A. Freezing point is lower for a solution than for a pure solvent
    Explanation
    When a solute is added to a solvent to form a solution, the freezing point of the solution decreases compared to the freezing point of the pure solvent. This is because the presence of the solute disrupts the arrangement of the solvent molecules, making it more difficult for them to form a solid lattice and freeze. As a result, a lower temperature is required to freeze the solution compared to the pure solvent.

    Rate this question:

  • 28. 

    Choose the correct arrangement of the following compounds according to their basicity strength :

    • A.

      NO3->NaH>NaOH

    • B.

      NaH>NO3->NaOH

    • C.

      NaH>NaOH>NO3-

    • D.

      We can't determine

    Correct Answer
    C. NaH>NaOH>NO3-
    Explanation
    The correct arrangement of the compounds according to their basicity strength is NaH>NaOH>NO3-. This means that NaH is the strongest base, followed by NaOH, and then NO3-. This is because NaH is a strong base due to its ability to donate hydroxide ions (OH-) easily, while NaOH is a weaker base because it is a salt of a strong base and a weak acid. NO3- is the weakest base as it is the conjugate base of a strong acid (HNO3).

    Rate this question:

  • 29. 

    Which of the following is the strongest ionization

    • A.

      PO4-3

    • B.

      H3PO4

    • C.

      HPO4-2

    • D.

      H2PO4-

    Correct Answer
    B. H3PO4
    Explanation
    H3PO4 is the strongest ionization among the given options. This is because it is a triprotic acid, meaning it can donate three protons (H+) in solution. The other options, PO4-3, HPO4-2, and H2PO4-, are all conjugate bases of H3PO4 and have fewer protons to donate. Therefore, H3PO4 has the highest ionization strength.

    Rate this question:

  • 30. 

    Which of the following statement(s) is(are) correct :

    • A.

      When the Ka increases, the pKa decreases

    • B.

      When the Ka decreases, the acidity increases

    • C.

      When the pOH decreases, the basicity increases

    • D.

      A + C

    Correct Answer
    D. A + C
    Explanation
    When the Ka increases, it means that the acid dissociates more readily in water, resulting in a higher concentration of hydronium ions (H3O+). A higher concentration of hydronium ions indicates a stronger acid, which leads to a lower pKa value. Therefore, the statement "When the Ka increases, the pKa decreases" is correct. Similarly, when the pOH decreases, it means that the concentration of hydroxide ions (OH-) decreases, indicating a higher concentration of hydronium ions. This suggests a stronger base, leading to an increase in basicity. Hence, the statement "When the pOH decreases, the basicity increases" is also correct.

    Rate this question:

  • 31. 

    In the reaction of acids with nitrogen-containing compounds, the result should be :

    • A.

      Water and salt

    • B.

      Salt and CO2

    • C.

      Water and CO2

    • D.

      None of the above

    Correct Answer
    D. None of the above
    Explanation
    In the reaction of acids with nitrogen-containing compounds, the result is not water and salt, salt and CO2, or water and CO2. The reaction between acids and nitrogen-containing compounds can result in various products depending on the specific compounds involved. It could lead to the formation of ammonium salts, nitric acid, or other nitrogen-containing compounds. Therefore, none of the given options accurately describe the result of this reaction.

    Rate this question:

  • 32. 

    What is the iupac name for following compound?

    • A.

      3-chloro-5,5-dimethyl-6-oxo-1-hexene

    • B.

      4-chloro-2,2-dimethyl-5-hexenal

    • C.

      2,2-dimethyl-4-chloro-1-hexanal-5-en

    • D.

      None of the above

    Correct Answer
    B. 4-chloro-2,2-dimethyl-5-hexenal
    Explanation
    The given compound has a chlorine atom attached to the fourth carbon atom, two methyl groups attached to the second carbon atom, and an aldehyde group attached to the fifth carbon atom. Therefore, the correct IUPAC name for this compound is 4-chloro-2,2-dimethyl-5-hexenal.

    Rate this question:

  • 33. 

    Give the iupac name for this molecule?

    • A.

      3-ethyl-5-formaldehydecyclohexanon

    • B.

      3-ethyl-5-oxocyclohexanal

    • C.

      5-ethyl-3-oxobenzaldehyde

    • D.

      5-oxo-3-ethylbenzaldehyde

    Correct Answer
    C. 5-ethyl-3-oxobenzaldehyde
    Explanation
    The given molecule consists of a benzene ring with a substituent at the 5th carbon and a carbonyl group at the 3rd carbon. The substituent at the 5th carbon is an ethyl group (-CH2CH3) and the carbonyl group at the 3rd carbon is an aldehyde (-CHO). Therefore, the correct IUPAC name for this molecule is 5-ethyl-3-oxobenzaldehyde.

    Rate this question:

  • 34. 

    Arrange the following compounds in order of increasing boiling point?

    • A.

      2>1>3>6>5>4

    • B.

      4>2>1>3>6>5

    • C.

      4>2>3>1>6>5

    • D.

      4>3>2>1>5>6

    Correct Answer
    B. 4>2>1>3>6>5
    Explanation
    The boiling point of a compound is determined by its intermolecular forces. The compound with the strongest intermolecular forces will have the highest boiling point. In this case, compound 4 has the strongest intermolecular forces, followed by compound 2, compound 1, compound 3, compound 6, and finally compound 5. Therefore, the correct order of increasing boiling point is 4>2>1>3>6>5.

    Rate this question:

  • 35. 

    Arrange the following compounds in order to increasing their reactivity?

    • A.

      1>3>2>5>4

    • B.

      1>3>2>4>5

    • C.

      1>3>4>2>5

    • D.

      1>3>5>2>4

    Correct Answer
    D. 1>3>5>2>4
    Explanation
    The given answer suggests that compound 1 is the most reactive, followed by compound 3, 5, 2, and 4 in increasing order of reactivity.

    Rate this question:

  • 36. 

    A molecular compound that reacts with jone's reagent and change tje color to green, when it reacts with (KMnO4) it yields (CH3COOH), the compound is?

    • A.

      CH3COCH3

    • B.

      HCOH

    • C.

      CH2(OH)CH3

    • D.

      CH3OCH3

    Correct Answer
    C. CH2(OH)CH3
    Explanation
    The compound CH2(OH)CH3 is the correct answer because it reacts with Jones reagent and changes the color to green. Additionally, when it reacts with KMnO4, it yields CH3COOH, which is acetic acid. This indicates that the compound has a hydroxyl group (OH) and a methyl group (CH3), which matches the structure of CH2(OH)CH3, also known as 2-propanol.

    Rate this question:

  • 37. 

    Which of the following reactants is the correct to yield this compound?

    • A.

      Propanal+2(2-methylpropanol)

    • B.

      Propanal+2-methylethanol

    • C.

      Ethanal+2(2-methylpropanol)

    • D.

      Isopropyl+2 ethanal

    Correct Answer
    A. Propanal+2(2-methylpropanol)
    Explanation
    The correct answer is propanal+2(2-methylpropanol) because it provides the necessary reactants to yield the desired compound. Propanal is the aldehyde needed to form the compound, and 2(2-methylpropanol) is an alcohol that can undergo a condensation reaction with propanal to form the desired compound. The other options do not provide the correct combination of reactants.

    Rate this question:

  • 38. 

    The yield compound of the following reactions is respectively CH3COH+NH3 CH3CH2COCH3+NH2OH 

    • A.

      Imine, oxime

    • B.

      Oxime, imine

    • C.

      Option 3

    • D.

      A + C

    Correct Answer
    D. A + C
    Explanation
    The yield compound of the first reaction, CH3COH+NH3, is an imine. An imine is formed when an aldehyde or ketone reacts with an amine. In this case, the aldehyde CH3COH reacts with NH3 to form an imine.

    The yield compound of the second reaction, CH3CH2COCH3+NH2OH, is an oxime. An oxime is formed when a ketone or aldehyde reacts with hydroxylamine. In this case, the ketone CH3CH2COCH3 reacts with NH2OH to form an oxime.

    Therefore, the correct answer is "imine, oxime" (Option 3, A + C).

    Rate this question:

  • 39. 

    An unknown organic compound that reacts with jone's reagent and the color changed to green, when it react's with 2,4-dinitrohydrazine it yield an orange precipitate in test tube. This organic compound must be:

    • A.

      Option 1

    • B.

      Option 2

    • C.

      Option 3

    • D.

      Option 4

    Correct Answer
    D. Option 4
    Explanation
    The organic compound must be an aldehyde. Jones reagent is a solution of chromic acid in sulfuric acid, which is commonly used to oxidize aldehydes to carboxylic acids. The green color change indicates the presence of an aldehyde. 2,4-dinitrohydrazine is a reagent used to test for the presence of carbonyl compounds, specifically aldehydes and ketones. The formation of an orange precipitate indicates that the unknown compound is an aldehyde. Therefore, the correct answer is Option 4.

    Rate this question:

  • 40. 

    What is(are) the functional group(groups) represented in this compound:

    • A.

      Amine

    • B.

      Ether

    • C.

      Amide

    • D.

      Amine, carbonyl

    Correct Answer
    C. Amide
    Explanation
    The correct answer is amide. An amide is a functional group that consists of a carbonyl group (C=O) bonded to a nitrogen atom (N). In the given compound, there is a carbonyl group bonded to a nitrogen atom, indicating the presence of an amide functional group. The other options mentioned (amine, ether, amine carbonyl) are not applicable to the compound as they do not accurately represent the functional groups present.

    Rate this question:

  • 41. 

    What is the IUPAC name of the following compound:

    • A.

      5-sec-butyl-3-tert-butyl octane

    • B.

      3-ethyl-5-propyl-2,2,6-trimethyl octane

    • C.

      5-sec-butyl-3-ethyl-2,2-dimethyl octane

    • D.

      4-propyl-6-ethyl-3,7,7-trimethyl octane

    Correct Answer
    B. 3-ethyl-5-propyl-2,2,6-trimethyl octane
    Explanation
    The correct answer is 3-ethyl-5-propyl-2,2,6-trimethyl octane. This is because it follows the rules of IUPAC nomenclature for naming organic compounds. The compound is a substituted octane with a total of 5 substituents. The longest carbon chain is 8 carbons, hence octane. The substituents are listed in alphabetical order, with the prefixes indicating the number of carbons in each substituent (ethyl and propyl). The positions of the substituents are indicated by numbers (3 and 5). Finally, the compound has additional methyl groups at positions 2 and 6, which are indicated by the prefix "2,2,6-trimethyl".

    Rate this question:

  • 42. 

    What are the hybridization of the starred carbon and the approximate bond angle

    • A.

      Sp3, 90

    • B.

      Sp3 , 109.5

    • C.

      Sp3 , 19.5

    • D.

      Sp2 ,90

    Correct Answer
    A. Sp3, 90
    Explanation
    The hybridization of the starred carbon is sp3, which means that it has four sigma bonds and no pi bonds. The approximate bond angle is 90 degrees, indicating that the four sigma bonds are arranged in a tetrahedral shape around the carbon atom.

    Rate this question:

  • 43. 

    How many primary carbons,tertiary carbons,quaternary hydrogens respectively in the following compound

    • A.

      4,3,0

    • B.

      5,3,1

    • C.

      4,4,1

    • D.

      5,4,0

    Correct Answer
    D. 5,4,0
    Explanation
    The compound in question has 5 primary carbons because primary carbons are bonded to only one other carbon atom. It has 4 tertiary carbons because tertiary carbons are bonded to three other carbon atoms. Lastly, it has 0 quaternary hydrogens because quaternary hydrogens are bonded to a quaternary carbon, which this compound does not have.

    Rate this question:

  • 44. 

    Which of these is a property of alkanes

    • A.

      Less dense than water

    • B.

      Odorous

    • C.

      Soluble in water

    • D.

      Non of the above

    Correct Answer
    A. Less dense than water
    Explanation
    Alkanes are hydrocarbons consisting of only carbon and hydrogen atoms bonded together. They are known for being less dense than water. This is because the carbon-hydrogen bonds in alkanes are nonpolar, resulting in a relatively low intermolecular force between molecules. As a result, alkanes tend to have lower densities than water, causing them to float on top of water.

    Rate this question:

  • 45. 

    Which of the following compounds has the least melting point

    • A.

      Octane

    • B.

      2,2-dimethyl heptane

    • C.

      Ethyl cyclohexane

    • D.

      Nonane

    Correct Answer
    C. Ethyl cyclohexane
    Explanation
    Ethyl cyclohexane has the least melting point compared to the other compounds listed. This is because ethyl cyclohexane is a smaller molecule with less branching and fewer carbon atoms compared to the other compounds. Smaller molecules tend to have weaker intermolecular forces, such as London dispersion forces, which are easier to overcome, resulting in a lower melting point. The other compounds, such as octane, 2,2-dimethyl heptane, and nonane, have larger and more complex structures with more carbon atoms and more branching, leading to stronger intermolecular forces and higher melting points.

    Rate this question:

  • 46. 

    Arrange the following compounds according to stability

    • A.

      1>2>3>4

    • B.

      4>2>1>3

    • C.

      2>3>1>4

    • D.

      3>2>4>1

    Correct Answer
    C. 2>3>1>4
    Explanation
    The answer suggests that compound 2 is the most stable, followed by compound 3, compound 1, and finally compound 4. Stability of compounds is often determined by factors such as bond strength, resonance, and electron distribution. Without further information, it is difficult to provide a detailed explanation for the given order of stability.

    Rate this question:

  • 47. 

    What's the IUPAC name of this compound ?

    • A.

      -propyl-4-heptyn-1-ol

    • B.

      1-hydroxo4-propyl-4-heptyne

    • C.

      4-propyl-7-hydroxo-3-heptyne

    • D.

      4-propylalcohol-3-heptyne

    Correct Answer
    A. -propyl-4-heptyn-1-ol
    Explanation
    The IUPAC name of the given compound is -propyl-4-heptyn-1-ol. This name indicates that the compound contains a propyl group (-propyl) attached to the fourth carbon atom (4-) of a heptyne chain. It also has a hydroxyl group (-ol) attached to the first carbon atom (1-) of the heptyne chain.

    Rate this question:

  • 48. 

    What is of the best reagent for 2°& 1° Alcohols in substitution reactions?

    • A.

      AlCl3

    • B.

      SOCl2

    • C.

      HBr

    • D.

      NaOH

    Correct Answer
    A. AlCl3
    Explanation
    AlCl3 is the best reagent for 2° and 1° alcohols in substitution reactions. AlCl3 is a Lewis acid that can act as a catalyst in the formation of alkyl halides from alcohols. It can coordinate with the alcohol molecule and activate it towards nucleophilic attack by a halide ion. This reaction is known as the Friedel-Crafts reaction. AlCl3 is particularly effective for the substitution of primary and secondary alcohols because it can stabilize the developing negative charge on the oxygen atom, facilitating the departure of the leaving group.

    Rate this question:

  • 49. 

    Name the following compound according to IUPAC

    • A.

      Butyl phenol

    • B.

      2-phenol-2-butanol

    • C.

      2-hydroxobutyl benzene

    • D.

      2-phenyl-2-butanol

    Correct Answer
    D. 2-phenyl-2-butanol
    Explanation
    The compound 2-phenyl-2-butanol is named according to the IUPAC nomenclature system. It is a secondary alcohol with a phenyl group attached to the second carbon of the butanol chain. The prefix "2-phenyl" indicates the position of the phenyl group, while "2-butanol" indicates the position of the hydroxyl group. The suffix "-ol" indicates that it is an alcohol.

    Rate this question:

  • 50. 

    One of the following is a match regarding to Acidity

    • A.

      Thiols are less acidic than phenol

    • B.

      Phenol is as acidic as alcohol

    • C.

      Alcohol is the most acidic compound

    • D.

      Thiophenol is more acidic than thiol

    Correct Answer
    D. Thiophenol is more acidic than thiol
    Explanation
    Thiophenol is more acidic than thiol because the presence of the sulfur atom in thiophenol stabilizes the negative charge on the conjugate base, making it easier to donate a proton. In contrast, thiols do not have this stabilizing effect, so they are less acidic.

    Rate this question:

Quiz Review Timeline +

Our quizzes are rigorously reviewed, monitored and continuously updated by our expert board to maintain accuracy, relevance, and timeliness.

  • Current Version
  • Mar 22, 2023
    Quiz Edited by
    ProProfs Editorial Team
  • Jan 06, 2020
    Quiz Created by
    Medbatch22019
Back to Top Back to top
Advertisement
×

Wait!
Here's an interesting quiz for you.

We have other quizzes matching your interest.