PVHS Algebra 2 Final

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| By Instructor.pvhs

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Quizzes Created: 13 | Total Attempts: 5,845

| Attempts: 172

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1/14 Questions

Population Growth 1 In the population of 1931 Geekville was 11931. If the growth rate is 5.8%, what was the population in ? 1993
- 10494
- 434910
- 202718
- 139437

About This Quiz

This test will contain information from the PVHS Algebra 2 coursework from sections 5-9

2.

Compound Interest 1 How much will you have in your account if:$57387 is invested at 11.2% compounded semi-annually for 84 years
- $211637693.12
- $542440089.7
- $2184.39
- $167350.18
Correct Answer

A. $542440089.7
3.

Radioactive Decay 2 You discovered a new radioactive isotope isotope and named it Geekonium-25. At 9 a.m., you have 74 mg in your petrie dish and at 7 p.m., you measure only 56 mg. What's the half-life?
- Half-life = 60.62 hours
- Half-life = 24.87 hours
- Half-life = 20.65 hours
- Half-life = 24.2 hours
Correct Answer

A. Half-life = 24.87 hours
4.

Radioactive Decay 2 You discovered a new radioactive isotope isotope and named it Geekonium-25. At 10 a.m., you have 31 mg in your petrie dish and at 2 p.m., you measure only 18 mg. What's the half-life?
- Half-life = 8.54 hours
- Half-life = 9.27 hours
- Half-life = 4.85 hours
- Half-life = 5.1 hours
Correct Answer

A. Half-life = 5.1 hours
5.

Compound Interest 1 How much will you have in your account if:$4865 is invested at 10.4% compounded monthly for 62 years
- $68986.34
- $65096.82
- $2987779.59
- $90372.21
Correct Answer

A. $2987779.59
6.

Radioactive Decay 1 The half-life of boogonium is 326 years. If you have 36 grams in 1923, how much will be left in 2080?
- 25.45 grams
- 34.64 grams
- 25.78 grams
- 18.21 grams
Correct Answer

A. 25.78 grams
7.

Population Growth 1 In the population of 1925 Geekville was 1329. If the growth rate is 8.6%, what was the population in ? 1971
- 69437
- 44812812
- 132696
- 77889
Correct Answer

A. 69437
8.

Radioactive Decay 1 The half-life of boogonium is 10 years. If you have 15 grams in 1930, how much will be left in 2053?
- 8.05 grams
- 0 grams
- 6.91 grams
- 18.21 grams
Correct Answer

A. 0 grams

Explanation

Since the half-life of boogonium is 10 years, it means that half of the substance will decay every 10 years. From 1930 to 2053, there is a time difference of 123 years, which is equivalent to 12.3 half-lives. Therefore, after 12.3 half-lives, there will be no boogonium left, resulting in 0 grams remaining.

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9.

Continuous Compound Interest 2 How long will it take: $49835 to grow into $85721 if it is invested at 10.6% compounded continuously
- 38.02 years
- 11.56 years
- 8.58 years
- 5.12 years
Correct Answer

A. 5.12 years

Explanation

The correct answer is 5.12 years. This can be calculated using the formula for continuous compound interest: A = P * e^(rt), where A is the final amount, P is the initial principal, r is the interest rate, and t is the time in years. Rearranging the formula to solve for t, we have t = ln(A/P) / r. Plugging in the values given in the question, we get t = ln(85721/49835) / 0.106. Evaluating this expression gives t ≈ 5.12 years.

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10.

Compound Interest 2 How long will it take: $27065 to grow into $88726 if it is invested at 2.3% compounded semi-annually
- 18.12 years
- 26.47 years
- 51.92 years
- 15.81 years
Correct Answer

A. 51.92 years
11.

Population Growth 1 In the population of 1931 Geekville was 29214. If the growth rate is 2.9%, what was the population in ? 1944
- 269870
- 577048
- 27657
- 42591
Correct Answer

A. 42591
12.

Compound Interest 2 How long will it take: $42192 to grow into $80437 if it is invested at 6.4% compounded daily
- 15.8 years
- 9.23 years
- 7.48 years
- 10.08 years
Correct Answer

A. 10.08 years
13.

Continuous Compound Interest 2 How long will it take: $6574 to grow into $53287 if it is invested at 2.8% compounded continuously
- 25.23 years
- 12.39 years
- 74.73 years
- 50.79 years
Correct Answer

A. 74.73 years

Explanation

The correct answer is 74.73 years. This can be calculated using the formula for continuous compound interest, which is A = P * e^(rt), where A is the final amount, P is the initial principal, e is Euler's number (approximately 2.71828), r is the interest rate, and t is the time in years. In this case, we have P = $6574, A = $53287, r = 2.8%, and we need to solve for t. Rearranging the formula, we get t = ln(A/P) / r. Plugging in the values, we get t = ln($53287/$6574) / 0.028, which is approximately equal to 74.73 years.

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14.

Radioactive Decay 2 You discovered a new radioactive isotope isotope and named it Geekonium-25. At 5 a.m., you have 85 mg in your petrie dish and at 6 p.m., you measure only 25 mg. What's the half-life?
- Half-life = 7.36 hours
- Half-life = 4.85 hours
- Half-life = 4.35 hours
- Half-life = 7.48 hours
Correct Answer

A. Half-life = 7.36 hours

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Jan 12, 2009

Quiz Created by
Instructor.pvhs

Pvhs Algebra 2 Final

Population Growth 1 In the population of 1931 Geekville was 11931. If the growth rate is 5.8%, what was the population in ? 1993

Quiz Preview

Compound Interest 1 How much will you have in your account if:$57387 is invested at 11.2% compounded semi-annually for 84 years

Radioactive Decay 2 You discovered a new radioactive isotope isotope and named it Geekonium-25. At 9 a.m., you have 74 mg in your petrie dish and at 7 p.m., you measure only 56 mg. What's the half-life?

Radioactive Decay 2 You discovered a new radioactive isotope isotope and named it Geekonium-25. At 10 a.m., you have 31 mg in your petrie dish and at 2 p.m., you measure only 18 mg. What's the half-life?

Compound Interest 1 How much will you have in your account if:$4865 is invested at 10.4% compounded monthly for 62 years

Radioactive Decay 1 The half-life of boogonium is 326 years. If you have 36 grams in 1923, how much will be left in 2080?

Population Growth 1 In the population of 1925 Geekville was 1329. If the growth rate is 8.6%, what was the population in ? 1971

Radioactive Decay 1 The half-life of boogonium is 10 years. If you have 15 grams in 1930, how much will be left in 2053?

Continuous Compound Interest 2 How long will it take: $49835 to grow into $85721 if it is invested at 10.6% compounded continuously

Compound Interest 2 How long will it take: $27065 to grow into $88726 if it is invested at 2.3% compounded semi-annually

Population Growth 1 In the population of 1931 Geekville was 29214. If the growth rate is 2.9%, what was the population in ? 1944

Compound Interest 2 How long will it take: $42192 to grow into $80437 if it is invested at 6.4% compounded daily

Continuous Compound Interest 2 How long will it take: $6574 to grow into $53287 if it is invested at 2.8% compounded continuously

Radioactive Decay 2 You discovered a new radioactive isotope isotope and named it Geekonium-25. At 5 a.m., you have 85 mg in your petrie dish and at 6 p.m., you measure only 25 mg. What's the half-life?