# Pvhs Algebra 2 Final

Approved & Edited by ProProfs Editorial Team
The editorial team at ProProfs Quizzes consists of a select group of subject experts, trivia writers, and quiz masters who have authored over 10,000 quizzes taken by more than 100 million users. This team includes our in-house seasoned quiz moderators and subject matter experts. Our editorial experts, spread across the world, are rigorously trained using our comprehensive guidelines to ensure that you receive the highest quality quizzes.
| By Instructor.pvhs
I
Instructor.pvhs
Community Contributor
Quizzes Created: 14 | Total Attempts: 5,908
Questions: 14 | Attempts: 150  Settings  This test will contain information from the PVHS Algebra 2 coursework from sections 5-9

• 1.

### Compound Interest 1   How much will you have in your account if:\$57387  is invested at  11.2%  compounded  semi-annually  for  84  years

• A.

\$211637693.12

• B.

\$542440089.7

• C.

\$2184.39

• D.

\$167350.18

B. \$542440089.7
• 2.

### Compound Interest 1   How much will you have in your account if:\$4865  is invested at  10.4%  compounded  monthly  for  62  years

• A.

\$68986.34

• B.

\$65096.82

• C.

\$2987779.59

• D.

\$90372.21

C. \$2987779.59
• 3.

• A.

269870

• B.

577048

• C.

27657

• D.

42591

D. 42591
• 4.

• A.

69437

• B.

44812812

• C.

132696

• D.

77889

A. 69437
• 5.

• A.

10494

• B.

434910

• C.

202718

• D.

139437

B. 434910
• 6.

### Continuous Compound Interest 2  How long will it take:  \$6574  to grow into  \$53287  if it is invested at  2.8%  compounded continuously

• A.

25.23 years

• B.

12.39 years

• C.

74.73 years

• D.

50.79 years

C. 74.73 years
Explanation
The correct answer is 74.73 years. This can be calculated using the formula for continuous compound interest, which is A = P * e^(rt), where A is the final amount, P is the initial principal, e is Euler's number (approximately 2.71828), r is the interest rate, and t is the time in years. In this case, we have P = \$6574, A = \$53287, r = 2.8%, and we need to solve for t. Rearranging the formula, we get t = ln(A/P) / r. Plugging in the values, we get t = ln(\$53287/\$6574) / 0.028, which is approximately equal to 74.73 years.

Rate this question:

• 7.

### Continuous Compound Interest 2  How long will it take:  \$49835  to grow into  \$85721  if it is invested at  10.6%  compounded continuously

• A.

38.02 years

• B.

11.56 years

• C.

8.58 years

• D.

5.12 years

D. 5.12 years
Explanation
The correct answer is 5.12 years. This can be calculated using the formula for continuous compound interest: A = P * e^(rt), where A is the final amount, P is the initial principal, r is the interest rate, and t is the time in years. Rearranging the formula to solve for t, we have t = ln(A/P) / r. Plugging in the values given in the question, we get t = ln(85721/49835) / 0.106. Evaluating this expression gives t ≈ 5.12 years.

Rate this question:

• 8.

### Compound Interest 2  How long will it take:  \$27065  to grow into  \$88726  if it is invested at  2.3%  compounded  semi-annually

• A.

18.12 years

• B.

26.47 years

• C.

51.92 years

• D.

15.81 years

C. 51.92 years
• 9.

### Compound Interest 2  How long will it take:  \$42192  to grow into  \$80437  if it is invested at  6.4%  compounded  daily

• A.

15.8 years

• B.

9.23 years

• C.

7.48 years

• D.

10.08 years

D. 10.08 years
• 10.

### Radioactive Decay 1  The half-life of boogonium is  10  years. If you have  15  grams in  1930,  how much will be left in  2053?

• A.

8.05 grams

• B.

0 grams

• C.

6.91 grams

• D.

18.21 grams

B. 0 grams
Explanation
Since the half-life of boogonium is 10 years, it means that half of the substance will decay every 10 years. From 1930 to 2053, there is a time difference of 123 years, which is equivalent to 12.3 half-lives. Therefore, after 12.3 half-lives, there will be no boogonium left, resulting in 0 grams remaining.

Rate this question:

• 11.

### Radioactive Decay 1  The half-life of boogonium is  326  years. If you have  36  grams in  1923,  how much will be left in  2080?

• A.

25.45 grams

• B.

34.64 grams

• C.

25.78 grams

• D.

18.21 grams

C. 25.78 grams
• 12.

### Radioactive Decay 2  You discovered a new radioactive isotope isotope and named it Geekonium-25. At  10  a.m., you have  31  mg in your petrie dish and at  2  p.m., you measure only  18  mg.  What's the half-life?

• A.

Half-life = 8.54 hours

• B.

Half-life = 9.27 hours

• C.

Half-life = 4.85 hours

• D.

Half-life = 5.1 hours

D. Half-life = 5.1 hours
• 13.

### Radioactive Decay 2  You discovered a new radioactive isotope isotope and named it Geekonium-25. At  5  a.m., you have  85  mg in your petrie dish and at  6  p.m., you measure only  25  mg.  What's the half-life?

• A.

Half-life = 7.36 hours

• B.

Half-life = 4.85 hours

• C.

Half-life = 4.35 hours

• D.

Half-life = 7.48 hours

A. Half-life = 7.36 hours
• 14.

### Radioactive Decay 2  You discovered a new radioactive isotope isotope and named it Geekonium-25. At  9  a.m., you have  74  mg in your petrie dish and at  7  p.m., you measure only  56  mg.  What's the half-life?

• A.

Half-life = 60.62 hours

• B.

Half-life = 24.87 hours

• C.

Half-life = 20.65 hours

• D.

Half-life = 24.2 hours Back to top