15 Questions
| Total Attempts: 471

Questions and Answers

- 1.Which of the following is an accurate description of Bit Depth
- A.
Defines the minimum dynamic range of a track

- B.
States how many samples are taken per second

- C.
States how much data passes per second

- D.
States the number of different values each sample can be

- 2.If the Bit Depth is 16bit, which of the following statements is true
- A.
There are 16 samples per second

- B.
There are 16 different dynamic levels each sample can be

- C.
Each sample can be any value of representable by 16 1's and 0's

- D.
Bit depth relates to the frequency response

- 3.If the bit depth was 8, how many different amplitude levels can be recorded
- A.
8

- B.
16

- C.
128

- D.
256

- 4.Which of the following make up the settings for a Red-Book Audio CD (pick 4)
- A.
Sample Rate = 44,100hz

- B.
Sample Rate = 48khz

- C.
Bit Depth = 128kb/s

- D.
Bit Depth = 16

- E.
Maximum Length = 74 minutes

- F.
Maximum Number of Tracks = 99

- G.
Minimum Number of Tracks = 3

- H.
Minimum Length = 5minutes

- I.
All tracks in WAV format

- 5.If the sample rate is 48khz which of the following statement is true
- A.
Each sample can be 48,000 different values

- B.
The highest recordable frequency is 48khz

- C.
The recorded wave form is sample 48,000 times per second

- D.
The track is sampled 48 times

- 6.Which of these statements is NOT true:
- A.
Increasing the sample rate increase the range of recordable frequencies

- B.
Increasing the sample rate increases the amount of data required to store the file

- C.
Increasing the sample rate increases the amount of time each wave form is sampled

- D.
Increasing the sample rate increases the range of dynamic levels available

- 7.Which of the following statements is an accurate description of Aliasing
- A.
Occurs as a result of the bit depth being too low

- B.
A "ghost" low frequency is recorded when a frequency above the sample rate is recorded

- C.
A ghost high frequency is recorded when a frequency below half the sample rate

- D.
Can be avoided by using a high-pass filter

- 8.An anti-aliasing filter can be created using which of the following EQ filters
- A.
Band-Pass

- B.
Low Pass

- C.
High Pass

- D.
High Shelf

- E.
Low Shelf

- 9.Which of the following statements is true regarding in relation to the Niquist Theory:
- A.
To avoid aliasing, the highest frequency must be half the sample rate

- B.
To avoid aliasing, the highest frequency must be double the sample rate

- C.
To record the wave form accurately, the highest frequency must be half the sample rate

- D.
To record the wave form accurately, the highest frequency must be double the sample rate

- 10.What is the minimum amount of times that a wave form must be sampled in order to be replayed at the correct frequency accuracy
- A.
1

- B.
2

- C.
3

- D.
4

- 11.If the sample rate is 48khz, what is the highest frequency which could be recorded without aliasing occuring.
- A.
96khz

- B.
48khz

- C.
24khz

- D.
24hz

- 12.Niquist theory applies to what kind of recording:
- A.
Digital Audio

- B.
MIDI

- C.
Analogue Audio

- D.
Kinetic Energy

- 13.Which of the following signals paths would be an accurate possible chain of events for Analogue to Digital Conversion
- A.
Analogue Signal > High Pass Filter > A/D Converter > Digital Signal

- B.
Digital Signal > D/A Converter > Analogue Signal > Amp > Speaker > Audible Signal

- C.
Digital Signal > A/D Converter > Analogue Signal > Amp > Speaker > Audible Signal

- D.
Audible Signal > Microphone > Analogue Signal > Low Pass Filter > A/D Converter > Digital Signal

- 14.Which of the following statements is
__NOT__true regarding an A/D Converter running at 48khz, 16bit- A.
Turns an analogue signal into a string of 1's and 0's

- B.
Measures the amplitude of the wave form 48,000 times per second and stores it as a 16bit word

- C.
Measures the frequency of the waveform 48,000 times per second

- D.
It generates 768000 bits per second

- 15.If the bit depth is 16, however many different levels of amplitude can be recorded
- A.
16

- B.
(2 x 16 =) 32

- C.
(16 to the power of 2 = 16 x 16 =) 256

- D.
(2 to the power of 16 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 =) 65, 536