Six Sigma Green Belt Certification Quiz!

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Six Sigma Green Belt Certification Quiz! - Quiz

Are you preparing for the Six Sigma Green Belt Certification exam? Test your knowledge and readiness with our comprehensive Six Sigma Green Belt Certification Quiz. This quiz is designed to help you master key concepts and methodologies such as DMAIC (Define, Measure, Analyze, Improve, Control), Lean principles, process improvement tools, and statistical analysis techniques.

With carefully crafted questions that simulate the real exam, you’ll gain insights into your strengths and identify areas that need further study. Learn about topics like process mapping, root cause analysis, variance reduction, and control charts to build your confidence and achieve your Green Belt. Read moreTake the quiz now to see how prepared you are for your Six Sigma journey!


Six Sigma Green Belt Certification Questions and Answers

  • 1. 

    Six Sigma can best be defined as:

    • A.

      A management methodology that uses only statistical tools to improve customer experience.

    • B.

      A customer-focused problem-solving methodology that uses powerful statistical tools to reduce variation and improve processes.

    • C.

      A management methodology that is primarily focused on achieving financial results.

    • D.

      A customer-focused problem-solving methodology used exclusively within the manufacturing sector.

    Correct Answer
    B. A customer-focused problem-solving methodology that uses powerful statistical tools to reduce variation and improve processes.
    Explanation
    Six Sigma is a customer-focused problem-solving methodology that uses powerful statistical tools to reduce variation and improve processes. It is not limited to the manufacturing sector and is applicable to various industries. The goal of Six Sigma is to achieve high-quality products and services by identifying and eliminating defects and errors. It involves measuring and analyzing data, identifying root causes of problems, and implementing solutions to improve efficiency and customer satisfaction. By reducing process variation, organizations can minimize defects and improve overall performance.

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  • 2. 

    Which Role is not traditionally performed by a Green Belt?

    • A.

      Data Gathering

    • B.

      Analysis

    • C.

      Lead Small Projects.

    • D.

      Coach and mentor other Six Sigma Practitioners.

    Correct Answer
    D. Coach and mentor other Six Sigma Practitioners.
    Explanation
    A Green Belt is a role in Six Sigma that is responsible for leading small projects, conducting data gathering and analysis. However, coaching and mentoring other Six Sigma Practitioners is not traditionally performed by a Green Belt. This role is usually assigned to a Black Belt or Master Black Belt, who have more experience and expertise in Six Sigma methodologies.

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  • 3. 

    A process has a mean of 10 and a standard deviation of 2. What is the tolerance of the process that exhibits the limits of normal variation?

    • A.

      5 to 15

    • B.

      4 to 16

    • C.

      2 to 8

    • D.

      6 to 14

    Correct Answer
    B. 4 to 16
    Explanation
    To determine the tolerance of a process with normal variation, we use the concept of standard deviations for a normal distribution. A range of normal variation typically falls within ±3 standard deviations from the mean.
    Given:
    Mean (μ) = 10
    Standard deviation (σ) = 2
    Calculating the limits:
    Lower Limit = Mean - 3 * Standard Deviation
    Lower Limit = 10 - 3 * 2
    Lower Limit = 10 - 6
    Lower Limit = 4
    Upper Limit = Mean + 3 * Standard Deviation
    Upper Limit = 10 + 3 * 2
    Upper Limit = 10 + 6
    Upper Limit = 16
    So, the tolerance of the process that exhibits the limits of normal variation is 4 to 16.

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  • 4. 

    A normal Distribution can best be described as: 

    • A.

      Bell-shaped, a variance of 1, the mean=median=mode.

    • B.

      Bell-shaped, symmetrical about the mean, a single mode.

    • C.

      Un-Symmetrical about the mean, a natural tolerance of three standard deviations, unimodal.

    • D.

      Symmetrical about the mean, bell-shaped, discrete data.

    Correct Answer
    B. Bell-shaped, symmetrical about the mean, a single mode.
    Explanation
    A normal distribution is a statistical distribution that is bell-shaped and symmetrical about the mean. This means that the data is evenly distributed on both sides of the mean, creating a symmetrical pattern. Additionally, a normal distribution typically has a single mode, which is the value that occurs most frequently in the data set. Therefore, the correct answer is "Bell-shaped, symmetrical about the mean, a single mode."

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  • 5. 

    A shape referred to as Platykurtic is: 

    • A.

      Flatter than the Normal Distribution.

    • B.

      Narrower than a Normal Distribution.

    • C.

      Same as a Normal Distribuiton.

    • D.

      None of the above answers.

    Correct Answer
    A. Flatter than the Normal Distribution.
    Explanation
    Platykurtic refers to a shape that is flatter than the normal distribution. In statistics, kurtosis is a measure of the peakedness or flatness of a distribution. A platykurtic distribution has a lower kurtosis value than the normal distribution, indicating a flatter shape with lighter tails. This means that the data points are spread out more evenly and have fewer extreme values compared to the normal distribution.

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  • 6. 

    A process is in-control and stable.  Describe the type of variation that exists in the process.

    • A.

      Special Cause variation.

    • B.

      Natural Variation.

    • C.

      Out-the-ordinary varation.

    • D.

      Non-random variation.

    Correct Answer
    B. Natural Variation.
    Explanation
    The correct answer is "Natural Variation." In a stable and in-control process, the variation that exists is considered to be natural or common cause variation. This type of variation is inherent to the process and is expected to occur even under normal operating conditions. It is caused by a combination of random factors and is predictable within certain limits. It is important to distinguish natural variation from special cause variation, which is caused by specific factors that are not inherent to the process and can lead to unexpected or out-of-control situations.

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  • 7. 

    Indicate which are examples of variable data: 1) Length, 2) Weight, 3) Decision on a coin toss, 4) Dollars, 5) Days

    • A.

      1,3,4,5

    • B.

      1,2,4

    • C.

      1,2,4,5

    • D.

      1,4,5

    Correct Answer
    C. 1,2,4,5
    Explanation
    Variable data refers to information that can vary or change. In this case, length, weight, dollars, and days are all examples of variable data. Length and weight can vary depending on the object or person being measured. Dollars can vary in value depending on the currency exchange rate or inflation. Days can vary as they represent units of time that can change depending on the calendar or specific context. Therefore, the correct answer is 1,2,4,5.

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  • 8. 

    Indicate which control char(s) is the most sensitive for measuring time as data:

    • A.

      Np chart.

    • B.

      X bar R Chart.

    • C.

      P Chart.

    • D.

      Individuals and Moving Range.

    Correct Answer
    B. X bar R Chart.
    Explanation
    The X bar R Chart is the most sensitive control chart for measuring time as data. This chart is used to monitor the central tendency and variability of a process over time. It consists of two charts - the X bar chart which tracks the average value of a process, and the R chart which tracks the range or variation within the process. By analyzing these charts, any deviations or shifts in the process can be detected quickly, making it an effective tool for measuring time as data.

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  • 9. 

    Which one of the characteristics below does not reflect common cause variation:

    • A.

      Trend

    • B.

      In-Control

    • C.

      Predictable

    • D.

      Stable

    Correct Answer
    A. Trend
    Explanation
    Common cause variation refers to the natural variation that is inherent in a process and is caused by random factors. A trend, on the other hand, refers to a consistent pattern or direction in the data over time. This indicates a systematic shift in the process, which is not a characteristic of common cause variation. Therefore, a trend does not reflect common cause variation.

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  • 10. 

    What Steps should you take when you notice special causes in a control chart?

    • A.

      Do nothing.

    • B.

      Continue taking data measurements to confirm your belief.

    • C.

      Stop and identify the Special Causes.

    • D.

      Stop, identify the special Causes and eliminate them.

    Correct Answer
    D. Stop, identify the special Causes and eliminate them.
    Explanation
    When special causes are noticed in a control chart, it is important to stop and identify them. This is because special causes indicate that there are factors outside of the normal variation that are affecting the process. By identifying these special causes, it becomes possible to understand and address the underlying issues causing the variation. Once the special causes are identified, steps can be taken to eliminate them and improve the process. Simply continuing to take data measurements or doing nothing would not address the root causes of the special variation.

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  • 11. 

    Your control chart shows seven consecutive points on one side of the mean. What does this indicate?

    • A.

      The process is in-control (within the UCL and LCL).

    • B.

      The process appears to be too table and should be questioned.

    • C.

      The process needs to be checked for special causes.

    • D.

      The wrong control chart has been selected.

    Correct Answer
    C. The process needs to be checked for special causes.
    Explanation
    When seven consecutive points on one side of the mean are observed on a control chart, it indicates that the process may have special causes of variation. Special causes are factors that are not part of the normal process and can lead to unpredictable outcomes. It is important to investigate and identify these special causes to understand and address any issues or deviations from the expected performance of the process. Therefore, the correct answer is that the process needs to be checked for special causes.

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  • 12. 

    The number of data points for a sample is 100. Indicate the approximate number of classes one needs to use for grouped data?  

    • A.

      10

    • B.

      5

    • C.

      20

    • D.

      100

    Correct Answer
    A. 10
    Explanation
    For grouped data, it is recommended to have a moderate number of classes to effectively summarize and analyze the data. Having too few classes can result in loss of information, while having too many classes can make the data difficult to interpret. With 100 data points, using approximately 10 classes would strike a balance between providing enough detail and maintaining clarity in the data presentation.

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  • 13. 

    If the salary of professionals is inversely proportional to their age, it indicates ___________ relationship between the two variables?

    • A.

      Positive

    • B.

      Negative

    • C.

      No Correlation

    • D.

      Linear

    Correct Answer
    B. Negative
    Explanation
    If the salary of professionals is inversely proportional to their age, it indicates a negative relationship between the two variables. This means that as the age of professionals increases, their salary decreases, and vice versa. In other words, there is a negative correlation between age and salary, suggesting that older professionals tend to earn less compared to younger professionals.

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  • 14. 

    Select the corect mean, median and mode for the following sample:     4,5,6,1,1,2,5,7,5

    • A.

      4,4,5

    • B.

      3,5,4

    • C.

      4,3,5

    • D.

      4,5,5

    Correct Answer
    D. 4,5,5
    Explanation
    1. Mean (Average):
    Sum of all numbers = 4 + 5 + 6 + 1 + 1 + 2 + 5 + 7 + 5 = 36
    Number of values = 9
    Mean = Sum of all numbers / Number of values
    Mean = 36 / 9
    Mean = 4
    2. Median (Middle Value):
    To find the median, we first arrange the numbers in ascending order:
    1, 1, 2, 4, 5, 5, 5, 6, 7
    Since there are 9 values (an odd number), the median is the middle value, which is the 5th value.
    Median = 5
    3. Mode (Most Frequent Value):
    The mode is the number that appears most frequently.
    In this sample, the number 5 appears three times, which is more than any other number.
    Mode = 5
    Conclusion:
    Mean = 4, Median = 5, Mode = 5

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  • 15. 

    Which of the following tools in Six Sigma Green Belt methodology is primarily used for identifying potential root causes of problems by visually mapping out the relationships between various factors?

    • A.

      Failure Mode and Effects Analysis (FMEA)

    • B.

      Control Charts

    • C.

      Pareto Chart

    • D.

      Ishikawa Diagram

    Correct Answer
    D. Ishikawa Diagram
    Explanation
    The Ishikawa Diagram, also known as the Fishbone Diagram, is a quality management tool used to identify potential causes of a problem. It organizes possible causes into categories, such as people, methods, machines, materials, environment, and measurement, enabling a systematic analysis of root causes.

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  • 16. 

    The Cp and Cpk values both turn out to be 1.9. What does this indicate?  

    • A.

      The process is capable.

    • B.

      The process is capable but not centered.

    • C.

      The process is highly capable and centered.

    • D.

      The process is not capable.

    Correct Answer
    C. The process is highly capable and centered.
    Explanation
    A Cp value of 1.9 indicates that the process is capable of producing within the specified tolerance limits. Similarly, a Cpk value of 1.9 indicates that the process is centered, meaning the mean of the process is close to the target value. Therefore, when both Cp and Cpk values are 1.9, it suggests that the process is highly capable and centered, meaning it is capable of consistently producing within the specified limits and the mean is close to the target value.

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  • 17. 

    A process you are monitoring produces 150,000 customer transactions per year. Your analysis indicates the percent non-conforming is 0.2%.  What is the DPMO?

    • A.

      300

    • B.

      1,800

    • C.

      2,000

    • D.

      20,000

    Correct Answer
    C. 2,000
    Explanation
    The DPMO (Defects Per Million Opportunities) is a measure of the number of defects in a process per one million opportunities. In this case, the percent non-conforming is given as 0.2%, which means that 0.2% of the customer transactions are defective. To calculate the DPMO, we multiply the percent non-conforming by one million. Therefore, 0.2% * 1,000,000 = 2,000. Hence, the correct answer is 2,000.

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  • 18. 

    Which of the following is a primary tool used in the Define phase of the DMAIC process?

    • A.

      Control Chart

    • B.

      Pareto Chart

    • C.

      SIPOC Diagram

    • D.

      Fishbone Diagram

    Correct Answer
    C. SIPOC Diagram
    Explanation
    In the Define phase of the DMAIC (Define, Measure, Analyze, Improve, Control) process, one of the primary tools used is the SIPOC Diagram. SIPOC stands for Suppliers, Inputs, Process, Outputs, and Customers. This diagram helps to identify and outline the critical elements of a process, providing a high-level view that helps define the project scope and objectives.

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  • 19. 

    The histogram you have constructed is skewed to the left. What should you do?

    • A.

      Consult with your legal department.

    • B.

      Develop the appropriate control chart.

    • C.

      It is still a normal distribution.

    • D.

      Stop the process and bring it back into control.

    Correct Answer
    B. Develop the appropriate control chart.
    Explanation
    The correct answer is to develop the appropriate control chart. This is because a control chart is a statistical tool used to monitor and control a process over time. By developing a control chart, you can analyze the process data and identify any patterns or trends that may be causing the left skew in the histogram. This will help you understand the process better and make any necessary adjustments or improvements to bring it back into control.

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  • 20. 

    The control chart most commonly used for between and within subgroup variation is the:

    • A.

      X Bar and R Chart.

    • B.

      X Bar and the Standard Deviation Chart.

    • C.

      X Bar and the Variance Chart.

    • D.

      X Bar and the Mean Chart.

    Correct Answer
    A. X Bar and R Chart.
    Explanation
    The control chart most commonly used for between and within subgroup variation is the X Bar and R Chart. This chart is used to monitor the process mean and variability by plotting the average of each subgroup (X Bar) and the range of each subgroup (R). It helps identify any shifts or trends in the process mean and variability, allowing for timely corrective actions to maintain process stability and improve quality. The X Bar and R Chart is widely used because it provides a comprehensive view of both mean and variation in the process.

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  • 21. 

    An attribute chart can be represented by all of the following EXCEPT:

    • A.

      P Chart

    • B.

      R Chart

    • C.

      NP Chart

    • D.

      C Chart

    Correct Answer
    B. R Chart
    Explanation
    An attribute chart is a graphical representation of data that measures the presence or absence of a particular attribute or characteristic. It is used to monitor the quality of a process or product. The P Chart, NP Chart, and C Chart are all examples of attribute charts commonly used in statistical process control. However, the R Chart is not an attribute chart, but rather a control chart used to monitor the variability of a process. It plots the range of a sample, which is a measure of dispersion, rather than the presence or absence of an attribute.

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  • 22. 

    List the following Sampling Plan steps in the correct sequence.   1) Decide who will collect the data, who will analyze it, and who will report the results. 2) Formulate a clear statement of the problem being addressed with the data. 3) List all of the important characteristics to be measured. 4) Select the best measurement technique for the desired data. 5) Define precisely what is to be measured with the data.

    • A.

      5,2,3,4,1

    • B.

      2,5,3,4,1

    • C.

      1,2,5,3,4

    • D.

      5,1,2,4,3

    Correct Answer
    B. 2,5,3,4,1
    Explanation
    The correct sequence of the Sampling Plan steps is as follows: 2) Formulate a clear statement of the problem being addressed with the data. 5) Define precisely what is to be measured with the data. 3) List all of the important characteristics to be measured. 4) Select the best measurement technique for the desired data. 1) Decide who will collect the data, who will analyze it, and who will report the results. This sequence ensures that the problem is clearly defined, the important characteristics are identified, the appropriate measurement technique is chosen, and the responsibilities for data collection, analysis, and reporting are assigned.

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  • 23. 

    Select the key attributes of successful Six Sigma programs. 1) Senior management commitment 2) High ROI projects 3) Projects with short durations 4) Proper funding 5) Well-trained staff 6) Properly scoped projects

    • A.

      1,3,5,6

    • B.

      1,4,5,6

    • C.

      1,5,6

    • D.

      1,2,4,5,6

    Correct Answer
    D. 1,2,4,5,6
    Explanation
    The key attributes of successful Six Sigma programs include senior management commitment, high ROI projects, proper funding, well-trained staff, and properly scoped projects. These attributes are crucial for the effective implementation of Six Sigma methodologies and achieving the desired results. Senior management commitment ensures the necessary support and resources are provided, while high ROI projects ensure that the efforts and investments yield significant returns. Proper funding ensures the availability of resources, and well-trained staff ensures the competency and capability to execute Six Sigma projects. Lastly, properly scoped projects ensure that the objectives and scope of the projects are clearly defined and aligned with organizational goals.

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  • 24. 

    These provide support, resources and remove roadblocks.  They have more in-depth understanding of the methods - measurements and interpretations of process measurements.  They are referred to as: 

    • A.

      Champions

    • B.

      Master Black Belts

    • C.

      Steering Committee

    • D.

      Process Owners

    Correct Answer
    A. Champions
    Explanation
    Champions are individuals who provide support, resources, and remove roadblocks in a project. They have a more in-depth understanding of the methods, measurements, and interpretations of process measurements. They play a crucial role in driving the success of the project by advocating for it and ensuring that necessary resources are allocated. They are not necessarily experts in the technical aspects of the project, but they have a broad understanding of the overall goals and objectives.

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  • 25. 

    A type of bar chart displaying the frequency of occurrence is called a _______________.

    • A.

      X bar R Control Chart

    • B.

      Pareto Chart

    • C.

      Histogram

    • D.

      Cumulative Frequency Graph

    Correct Answer
    C. Histogram
    Explanation
    A histogram is a type of bar chart that displays the frequency of occurrence of different values or ranges of values. It is commonly used to represent the distribution of data and identify patterns or trends. Unlike other types of bar charts, a histogram does not require equal intervals between the bars, allowing for a more accurate representation of the data. Therefore, a histogram is the correct answer for this question.

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  • 26. 

    What are the 3 key attributes of Six Sigma that best summarize why it is a compelling methodology for reducing variation and improving processes in the mind of Senior Management?

    • A.

      Data Driven, Creative, Streamlined

    • B.

      Customer Focused, Data Driven, ROI Oriented

    • C.

      Customer Focused, Statistical Emphasis, Conformity - Driven

    • D.

      Data Driven, Methodical, ROI Oriented

    Correct Answer
    B. Customer Focused, Data Driven, ROI Oriented
    Explanation
    The three key attributes of Six Sigma that best summarize why it is a compelling methodology for reducing variation and improving processes in the mind of Senior Management are: Customer Focused, Data Driven, and ROI Oriented. This means that Six Sigma places a strong emphasis on understanding and meeting customer needs, using data and statistical analysis to drive decision-making and problem-solving, and ultimately focusing on achieving a return on investment by improving processes and reducing costs.

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  • 27. 

    A company using Six Sigma methodology is operating at a 99.99967% defect-free rate.  What is its Sigma Level and failure rate?

    • A.

      3 Sigma, 3.4 DPMO

    • B.

      4.5 Sigma, 233 DPMO

    • C.

      5.0 Sigma, 233 DPMO

    • D.

      6 Sigma, 3.4 DPMO

    Correct Answer
    D. 6 Sigma, 3.4 DPMO
    Explanation
    The correct answer is 6 Sigma, 3.4 DPMO. Six Sigma is a measure of the quality of a process, indicating how many standard deviations fit within the specification limits. A 6 Sigma level corresponds to a defect rate of 3.4 defects per million opportunities (DPMO). This means that the company is operating at a very high level of quality, with a very low rate of defects.

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  • 28. 

    Select 3 types of Analysis tools to identify root causes/data relationships commonly used in the Six Sigma methodology.

    • A.

      Control Charts, Pareto Charts, Fish-Bone Diagrams

    • B.

      Pareto Charts, Capability Indices, Control Charts

    • C.

      Pareto Charts, Fish-Bone Diagrams, Scatter Plot Diagrams

    • D.

      Scatter Plot Diagrams, Pareto Charts, Correlation

    Correct Answer
    A. Control Charts, Pareto Charts, Fish-Bone Diagrams
    Explanation
    Control Charts, Pareto Charts, and Fish-Bone Diagrams are three types of analysis tools commonly used in the Six Sigma methodology to identify root causes and data relationships. Control Charts are used to monitor and control process performance over time, Pareto Charts are used to prioritize and focus on the most significant factors affecting a process, and Fish-Bone Diagrams (also known as Cause-and-Effect or Ishikawa Diagrams) are used to visually display the potential causes contributing to a problem or effect. These tools help in analyzing data, identifying patterns, and understanding the root causes of process variations or defects.

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  • 29. 

    List the 3 key activities - in correct order - for determining if a proceess is normally distributed, in-control and capable of consistently meeting customer requirements.

    • A.

      Construct a histogram, Prepare Control Charts, Calculate Capability Indices

    • B.

      Construct a SIPOC, Prepare Control Charts, Calculate Cp and Cpk.

    • C.

      Calculate the 3 measures of Central Tendency, Calculate Capability Indices, Prepare Control Charts

    • D.

      Prepare CTQs, Construct Control Charts, Calculate Capability Indices

    Correct Answer
    A. Construct a histogram, Prepare Control Charts, Calculate Capability Indices
    Explanation
    To determine if a process is normally distributed, in-control, and capable of consistently meeting customer requirements, the first step is to construct a histogram. This allows us to visualize the distribution of the data and check if it follows a normal distribution. The next step is to prepare control charts, which help monitor the process over time and identify any variations or out-of-control points. Finally, calculating capability indices such as Cp and Cpk provides a quantitative measure of how well the process meets customer requirements. By following these three key activities in the correct order, we can assess the process's performance and make any necessary improvements.

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  • 30. 

    The average time spent waiting in queue for a bank teller is 8 minutes.  The Standard Deviation is 30 seconds.  What is the tolerance of the process that exhibits the limits of normal variation?

    • A.

      6 to 10 minutes

    • B.

      7 to 9 minutes

    • C.

      6.5 minutes to 9.5 minutes

    • D.

      3 minutes to 12 minutes

    Correct Answer
    C. 6.5 minutes to 9.5 minutes
    Explanation
    The tolerance of the process that exhibits the limits of normal variation is 6.5 minutes to 9.5 minutes. This means that the average time spent waiting in queue for a bank teller can vary between 6.5 minutes and 9.5 minutes, considering the standard deviation of 30 seconds.

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  • 31. 

    The X Bar R Chart uses two control charts to monitor a process.  What are they?

    • A.

      Mean and Standard Deviation

    • B.

      Mean and Range

    • C.

      Mean and Variance

    • D.

      Grand Average and Variance

    Correct Answer
    B. Mean and Range
    Explanation
    The X Bar R Chart uses two control charts to monitor a process: the mean chart and the range chart. The mean chart helps track the central tendency of the process by monitoring the average values of samples taken over time. The range chart, on the other hand, measures the variability or dispersion within each sample by tracking the difference between the highest and lowest values. By using both charts together, the X Bar R Chart provides a comprehensive view of the process performance, allowing for effective monitoring and identification of any potential issues or variations.

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  • 32. 

    Select the correct mean, median and mode for the following sample: 5,3,3,6,3,4,10.

    • A.

      4.86,4,3

    • B.

      4.86,3,4.5

    • C.

      5,3,4.5

    • D.

      4.86,3,4

    Correct Answer
    A. 4.86,4,3
    Explanation
    The mean is calculated by adding up all the numbers in the sample and then dividing by the total number of values. In this case, the sum of the numbers is 34 and there are 7 values, so the mean is 34/7 = 4.86.

    The median is the middle value when the numbers are arranged in ascending order. In this case, when the numbers are arranged in ascending order, we have 3,3,3,4,5,6,10. Since there are 7 values, the middle value is the 4th value, which is 4.

    The mode is the value that appears most frequently in the sample. In this case, the value that appears most frequently is 3.

    Therefore, the correct mean, median, and mode for the given sample are 4.86, 4, and 3 respectively.

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  • 33. 

    In Six Sigma Green Belt methodology, what does the acronym DMAIC stand for?

    • A.

      Define, Measure, Analyze, Implement, Control

    • B.

      Data, Methodology, Analysis, Implementation, Continuous Improvement

    • C.

      Direct, Manage, Analyze, Improve, Change

    • D.

      Document, Measure, Audit, Inspect, Correct

    Correct Answer
    A. Define, Measure, Analyze, Implement, Control
    Explanation
    DMAIC is a structured problem-solving methodology used in Six Sigma. It involves five phases: Define the problem and customer requirements, Measure current process performance, Analyze the data to identify root causes, Improve the process by implementing solutions, and Control the process to sustain improvements.

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  • 34. 

    A process has the following X values (1,2,3,4,5) and Y values (2,4,6,8,10).  What is the relationship between the two variables?

    • A.

      Linear

    • B.

      Negative

    • C.

      Positive and Linear

    • D.

      No Correlation

    Correct Answer
    C. Positive and Linear
    Explanation
    To determine the relationship between the given X and Y values:
    X values: 1, 2, 3, 4, 5
    Y values: 2, 4, 6, 8, 10
    Let's analyze the pattern:
    Checking for Linearity:
    As X increases by 1, Y increases by 2.
    For each unit increase in X, there is a consistent increase in Y by 2.
    This indicates a direct, proportional relationship where Y = 2X.
    Checking for Positive or Negative Relationship:
    As X increases, Y also increases. This indicates a positive relationship.
    Type of Correlation:
    Since the increase in Y is consistent and proportional to the increase in X, the relationship is both positive and linear.

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  • 35. 

    A company generates 12,000 orders per month.  Each order has the possibility of 4 errors.  Approxiately how many opportunities for defects are provided during the year?

    • A.

      1,000,000

    • B.

      84,000

    • C.

      144,000

    • D.

      576,000

    Correct Answer
    D. 576,000
    Explanation
    The company generates 12,000 orders per month. Each order has the possibility of 4 errors. To find the total number of opportunities for defects provided during the year, we multiply the number of orders per month by the number of errors per order and then multiply by 12 to account for the 12 months in a year. Therefore, the total number of opportunities for defects provided during the year is 12,000 * 4 * 12 = 576,000.

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  • 36. 

    If the company is operating at 3 Sigma in the above example what is the percent conformance?

    • A.

      99.73%

    • B.

      99.97%

    • C.

      99.997%

    • D.

      68.26%

    Correct Answer
    A. 99.73%
    Explanation
    If the company is operating at 3 Sigma, it means that the process has a standard deviation of 1, which corresponds to a defect rate of 0.27%. This implies that the process has a conformance rate of 99.73%, which is the percentage of products or services that meet the required specifications.

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  • 37. 

    A process has a CP = 1 nd a Cpk =  1.  Interpret these capability indices:

    • A.

      The process is centered but not capable

    • B.

      The process is not in control

    • C.

      The process is not capable

    • D.

      The Process is centered and capable

    Correct Answer
    D. The Process is centered and capable
    Explanation
    The given CP and Cpk values indicate that the process is centered around the target value and is also capable of producing within the specified tolerance limits. A CP value of 1 indicates that the process spread is equal to the tolerance range, while a Cpk value of 1 indicates that the process is centered within the tolerance limits. Therefore, the process is both centered and capable.

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  • 38. 

    What can you say about Control Limits and Specification Limits?

    • A.

      There is no difference between the terms; both are used to indicate if a process is in control

    • B.

      Control Limits are set by the customers; Specification Limits are derived by the process

    • C.

      Control Limits are derived by the process; Specification Limits are set by the customer

    • D.

      Control Limits are typically 3 standard deviations from the mean; Specification Limits are typically 3 standard deviations from the target

    Correct Answer
    C. Control Limits are derived by the process; Specification Limits are set by the customer
    Explanation
    Control Limits and Specification Limits are two different concepts in process control. Control Limits are statistical boundaries that are calculated based on the data collected from the process itself. They indicate the natural variation of the process and help determine if the process is in control or not. On the other hand, Specification Limits are predetermined boundaries set by the customer or the requirements of the product. They define the acceptable range of values for the process output to meet customer expectations. Therefore, Control Limits are derived by the process, while Specification Limits are set by the customer.

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  • 39. 

    A process is out-of-control.  Describe the type of variation that exists in the process.

    • A.

      Random Variation

    • B.

      Special Cause Variation

    • C.

      Common Cause Variation

    • D.

      Inherent Variation

    Correct Answer
    B. Special Cause Variation
    Explanation
    Special Cause Variation refers to the type of variation that occurs due to specific, identifiable causes that are not part of the normal process. These causes are typically sporadic and unpredictable, leading to irregular patterns in the data. Special cause variation is often caused by external factors, human error, equipment malfunction, or other factors that are not inherent to the process itself. It is important to identify and address special cause variation to bring the process back into control and ensure consistent and predictable outcomes.

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  • 40. 

    A process you are monitoring over time exhibits inherent variation.  What strategy should you use to mange the process?

    • A.

      Take immediate action to identify root causes of the common cause variation

    • B.

      Increase the specification limits to ensure the process is capable

    • C.

      Continually and gradually improve the stable process

    • D.

      Stop the process, identify the causes, and eliminate them

    Correct Answer
    C. Continually and gradually improve the stable process
    Explanation
    The correct answer is to continually and gradually improve the stable process. This strategy acknowledges that there will always be inherent variation in a process and focuses on making incremental improvements over time. By continuously monitoring and analyzing the process, identifying areas for improvement, and implementing small changes, the process can be optimized and made more efficient. This approach recognizes that eliminating all variation is not feasible or necessary, but rather aims to make consistent and gradual improvements to enhance overall performance.

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  • 41. 

    You are monitoring a process and evidence of trending in the control chart.  What is the most likely issue going on?

    • A.

      New operators

    • B.

      Different shifts

    • C.

      Changes in materials

    • D.

      Wear of machinery

    Correct Answer
    C. Changes in materials
    Explanation
    The most likely issue going on is changes in materials. The evidence of trending in the control chart suggests that there is a consistent pattern or shift in the process, which can be attributed to the changes in materials being used. These changes may have an impact on the quality or performance of the process, leading to the observed trend in the control chart.

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  • 42. 

    Which item below most naturally follows the development of a SIPOC diagram?

    • A.

      A Process Map

    • B.

      Voice of the Customer

    • C.

      Critical-to-Quality Requirements

    • D.

      Project Charter

    Correct Answer
    C. Critical-to-Quality Requirements
    Explanation
    After developing a SIPOC (Supplier, Input, Process, Output, Customer) diagram, the next logical step would be to identify the critical-to-quality requirements. These requirements are the specific characteristics or features that are most important to the customer and directly impact the quality of the product or service. By identifying and prioritizing these requirements, the organization can ensure that their processes are aligned with customer expectations and deliver the desired quality outcomes. The critical-to-quality requirements serve as a basis for making improvements and driving continuous improvement efforts within the organization.

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  • 43. 

    The Variance for an equipment installation is 36 square minutes.  What is the Standard Deviation?

    • A.

      72 minutes

    • B.

      18 minutes

    • C.

      6 minutes

    • D.

      Need to know the mean to compute

    Correct Answer
    C. 6 minutes
    Explanation
    The correct answer is 6 minutes. The variance is the square of the standard deviation, so to find the standard deviation, we take the square root of the variance. In this case, the square root of 36 is 6. Therefore, the standard deviation is 6 minutes.

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  • 44. 

    If no correlation exists between two variables, then: 

    • A.

      As one variable changes, one cannot predict a value for the other variable

    • B.

      As one variable increases, the other variable decreases

    • C.

      As one variable decreases, the other variable decreases

    • D.

      As one variable decreases, the other variable increases

    Correct Answer
    A. As one variable changes, one cannot predict a value for the other variable
    Explanation
    If no correlation exists between two variables, it means that there is no relationship or pattern between them. Therefore, as one variable changes, it is not possible to predict or determine a specific value for the other variable. In other words, the values of the two variables are independent of each other and do not influence or affect one another.

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  • 45. 

    The term Design of Experiments was coined by: 

    • A.

      Genichi Taguchi

    • B.

      W. Edwards Deming

    • C.

      Sir Ronald A. Fisher

    • D.

      Joseph Juran

    Correct Answer
    C. Sir Ronald A. Fisher
    Explanation
    The term "Design of Experiments" (DOE) was coined by Sir Ronald A. Fisher, a pioneering British statistician. Fisher introduced DOE in the early 20th century to optimize agricultural experiments, providing a structured method for determining the relationship between factors affecting a process and the output of that process. His work laid the foundation for modern statistical science and experimental design.

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  • 46. 

    If the number of data points given is 121, the number of class intervals for constructing a HIstogram would be calculated as: 

    • A.

      10

    • B.

      20

    • C.

      11

    • D.

      12

    Correct Answer
    C. 11
    Explanation
    The number of class intervals for constructing a histogram is typically determined using a formula called the square root rule, which states that the number of class intervals should be approximately equal to the square root of the number of data points. In this case, the square root of 121 is 11, so the number of class intervals for constructing the histogram would be 11.

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  • 47. 

    If the Z USL and Z LSL are calculated as 3.24 and 3.42 respectively waht is the percentage non-conformance?

    • A.

      .0913%

    • B.

      .00913%

    • C.

      .0781%

    • D.

      .00781%

    Correct Answer
    A. .0913%
    Explanation
    The percentage non-conformance can be calculated by subtracting the Z LSL from the Z USL and then multiplying the result by 100. In this case, the difference between 3.24 and 3.42 is 0.18. Multiplying this by 100 gives us 18%. However, the answer options are in decimal form, so we need to convert 18% to decimal form, which is 0.18. Therefore, the correct answer is .0913%.

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  • 48. 

    Collecting the customer needs and converting them to rquirements is referred to as:

    • A.

      Voice of the Process

    • B.

      Voice of the Customer

    • C.

      Requirements Manipulation

    • D.

      QFC

    Correct Answer
    B. Voice of the Customer
    Explanation
    Collecting the customer needs and converting them to requirements is referred to as "Voice of the Customer." This process involves actively listening to the customer's feedback, preferences, and expectations to understand their needs accurately. By gathering this information, businesses can align their products or services to meet customer expectations and enhance customer satisfaction. The Voice of the Customer is crucial in product development and improvement, as it helps organizations prioritize their efforts and make informed decisions based on customer insights.

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  • Current Version
  • Sep 16, 2024
    Quiz Edited by
    ProProfs Editorial Team
  • Oct 03, 2012
    Quiz Created by
    PracticeExcellen
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