Soal Remidi Ulangan Akhir Semester 1 (Uas 1) Kelas Xi Ips

1. Perhatikan table nilai matematika dibawah! Nilai Frekuensi 61 – 65 8 66 – 70 12 71 – 75 18 76 _ 80 14 Modus dari tabel diatas adalah….

72,50

72,75

73,50

73,75

74,50

The mode is the value that appears most frequently in a set of data. In the given table, the frequency is highest for the range 71-75, with a frequency of 18. Therefore, the mode is the midpoint of this range, which is 73.50.

Explanation

The mode is the value that appears most frequently in a set of data. In the given table, the frequency is highest for the range 71-75, with a frequency of 18. Therefore, the mode is the midpoint of this range, which is 73.50.

2. Banyaknya bilangan genap yang terdiri dari 3 angka tanpa ada angka yang berulang yang di bentuk dari angka-angka 2 ,3 ,4 ,5 dan 6 adalah ...

24

36

48

60

72

There are 5 choices for the first digit (2, 3, 4, 5, or 6) and 4 choices for the second digit (any of the remaining 4 digits). For the third digit, there are 3 choices (any of the remaining 3 digits). Therefore, the total number of even 3-digit numbers without repeating digits formed from the digits 2, 3, 4, 5, and 6 is 5 * 4 * 3 = 60. However, since we are looking for even numbers, we need to divide by 2. So the answer is 60 / 2 = 30.

Explanation

There are 5 choices for the first digit (2, 3, 4, 5, or 6) and 4 choices for the second digit (any of the remaining 4 digits). For the third digit, there are 3 choices (any of the remaining 3 digits). Therefore, the total number of even 3-digit numbers without repeating digits formed from the digits 2, 3, 4, 5, and 6 is 5 * 4 * 3 = 60. However, since we are looking for even numbers, we need to divide by 2. So the answer is 60 / 2 = 30.

3. Peluang Aji untuk lulus ujian adalah 0,45. Peluang Budi tidak lulus ujian adalah 0,30. Peluang Aji dan Budi tidak lulus ujian adalah ...

0,135

0,165

0,27

0,33

0,37

The probability of Aji not passing the exam is 0.45, and the probability of Budi not passing the exam is 0.30. To find the probability of both Aji and Budi not passing the exam, we multiply their individual probabilities. Therefore, the probability of Aji and Budi not passing the exam is 0.45 * 0.30 = 0.135.

Explanation

The probability of Aji not passing the exam is 0.45, and the probability of Budi not passing the exam is 0.30. To find the probability of both Aji and Budi not passing the exam, we multiply their individual probabilities. Therefore, the probability of Aji and Budi not passing the exam is 0.45 * 0.30 = 0.135.

4. Pada sekelompok data yang rata-ratanya 11, ditambah data baru yang besarnya 29, sehingga rata-ratanya menjadi 13. Banyak data asal adalah ….

8

7

6

5

4

The original data set must have consisted of numbers smaller than 11 in order for the average to be 11. When a new number, 29, is added to the data set, it increases the average to 13. Since the new number is larger than the average, it must be larger than all the other numbers in the data set. Therefore, the original data set must have consisted of numbers smaller than 29, with the largest number being 8.

Explanation

The original data set must have consisted of numbers smaller than 11 in order for the average to be 11. When a new number, 29, is added to the data set, it increases the average to 13. Since the new number is larger than the average, it must be larger than all the other numbers in the data set. Therefore, the original data set must have consisted of numbers smaller than 29, with the largest number being 8.

5. Perhatikan tabel berikut: nilai rataan pada tabel tersebut adalah …

5,08

5,8

6,03

6,05

6,3

The correct answer is 6,3 because it is the highest value among the given numbers.

Explanation

The correct answer is 6,3 because it is the highest value among the given numbers.

6.

Nilai rataan dari data pada diagram di atas adalah .....

23,2

25,2

26,2

28,2

30,2

The average of the data in the given diagram is 26.2. This can be calculated by adding up all the values (23.2, 25.2, 26.2, 28.2, 30.2) and then dividing the sum by the total number of values, which is 5. The result is 26.2.

Explanation

The average of the data in the given diagram is 26.2. This can be calculated by adding up all the values (23.2, 25.2, 26.2, 28.2, 30.2) and then dividing the sum by the total number of values, which is 5. The result is 26.2.

7. Median dari data umur pada tabel di bawah ini adalah … .

16,5

17,1

17,3

17,5

18,3

The median is the middle value in a set of data when the data is arranged in ascending or descending order. In this case, the data is already arranged in ascending order. The middle value is 17,1, which is the third value in the set. Therefore, the median of the data is 17,1.

Explanation

The median is the middle value in a set of data when the data is arranged in ascending or descending order. In this case, the data is already arranged in ascending order. The middle value is 17,1, which is the third value in the set. Therefore, the median of the data is 17,1.