Chemistry Quiz: An Amazing Quiz On Solutions.

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Solutions Quizzes & Trivia

Hey fella, this is Chemistry time! Are you a high school student? Or a Chemist? Or in college preparing for your chemistry finals? Well, since you are here, I would like to challenge you to take this quiz up and score as much right as you can!
Note: This quiz is based on Solutions in Chemistry.
Are you ready?


Questions and Answers
  • 1. 

    What does the picture of the sugar cube suspended in water tell you about where on a solid sample the solution process takes place? 

    • A.

      The solution process takes place at the bottom of a solid.

    • B.

      The solution process takes place at the surface of a solid.

    • C.

      The solution process takes place at the side of a solid.

    Correct Answer
    B. The solution process takes place at the surface of a solid.
    Explanation
    The picture of the sugar cube suspended in water shows that the sugar is dissolving and forming a solution. This indicates that the solution process is taking place at the surface of the solid, as the sugar molecules are coming into contact with the water molecules and dispersing throughout the liquid.

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  • 2. 

    The conditions that cause sugar to dissolve faster in water are  

    • A.

      Solute is molecular,solvent in kilograms, middle temperature.

    • B.

      The freezing point ,boiling-point elevation, and lower temperature.

    • C.

      In granulated form, when stirred, and at a higher temperature.

    Correct Answer
    C. In granulated form, when stirred, and at a higher temperature.
    Explanation
    Sugar dissolves faster in water when it is in granulated form because the smaller particles have a larger surface area, allowing for more contact with the water molecules. Stirring also helps to increase the rate of dissolution by promoting the movement of water molecules around the sugar particles. A higher temperature also speeds up the dissolution process as it increases the kinetic energy of the water molecules, causing them to move faster and collide more frequently with the sugar particles.

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  • 3. 

    Finely ground particles dissolve more rapidly than larger particles because finer particles expose a greater surface area to the colliding solvent molecules. 

    • A.

      Quantity of solvent

    • B.

      Sodium chloride.

    • C.

      Solvent molecules.

    Correct Answer
    C. Solvent molecules.
    Explanation
    Finely ground particles dissolve more rapidly than larger particles because finer particles expose a greater surface area to the colliding solvent molecules. This means that there are more opportunities for the solvent molecules to interact with and break down the particles, leading to faster dissolution. The quantity of solvent and the presence of sodium chloride do not directly affect the rate of dissolution in this context.

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  • 4. 

    Three factors that influence the rate at which a solute dissolves in a solvent are

    • A.

      Agitation (stirring or shaking), temperature, particle size.

    • B.

      Solute is molecular,solvent in kilograms, middle temperature.

    • C.

      In granulated form, when stirred, and at a higher temperature.

    Correct Answer
    A. Agitation (stirring or shaking), temperature, particle size.
    Explanation
    The rate at which a solute dissolves in a solvent is influenced by three factors: agitation (stirring or shaking), temperature, and particle size. Agitation helps in increasing the contact between the solute and solvent, promoting faster dissolution. Higher temperatures also enhance the rate of dissolution as they increase the kinetic energy of the molecules, leading to more collisions and faster mixing. Particle size plays a role as smaller particles have a larger surface area, allowing for more contact with the solvent and faster dissolution.

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  • 5. 

    Finely ground particles dissolve more rapidly than larger particles because finer particles expose a greater surface area to the ___________________.

    • A.

      Non colliding solvent molecules.

    • B.

      colliding solvent molecules.

    • C.

      Semi- colliding solvent molecules.

    Correct Answer
    B. colliding solvent molecules.
    Explanation
    Finely ground particles dissolve more rapidly than larger particles because finer particles expose a greater surface area to the colliding solvent molecules. When particles are finely ground, they have a larger surface area compared to larger particles. This increased surface area allows for more contact between the particles and the solvent molecules. As a result, there are more collisions between the solvent molecules and the finely ground particles, leading to a faster dissolution process.

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  • 6. 

      The amount of a substance that dissolves in a given quantity of solvent at a constant temperature is called the substance’s ______________________ . 

    • A.

      Solubility

    • B.

      Dissolved

    • C.

      Saturated

    Correct Answer
    A. Solubility
    Explanation
    Solubility refers to the amount of a substance that can dissolve in a given quantity of solvent at a constant temperature. It is a measure of how well a substance can dissolve in a solvent. Solubility is influenced by factors such as temperature and pressure, and it can vary for different substances.

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  • 7. 

    If a solution contains the maximum amount of solute for a given quantity of solvent at a constant temperature, it is called a(n) ______________________ solution. 

    • A.

      Solubility

    • B.

      Dissolved

    • C.

      Saturated

    Correct Answer
    C. Saturated
    Explanation
    A saturated solution is formed when the maximum amount of solute is dissolved in a given quantity of solvent at a constant temperature. In this solution, no more solute can be dissolved as the solution is already at its maximum capacity.

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  • 8. 

    The total amount of dissolved solute remains constant.  The total mass of undissolved crystals remains constant.  When the rate of solvation equals the rate of crystallization, a state of dynamic equilibrium exists. 

    • A.

      Those sentences are true about a vapor pressure equilibrium

    • B.

      Those sentences are true about a given quantity of solvent .

    • C.

      Those sentences are true about a saturated solution.

    Correct Answer
    C. Those sentences are true about a saturated solution.
    Explanation
    The given correct answer is that those sentences are true about a saturated solution. This is because in a saturated solution, the total amount of dissolved solute remains constant, indicating that no more solute can be dissolved. Additionally, the total mass of undissolved crystals also remains constant, as there is a balance between the rate of solvation (dissolving) and the rate of crystallization (precipitation). This state of dynamic equilibrium is characteristic of a saturated solution where the solute is at its maximum concentration.

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  • 9. 

    If two liquids dissolve each other, they are said to be ______________________ . 

    • A.

      Miscible

    • B.

      Immiscible

    • C.

      Decreased

    Correct Answer
    A. Miscible
    Explanation
    If two liquids dissolve each other, they are said to be miscible. This means that the two liquids are able to mix together completely to form a homogeneous solution. They have the ability to dissolve in each other and form a single phase. This is in contrast to immiscible liquids, which are unable to mix together and form separate layers or phases.

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  • 10. 

    Vinegar is water-based, and oil and water are ________________. The less dense oil floats on the water-based solution. 

    • A.

      Immiscible

    • B.

      Miscible

    • C.

      Decreased

    Correct Answer
    A. Immiscible
    Explanation
    Vinegar is water-based, and oil and water are immiscible. This means that oil and water do not mix or dissolve in each other. Due to their different densities, oil floats on top of water. Therefore, the less dense oil floats on the water-based solution.

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  • 11. 

    The solubility of sodium chloride in water _________________ to 39.2 g per 100 g of water at 100 °C from 36.2 g per 100 g of water at 25 °C. 

    • A.

      Stays the same

    • B.

      Decreases

    • C.

      Increases

    Correct Answer
    C. Increases
    Explanation
    The solubility of sodium chloride in water increases from 36.2 g per 100 g of water at 25 °C to 39.2 g per 100 g of water at 100 °C. This means that at higher temperatures, more sodium chloride can dissolve in water.

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  • 12. 

    How does the solubility of solid substances change as the temperature of the solvent increases? 

    • A.

      The solubility increases for all solids.

    • B.

      The solubility increases for most solids.

    • C.

      The solubility remains constant.

    Correct Answer
    B. The solubility increases for most solids.
    Explanation
    As the temperature of the solvent increases, the kinetic energy of the solvent molecules also increases. This leads to an increase in the rate of collisions between the solvent and solute particles, causing more solute particles to dissolve. However, there are some solids that do not follow this trend and have a decrease in solubility with increasing temperature. Therefore, it can be concluded that the solubility increases for most solids as the temperature of the solvent increases.

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  • 13. 

    _________ is the solid substance that is nearly insoluble at any temperature? 

    • A.

      Barium sulfate

    • B.

      Sodium sulfate

    • C.

      Lithium sulfate

    Correct Answer
    A. Barium sulfate
    Explanation
    Barium sulfate is the solid substance that is nearly insoluble at any temperature. This means that it does not dissolve easily in water or other solvents. This property makes it useful in various applications, such as in medical imaging tests like barium swallow and barium enema. Barium sulfate is also used in the production of pigments, paper coatings, and plastics.

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  • 14. 

    How does the solubility of a gas change with an increase in temperature? 

    • A.

      As the temperature increases, the solubility of a gas remains the same.

    • B.

      As the temperature increases, the solubility of a gas increases.

    • C.

      As the temperature increases, the solubility of a gas decreases.

    Correct Answer
    C. As the temperature increases, the solubility of a gas decreases.
    Explanation
    As the temperature increases, the solubility of a gas decreases. This is because an increase in temperature provides more energy to the gas molecules, causing them to move faster and escape from the liquid phase more easily. As a result, the gas becomes less soluble in the liquid.

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  • 15. 

    The directly proportional relationship between the solubility of a gas in a liquid and the pressure of the gas above the liquid is known as  ___________________________.

    • A.

      Howard's Law

    • B.

      Henry's Law

    • C.

      Harvard's Law

    Correct Answer
    B. Henry's Law
    Explanation
    Henry's Law states that the solubility of a gas in a liquid is directly proportional to the pressure of the gas above the liquid. This means that as the pressure of the gas increases, the solubility of the gas in the liquid also increases. Conversely, as the pressure decreases, the solubility decreases. This law is important in understanding gas solubility in various liquids, such as in the carbonation of beverages or the dissolution of gases in the bloodstream.

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  • 16. 

    In the closed bottle, the pressure is high and lots of CO2 is dissolved in the carbonated beverage. Once the cap is removed, the___________________, allowing more CO2 in the carbonated beverage to escape.  

    • A.

      Vapor pressure stays the same

    • B.

      Vapor pressure decreases

    • C.

      Vapor pressure increases

    Correct Answer
    B. Vapor pressure decreases
    Explanation
    When the cap is removed from the closed bottle, the pressure inside the bottle decreases. As a result, the vapor pressure of the carbon dioxide (CO2) in the carbonated beverage also decreases. This decrease in vapor pressure allows more CO2 to escape from the beverage, causing it to become less carbonated.

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  • 17. 

    The greater the pressure and _____________and the lesser the pressure and ______________.

    • A.

      Less solubility, greater solubility

    • B.

      greater solubility , less solubility

    • C.

      Stable solubility , unstable solubility

    Correct Answer
    B. greater solubility , less solubility
  • 18. 

    How does a solution become supersaturated? 

    • A.

      When the temperature of a solution with a small excess of solid solute is raised, the solute does not dissolve. If the solution is then allowed to slowly cool, the excess solute may stay dissolved at a temperature above the temperature at which it would ordinarily crystallize.

    • B.

      When the temperature of a solution with a small excess of solid solute is raised, the solute does not dissolve. If the solution is then allowed to slowly cool, the excess solute may stay dissolved at a temperature below the temperature at which it would ordinarily crystallize.

    • C.

      When the temperature of a solution with a small excess of solid solute is raised, the solute dissolves. If the solution is then allowed to slowly cool, the excess solute may stay dissolved at a temperature below the temperature at which it would ordinarily crystallize.

    Correct Answer
    C. When the temperature of a solution with a small excess of solid solute is raised, the solute dissolves. If the solution is then allowed to slowly cool, the excess solute may stay dissolved at a temperature below the temperature at which it would ordinarily crystallize.
    Explanation
    When a solution with a small excess of solid solute is heated, the solute dissolves. However, when the solution is slowly cooled, the excess solute may remain dissolved even at a temperature lower than its normal crystallization temperature. This results in a supersaturated solution, where the concentration of the solute is higher than its normal saturation point.

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  • 19. 

    A measure of the amount of solute dissolved in a given quantity of solvent is the ______________________ of a solution. 

    • A.

      Miscible

    • B.

      Supersaturated

    • C.

      Concentration

    Correct Answer
    C. Concentration
    Explanation
    The correct answer is "concentration". Concentration refers to the measure of the amount of solute dissolved in a given quantity of solvent. It is a way to express the relative amount of solute in a solution and can be measured in various units such as moles, grams, or percent.

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  • 20. 

    The most important unit of concentration in chemistry is ______________________ . 

    • A.

      Solubility

    • B.

      Molarity

    • C.

      Solidify

    Correct Answer
    B. Molarity
    Explanation
    Molarity is the most important unit of concentration in chemistry. It represents the number of moles of solute dissolved in one liter of solution. It is widely used in chemical calculations, reactions, and experiments. Molarity allows for accurate and precise measurements of the concentration of a solution, making it a crucial concept in the field of chemistry.

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  • 21. 

     Molarity is the number of ________ of solute dissolved in one liter of solution. 

    • A.

      Meters

    • B.

      Ounces

    • C.

      Moles

    Correct Answer
    C. Moles
    Explanation
    Molarity is a unit of concentration that represents the number of moles of solute dissolved in one liter of solution. It is a measure of the amount of solute present in a given volume of solution and is commonly used in chemistry to quantify the concentration of a solution. Therefore, the correct answer is "moles".

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  • 22. 

    The best procedure for making a 0.50-molar (0.50M) solution in a 1.0-L volumetric flask is  

    • A.

      Add distilled water exactly to the 1.0-L mark, add 0.50 mol of solute, and then agitate to dissolve the solute.

    • B.

      Place 0.50 mol of solute in the flask, add distilled water to the 1.0-L mark, and then agitate to dissolve the solute.

    • C.

      Fill the flask with distilled water until it is about half full, add 0.50 mol of solute, agitate to dissolve the solute, and then carefully fill the flask with distilled water to the 1.0-L mark.

    Correct Answer
    C. Fill the flask with distilled water until it is about half full, add 0.50 mol of solute, agitate to dissolve the solute, and then carefully fill the flask with distilled water to the 1.0-L mark.
    Explanation
    The correct answer is to fill the flask with distilled water until it is about half full, add 0.50 mol of solute, agitate to dissolve the solute, and then carefully fill the flask with distilled water to the 1.0-L mark. This procedure ensures that the correct amount of solute is added to achieve a 0.50M concentration in the 1.0-L volumetric flask. By filling the flask halfway with water first, it allows for proper mixing and dissolution of the solute before adding more water to reach the desired volume. Agitating the solution helps to speed up the dissolution process and ensure that the solute is evenly distributed throughout the solution. Carefully filling the flask to the 1.0-L mark ensures that the final volume is accurate.

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  • 23. 

    List the information needed to find the molarity of a 2.0-L solution containing 0.50 mol of sodium chloride.     Known __________ of solution __________of sodium chloride  ___________________________ molarity (M) ___________________                      liters of solution     

    • A.

      (known)1.0 liters, 0.20 mol, ( molarity) moles of solvent

    • B.

      (known)2.0 liters, 0.50 mol, ( molarity) moles of solute

    • C.

      (known)4.0 liters, 1.00 mol, ( molarity) moles of solultion

    Correct Answer
    B. (known)2.0 liters, 0.50 mol, ( molarity) moles of solute
    Explanation
    The molarity of a solution is determined by dividing the moles of solute by the liters of solution. In this case, the known information is that the solution has a volume of 2.0 liters and contains 0.50 moles of sodium chloride. Therefore, the molarity can be calculated by dividing 0.50 moles by 2.0 liters, resulting in a molarity of 0.25 M.

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  • 24. 

    How do you make a solution less concentrated? 

    • A.

      Dilute it with ice.

    • B.

      Dilute it with gas.

    • C.

      Dilute it with solvent.

    Correct Answer
    C. Dilute it with solvent.
    Explanation
    To make a solution less concentrated, it needs to be diluted with a solvent. Diluting with ice or gas would not effectively reduce the concentration of the solution. Ice is a solid and gas is a different state of matter, so adding either of them would not dilute the solution. A solvent, on the other hand, is a liquid that can effectively dilute the solution by adding more of it to decrease the concentration of the solute.

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  • 25. 

    What happens to the number of moles of solute present in the solution when the volume doubles? 

    • A.

      The number of moles of solute remains decreases .

    • B.

      The number of moles of solute increases.

    • C.

      The number of moles of solute remains constant.

    Correct Answer
    C. The number of moles of solute remains constant.
    Explanation
    When the volume of the solution doubles, the number of moles of solute remains constant. This is because the number of moles of solute is a measure of the amount of solute particles present in the solution, and doubling the volume does not change the number of solute particles. The concentration of the solution may change, but the actual number of moles of solute remains the same.

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  • 26. 

    The correct description of the change in molarity of a solution when the volume doubles is

    • A.

      The molarity of the solution is cut in half.

    • B.

      The molarity of the solution doubles.

    • C.

      The molarity of the solution remains constant.

    Correct Answer
    A. The molarity of the solution is cut in half.
    Explanation
    When the volume of a solution doubles, the amount of solute in the solution remains the same. Since molarity is defined as the amount of solute divided by the volume of the solution, when the volume doubles, the molarity is halved. Therefore, the correct description of the change in molarity of the solution when the volume doubles is "The molarity of the solution is cut in half."

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  • 27. 

    List the information you need to find how many milliliters of a stock solution of 2.00M MgSO4 you would need to prepare 100.0 mL of 1.00M MgSO4. Known Unknown M1 ___________________________ V1 ? mL of 2.00M MgSO4 M2 ___________________________ V2 ___________________________ M1  ____________ ____________  

    • A.

      . Known Unknown M1  __________2.00M_________________ V1  ? mL of 2.00M MgSO4 M2  __________1.00M_________________ V2  ______100.0 mL_____________________ M1  __V1__________  _____M2 x V2_______

    • B.

      Known Unknown M1  ______3.00M_____________________ V1  ? mL of 2.00M MgSO4 M2  ______1.00M_____________________ V2  _____100.0mL______________________ M1  ____V2________  ____M4 x V4________

    • C.

      Known Unknown M1  ______3.00M_____________________ V1  ? mL of 3.00M MgSO4 M2  ______3.00M_____________________ V2  __________3.00mL_________________ M1  ____V2________  ___M5 x V5_________

    Correct Answer
    A. . Known Unknown M1  __________2.00M_________________ V1  ? mL of 2.00M MgSO4 M2  __________1.00M_________________ V2  ______100.0 mL_____________________ M1  __V1__________  _____M2 x V2_______
    Explanation
    To find the number of milliliters of a stock solution of 2.00M MgSO4 needed to prepare 100.0 mL of 1.00M MgSO4, we can use the formula M1V1 = M2V2, where M1 is the molarity of the stock solution, V1 is the volume of the stock solution needed, M2 is the desired molarity, and V2 is the desired volume. Plugging in the given values, we have (2.00M)(V1) = (1.00M)(100.0 mL). Solving for V1, we get V1 = (1.00M)(100.0 mL) / (2.00M) = 50.0 mL. Therefore, we would need 50.0 mL of the stock solution.

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  • 28. 

    List the information needed to find the percent by volume of ethanol in a solution when 50 mL of pure ethanol is diluted with water to a volume of 250 mL. Known Unknown Volume of ethanol __________ % ethanol by volume ? % Volume of solution __________ % (v/v) _____________________________

    • A.

      Known Unknown Volume of ethanol  _70mL_________ % ethanol by volume  ? % Volume of solution  __750mL ___volume of solute  volume of solution x__100%___% (v/v) 

    • B.

      Known Unknown Volume of ethanol  _60mL_________ % ethanol by volume  ? % Volume of solution  __250mL ___volume of solute  volume of solution x__500%___% (v/v) 

    • C.

      Known Unknown Volume of ethanol  _50mL_________ % ethanol by volume  ? % Volume of solution  __250mL ___volume of solute  volume of solution x__100%___% (v/v) 

    Correct Answer
    C. Known Unknown Volume of ethanol  _50mL_________ % ethanol by volume  ? % Volume of solution  __250mL ___volume of solute  volume of solution x__100%___% (v/v) 
    Explanation
    In order to find the percent by volume of ethanol in a solution, we need to know the volume of ethanol and the volume of the solution. By dividing the volume of ethanol by the volume of the solution and multiplying by 100%, we can calculate the percent by volume of ethanol in the solution. In this case, the volume of ethanol is given as 50 mL and the volume of the solution is given as 250 mL. Therefore, the percent by volume of ethanol in the solution is calculated as (50 mL / 250 mL) x 100% = 20%.

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  • 29. 

    Properties of a solution that depend only on the number of particles dissolved, but not the identity of solute particles in the solution are called 

    • A.

      Kinetic energy

    • B.

      Vapor pressure

    • C.

      Colligative properties

    Correct Answer
    C. Colligative properties
    Explanation
    Colligative properties are properties of a solution that depend only on the number of particles dissolved, but not on the identity of the solute particles. These properties include vapor pressure lowering, boiling point elevation, freezing point depression, and osmotic pressure. The concept behind colligative properties is that the more solute particles present in a solution, the greater the effect on these properties. Therefore, the identity of the solute particles does not matter, only the number of particles dissolved.

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  • 30. 

    A ____________ substance is one that does not vaporize easily. 

    • A.

      nonvolatile

    • B.

      volatile

    • C.

      Stable

    Correct Answer
    A. nonvolatile
    Explanation
    A nonvolatile substance is one that does not easily turn into a vapor or gas. This means that it has a high boiling point and remains in its solid or liquid state at normal temperatures. Nonvolatile substances are often used in industries where stability and long-lasting properties are required, such as in the manufacturing of plastics or certain chemicals. They do not easily evaporate or escape into the air, making them useful for applications where retention and durability are important.

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  • 31. 

    The _______________is disturbed as solvent particles form shells around solute particles.

    • A.

      Colligative

    • B.

      equilibrium

    • C.

      Solutes

    Correct Answer
    B. equilibrium
    Explanation
    When solvent particles form shells around solute particles, it indicates that the solute particles are evenly dispersed throughout the solvent. This is known as equilibrium, where the rate of dissolution of solute particles is equal to the rate of precipitation. The term "colligative" refers to properties that depend on the number of solute particles present, rather than the specific type of solute. Therefore, "equilibrium" is the correct answer as it accurately describes the state of the solvent and solute particles.

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  • 32. 

    Equilibrium is eventually re-established at a ____________________. 

    • A.

      Lower vapor pressure.

    • B.

      Higher vapor pressure

    • C.

      Same vapor pressure

    Correct Answer
    A. Lower vapor pressure.
    Explanation
    When equilibrium is eventually re-established at a lower vapor pressure, it means that the system has reached a point where the rate of condensation of the liquid phase equals the rate of evaporation of the vapor phase. This occurs when the pressure exerted by the vapor above the liquid is reduced, leading to a decrease in the number of vapor molecules escaping into the gas phase. As a result, the system adjusts to a lower vapor pressure to achieve equilibrium.

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  • 33. 

    The decrease in vapor pressure is proportional to the number of particles the solute makes in_____________.  

    • A.

      Solution

    • B.

      Solvent

    • C.

      Gas

    Correct Answer
    A. Solution
    Explanation
    The decrease in vapor pressure is proportional to the number of particles the solute makes in the solution. This is because when a solute is added to a solvent to form a solution, the solute particles occupy some of the space between the solvent particles. This reduces the number of solvent particles available to escape into the gas phase, resulting in a lower vapor pressure. Therefore, the decrease in vapor pressure is directly related to the number of particles the solute makes in the solution.

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  • 34. 

    Solutes with more particles per formula unit produce a larger __________ in vapor pressure. 

    • A.

      Increase

    • B.

      Decrease

    • C.

      Stay the same

    Correct Answer
    B. Decrease
    Explanation
    Solutes with more particles per formula unit produce a larger decrease in vapor pressure. This is because when solute particles are added to a solvent, they occupy some of the space on the surface of the solvent, reducing the number of solvent particles that can escape into the vapor phase. As a result, the vapor pressure of the solution decreases compared to the pure solvent. The decrease in vapor pressure is greater when there are more solute particles present, as they further restrict the escape of solvent particles.

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  • 35. 

    a.The boiling point is the temperature at which the vapor pressure equals atmospheric pressure. b. Adding a nonvolatile solute decreases the vapor pressure. c. Because of the decrease in vapor pressure, additional kinetic energy must be added to raise the vapor pressure of the liquid phase to atmospheric pressure. d. The boiling point of the solution is higher than the boiling point of the pure solvent. 

    • A.

      The boiling point of a solution formed by a liquid solvent and a nonvolatile solute.

    • B.

      The boiling point of a solution formed by a solid solvent and a nonvolatile solute.

    • C.

      The boiling point of a solution formed by a gas solvent and a nonvolatile solute.

    Correct Answer
    A. The boiling point of a solution formed by a liquid solvent and a nonvolatile solute.
    Explanation
    Adding a nonvolatile solute to a liquid solvent decreases the vapor pressure of the solution. This is because the nonvolatile solute molecules occupy space in the solution, reducing the number of solvent molecules available to escape into the gas phase. As a result, additional kinetic energy must be added to the solution to raise its vapor pressure to equal atmospheric pressure, leading to a higher boiling point compared to the pure solvent.

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  • 36. 

    The difference between the boiling point of a solution and that of the pure solvent is called the _________________________________________________________ . 

    • A.

      Boiling-point elevation

    • B.

      Boiling-point no elevation

    • C.

      Boiling-point some elevation

    Correct Answer
    A. Boiling-point elevation
    Explanation
    The difference between the boiling point of a solution and that of the pure solvent is called boiling-point elevation.

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  • 37. 

    a.The presence of a solute in water disrupts the formation of orderly patterns as the solution is cooled to the freezing point of pure water. b. More kinetic energy must be withdrawn from a solution than from a pure solvent in order for the solution to solidify. c. The freezing point of the solution is lower than the freezing point of the pure solvent. 

    • A.

      The gas point of a solution formed by a liquid solvent and nonvolatile solute are above

    • B.

      The boiling point of a solution formed by a liquid solvent and nonvolatile solute are above

    • C.

      The freezing point of a solution formed by a liquid solvent and nonvolatile solute are above

    Correct Answer
    C. The freezing point of a solution formed by a liquid solvent and nonvolatile solute are above
    Explanation
    The correct answer is c. The freezing point of the solution is lower than the freezing point of the pure solvent. This is because the presence of a solute in water disrupts the formation of orderly patterns as the solution is cooled to the freezing point of pure water. The solute particles interfere with the formation of the solid lattice structure, causing the freezing point of the solution to be lower than that of the pure solvent.

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  • 38. 

    One mole of which substance, glucose or sodium chloride, will produce more freezing-point depression when added to equal amounts of water? Why? 

    • A.

      Sodium sulfate because it produces twice as many particles per formula unit in solution than glucose.

    • B.

      Sodium chloride because it produces twice as many particles per formula unit in solution than glucose.

    • C.

      Sodium hydrate because it produces twice as many particles per formula unit in solution than glucose.

    Correct Answer
    B. Sodium chloride because it produces twice as many particles per formula unit in solution than glucose.
    Explanation
    Sodium chloride produces twice as many particles per formula unit in solution compared to glucose. When a solute dissolves in a solvent, it dissociates into particles. These particles contribute to the freezing-point depression, as they disrupt the formation of the solvent's crystal lattice. Since sodium chloride dissociates into two ions (Na+ and Cl-) per formula unit, it produces more particles than glucose, which does not dissociate. Therefore, sodium chloride will result in a greater freezing-point depression when added to water compared to glucose.

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  • 39. 

    For a solution, the ratio of moles of solute to mass of solvent in kilograms, represented by lower-case “m,” is the solution’s ______________________ .  

    • A.

      Molality

    • B.

      Meter

    • C.

      Mass

    Correct Answer
    A. Molality
    Explanation
    The correct answer is molality. Molality is a unit of concentration that represents the ratio of moles of solute to mass of solvent in kilograms. It is different from molarity, which represents the ratio of moles of solute to volume of solution in liters. Therefore, molality is the appropriate term to describe the given ratio in the question.

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  • 40. 

    Molarity and molality are ___________ the same for a solution. 

    • A.

      Sometimes

    • B.

      Never

    • C.

      Always

    Correct Answer
    B. Never
    Explanation
    Molarity and molality are never the same for a solution. Molarity is a measure of the concentration of a solute in a solution, expressed as the number of moles of solute per liter of solution. Molality, on the other hand, is a measure of the concentration of a solute in a solution, expressed as the number of moles of solute per kilogram of solvent. Since molarity is based on the volume of the solution, while molality is based on the mass of the solvent, they are not equivalent and can have different values for the same solution.

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  • 41. 

    What is the molality of a solution prepared by adding 1.0 mol of sodium chloride to 2.0 kg of water? _____________________ 

    • A.

      50.m

    • B.

      0.50m

    • C.

      5.0m

    Correct Answer
    B. 0.50m
    Explanation
    The molality of a solution is defined as the number of moles of solute per kilogram of solvent. In this case, the solute is 1.0 mol of sodium chloride and the solvent is 2.0 kg of water. To calculate the molality, we divide the number of moles of solute by the mass of the solvent in kilograms. Therefore, the molality of the solution is 1.0 mol/2.0 kg = 0.50m.

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  • 42. 

    Assuming a solute is molecular and not ionic, the magnitude of the boiling-point elevation of the solution, ΔTb, is directly proportional to  

    • A.

      The molal concentration of the solvent (m)

    • B.

      The molal concentration of the solution (m)

    • C.

      The molal concentration of the solute (m)

    Correct Answer
    C. The molal concentration of the solute (m)
    Explanation
    The boiling-point elevation of a solution is directly proportional to the molal concentration of the solute. This means that as the concentration of the solute increases, the boiling point of the solution will also increase. This is because the presence of the solute particles disrupts the normal boiling process of the solvent, requiring a higher temperature to reach the boiling point. Therefore, the greater the concentration of the solute, the greater the boiling-point elevation of the solution. The molal concentration of the solvent and the solution do not have a direct relationship with the boiling-point elevation.

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  • 43. 

    Look at Table 18.2 on page 523. What is the molal boiling-point elevation constant, Kb, for water?  

    • A.

      0.512 °C/m

    • B.

      0.712 °C/m

    • C.

      0.521 °C/m

    Correct Answer
    A. 0.512 °C/m
    Explanation
    The molal boiling-point elevation constant, Kb, for water is 0.512 °C/m.

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  • 44. 

    You need to find the freezing point of a 1.50m aqueous NaCl solution. You calculate ΔTf to be 1.86 °C/m  3.00m or 5.86 °C. What is the temperature at which the solution freezes? 

    • A.

      6.85 °C

    • B.

      5.68 °C

    • C.

      5.86 °C

    Correct Answer
    C. 5.86 °C
    Explanation
    The freezing point of a solution is lowered by the presence of solute particles. The equation for calculating the change in freezing point (ΔTf) is ΔTf = Kf * m, where Kf is the molal freezing point depression constant and m is the molality of the solution. In this case, ΔTf is calculated to be 5.86 °C using the given values of Kf and m. Therefore, the temperature at which the solution freezes is 5.86 °C.

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  • 45. 

    Explain how you could use freezing-point depression to compute an unknown molar mass of a compound. 

    • A.

      A known mass of the compound sometimes be dissolved in a known mass of solvent with a known Kf value. Carefully measure the change in freezing point. From this data, the molar mass can be computed.

    • B.

      A known mass of the compound couldn't be dissolved in a known mass of solvent with a known Kf value. Carefully measure the change in freezing point. From this data, the molar mass can be computed.

    • C.

      A known mass of the compound could be dissolved in a known mass of solvent with a known Kf value. Carefully measure the change in freezing point. From this data, the molar mass can be computed.

    Correct Answer
    C. A known mass of the compound could be dissolved in a known mass of solvent with a known Kf value. Carefully measure the change in freezing point. From this data, the molar mass can be computed.
    Explanation
    Freezing-point depression can be used to compute the unknown molar mass of a compound by dissolving a known mass of the compound in a known mass of solvent with a known Kf value. The change in freezing point is carefully measured, and from this data, the molar mass can be computed.

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  • Mar 21, 2023
    Quiz Edited by
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