ข้อสอบเคมีent'(ความเข้มข้นของสารละลาย)

The given question provides the density of a certain type of orange juice, which is 1.13 g/cm3. It also states that the juice contains 8% acetic acid by weight. To find the concentration of the juice in terms of mol/dm3, we need to convert the density to g/dm3. Since 1 cm3 = 1 mL and 1 dm3 = 1000 mL, the density of the juice is 1130 g/dm3.

Next, we need to calculate the molar mass of acetic acid (CH3COOH), which is 60.05 g/mol. To find the concentration in mol/dm3, we divide the weight percent of acetic acid by the molar mass and multiply by 10.

8% * 1130 g/dm3 / 60.05 g/mol * 10 = 1.51 mol/dm3.

Therefore, the correct answer is 1.51.

The question provides information about the concentration of acid B in a solution formed by passing gas A into water. It states that the concentration of acid B is 30% by mass and has a density of 1.1 grams per cubic centimeter. It also mentions that the molecular weight of B is 66. To find the concentration of B in moles per decimeter cubed, we need to convert the given density to moles per liter. By dividing the density by the molecular weight of B, we get the concentration of B in moles per liter, which is 5. Therefore, the answer is 5.

The given question states that a liquid with the formula A3B has a specific gravity of 1.50, with the atomic masses of A and B being 33 and 21 respectively. When 20 cm3 of A3B is mixed with water to a final volume of 500 cm3, the resulting solution will have a concentration of how many mol/dm3.

To find the concentration, we need to calculate the number of moles of A3B in the solution. The specific gravity of 1.50 indicates that the density of A3B is 1.50 times that of water. Since the volume of A3B is 20 cm3, the mass of A3B is (20 cm3) * (1.50 g/cm3) = 30 g.

The molar mass of A3B is (33 g/mol) * 3 + (21 g/mol) = 150 g/mol. Therefore, the number of moles of A3B is (30 g) / (150 g/mol) = 0.20 mol.

The final volume of the solution is 500 cm3, which is equal to 0.500 dm3.

Therefore, the concentration of the solution is (0.20 mol) / (0.500 dm3) = 0.40 mol/dm3.

Since the answer choices are not provided in the question, we cannot determine the correct answer based on the given information.

The correct answer is C>A>B. This is because the question asks for the correct order of concentration of the solutes in the solutions A, B, and C. According to the given information, solution C has a concentration of 10% NaOH by mass per volume, which is the highest concentration among the three solutions. Solution A has a concentration of NaCl at 58.5 g/dm3, which is higher than the concentration of Na2SO4 in solution B at 71 g/dm3. Therefore, the correct order of concentration from highest to lowest is C>A>B.