Pvhs Algebra 2 Final

Reviewed by Editorial Team
The ProProfs editorial team is comprised of experienced subject matter experts. They've collectively created over 10,000 quizzes and lessons, serving over 100 million users. Our team includes in-house content moderators and subject matter experts, as well as a global network of rigorously trained contributors. All adhere to our comprehensive editorial guidelines, ensuring the delivery of high-quality content.
Learn about Our Editorial Process
| By Instructor.pvhs
I
Instructor.pvhs
Community Contributor
Quizzes Created: 13 | Total Attempts: 5,850
| Attempts: 172 | Questions: 14
Please wait...
Question 1 / 14
0 %
0/100
Score 0/100
1. Population Growth 1   In  the population of  1931  Geekville was  11931.  If the growth rate is  5.8%,  what was  the population in ?  1993

Explanation

not-available-via-ai

Submit
Please wait...
About This Quiz
Pvhs Algebra 2 Final - Quiz


This test will contain information from the PVHS Algebra 2 coursework from sections 5-9

2. Compound Interest 1   How much will you have in your account if: $57387  is invested at  11.2%  compounded  semi-annually  for  84  years

Explanation

not-available-via-ai

Submit
3. Radioactive Decay 2   You discovered a new radioactive isotope isotope and named it Geekonium-25. At  9  a.m., you have  74  mg in your petrie dish and at  7  p.m., you measure only  56  mg.  What's the half-life?

Explanation

not-available-via-ai

Submit
4. Radioactive Decay 2   You discovered a new radioactive isotope isotope and named it Geekonium-25. At  10  a.m., you have  31  mg in your petrie dish and at  2  p.m., you measure only  18  mg.  What's the half-life?

Explanation

not-available-via-ai

Submit
5. Compound Interest 1   How much will you have in your account if: $4865  is invested at  10.4%  compounded  monthly  for  62  years

Explanation

not-available-via-ai

Submit
6. Radioactive Decay 1   The half-life of boogonium is  326  years. If you have  36  grams in  1923,  how much will be left in  2080?

Explanation

not-available-via-ai

Submit
7. Population Growth 1   In  the population of  1925  Geekville was  1329.  If the growth rate is  8.6%,  what was  the population in ?  1971

Explanation

not-available-via-ai

Submit
8. Radioactive Decay 1   The half-life of boogonium is  10  years. If you have  15  grams in  1930,  how much will be left in  2053?

Explanation

Since the half-life of boogonium is 10 years, it means that half of the substance will decay every 10 years. From 1930 to 2053, there is a time difference of 123 years, which is equivalent to 12.3 half-lives. Therefore, after 12.3 half-lives, there will be no boogonium left, resulting in 0 grams remaining.

Submit
9. Continuous Compound Interest 2   How long will it take:  $49835  to grow into  $85721  if it is invested at  10.6%  compounded continuously

Explanation

The correct answer is 5.12 years. This can be calculated using the formula for continuous compound interest: A = P * e^(rt), where A is the final amount, P is the initial principal, r is the interest rate, and t is the time in years. Rearranging the formula to solve for t, we have t = ln(A/P) / r. Plugging in the values given in the question, we get t = ln(85721/49835) / 0.106. Evaluating this expression gives t ≈ 5.12 years.

Submit
10. Compound Interest 2   How long will it take:  $27065  to grow into  $88726  if it is invested at  2.3%  compounded  semi-annually

Explanation

not-available-via-ai

Submit
11. Population Growth 1   In  the population of  1931  Geekville was  29214.  If the growth rate is  2.9%,  what was  the population in ?  1944

Explanation

not-available-via-ai

Submit
12. Compound Interest 2   How long will it take:  $42192  to grow into  $80437  if it is invested at  6.4%  compounded  daily

Explanation

not-available-via-ai

Submit
13. Continuous Compound Interest 2   How long will it take:  $6574  to grow into  $53287  if it is invested at  2.8%  compounded continuously

Explanation

The correct answer is 74.73 years. This can be calculated using the formula for continuous compound interest, which is A = P * e^(rt), where A is the final amount, P is the initial principal, e is Euler's number (approximately 2.71828), r is the interest rate, and t is the time in years. In this case, we have P = $6574, A = $53287, r = 2.8%, and we need to solve for t. Rearranging the formula, we get t = ln(A/P) / r. Plugging in the values, we get t = ln($53287/$6574) / 0.028, which is approximately equal to 74.73 years.

Submit
14. Radioactive Decay 2   You discovered a new radioactive isotope isotope and named it Geekonium-25. At  5  a.m., you have  85  mg in your petrie dish and at  6  p.m., you measure only  25  mg.  What's the half-life?

Explanation

not-available-via-ai

Submit
View My Results

Quiz Review Timeline (Updated): Oct 17, 2024 +

Our quizzes are rigorously reviewed, monitored and continuously updated by our expert board to maintain accuracy, relevance, and timeliness.

  • Current Version
  • Oct 17, 2024
    Quiz Edited by
    ProProfs Editorial Team
  • Jan 12, 2009
    Quiz Created by
    Instructor.pvhs
Cancel
  • All
    All (14)
  • Unanswered
    Unanswered ()
  • Answered
    Answered ()
Population Growth 1 ...
Compound Interest 1 ...
Radioactive Decay 2 ...
Radioactive Decay 2 ...
Compound Interest 1 ...
Radioactive Decay 1 ...
Population Growth 1 ...
Radioactive Decay 1 ...
Continuous Compound Interest 2 ...
Compound Interest 2 ...
Population Growth 1 ...
Compound Interest 2 ...
Continuous Compound Interest 2 ...
Radioactive Decay 2 ...
Alert!

Advertisement