Combined Gas Law Online Quiz

1. What is the name of the phase change that exists when a solid turns into a liquid?

Depositon

Melting

Sublimation

Freezing

Melting is the correct answer because it refers to the phase change that occurs when a solid substance is heated and transforms into a liquid state. This process involves the breaking of intermolecular forces within the solid, allowing the particles to move more freely and take on the shape of their container.

Explanation

Melting is the correct answer because it refers to the phase change that occurs when a solid substance is heated and transforms into a liquid state. This process involves the breaking of intermolecular forces within the solid, allowing the particles to move more freely and take on the shape of their container.

2. What type of relationship is shown between temperature and pressure?

Direct

Indirect (inverse)

Exponential

Logarithmic

The relationship between temperature and pressure is direct, meaning that as temperature increases, pressure also increases. This is because as temperature rises, the average kinetic energy of the gas molecules increases, leading to more frequent and forceful collisions with the container walls, resulting in an increase in pressure.

Explanation

The relationship between temperature and pressure is direct, meaning that as temperature increases, pressure also increases. This is because as temperature rises, the average kinetic energy of the gas molecules increases, leading to more frequent and forceful collisions with the container walls, resulting in an increase in pressure.

3. Which of the following terms is used to describe the average kinetic energy of the molecules in a sample?

Manometer

Temperature

Pressure

Volume

Temperature is the correct answer because it is the term used to describe the average kinetic energy of the molecules in a sample. Temperature is a measure of the average speed and energy of the particles in a substance. It is directly related to the kinetic energy of the molecules, with higher temperatures corresponding to higher average kinetic energies.

Explanation

Temperature is the correct answer because it is the term used to describe the average kinetic energy of the molecules in a sample. Temperature is a measure of the average speed and energy of the particles in a substance. It is directly related to the kinetic energy of the molecules, with higher temperatures corresponding to higher average kinetic energies.

4. Carbon dioxide occupies a 2.54 L container at STP. What will be the volume when the pressure is 150 KPa and 26 C?

1.89 L

42300 L

0.163 L

14.1 L

At STP (Standard Temperature and Pressure), the volume of carbon dioxide in a 2.54 L container is given. To find the volume at a different pressure and temperature, we can use the ideal gas law equation, PV = nRT. Since the amount of gas (n) and the gas constant (R) are constant, we can rearrange the equation to solve for the new volume. By plugging in the given values for pressure, temperature, and the initial volume, we can calculate the new volume, which is 1.89 L.

Explanation

At STP (Standard Temperature and Pressure), the volume of carbon dioxide in a 2.54 L container is given. To find the volume at a different pressure and temperature, we can use the ideal gas law equation, PV = nRT. Since the amount of gas (n) and the gas constant (R) are constant, we can rearrange the equation to solve for the new volume. By plugging in the given values for pressure, temperature, and the initial volume, we can calculate the new volume, which is 1.89 L.

5. If the pressure exerted on a gas is tripled, what will happen to the volume (assuming the temperature and amount of gas remains constant)?

X2

X3

X 1/2

X 1/3

When the pressure exerted on a gas is tripled, the volume of the gas will decrease by a factor of 1/3. This is because according to Boyle's Law, there is an inverse relationship between the pressure and volume of a gas when the temperature and amount of gas remain constant. As the pressure increases, the volume decreases proportionally. Therefore, if the pressure is tripled, the volume will decrease by a factor of 1/3.

Explanation

When the pressure exerted on a gas is tripled, the volume of the gas will decrease by a factor of 1/3. This is because according to Boyle's Law, there is an inverse relationship between the pressure and volume of a gas when the temperature and amount of gas remain constant. As the pressure increases, the volume decreases proportionally. Therefore, if the pressure is tripled, the volume will decrease by a factor of 1/3.

6. Which of the following is not a standard pressure measurement?

101.3 kPa

1 atm

760 mm Hg

273 K

The given options consist of different units used to measure pressure. 101.3 kPa, 1 atm, and 760 mm Hg are all standard pressure measurements commonly used in various fields. However, 273 K is not a standard pressure measurement. It is actually a standard temperature measurement in Kelvin. Pressure and temperature are two different physical properties, and therefore, 273 K cannot be considered a standard pressure measurement.

Explanation

The given options consist of different units used to measure pressure. 101.3 kPa, 1 atm, and 760 mm Hg are all standard pressure measurements commonly used in various fields. However, 273 K is not a standard pressure measurement. It is actually a standard temperature measurement in Kelvin. Pressure and temperature are two different physical properties, and therefore, 273 K cannot be considered a standard pressure measurement.

7. A balloon is inflated to a volume of 130 ml at a pressure of 690 mmHg. If the pressure is increased to 1000 mmHg, what will the new volume be?

188 ml

98.8 ml

89.7 ml

40300 ml

When the pressure of a gas increases, its volume decreases, assuming the temperature and amount of gas remain constant. This relationship is described by Boyle's Law. In this question, the initial volume of the balloon is 130 ml at a pressure of 690 mmHg. When the pressure is increased to 1000 mmHg, the new volume can be calculated using Boyle's Law equation: P1V1 = P2V2. Plugging in the values, we get (690 mmHg)(130 ml) = (1000 mmHg)(V2). Solving for V2, we find that the new volume is 89.7 ml.

Explanation

When the pressure of a gas increases, its volume decreases, assuming the temperature and amount of gas remain constant. This relationship is described by Boyle's Law. In this question, the initial volume of the balloon is 130 ml at a pressure of 690 mmHg. When the pressure is increased to 1000 mmHg, the new volume can be calculated using Boyle's Law equation: P1V1 = P2V2. Plugging in the values, we get (690 mmHg)(130 ml) = (1000 mmHg)(V2). Solving for V2, we find that the new volume is 89.7 ml.

8. The volume of a gas is increased from 150.0 mL to 350.0 mL by heating it. If the original temperature of the gas was 25.0 °C?

-146 C

10.7 C

426.85 C

150 C

To solve this problem, we can use Charles's Law, which states that the volume of a gas is directly proportional to its temperature when pressure and the number of moles of gas are constant.

The equation for Charles's Law is:

V₁/T₁ = V₂/T₂

Where: V₁ = Initial volume T₁ = Initial temperature V₂ = Final volume T₂ = Final temperature

Given: V₁ = 150.0 mL T₁ = 25.0 °C = 25.0 + 273.15 K = 298.15 K (converting Celsius to Kelvin) V₂ = 350.0 mL

We need to find T₂.

Using Charles's Law:

150.0 mL / 298.15 K = 350.0 mL / T₂

Now, let's solve for T₂:

T₂ = (350.0 mL * 298.15 K) / 150.0 mL T₂ = 700.0 K

Now, we need to convert the temperature back to Celsius:

T₂ = 700.0 K - 273.15 T₂ ≈ 426.85 °C

Explanation

To solve this problem, we can use Charles's Law, which states that the volume of a gas is directly proportional to its temperature when pressure and the number of moles of gas are constant.

The equation for Charles's Law is:

V₁/T₁ = V₂/T₂

Where: V₁ = Initial volume T₁ = Initial temperature V₂ = Final volume T₂ = Final temperature

Given: V₁ = 150.0 mL T₁ = 25.0 °C = 25.0 + 273.15 K = 298.15 K (converting Celsius to Kelvin) V₂ = 350.0 mL

We need to find T₂.

Using Charles's Law:

150.0 mL / 298.15 K = 350.0 mL / T₂

Now, let's solve for T₂:

T₂ = (350.0 mL * 298.15 K) / 150.0 mL T₂ = 700.0 K

Now, we need to convert the temperature back to Celsius:

T₂ = 700.0 K - 273.15 T₂ ≈ 426.85 °C

9. How many mm Hg is equal to 121 kPa?

1.19

16.1

636

908

121 kPa is equal to 908 mm Hg. This conversion is based on the fact that 1 kPa is equal to 7.5 mm Hg. Therefore, to convert kPa to mm Hg, you multiply the value in kPa by 7.5. In this case, 121 multiplied by 7.5 equals 908 mm Hg.

Explanation

121 kPa is equal to 908 mm Hg. This conversion is based on the fact that 1 kPa is equal to 7.5 mm Hg. Therefore, to convert kPa to mm Hg, you multiply the value in kPa by 7.5. In this case, 121 multiplied by 7.5 equals 908 mm Hg.

10. In which of the following sets of conditions would a gas most act as a real gas?

High temperature and low pressure

High temperature and high pressure

Low temperature and high pressure

Low temperature and low pressure

At low temperature and high pressure, the gas particles are closer together and have less kinetic energy. This means that the intermolecular forces between the particles become more significant, causing the gas to deviate from ideal gas behavior and behave more like a real gas. In contrast, at high temperature and low pressure, the gas particles have greater kinetic energy and are more spread out, minimizing the effect of intermolecular forces and promoting ideal gas behavior.

Explanation

At low temperature and high pressure, the gas particles are closer together and have less kinetic energy. This means that the intermolecular forces between the particles become more significant, causing the gas to deviate from ideal gas behavior and behave more like a real gas. In contrast, at high temperature and low pressure, the gas particles have greater kinetic energy and are more spread out, minimizing the effect of intermolecular forces and promoting ideal gas behavior.