Algebra 2 Semester Exam Practice
(94).jpg "Algebra 2 Semester Exam Practice - Quiz")
Note: ^ is used to note exponents ie. X^2 reads x to the second power.
It is importantthat when entering answers you use spaces between operation symbols.
Ex. 2x + 3y instead of 2x+3y
And no spaces before and after parenthesis or exponents
Ex. 2(x^-2 + 3)
- 1.
Evaluate the given expression if x = 4, y = 8, w = -2 and z = 3. (x-y)² + 5wz
- A.
-14
- B.
14
- C.
44
- D.
34
Correct Answer
A. -14 -
- 2.
Simplify 5x + 2y – 7x + y
Correct Answer
-2x + 3y, 3y - 2x, -2x+3y, 3y-2x - 3.
Simplify 6(4x + 8y) + 2(3x – 6y)
Correct Answer
30x + 36y, 30x+36y, 36y + 30x, 36y+30x - 4.
Simplify (4x² + 3x + 3) + (5x² – 13x – 8). Use ^ for powers ie. x^2 is x to the second power.
Correct Answer
9x^2 - 10x - 5, 9x2 - 10x - 5 - 5.
Simplify (-10x² – 4x + 8)- (6x² + 10x -3)
Correct Answer
-16x^2 - 14x + 11 - 6.
Simplify -3xy(6xy³- 4xy + 7y²)
- A.
-18x^2y^4 + 12x^2y^2 - 21xy^3
- B.
-18x^2y^4 - 12x^2y^2 - 21xy^3
- C.
3x^2y^4 - 7x^2y^2 + 4xy^3
- D.
3x^2y^4 + 7x^2y^2 - 4xy^3
Correct Answer
A. -18x^2y^4 + 12x^2y^2 - 21xy^3 -
- 7.
Simplify 10squrt(162) - squrt(405) - squrt(200)
Correct Answer
80squrt(2) - 9squrt(5)Explanation
squrt = sqare root. When typing your answer write it in the way the question is given.
Example: 30squrt(18) - squrt(5)Rate this question:
- 8.
- A.
A
- B.
B
- C.
C
- D.
D
Correct Answer
B. B -
- 9.
- A.
A
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B
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C
- D.
D
Correct Answer
A. A -
- 10.
Solve 24p - 12 = 50; p = _____, round to the nearest hundredth.
Correct Answer
2.58Explanation
To solve the equation 24p - 12 = 50, we need to isolate the variable p. First, we add 12 to both sides of the equation, which gives us 24p = 62. Then, we divide both sides by 24 to solve for p. Simplifying this gives us p = 62/24 = 2.5833333. Rounding to the nearest hundredth, we get p ≈ 2.58.Rate this question:
- 11.
Solve 5x - 23 = 56; x = ____, round to the nearest tenth.
Correct Answer
15.8Explanation
To solve the equation 5x - 23 = 56, we need to isolate the variable x. First, we add 23 to both sides of the equation to get 5x = 79. Then, we divide both sides by 5 to solve for x, which gives us x = 15.8. Rounding to the nearest tenth, we get the final answer of 15.8.Rate this question:
- 12.
Solve- abs(x - 2) = 27, X = ____
- A.
29
- B.
25
- C.
-25
- D.
29, -25
Correct Answer
D. 29, -25Explanation
abs(x-2) means the absolute value of x - 2Rate this question:
-
- 13.
Find the value of f(6) if f(x) = -4x - 2.
- A.
26
- B.
-26
- C.
24
- D.
-24
Correct Answer
B. -26Explanation
To find the value of f(6), we substitute x = 6 into the given function f(x) = -4x - 2. Therefore, f(6) = -4(6) - 2 = -24 - 2 = -26.Rate this question:
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- 14.
Find the slope of the line that passes through the pair of points (-3,-5) and (7,5).In your answer type the number only.
Correct Answer
1 - 15.
Write an equation in slope-intercept form for the line that satisfies the following condition. Slope 3, and passes through (5,20).Use spaces between operation symbols when typing your answer. Ex. y = 3x - 2
Correct Answer
y = 3x + 5 - 16.
Solve the system of equations. x – y = 4 and y = 2x – 6
- A.
X = 2 y = 2
- B.
X = -2 y = 2
- C.
X = -2 y = -2
- D.
X = 2 y = -2
Correct Answer
D. X = 2 y = -2 -
- 17.
Solve the system of equations. 2x + 5y = 12 and x – 3y = -2
- A.
X = 4.8 y = 3.0
- B.
X = 2.4 y = 1.5
- C.
X = 1.2 y = 0.75
- D.
X = 7.2 y = 4.5
Correct Answer
B. X = 2.4 y = 1.5 -
- 18.
Describe the system of equation as consistent and independent, consistent and dependent, or none of these. 3x – 2y = 1 and 6x – 9y = 63
- A.
Consistent and independent
- B.
Consistent and dependent
- C.
None of these
Correct Answer
A. Consistent and independentExplanation
The system of equations is consistent because there is at least one solution that satisfies both equations. It is also independent because the coefficients of x and y in both equations are not proportional to each other. Therefore, the system has a unique solution.Rate this question:
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- 19.
Express the given number or expression in scientific notation. Round to the nearest hundredth. 0.0000269074
Correct Answer
2.69 x 10^-5Explanation
use spaces between x
ex. 1.23 x 10^-5Rate this question:
- 20.
Factor 4xy – 3y – 40x + 30
- A.
(4x - 3)(2y - 20)
- B.
(12x - 9)(2y - 20)
- C.
(y - 10)(4x - 3)
- D.
Y(4x - 3) - 10(4x - 3)
Correct Answer
C. (y - 10)(4x - 3) -
- 21.
Factor 2x² + 3x – 9
Correct Answer
(2x - 3)(x + 3)
(x + 3)(2x -3)Explanation
Type no spaces after parenthesis or between
Ex. (x - 2)(x + 3)Rate this question:
- 22.
(5 + ί) + (6 - 12ί)
- A.
11 + 11i
- B.
11 - 11i
- C.
30 - 72i
- D.
11 + 13i
Correct Answer
B. 11 - 11i -
- 23.
(4 - 10ί) + (15 - 16ί)
Correct Answer
19 - 26i
-26i + 19Explanation
use spaces between operation symbolsRate this question:
- 24.
Solve: squrt(2x - 2) + 12 = 14x = ____ Type the number only for your answer.
Correct Answer
3Explanation
squrt(2x - 2), means the square root of 2x - 2Rate this question:
- 25.
Solve: squrt(x - 3) + 6 = 15
- A.
64
- B.
84
- C.
74
- D.
34
Correct Answer
B. 84Explanation
To solve the equation, we first isolate the square root term by subtracting 6 from both sides: sqrt(x - 3) = 9. Then, we square both sides to eliminate the square root: x - 3 = 81. Adding 3 to both sides gives us x = 84. Therefore, the correct answer is 84.Rate this question:
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- 26.
M + 5 < 4 or m + 2 > 9
- A.
M > -1 or m< 7
- B.
M . -1 or m > 7
- C.
M < -1 or m > 7
- D.
M > - 1 or m > 7
Correct Answer
C. M < -1 or m > 7Explanation
The given equation is a compound inequality with two parts connected by "or". To solve it, we need to solve each part separately and then combine the solutions.
For the first part, m + 5 < 4, we subtract 5 from both sides to isolate m, giving us m < -1.
For the second part, m + 2 > 9, we subtract 2 from both sides to isolate m, giving us m > 7.
Combining the solutions, we get m < -1 or m > 7. This means that m can be any value less than -1 or any value greater than 7.Rate this question:
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- 27.
Simplify sqrt(36x^12y^8)
- A.
6x^6y^4
- B.
6x^12y^8
- C.
9x^12y^8
- D.
9x^6y^4
Correct Answer
A. 6x^6y^4Explanation
To simplify the given expression, we need to find the square root of each term. The square root of 36 is 6, the square root of x^12 is x^6, and the square root of y^8 is y^4. Therefore, the simplified expression is 6x^6y^4.Rate this question:
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- 28.
Express the product in Scientific notation. Round to the nearest hundredth and use spaces between x, and no spaces before or after parenthesis or ^. (6.34 x 10^-3)(6.3 x 10^-5)
Correct Answer
3.99 x 10^-7Explanation
To multiply numbers in scientific notation, we multiply the coefficients and add the exponents. In this case, the product of the coefficients is 6.34 x 6.3 = 39.882. The exponents are -3 and -5, so we add them to get -8. Rounding 39.882 to the nearest hundredth gives us 39.88. Therefore, the product in scientific notation is 3.99 x 10^-7.Rate this question:
- 29.
Simplify squrt(-200x^8y^12)
- A.
-10x^4y^6squrt(2)
- B.
-10ix^4y^6squrt(2)
- C.
10x^4y^6squrt(-2)
- D.
10ix^4y^6squrt(2)
Correct Answer
D. 10ix^4y^6squrt(2) -
- 30.
Evaluate squrt(-300) x squrt(-400)
- A.
Squrt(1200)
- B.
20squrt(3)
- C.
200isqurt(3)
- D.
-200squrt(3)
Correct Answer
D. -200squrt(3) -
- 31.
Simplify sqrt(200x^17y^24)
- A.
10x^8y^12squrt(2x)
- B.
10x^8y^12squrt(2)
- C.
10y^12squrt(2x^17)
- D.
10squrt(2x^17y^24)
Correct Answer
A. 10x^8y^12squrt(2x) -
- 32.
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A
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B
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C
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D
Correct Answer
B. B -
- 33.
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A
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B
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C
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D
Correct Answer
B. B -
- 34.
What is squrt(1344) divided by squrt(7)
- A.
192
- B.
32squrt(6)
- C.
8squrt(3)
- D.
Squrt(192)
Correct Answer
C. 8squrt(3)Explanation
The given question asks for the result of dividing the square root of 1344 by the square root of 7. Simplifying this expression, we can rewrite the square root of 1344 as the square root of 64 times the square root of 21, which becomes 8 times the square root of 21. Similarly, the square root of 7 cannot be simplified further. Therefore, dividing 8 times the square root of 21 by the square root of 7 gives us 8 times the square root of 3.Rate this question:
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- 35.
- A.
A
- B.
B
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C
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D
Correct Answer
C. C -
- 36.
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A
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B
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C
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D
Correct Answer
A. A -
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Sep 02, 2024Quiz Edited by
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Jan 09, 2009Quiz Created by
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