Pvhs Algebra 2 Final

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  • 1/14 Questions

    Population Growth 1  In  the population of  1931  Geekville was  11931.  If the growth rate is  5.8%,  what was  the population in ?  1993

    • 10494
    • 434910
    • 202718
    • 139437
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About This Quiz


This test will contain information from the PVHS Algebra 2 coursework from sections 5-9

Pvhs Algebra 2 Final - Quiz

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  • 2. 

    Compound Interest 1   How much will you have in your account if:$57387  is invested at  11.2%  compounded  semi-annually  for  84  years

    • $211637693.12

    • $542440089.7

    • $2184.39

    • $167350.18

    Correct Answer
    A. $542440089.7
  • 3. 

    Radioactive Decay 2  You discovered a new radioactive isotope isotope and named it Geekonium-25. At  9  a.m., you have  74  mg in your petrie dish and at  7  p.m., you measure only  56  mg.  What's the half-life?

    • Half-life = 60.62 hours

    • Half-life = 24.87 hours

    • Half-life = 20.65 hours

    • Half-life = 24.2 hours

    Correct Answer
    A. Half-life = 24.87 hours
  • 4. 

    Radioactive Decay 2  You discovered a new radioactive isotope isotope and named it Geekonium-25. At  10  a.m., you have  31  mg in your petrie dish and at  2  p.m., you measure only  18  mg.  What's the half-life?

    • Half-life = 8.54 hours

    • Half-life = 9.27 hours

    • Half-life = 4.85 hours

    • Half-life = 5.1 hours

    Correct Answer
    A. Half-life = 5.1 hours
  • 5. 

    Compound Interest 1   How much will you have in your account if:$4865  is invested at  10.4%  compounded  monthly  for  62  years

    • $68986.34

    • $65096.82

    • $2987779.59

    • $90372.21

    Correct Answer
    A. $2987779.59
  • 6. 

    Radioactive Decay 1  The half-life of boogonium is  326  years. If you have  36  grams in  1923,  how much will be left in  2080?

    • 25.45 grams

    • 34.64 grams

    • 25.78 grams

    • 18.21 grams

    Correct Answer
    A. 25.78 grams
  • 7. 

    Population Growth 1  In  the population of  1925  Geekville was  1329.  If the growth rate is  8.6%,  what was  the population in ?  1971

    • 69437

    • 44812812

    • 132696

    • 77889

    Correct Answer
    A. 69437
  • 8. 

    Radioactive Decay 1  The half-life of boogonium is  10  years. If you have  15  grams in  1930,  how much will be left in  2053?

    • 8.05 grams

    • 0 grams

    • 6.91 grams

    • 18.21 grams

    Correct Answer
    A. 0 grams
    Explanation
    Since the half-life of boogonium is 10 years, it means that half of the substance will decay every 10 years. From 1930 to 2053, there is a time difference of 123 years, which is equivalent to 12.3 half-lives. Therefore, after 12.3 half-lives, there will be no boogonium left, resulting in 0 grams remaining.

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  • 9. 

    Continuous Compound Interest 2  How long will it take:  $49835  to grow into  $85721  if it is invested at  10.6%  compounded continuously

    • 38.02 years

    • 11.56 years

    • 8.58 years

    • 5.12 years

    Correct Answer
    A. 5.12 years
    Explanation
    The correct answer is 5.12 years. This can be calculated using the formula for continuous compound interest: A = P * e^(rt), where A is the final amount, P is the initial principal, r is the interest rate, and t is the time in years. Rearranging the formula to solve for t, we have t = ln(A/P) / r. Plugging in the values given in the question, we get t = ln(85721/49835) / 0.106. Evaluating this expression gives t ≈ 5.12 years.

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  • 10. 

    Compound Interest 2  How long will it take:  $27065  to grow into  $88726  if it is invested at  2.3%  compounded  semi-annually

    • 18.12 years

    • 26.47 years

    • 51.92 years

    • 15.81 years

    Correct Answer
    A. 51.92 years
  • 11. 

    Population Growth 1  In  the population of  1931  Geekville was  29214.  If the growth rate is  2.9%,  what was  the population in ?  1944

    • 269870

    • 577048

    • 27657

    • 42591

    Correct Answer
    A. 42591
  • 12. 

    Compound Interest 2  How long will it take:  $42192  to grow into  $80437  if it is invested at  6.4%  compounded  daily

    • 15.8 years

    • 9.23 years

    • 7.48 years

    • 10.08 years

    Correct Answer
    A. 10.08 years
  • 13. 

    Continuous Compound Interest 2  How long will it take:  $6574  to grow into  $53287  if it is invested at  2.8%  compounded continuously

    • 25.23 years

    • 12.39 years

    • 74.73 years

    • 50.79 years

    Correct Answer
    A. 74.73 years
    Explanation
    The correct answer is 74.73 years. This can be calculated using the formula for continuous compound interest, which is A = P * e^(rt), where A is the final amount, P is the initial principal, e is Euler's number (approximately 2.71828), r is the interest rate, and t is the time in years. In this case, we have P = $6574, A = $53287, r = 2.8%, and we need to solve for t. Rearranging the formula, we get t = ln(A/P) / r. Plugging in the values, we get t = ln($53287/$6574) / 0.028, which is approximately equal to 74.73 years.

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  • 14. 

    Radioactive Decay 2  You discovered a new radioactive isotope isotope and named it Geekonium-25. At  5  a.m., you have  85  mg in your petrie dish and at  6  p.m., you measure only  25  mg.  What's the half-life?

    • Half-life = 7.36 hours

    • Half-life = 4.85 hours

    • Half-life = 4.35 hours

    • Half-life = 7.48 hours

    Correct Answer
    A. Half-life = 7.36 hours

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  • Oct 17, 2024
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