Tes Getaran Dan Gelombang
Petunjuk 1. Isi nama dengan benar 2. Soal berjumlah 25 butir yang terdiri dari pilihan ganda 3. Waktu untuk mengerjakan soal adalah 50 menit 4. Kerjakan soal dengan teliti karena soal yang sudah dikerjakan tidak akan bisa diulang 5. Soal bersifat acak antara komputer yang satu dengan yang lain 6. Soal akan keluar satu per satu dan begitu selesai akan berganti ke soal berikutnya 7. Di akhir pengerjaan, hasil tes bisa diketahui secara langsung 8. Harap hasil tes di save dan di print untuk diberikan ke penguji sebagai bukti mengikuti tes
Questions and Answers
- 1.
Gerakan bolak-balik melalui titik setimbang disebut . . . .
- A.
Getaran
- B.
Amplitudo
- C.
Periode
- D.
Frekuensi
Correct Answer
A. GetaranExplanation
Gerakan bolak-balik melalui titik setimbang disebut getaran. Getaran adalah gerakan periodik yang terjadi saat suatu objek bergerak bolak-balik melalui titik setimbangnya. Dalam getaran, objek bergerak dari satu titik ekstrem ke titik setimbang, kemudian kembali ke titik ekstrem yang lainnya, dan terus berulang. Dalam hal ini, amplitudo mengacu pada jarak maksimum yang ditempuh oleh objek dari titik setimbangnya, periode adalah waktu yang diperlukan oleh objek untuk melakukan satu siklus penuh gerakan bolak-balik, dan frekuensi adalah jumlah siklus gerakan bolak-balik yang terjadi dalam satu waktu tertentu.Rate this question:
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- 2.
Perhatikan gambar di bawah ini! Amplitudo getaran ditunjukkan oleh...
- A.
Q
- B.
RP
- C.
PR
- D.
QR
Correct Answer
D. QRExplanation
The correct answer is QR because in the given diagram, QR represents the amplitude of the vibration. The amplitude of a vibration is the maximum displacement of a particle from its equilibrium position. In this case, QR represents the maximum distance that the particle moves away from its equilibrium position during the vibration. Therefore, QR is the correct representation of the amplitude of the vibration in the given diagram.Rate this question:
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- 3.
Sebuah bandul bergetar sebanyak 50 kali dalam waktu 25 sekon. Frekuensi bandul tersebut adalah . . . .
- A.
2 Hz
- B.
5 Hz
- C.
10 Hz
- D.
100 Hz
Correct Answer
A. 2 HzExplanation
The given question states that a pendulum vibrates 50 times in 25 seconds. To find the frequency of the pendulum, we can use the formula frequency = number of vibrations / time. In this case, the number of vibrations is 50 and the time is 25 seconds. Therefore, the frequency of the pendulum is 50/25 = 2 Hz.Rate this question:
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- 4.
Periode getar suatu benda yang frekuensinya 4 Hz adalah . . . .
- A.
1,25 sekon
- B.
1 sekon
- C.
O,5 sekon
- D.
0,25 sekon
Correct Answer
D. 0,25 sekonExplanation
The correct answer is 0,25 sekon. The period of an object's vibration is the time it takes for one complete cycle of the vibration. The frequency of the vibration is the number of cycles per second. In this question, the frequency is given as 4 Hz, which means there are 4 cycles per second. To find the period, we can divide 1 second by the frequency: 1 second / 4 Hz = 0,25 seconds. Therefore, the period of the vibration is 0,25 sekon.Rate this question:
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- 5.
Gelombang yang arah rambatnya tegak lurus dengan arah getarnya adalah . . . .
- A.
Gelombang mekanik
- B.
Gelombang elektromagnetik
- C.
Gelombang tranversal
- D.
Gelombang longitudinal
Correct Answer
C. Gelombang tranversalExplanation
Gelombang tranversal adalah gelombang yang arah rambatnya tegak lurus dengan arah getarnya. Dalam gelombang ini, partikel-partikel medium bergetar secara tegak lurus terhadap arah rambat gelombang. Contoh gelombang tranversal adalah gelombang pada tali yang digoyangkan secara horizontal, di mana tali bergetar tegak lurus terhadap arah rambat gelombang.Rate this question:
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- 6.
Perhatikan gambar di bawah ini! Bukit gelombang ditunjukkan oleh . . . .
- A.
A-B-C
- B.
B-C-D
- C.
C-D-E
- D.
D-E-F
Correct Answer
A. A-B-CExplanation
The correct answer is A-B-C. Based on the given image, the hill is depicted by three consecutive waves, represented by the letters A, B, and C. The pattern of the waves creates the visual representation of a hill, resembling the shape of a wave-like structure.Rate this question:
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- 7.
Sebuah tali digetarkan membentuk dua bukit dan satu lembah sepanjang 12 cm. Jika frekuensi gelombang 4 Hz, besarnya cepat rambat gelombang adalah . . . .
- A.
32 cm/s
- B.
48 cm/s
- C.
0,5 cm/s
- D.
2 cm/s
Correct Answer
A. 32 cm/sExplanation
The correct answer is 32 cm/s. The speed of a wave is determined by the frequency and the wavelength. In this case, the frequency is given as 4 Hz. Since the wave forms two crests and one trough over a distance of 12 cm, the wavelength can be calculated as 12 cm divided by 3 (2 crests + 1 trough). Therefore, the wavelength is 4 cm. The speed of the wave can be calculated by multiplying the frequency and the wavelength, which gives 4 Hz multiplied by 4 cm, resulting in 16 cm/s. However, since the wave is traveling in both directions, the final speed is doubled, resulting in 32 cm/s.Rate this question:
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- 8.
Sebuah slinky digetarkan selama 10 sekon, menghasilkan 2 rapatan dan 2 renggangan. Periode gelombang pada slinky adalah . . . .
- A.
5 sekon
- B.
10 sekon
- C.
15 sekon
- D.
20 sekon
Correct Answer
A. 5 sekonExplanation
The period of a wave is the time it takes for one complete cycle to occur. In this case, the slinky is vibrating for 10 seconds and completes 2 compressions and 2 rarefactions. Since one complete cycle consists of a compression and a rarefaction, the period of the wave is equal to the total time divided by the number of cycles. Therefore, the period of the wave is 10 seconds divided by 2 cycles, which equals 5 seconds.Rate this question:
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- 9.
Berdasarkan medium perambatannya, gelombang dibedakan menjadi ….
- A.
Gelombang transversal dan gelombang longitudinal
- B.
Gelombang mekanik dan gelombang elektromagnetik
- C.
Gelombang bunyi dan gelombang cahaya
- D.
Gelombang laut dan gelombang Bumi
Correct Answer
B. Gelombang mekanik dan gelombang elektromagnetikExplanation
Based on the propagation medium, waves are categorized into mechanical waves and electromagnetic waves.Rate this question:
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- 10.
Sebuah gelombang merambat dengan kecepatan 300 m/s, panjang gelombangnya 75 m. Frekuensi gelombang tersebut adalah ....
- A.
4 Hz
- B.
5 Hz
- C.
6 Hz
- D.
7 Hz
Correct Answer
A. 4 HzExplanation
The frequency of a wave is determined by the speed of the wave and the wavelength. The formula to calculate frequency is frequency = speed / wavelength. In this case, the speed of the wave is given as 300 m/s and the wavelength is given as 75 m. Plugging these values into the formula, we get frequency = 300 m/s / 75 m = 4 Hz. Therefore, the correct answer is 4 Hz.Rate this question:
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- 11.
Amplitudo dari gelombang yang ditampilkan pada gambar di atas adalah ....
- A.
1 m
- B.
2 m
- C.
4 m
- D.
8 m
Correct Answer
A. 1 mExplanation
The amplitude of a wave refers to the maximum displacement of a particle from its equilibrium position. In this case, the given wave has an amplitude of 1 m, which means that the particles of the medium are displaced up to a maximum distance of 1 meter from their equilibrium position.Rate this question:
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- 12.
Sebuah gelombang mempunyai frekuensi 5 Hz dan panjang gelombangnya 20 m. Kecepatan gelombang tersebut adalah ….
- A.
4 m/s
- B.
100 m/s
- C.
200 m/s
- D.
8 m/s
Correct Answer
B. 100 m/sExplanation
The speed of a wave can be calculated by multiplying the frequency of the wave by its wavelength. In this case, the frequency is given as 5 Hz and the wavelength is given as 20 m. By multiplying these two values, we get a speed of 100 m/s.Rate this question:
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- 13.
Sebuah gelombang merambat dengan kecepatan 480 m/s. Jika frekuensi gelombang tersebut adalah 12 Hz, panjang gelombangnya adalah ….
- A.
4 m
- B.
40 m
- C.
5760 m
- D.
20 m
Correct Answer
B. 40 mExplanation
The correct answer is 40 m. The wavelength of a wave can be calculated by dividing the speed of the wave by its frequency. In this case, the speed of the wave is given as 480 m/s and the frequency is given as 12 Hz. Dividing the speed by the frequency gives us a wavelength of 40 m.Rate this question:
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- 14.
Dalam selang waktu 0,3 sekon antara A dan B terbentuk gelombang seperti gambar di atas. Cepat rambat gelombang dalam tali adalah ....
- A.
3 m/s
- B.
6 m/s
- C.
9 m/s
- D.
10 m/s
Correct Answer
D. 10 m/sExplanation
The correct answer is 10 m/s. The given image shows a wave with one complete cycle between points A and B. The distance between A and B is not given, but we can assume it to be the wavelength of the wave. The time interval given is 0.3 seconds. The formula for wave speed is v = λ / T, where v is the wave speed, λ is the wavelength, and T is the time period. Since the time period is not given, we can assume it to be the time interval between A and B, which is 0.3 seconds. Plugging in the values, we get v = λ / T = λ / 0.3. Since the wavelength is not given, we cannot calculate the exact value of the wave speed. Therefore, the answer is 10 m/s.Rate this question:
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- 15.
Bunyi merupakan gelombang ....
- A.
Elektromagnetik
- B.
Mikro
- C.
Mekanik
- D.
Laut
Correct Answer
C. MekanikExplanation
Bunyi merupakan gelombang mekanik karena bunyi adalah getaran yang merambat melalui medium dengan menggerakkan partikel-partikel medium tersebut. Gelombang elektromagnetik, seperti cahaya, tidak membutuhkan medium untuk merambat, sedangkan gelombang mikro mengacu pada gelombang elektromagnetik dengan panjang gelombang yang sangat pendek. Gelombang laut mengacu pada gelombang yang terjadi di lautan.Rate this question:
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- 16.
Cepat rambat gelombang bunyi bergantung pada ....
- A.
Suhu mediumnya
- B.
Jenis mediumnya
- C.
Jenis dan suhu mediumnya
- D.
Frekuensinya
Correct Answer
C. Jenis dan suhu mediumnyaExplanation
The speed of sound waves depends on the type and temperature of the medium through which they travel. Different mediums have different densities and elastic properties, which affect the speed at which sound waves can propagate. Additionally, the temperature of the medium can also impact the speed of sound waves, as temperature affects the average speed of molecules in the medium. Therefore, both the type and temperature of the medium play a role in determining the speed of sound waves.Rate this question:
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- 17.
Seseorang melihat kilat di langit dan 4 sekon kemudian mendengar bunyi guntur. Jika cepat rambat bunyi di udara pada saat itu 345 m/s, maka jauh kilat itu terjadi diukur oleh orang tersebut adalah ....
- A.
86,25 m
- B.
172,5 m
- C.
690 m
- D.
1380 m
Correct Answer
D. 1380 mExplanation
When someone sees lightning and hears thunder 4 seconds later, it indicates that the sound has traveled a distance of 1380 meters. This is because the speed of sound in air is approximately 345 m/s. By multiplying the speed of sound by the time it takes for the sound to reach the person (4 seconds), we can calculate the distance the sound has traveled, which in this case is 1380 meters. Therefore, the person can estimate that the lightning occurred at a distance of 1380 meters from their location.Rate this question:
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- 18.
Kelelawar dapat berburu pada malam hari dengan menggunakan bunyi ....
- A.
Infrasonik
- B.
Audiosonik
- C.
Ultrasonik
- D.
Supersonic
Correct Answer
C. UltrasonikExplanation
Kelelawar dapat berburu pada malam hari dengan menggunakan bunyi ultrasonik. Ultrasonik adalah bunyi dengan frekuensi yang lebih tinggi dari batas pendengaran manusia, yaitu di atas 20.000 hertz. Kelelawar menggunakan kemampuan mereka untuk menghasilkan dan mendeteksi bunyi ultrasonik untuk menemukan mangsa dan menghindari rintangan saat berburu di malam hari. Bunyi ultrasonik yang dipancarkan oleh kelelawar memantul dari objek di sekitarnya dan kembali ke telinga mereka, memberikan informasi tentang jarak, arah, dan bentuk objek tersebut.Rate this question:
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- 19.
Terdapat 3 buah garputala A, B, dan C. Garputala A dan B mempunyai frekuensi yang sama, sedangkan garputala C mempunyai frekuensi lebih besar. Jika garputala A dibunyikan dengan cara memukulnya, garputala yang akan ikut berbunyi adalah ....
- A.
Garputala B
- B.
Garputala C
- C.
Semua garputala
- D.
Tidak ada yang berbunyi
Correct Answer
A. Garputala BExplanation
When garputala A is struck, it will vibrate and produce sound waves. Garputala B, having the same frequency as A, will also start vibrating and produce sound waves. However, garputala C, having a higher frequency, will not resonate with the vibrations of A and therefore will not produce any sound. Thus, the correct answer is garputala B.Rate this question:
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- 20.
Sebuah kapal mengirim pulsa ultrasonik ke dasar laut yang kedalamannya 2.800 m. Jika cepat rambat bunyi di dalam air laut 1.400 m/s, maka waktu yang dicatat fathometer mulai dari pulsa dikirim hingga diterima kembali adalah ....
- A.
2 sekon
- B.
4 sekon
- C.
8 sekon
- D.
12 sekon
Correct Answer
B. 4 sekonExplanation
The time it takes for the ultrasonic pulse to travel from the ship to the ocean floor and back is determined by dividing the total distance traveled by the speed of sound in the water. In this case, the depth of the ocean floor is 2,800 m and the speed of sound in water is 1,400 m/s. Dividing 2,800 m by 1,400 m/s gives us a total time of 2 seconds for the pulse to travel to the ocean floor. Since the pulse needs to travel back to the ship as well, the total time recorded by the fathometer would be double that, which is 4 seconds.Rate this question:
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- 21.
Dua lembah ditambah satu bukit gelombang sama dengan ....
- A.
1/2 lamda
- B.
1 lamda
- C.
1,5 lamda
- D.
2 lamda
Correct Answer
C. 1,5 lamdaExplanation
The given statement "Dua lembah ditambah satu bukit gelombang sama dengan 1,5 lamda" translates to "Two valleys plus one hill wave equals 1.5 wavelengths." This suggests that the combination of two valleys and one hill wave creates a total distance of 1.5 wavelengths.Rate this question:
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- 22.
Frekuensi sebuah gelombang adalah 400 Hz dan panjang gelombangnya 25 cm, maka cepat rambat gelombang tersebut adalah ….
- A.
1600 m/s
- B.
1000 m/s
- C.
400 m/s
- D.
100 m/s
Correct Answer
D. 100 m/sExplanation
The speed of a wave is determined by the product of its frequency and wavelength. In this case, the frequency is given as 400 Hz and the wavelength is given as 25 cm. To find the speed, we multiply these two values together: 400 Hz * 25 cm = 10,000 cm/s. However, the answer choices are given in meters per second, so we need to convert cm/s to m/s by dividing by 100: 10,000 cm/s / 100 = 100 m/s. Therefore, the correct answer is 100 m/s.Rate this question:
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- 23.
Suatu pegas melakukan 150 getaran dalam waktu 0,5 menit. Frekuensi getaran pegas adalah ....
- A.
300 Hz
- B.
75 Hz
- C.
30 Hz
- D.
5 Hz
Correct Answer
D. 5 HzExplanation
The frequency of an oscillation is calculated by dividing the number of oscillations by the time taken. In this case, the pegas (spring) completes 150 oscillations in 0.5 minutes. To find the frequency, we divide 150 by 0.5, which equals 300 oscillations per minute. However, the answer options are given in Hz (oscillations per second), so we need to convert the frequency from minutes to seconds. There are 60 seconds in a minute, so dividing 300 by 60 gives us a frequency of 5 Hz.Rate this question:
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- 24.
Sebuah getaran menghasilkan frekuensi 50 Hz. Periode getarannya adalah ….
- A.
0,5 sekon
- B.
0,2 sekon
- C.
0,02 sekon
- D.
0,05 sekon
Correct Answer
C. 0,02 sekonExplanation
The correct answer is 0.02 seconds. The period of a vibration is the time it takes for one complete cycle of the vibration. In this case, the vibration has a frequency of 50 Hz, which means it completes 50 cycles in one second. To find the period, we can divide 1 second by the frequency: 1 second / 50 Hz = 0.02 seconds. Therefore, the period of the vibration is 0.02 seconds.Rate this question:
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- 25.
Frekuensi sebuah gelombang adalah 400 Hz dan panjang gelombang adalah 50 cm. Cepat rambat gelombang tersebut adalah ....
- A.
1600 m/s
- B.
800 m/s
- C.
400 m/s
- D.
200 m/s
Correct Answer
D. 200 m/sExplanation
The speed of a wave can be calculated using the formula v = fλ, where v is the speed, f is the frequency, and λ is the wavelength. In this case, the frequency is given as 400 Hz and the wavelength as 50 cm. Converting the wavelength to meters (since the speed is usually measured in m/s), we get 0.5 m. Plugging these values into the formula, we get v = 400 Hz * 0.5 m = 200 m/s. Therefore, the correct answer is 200 m/s.Rate this question:
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.jpg "Perhatikan gambar di bawah ini!
Amplitudo getaran ditunjukkan oleh...")
.JPG "Dalam selang waktu 0,3 sekon antara A dan B terbentuk gelombang seperti gambar di atas. Cepat rambat gelombang dalam tali adalah ....")
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Mar 22, 2023Quiz Edited by
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