Cutting the Cord: Wireless Communication Principles Quiz

If the energy of a photon is proportional to its frequency (E=hf), then increasing frequency increases the energy of each photon; if the work function of the metal remains constant, then the excess energy provided by the photon must be converted into kinetic energy; therefore, higher frequency results in higher maximum kinetic energy for the electrons.

If light intensity is defined as the number of photons striking a surface per unit time, then increasing intensity increases the number of available photons; if each photon can eject one electron, then more photons will result in more emitted electrons; therefore, the current (rate of emission) is proportional to intensity.

If wave theory suggests that light energy is spread out and builds up over time, then it cannot explain the instantaneous emission of electrons at low intensities; if the photoelectric effect shows that energy is delivered in discrete "packets" (photons), then it demonstrates particle-like behavior; therefore, the photoelectric effect is the evidence for the particle nature.

If electrons are bound to a metal by atomic forces, then a specific amount of energy must be supplied to break that bond; if this energy is a characteristic property of the material, then it is defined as the work function.

If de Broglie hypothesized that matter has wave-like properties, then he must relate a wave property (wavelength) to a particle property (momentum); if the relationship is defined by the constant h, then the wavelength λ is equal to Planck's constant divided by momentum (p).

If classical wave theory states that light energy depends on intensity (amplitude), then any frequency of light should eventually eject an electron if given enough time; if experiments show that no electrons are ejected below a specific frequency regardless of intensity, then classical theory fails; therefore, the prediction was incorrect.

If the energy of the photon (hf) is used to overcome the work function (ϕ), then hf=ϕ+Kmax​; if f is the threshold frequency (f0​), then hf0​ is exactly equal to ϕ; if the energies are equal, then the remaining kinetic energy must be zero.

If Einstein related photon energy to frequency, then E=hf is relevant; if de Broglie related wavelength to momentum, then λ=h/p is relevant; if the conservation of energy is applied to electron emission, then Kmax​=hf−ϕ is relevant; since F=ma and V=IR are classical mechanics and circuit laws, they are not specific to this quantum topic.

If momentum p is equal to mass times velocity (mv), then doubling velocity doubles the momentum; if the wavelength λ is h/p, then an increase in the denominator by a factor of 2 results in the value being multiplied by 1/2; therefore, the wavelength is halved.

If E is proportional to f, then there must be a mathematical constant to equate them; if Max Planck derived this constant to solve the blackbody radiation problem, then it is called Planck's constant (h).

If a negative potential is applied to the collector to repel electrons, then only electrons with enough energy can reach it; if the potential is increased until the most energetic electron is stopped (Vs​), then eVs​ equals the maximum kinetic energy; therefore, stopping potential measures Kmax​.

If λ=h/p and Planck's constant h is extremely small (6.63×10−34), then a large mass in the denominator will result in an incredibly small wavelength; if the wavelength is smaller than the dimensions of any aperture, then diffraction and wave effects cannot be detected; therefore, the statement is true.

If Einstein published four groundbreaking papers in 1905, then all were significant; if the Nobel committee sought a discovery with clear experimental proof and fundamental impact on quantum theory, then they chose his law of the photoelectric effect; therefore, this was the primary reason for his prize.

If the energy of a photon is E=hf, and frequency (f) determines the color in the wave model, then the energy of the individual photon must correspond to that color; if blue light has a higher frequency than red light, then a blue photon has more energy than a red photon.

If a photon behaves like a particle, then it can collide with an electron and transfer momentum; if the photon loses energy during the collision, then its frequency must decrease and its wavelength must increase; if Arthur Compton discovered this shift, then it is the Compton Effect.

If the frequency is below the threshold, then no individual photon has enough energy to overcome the work function; if the photoelectric effect is a one-to-one interaction between a photon and an electron, then adding more "weak" photons (increasing intensity) still results in zero ejections; therefore, the statement is false.

If light shows interference (wave) and the photoelectric effect (particle), then it has dual nature; if electrons show diffraction (wave) and collisions (particle), then matter has dual nature; if these properties are universal at the quantum level, then everything exhibits both behaviors.

If eVs​=hf−ϕ, then the stopping potential (Vs​) depends on the energy of the incoming photons (hf); if the work function (ϕ) is determined by the metal type, then that also affects Vs​; since intensity and area only affect the number of electrons and not their individual energy, they do not affect the stopping potential.

If λ=h/(mv) and both have the same velocity v, then the wavelength depends inversely on mass m; if an electron has a much smaller mass than a proton, then the resulting fraction (h/mv) will be larger for the electron; therefore, the electron has a longer wavelength.

If stopping potential depends only on the maximum kinetic energy of the electrons, and Kmax​ is determined by the equation hf−ϕ, then changing intensity does not change the energy of individual photons; if the photon energy and work function are unchanged, then Kmax​ and the stopping potential remain exactly the same.