Physics Of Ultrasound! Trivia Questions And Facts Quiz

Reviewed by Matt Balanda
Matt Balanda, BS (Aerospace Engineering) |
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Matt Balanda, a Calvary Chapel Christian School leader with a Bachelor's in Aerospace Engineering and Mathematics, transitioned from Aerospace Engineering to Education with a Master's from California Baptist University. As the High School Vice-Principal and Physics teacher, he nurtures students' love of learning and faith, creating an enriching and transformational educational experience.
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  • 1/170 Questions

    Which of the following is the best lateral resolution?

    • 15 mm
    • 6 mm
    • 0.06 cm
    • 2 cm
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About This Quiz

Are you a medical student looking for a quiz to test out what you know about the Physics of ultrasound? If so then you are in luck as the quiz below is perfect for you as it is used by students preparing for their exams too. Do give it a try and see just how much you can remember.

Physics Of Ultrasound! Trivia Questions And Facts Quiz - Quiz

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  • 2. 

    Which of the following metric prefixes is used to represent a factor of 10^6?

    • Deca

    • Centi

    • Deci

    • Micro

    Correct Answer
    A. Micro
    Explanation
    Micro is the metric prefix that represents a factor of 10^6, meaning one millionth. Deca represents a factor of 10, centi represents a factor of 10^-2 (or one hundredth), and deci represents a factor of 10^-1 (or one-tenth).

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  • 3. 

    If the spatial pulse length is 10mm, what is the axial resolution?

    • 0.5 cm

    • 5 cm

    • 10 mm

    • 1 cm

    Correct Answer
    A. 0.5 cm
    Explanation
    The axial resolution is a measure of the ability of an ultrasound system to distinguish between two closely spaced objects along the direction of the ultrasound beam. It is determined by the spatial pulse length, which is the distance that an ultrasound pulse occupies in the axial direction. In this case, the spatial pulse length is given as 10mm. The axial resolution is typically half of the spatial pulse length, so the axial resolution would be 0.5 cm.

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  • 4. 

    The more bits per pixel

    • The better the resolution

    • The higher the pixel density

    • The more shades of gray

    • Higher reliability

    Correct Answer
    A. The more shades of gray
    Explanation
    The statement suggests that the more bits per pixel, the better the resolution. This is because a higher number of bits allows for a greater range of colors or shades to be represented, resulting in a more detailed and accurate image. Therefore, the more shades of gray can be displayed, indicating a higher level of resolution and image quality. The other options mentioned in the question, such as pixel density and reliability, are not directly related to the number of bits per pixel.

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  • 5. 

    Refraction only occurs if there is :

    • Normal incidence and different impedances

    • Indirect intensity and differenct propagation speeds

    • Oblique incidence and different propagation speeds

    • Oblique frequency and identical impedances

    Correct Answer
    A. Oblique incidence and different propagation speeds
    Explanation
    Refraction occurs when light passes from one medium to another with a different propagation speed, and when the incident light is at an oblique angle. In this case, the correct answer states that refraction only occurs when there is oblique incidence (light hitting the interface at an angle) and different propagation speeds between the two mediums. This is because the change in speed causes the light to change direction as it enters the second medium, resulting in refraction.

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  • 6. 

    If the frequency of an US wave is doubled, what happens to the period?

    • Doubles

    • Halved

    • Remains the same

    • 4 times greater

    Correct Answer
    A. Halved
    Explanation
    When the frequency of an ultrasound wave is doubled, the period of the wave is halved. The frequency of a wave refers to the number of complete cycles of the wave that occur in one second, while the period refers to the time it takes for one complete cycle to occur. Since frequency and period are inversely related, doubling the frequency will result in halving the period. This means that the time it takes for one complete cycle of the wave to occur will be reduced by half when the frequency is doubled.

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  • 7. 

    Enhancement, multipath and side lobes result in:

    • Image distortion

    • Clearer images

    • Artifact

    • Resolution problems

    Correct Answer
    A. Artifact
    Explanation
    Enhancement, multipath, and side lobes can result in artifacts. These artifacts are unwanted distortions or anomalies that appear in images. They can be caused by various factors such as signal interference, improper image processing, or limitations in the imaging system. Artifacts can degrade the quality and accuracy of the images, making them less reliable for analysis or diagnosis. Therefore, the presence of enhancement, multipath, and side lobes can introduce artifacts in the images.

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  • 8. 

    Shadowing may result from high amounts of reflection of US energy.

    • True

    • False

    Correct Answer
    A. True
    Explanation
    Shadowing occurs when there is a high amount of reflection of ultrasound (US) energy. When there is a significant reflection of US energy, it can create areas of reduced or absent signal, resulting in shadowing. This can happen when the US beam encounters highly reflective structures such as bones or air interfaces. Therefore, the statement that shadowing may result from high amounts of reflection of US energy is true.

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  • 9. 

    The manufacturer increases the number of lines per frame.  As a result, which of the following may have to decreased. FRAME RATE (TRUE OR FALSE)

    • True

    • False

    Correct Answer
    A. True
    Explanation
    When the manufacturer increases the number of lines per frame, it means that more information is being displayed in each frame. This increase in information can put a strain on the system's processing power and resources. To compensate for this, the frame rate may have to be decreased. This is because the system may not be able to handle the increased workload of processing more lines per frame at the same frame rate as before. Therefore, the statement "True" is correct.

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  • 10. 

    The gray scale can be changed by the sonographer

    • True

    • Fales

    Correct Answer
    A. True
    Explanation
    The given statement is true because the grayscale in ultrasound imaging can be adjusted by the sonographer. This allows them to manipulate the brightness and contrast levels, enhancing the visibility of different tissues and structures in the image. By changing the grayscale, the sonographer can optimize the image quality and improve the accuracy of their diagnosis.

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  • 11. 

    Multiple reflections that are equally spaced are called:

    • Refractions

    • Reverberations

    • Shadows

    • Comets

    Correct Answer
    A. Reverberations
    Explanation
    Reverberations are multiple reflections that are equally spaced. When sound waves bounce off surfaces and create echoes, they can produce a series of reflections that occur at regular intervals. This phenomenon is known as reverberation. It is commonly experienced in large enclosed spaces, such as concert halls or caves, where sound waves bounce off walls, ceilings, and floors, creating a prolonged and sustained sound.

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  • 12. 

    What determines the frequency of a sound beam from a pulsed transducer?

    • Voltage applied to the PZT

    • PZT thickness

    • Frequency of the system

    • PRF of the pulser

    Correct Answer
    A. PZT thickness
    Explanation
    The frequency of a sound beam from a pulsed transducer is determined by the PZT thickness. The PZT (lead zirconate titanate) is a piezoelectric material that converts electrical energy into mechanical vibrations. The thickness of the PZT determines the resonant frequency at which it vibrates. Therefore, by adjusting the thickness of the PZT, the frequency of the sound beam can be controlled.

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  • 13. 

    Which has the greatest amount of attenuation?

    • Bone

    • Fat

    • Water

    • Muscle

    Correct Answer
    A. Bone
    Explanation
    Bone has the greatest amount of attenuation compared to fat, water, and muscle. Attenuation refers to the reduction in intensity of a signal as it passes through a medium. Bone is denser and has a higher atomic number compared to the other options, causing it to absorb and scatter more of the signal, resulting in a higher level of attenuation.

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  • 14. 

    The more pixels per inch:

    • The better the temporal resolution

    • The better the spatial resolution

    • The more shades of gray

    • The higher the reliability

    Correct Answer
    A. The better the spatial resolution
    Explanation
    The statement suggests that as the number of pixels per inch increases, the spatial resolution improves. Spatial resolution refers to the level of detail that can be observed in an image, and it is directly influenced by the number of pixels. Therefore, a higher number of pixels per inch would result in a clearer and more detailed image, leading to better spatial resolution.

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  • 15. 

    Refraction only occurs if there is :

    • Normal incidence and differenct impedances

    • Indirect intensity and differenct propagation speeds

    • Oblique incidence and different propagation speeds

    • Oblique frequency and identical impedances

    Correct Answer
    A. Oblique incidence and different propagation speeds
    Explanation
    Refraction occurs when light waves pass from one medium to another medium with a different propagation speed. In this case, the correct answer states that refraction only occurs when there is oblique incidence (angle of incidence is not 90 degrees) and different propagation speeds between the two mediums. This means that when light enters a medium at an angle and the speed of light changes as it travels through the medium, refraction will occur.

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  • 16. 

    Which is not an acoustic variable?

    • Density

    • Pressure

    • Distance

    • Intensity

    Correct Answer
    A. Intensity
    Explanation
    Intensity is not an acoustic variable because it refers to the power or energy of a sound wave per unit area. Acoustic variables, on the other hand, are physical quantities that can be directly measured or calculated from the properties of a sound wave, such as density, pressure, and distance. Intensity is derived from these variables and represents the strength or loudness of the sound wave.

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  • 17. 

    Put these intensities in decreasing order

    • SATP

    • SPTP

    • SATA

    • SPTP, SATP, SATA

    • SPTP SATA, SATP

    Correct Answer
    A. SPTP, SATP, SATA
    Explanation
    The given answer suggests that the intensities should be arranged in decreasing order. Among the options provided, "SPTP" has the highest intensity, followed by "SATP", and finally "SATA" with the lowest intensity. Therefore, the correct order is "SPTP, SATP, SATA".

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  • 18. 

    What is the approximate attenuation coefficient of 1MHz US in soft tissue?

    • 0.5 dBcm

    • 1cm

    • 3dBcm

    • 1dB

    Correct Answer
    A. 0.5 dBcm
    Explanation
    The approximate attenuation coefficient of 1MHz US in soft tissue is 0.5 dBcm. Attenuation coefficient refers to the rate at which ultrasound waves decrease in intensity as they pass through a medium. In soft tissue, the attenuation coefficient at 1MHz is approximately 0.5 dB per centimeter of distance traveled. This means that for every centimeter the ultrasound waves travel in soft tissue, their intensity decreases by 0.5 dB.

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  • 19. 

    If the frequency is decreased, the numerical value of the radial resolution is

    • Increased

    • Decreased

    • Unchanges

    Correct Answer
    A. Increased
    Explanation
    When the frequency is decreased, the numerical value of the radial resolution is increased. Radial resolution refers to the ability to distinguish between two closely spaced objects in an imaging system. A higher numerical value indicates a better resolution, meaning that the system can differentiate between objects that are closer together. Therefore, when the frequency is decreased, the system can better distinguish between closely spaced objects, resulting in an increased radial resolution.

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  • 20. 

    The time from the beginning of a pulse until its end is__________?

    • Period

    • Pulse duration

    • Pulse length

    • PRF

    Correct Answer
    A. Pulse duration
    Explanation
    The time from the beginning of a pulse until its end is referred to as the pulse duration. This term specifically measures the length of time that a pulse signal remains active or "on" before it turns off. It is different from the pulse length, which typically refers to the physical length or spatial extent of the pulse. The period, on the other hand, represents the time taken for one complete cycle of a repetitive waveform, while PRF stands for Pulse Repetition Frequency, which measures the number of pulses occurring in one second.

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  • 21. 

    If we increase the frequency the near zone length is

    • Increased

    • Decreased

    • Unchanges

    Correct Answer
    A. Increased
    Explanation
    Increasing the frequency of a wave causes the near zone length to increase. The near zone is the region close to the source where the wave is still undergoing changes and has not fully developed into a far-field wave. As the frequency increases, the wavelength decreases, resulting in a shorter distance for the wave to fully develop. This causes the near zone length to increase as the wave takes longer to reach the far-field.

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  • 22. 

    If we increase the frequency, the near zone length is

    • Increased

    • Decreased

    • Unchanged

    Correct Answer
    A. Increased
    Explanation
    Increasing the frequency of a wave leads to a decrease in its wavelength. As the wavelength decreases, the near zone length, which is the distance from the source where the wave is still in its near field, increases. This means that as the frequency increases, the near zone length is increased.

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  • 23. 

    The digital scan converter has a number of pixels assigned to each bit.

    • True

    • False

    Correct Answer
    A. False
    Explanation
    The statement is false because the digital scan converter does not have a specific number of pixels assigned to each bit. The digital scan converter is responsible for converting analog signals into digital signals and storing them in memory. It does not assign a fixed number of pixels to each bit, as the number of pixels can vary depending on the resolution of the display device.

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  • 24. 

    From a safety standpoint, which one of the following methods is best?

    • Low transmitter output and high receiver gain

    • High transmitter output and low receiver gain

    • High near gain and low far gain

    • Low near gain and high far gain

    • High reject and high transmitter output

    Correct Answer
    A. Low transmitter output and high receiver gain
    Explanation
    A low transmitter output and high receiver gain is the best method from a safety standpoint because it allows for a stronger signal to be received while minimizing the risk of interference or overload. This ensures that the receiver can accurately detect and interpret the incoming signal, reducing the chances of errors or miscommunication. Additionally, a lower transmitter output helps to conserve power and minimize the potential for electromagnetic interference with other devices. Overall, this method prioritizes safety by optimizing signal reception and minimizing potential risks.

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  • 25. 

    If the transducer diameter increases, the lateral resolution at its smalles dimension is

    • Increased

    • Decreased

    • Unchanged

    Correct Answer
    A. Increased
    Explanation
    When the transducer diameter increases, the lateral resolution at its smallest dimension is increased. This is because a larger transducer diameter allows for a narrower beam width, resulting in improved lateral resolution. A narrower beam width means that the ultrasound waves are more focused and can better distinguish small structures or details in the imaging area. Therefore, increasing the transducer diameter enhances the ability to resolve fine details and improves the lateral resolution.

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  • 26. 

    The wavelength of a cycle in an ultrasound wave can be reported with which units?

    • Units of time (seco, min, etc)

    • Units of distance (feet, cm)

    • Units of area (m^2, etc

    • Mm only

    Correct Answer
    A. Units of distance (feet, cm)
    Explanation
    Ultrasound waves are a type of mechanical waves that travel through a medium, such as air or water. The wavelength of a wave is the distance between two consecutive points in the wave that are in phase, or have the same position in their cycle. In the case of ultrasound waves, the wavelength is the distance between two consecutive compressions or rarefactions. Since distance is the measure of length between two points, the wavelength of a cycle in an ultrasound wave can be reported with units of distance, such as feet or centimeters.

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  • 27. 

    For Doppler, which incident angle results in no shift?

    • 180 degrees

    • 90 degrees

    • 0 degree

    • 45 degrees

    Correct Answer
    A. 90 degrees
    Explanation
    When it comes to Doppler effect, the incident angle that results in no shift is 90 degrees. This means that when the source of the waves and the observer are perpendicular to each other, there will be no change in frequency or wavelength observed. At this angle, the waves are neither compressed nor stretched, resulting in no shift in the frequency.

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  • 28. 

    All of the following are true EXCEPT:

    • Two waves with identical frequencies must interfere constructively

    • Constructive interference is associated with waves that are in phase

    • Out of phase waves interfere destructively

    • Waves of different frequencies may exhibit both contructive and destructive interference at different times

    Correct Answer
    A. Two waves with identical frequencies must interfere constructively
    Explanation
    This statement is not true because two waves with identical frequencies can interfere both constructively and destructively depending on their phase relationship. If the waves are in phase, they will interfere constructively, but if they are out of phase, they will interfere destructively.

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  • 29. 

    Doppler shifts always occur if the source and observer are in motion relative to each other and the angle between the motion and the sound beam is not 90 degrees.

    • True

    • False

    Correct Answer
    A. True
    Explanation
    The Doppler effect is a phenomenon that occurs when there is relative motion between a source of sound waves and an observer. It causes a shift in the frequency of the sound waves heard by the observer. This shift in frequency, known as the Doppler shift, can be either an increase or decrease depending on the relative motion. However, for the Doppler shift to occur, it is necessary that the angle between the motion of the source and observer and the sound beam is not 90 degrees. Therefore, the statement that Doppler shifts always occur if the source and observer are in motion relative to each other and the angle between the motion and the sound beam is not 90 degrees is true.

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  • 30. 

    Increasing the frequency increases the penetration depth.

    • True

    • False

    Correct Answer
    A. False
    Explanation
    Increasing the frequency does not increase the penetration depth. In fact, higher frequency waves have shorter wavelengths and are more easily absorbed or scattered by objects they encounter, resulting in shallower penetration. Lower frequency waves, on the other hand, have longer wavelengths and can penetrate deeper into materials. Therefore, the statement is false.

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  • 31. 

    If we increase the transducer diameter, the beam diameter in the far zone is

    • Increased

    • Decreased

    • Unchanges

    Correct Answer
    A. Decreased
    Explanation
    When the transducer diameter is increased, the beam diameter in the far zone is decreased. This is because the transducer acts as the source of the ultrasound beam, and a larger transducer diameter means that the beam will spread out less as it propagates in the far zone. As a result, the beam becomes narrower and the diameter decreases.

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  • 32. 

    What component of the US unit contains the memory bank?

    • Transducer

    • Receiver

    • Display

    • Scan converter

    Correct Answer
    A. Scan converter
    Explanation
    The scan converter is the component of the US unit that contains the memory bank. It is responsible for converting the electrical signals received from the transducer into a format that can be displayed on the screen. The scan converter stores and processes the data received from the transducer, allowing for the creation of the ultrasound image. The receiver is responsible for amplifying and digitizing the signals, while the display is where the final image is shown. Therefore, the correct answer is scan converter.

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  • 33. 

    The manufacturer increases the number of lines per frame.  As a result, which of the following may have to decreased. Power Output

    • True

    • False

    Correct Answer
    A. False
    Explanation
    Increasing the number of lines per frame does not necessarily mean that the power output has to be decreased. The two variables are not directly related, so it is possible for the power output to remain the same or even increase despite the increase in the number of lines per frame. Therefore, the statement is false.

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  • 34. 

    What artifact has a grainy appearance and is caused by the interference effects of scattered sound?

    • Spackle

    • Reverberation

    • Slice tickness

    • Speckle

    • Section thickness

    Correct Answer
    A. Speckle
    Explanation
    Speckle is the correct answer because it refers to an artifact that has a grainy appearance and is caused by the interference effects of scattered sound. When sound waves scatter and interfere with each other, they create a speckled pattern, resulting in a grainy appearance. This phenomenon is commonly observed in ultrasound imaging, where speckle can affect the clarity and quality of the image.

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  • 35. 

    Two waves arrive at the same location and interfere.  The resultant sound wave is smaller that either of the two original waves.  What is this called?

    • Constructive interference

    • Angular interaction

    • Destructive interference

    • In-phase waves

    Correct Answer
    A. Destructive interference
    Explanation
    Destructive interference occurs when two waves combine in such a way that they cancel each other out, resulting in a smaller wave or no wave at all. In this scenario, the two waves arriving at the same location interfere destructively, leading to a resultant sound wave that is smaller than either of the original waves.

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  • 36. 

    If the frequency of US is increased from 0.77 MHz to 1.54 MHz, what happens to the wavelength?

    • Doubles

    • Halved

    • Remains the same

    • 4 times greater

    Correct Answer
    A. Halved
    Explanation
    When the frequency of a wave increases, the wavelength decreases. This is because wavelength and frequency are inversely proportional to each other. Therefore, if the frequency of US is increased from 0.77 MHz to 1.54 MHz, the wavelength will be halved.

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  • 37. 

    All of the following will improve temporal resolution EXCEPT

    • Increased line density

    • Single rather than multi focus

    • Higher frame rate

    • Shallower depth of view

    • Slower speed of sound in a medium

    Correct Answer
    A. Increased line density
    Explanation
    Increasing line density will actually improve temporal resolution. Temporal resolution refers to the ability to accurately capture and display fast-moving objects or changes over time. By increasing line density, more information can be captured and displayed in each frame, resulting in a higher temporal resolution. Therefore, the correct answer is that increasing line density will not decrease temporal resolution.

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  • 38. 

    The duty factor for continuous wave ultrasound is

    • 10.0

    • 1%

    • 1.0

    • 0.0%

    Correct Answer
    A. 1.0
    Explanation
    The duty factor for continuous wave ultrasound refers to the percentage of time that the ultrasound wave is actually being transmitted. A duty factor of 1.0 means that the ultrasound wave is being transmitted for 100% of the time, indicating a continuous transmission without any interruptions or pauses.

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  • 39. 

    Is Intensity an acoustic variable?

    • True

    • False

    Correct Answer
    A. False
    Explanation
    Intensity is not an acoustic variable. Acoustic variables are physical properties that describe sound waves, such as frequency, amplitude, and wavelength. Intensity, on the other hand, is a measure of the power or energy carried by a sound wave per unit area. It is not considered a fundamental acoustic variable, but rather a derived quantity that depends on the amplitude of the wave. Therefore, the statement "Intensity is an acoustic variable" is false.

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  • 40. 

    True of False:  With standard diagnostic imaging instrumentation, the sonographer has the ability to vary the amplitude of a sound wave produced by the transducer.

    • Ture

    • False

    Correct Answer
    A. Ture
    Explanation
    With standard diagnostic imaging instrumentation, the sonographer has the ability to vary the amplitude of a sound wave produced by the transducer. This means that the sonographer can adjust the strength or intensity of the sound wave that is being emitted. This ability is important because it allows the sonographer to optimize the imaging process by adjusting the amplitude according to the specific needs of the patient and the area being examined. By varying the amplitude, the sonographer can control the depth of penetration and the resolution of the resulting image.

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  • 41. 

    (TRUE OR FALSE) The power in the wave increases as it travels through the mass. (An ultrasound pulse propagates from soft tissue through a mass.  Sound's propagation speed in the mass is 1575 m/s.)

    • True

    • False

    Correct Answer
    A. False
    Explanation
    The power in a wave does not increase as it travels through a mass. In fact, as a wave propagates through a medium, it tends to lose energy due to various factors such as absorption, scattering, and reflection. Therefore, the power of the wave decreases as it travels through the mass.

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  • 42. 

    Which of the following sound waves is ultrasonic and least useful in diagnostic imaging?

    • 30 KHz

    • 8 MHz

    • 8,000 Hz

    • 3,000 kHz

    • 15 Hz

    Correct Answer
    A. 30 KHz
    Explanation
    Ultrasonic sound waves refer to sound waves with frequencies above the range of human hearing, typically above 20 kHz. Diagnostic imaging techniques like ultrasound use sound waves in the MHz range, such as 8 MHz, to produce detailed images of internal structures. Therefore, the sound wave with a frequency of 30 KHz is ultrasonic but least useful in diagnostic imaging as it falls below the typical range used for this purpose.

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  • 43. 

    Which of the following sound waves is ultrasonic and least useful in diagnostic imaging?

    • 30 KHZ

    • 8 MHz

    • 8,000 Hz

    • 3,000 kHz

    • 15 Hz

    Correct Answer
    A. 30 KHZ
    Explanation
    Ultrasonic sound waves have a frequency greater than 20,000 Hz. Among the given options, the sound wave with a frequency of 30 KHz is ultrasonic. Diagnostic imaging typically uses sound waves with frequencies in the range of 1-20 MHz, so the sound wave with a frequency of 30 KHz would be least useful in diagnostic imaging.

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  • 44. 

    If a reflector is moved twice as far away from the tranducer, how will this affect the time of flight of a sound pulse?

    • Quadruple it

    • Double it

    • No change

    • Halve it

    Correct Answer
    A. Double it
    Explanation
    When a reflector is moved twice as far away from the transducer, the time of flight of a sound pulse will double. This is because the time of flight is directly proportional to the distance traveled by the sound pulse. When the reflector is moved twice as far away, the distance traveled by the sound pulse also doubles, resulting in a doubling of the time taken for the pulse to reach the reflector and return to the transducer.

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  • 45. 

    _____________ is the distance covered by one cycle

    • Pulse length

    • Wavelength

    • Cycle distance

    • Cycle duration

    Correct Answer
    A. Wavelength
    Explanation
    The correct answer is "wavelength". Wavelength refers to the distance between two consecutive points in a wave that are in phase. It is commonly used to measure the distance covered by one complete cycle of a wave, whether it is a sound wave, electromagnetic wave, or any other type of wave. The wavelength is an important characteristic of a wave and is often used to determine various properties of the wave, such as its frequency and speed.

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  • 46. 

    If the frequency is decreased, the numberical value of the radial resolution is

    • Increased

    • Decreased

    • Unchanged

    Correct Answer
    A. Increased
    Explanation
    When the frequency is decreased, the numerical value of the radial resolution is increased. Radial resolution refers to the ability to distinguish between two closely spaced objects in an imaging system. A higher numerical value indicates a better ability to distinguish between these objects, meaning that the resolution is improved. Therefore, when the frequency is decreased, the radial resolution is increased.

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  • 47. 

    What information does Doppler shift provide?

    • Flow

    • Cardiac out put

    • Velocity

    • Speed

    Correct Answer
    A. Velocity
    Explanation
    Doppler shift provides information about velocity. Doppler shift is the change in frequency or wavelength of a wave as observed by an observer moving relative to the source of the wave. In the context of medicine, Doppler shift is commonly used to measure the velocity of blood flow in the body. By analyzing the change in frequency of sound waves reflected by moving blood cells, Doppler ultrasound can provide information about the velocity of blood flow in different areas of the body. Therefore, velocity is the information that Doppler shift provides.

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  • 48. 

    If a wave's amplitude is doubled, what happens to the power?

    • Nothing

    • Halved

    • Dpib;ed

    • Quadrupled

    Correct Answer
    A. Quadrupled
    Explanation
    When a wave's amplitude is doubled, the power of the wave is quadrupled. This is because power is directly proportional to the square of the amplitude. Therefore, if the amplitude is doubled, the power will increase by a factor of four.

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  • 49. 

    If the spatial pulse length is 10 mm, what is the axial resolution?

    • 0.5 cm

    • 5 cm

    • 10 mm

    • 1 cm

    Correct Answer
    A. 0.5 cm
    Explanation
    The axial resolution of an ultrasound system is determined by the spatial pulse length, which is the distance covered by one pulse. In this case, the spatial pulse length is given as 10 mm. The axial resolution is typically half of the spatial pulse length, so the axial resolution would be 0.5 cm.

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Matt Balanda |BS (Aerospace Engineering) |
Science Teacher
Matt Balanda, a Calvary Chapel Christian School leader with a Bachelor's in Aerospace Engineering and Mathematics, transitioned from Aerospace Engineering to Education with a Master's from California Baptist University. As the High School Vice-Principal and Physics teacher, he nurtures students' love of learning and faith, creating an enriching and transformational educational experience.

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