REMEDIAL MATEMATIKA WAJIB KELAS XI

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| By Matkelasxiips1si

Matkelasxiips1si

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Quizzes Created: 1 | Total Attempts: 127

Questions: 20 | Attempts: 127 | Updated: Jul 22, 2024

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Remedial Matematika Wajib Kelas Xi - Quiz

SEMOGA SUKSES
; &nbs p; Marcelinus Sinaga

Questions and Answers

1.
- A.
  
  3x² + 8x
- B.
  
  3x² + 8x + 2
- C.
  
  3x² + 8x + 3
- D.
  
  3x² + 8x + 4
- E.
  
  3x² + 8x + 5
Correct Answer
E. 3x² + 8x + 5
2.
- A.
  
  2x+1
- B.
  
  2x + 2
- C.
  
  2x+ 4
- D.
  
  4x +1
- E.
  
  4x + 2
Correct Answer
A. 2x+1
3.

Nilai minimum Kurva parabola dari fungsi kuadrat f (x) = x² – 8x adalah … .
- A.
  
  -13
- B.
  
  -14
- C.
  
  -15
- D.
  
  -16
- E.
  
  -17
Correct Answer
D. -16

Explanation
The minimum value of a parabola can be found by using the vertex formula, which is -b/2a. In this case, the coefficient of x^2 is 1 and the coefficient of x is -8. Plugging these values into the formula, we get -(-8)/2(1) = 8/2 = 4. Therefore, the minimum value of the parabola is f(4) = 4^2 - 8(4) = 16 - 32 = -16.

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4.

Nilai maksimum kurva parabola dari fungsi kuadrat f(x) = 4x – x² adalah … .
- A.
  
  3
- B.
  
  4
- C.
  
  5
- D.
  
  6
- E.
  
  7
Correct Answer
B. 4

Explanation
The maximum value of a parabola can be found by determining the vertex of the parabola. In this case, the given quadratic function f(x) = 4x - x^2 is in the form of f(x) = ax^2 + bx + c, where a = -1, b = 4, and c = 0. To find the x-coordinate of the vertex, we can use the formula x = -b/2a. Plugging in the values, we get x = -4/(2*(-1)) = -4/(-2) = 2. To find the y-coordinate of the vertex, we substitute x = 2 into the function: f(2) = 4(2) - (2^2) = 8 - 4 = 4. Therefore, the maximum value of the parabola is 4.

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5.

Nilai Optimum dari kurva Fungsi h(x) = x² – 4x + 6 adalah … .
- A.
  
  Maksimum = -2
- B.
  
  Maksimum = 2
- C.
  
  Minimum = 2
- D.
  
  Minimum = - 2
- E.
  
  Minimum = 0
Correct Answer
C. Minimum = 2

Explanation
The given function is a quadratic function in the form of h(x) = x^2 - 4x + 6. To find the optimum value, we need to find the vertex of the parabola. The vertex of a quadratic function in the form of ax^2 + bx + c can be found using the formula x = -b/2a. In this case, a = 1 and b = -4. Plugging these values into the formula, we get x = -(-4)/2(1) = 2. So, the x-coordinate of the vertex is 2. To find the corresponding y-coordinate, we substitute x = 2 into the function h(x) = x^2 - 4x + 6. h(2) = 2^2 - 4(2) + 6 = 4 - 8 + 6 = 2. Therefore, the minimum value of the function is 2.

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6.

Interval x yang membuat kurva fungsi g (x) = x² + 4x – 9 selalu turun adalah … .
- A.
  
  X > - 4
- B.
  
  X > - 2
- C.
  
  X < 0
- D.
  
  X < -2
- E.
  
  X < -4
Correct Answer
E. X < -4

Explanation
The correct answer is x < -4. This is because when we analyze the given function g(x) = x^2 + 4x - 9, we can see that the coefficient of the x^2 term is positive, indicating an upward opening parabola. Therefore, the curve of the function g(x) will be decreasing (or "always turun") when x is less than -4, as the values of x become more negative.

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7.

Interval yang membuat kurva fungsi f (x) = x² – 5x + 6 selalu naik adalah … .
- A.
  
  X > 0
- B.
  
  X > 12
- C.
  
  X > 1
- D.
  
  X > 32
- E.
  
  X > 52
Correct Answer
E. X > 52

Explanation
The correct answer is x > 52 because for any value of x greater than 52, the function f(x) = x^2 - 5x + 6 will always increase. This can be determined by analyzing the quadratic equation and observing that the coefficient of the x^2 term is positive, indicating an upward opening parabola. Therefore, the function will always have a positive slope and continue to rise as x increases beyond 52.

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8.

Interval x yang membuat kurva fungsi f (x) = x² + 6x – 4 tidak pernah turun adalah … .
- A.
  
  X ≤ - 5
- B.
  
  X ≤ - 4
- C.
  
  X ≥ - 3
- D.
  
  X ≥ - 4
- E.
  
  X ≥ 0
Correct Answer
C. X ≥ - 3

Explanation
The correct answer is x ≥ -3. This is because the equation f(x) = x^2 + 6x - 4 represents a quadratic function. The graph of a quadratic function is a parabola that opens upward if the coefficient of x^2 is positive. In this case, the coefficient of x^2 is 1, which is positive. When x ≥ -3, the function f(x) = x^2 + 6x - 4 will never decrease because the parabola opens upward. Therefore, the interval x ≥ -3 ensures that the curve of the function never decreases.

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9.

Interval x yang membuat kurva fungsi g (x) = 7 – 3x - x² tidak pernah Naik adalah … .
- A.
  
  X ≥ 3/2
- B.
  
  X ≥ - 3/2
- C.
  
  X ≤ - 3/2
- D.
  
  X ≤ 12
- E.
  
  X ≤ 32
Correct Answer
B. X ≥ - 3/2

Explanation
The given function is a quadratic function, g(x) = 7 - 3x - x^2. To find the interval where the function never increases, we need to find the values of x for which the derivative of the function is always negative. The derivative of g(x) is -3 - 2x. To find when the derivative is negative, we set -3 - 2x < 0 and solve for x. Simplifying the inequality, we get x > -3/2. Therefore, the interval x ≥ -3/2 is the correct answer.

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10.

Nilai stasioner Fungsi y = x³ – 3x² + 3x -2 adalah … .
- A.
  
  X = 0
- B.
  
  X = 1
- C.
  
  Y = 1
- D.
  
  Y = 0
- E.
  
  Y = -1
Correct Answer
B. X = 1

Explanation
The stationary value of a function occurs where the derivative is equal to zero. To find the stationary values of the function y = x^3 - 3x^2 + 3x - 2, we need to find the derivative and set it equal to zero. The derivative of the function is y' = 3x^2 - 6x + 3. Setting this equal to zero and solving for x, we get x = 1. Therefore, the stationary value of the function is x = 1.

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11.
- A.
  
  -1
- B.
  
  0
- C.
  
  1
- D.
  
  0 atau 1
- E.
  
  -1 atau 1
Correct Answer
B. 0
12.

Gradien garis singgung pada kurva f (x) = x² +1 di titik (1,2) adalah … .
- A.
  
  -2
- B.
  
  -1
- C.
  
  0
- D.
  
  1
- E.
  
  2
Correct Answer
E. 2

Explanation
The gradient of the tangent line at the point (1,2) on the curve f(x) = x^2 + 1 is 2. This means that the slope of the tangent line at that point is 2, indicating that the curve is steeply increasing at that point.

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13.

Nilai Gradien Garis singgung pada kurva y = f(x) = - x² + 3x + 1 pada titik yang berabsis x = -1 adalah … .
- A.
  
  5
- B.
  
  4
- C.
  
  3
- D.
  
  2
- E.
  
  1
Correct Answer
A. 5

Explanation
The gradient of a tangent line to a curve represents the slope of the line at a specific point. In this case, the curve is represented by the equation y = -x^2 + 3x + 1. To find the gradient at x = -1, we need to find the derivative of the equation and substitute x = -1 into it. The derivative of -x^2 + 3x + 1 is -2x + 3. Substituting x = -1 into this equation gives us -2(-1) + 3 = 5. Therefore, the gradient of the tangent line at x = -1 is 5.

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14.
- A.
  
  2x + 12y
- B.
  
  2x - 12y – 13
- C.
  
  2x + 12y + 13
- D.
  
  2x + 12y – 13
- E.
  
  2x + 12y + 13
Correct Answer
D. 2x + 12y – 13
15.

Garis singgung pada parabola y = x² – 4 yang tegak lurus pada garis y = x+ 3 memotong sumbu Y adalah … .
- A.
- B.
- C.
- D.
- E.
Correct Answer
C.

Explanation
The tangent line to the parabola y = x^2 - 4 that is perpendicular to the line y = x + 3 will intersect the y-axis at a certain point.

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16.
- A.
  
  8 + c
- B.
  
  X + c
- C.
  
  8x + c
- D.
  
  9x + c
- E.
  
  10x + c
Correct Answer
C. 8x + c
17.
- A.
  
  5x + c
- B.
  
  5x – c
- C.
- D.
- E.
Correct Answer
D.
18.
- A.
  
  6x +1 + c
- B.
  
  2x³- x + c
- C.
  
  2x³+ x - c
- D.
  
  2x³+ x + c
- E.
  
  3x³+ x + c
Correct Answer
D. 2x³+ x + c
19.
- A.
  
  2x³ + x² + x + c
- B.
  
  2x³ + x² + x - c
- C.
  
  2x³ - x² + x + c
- D.
  
  2x³ + x² + c
- E.
  
  3x³ + x² + x + c
- F.
  
  3x³ + x² + x + c
Correct Answer
C. 2x³ - x² + x + c
20.
- A.
- B.
- C.
- D.
- E.
Correct Answer
A.

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Current Version
Jul 22, 2024

Quiz Edited by
ProProfs Editorial Team
Jun 09, 2020

Quiz Created by
Matkelasxiips1si

Remedial Matematika Wajib Kelas Xi

Nilai minimum Kurva parabola dari fungsi kuadrat f (x) = x2 – 8x adalah … .

Nilai maksimum kurva parabola dari fungsi kuadrat f(x) = 4x – x2 adalah … .

Nilai Optimum dari kurva Fungsi h(x) = x2 – 4x + 6 adalah … .

Interval x yang membuat kurva fungsi g (x) = x2 + 4x – 9 selalu turun adalah … .

Interval yang membuat kurva fungsi f (x) = x2 – 5x + 6 selalu naik adalah … .

Interval x yang membuat kurva fungsi f (x) = x2 + 6x – 4 tidak pernah turun adalah … .

Interval x yang membuat kurva fungsi g (x) = 7 – 3x - x2 tidak pernah Naik adalah … .

Nilai stasioner Fungsi y = x3 – 3x2 + 3x -2 adalah … .

Gradien garis singgung pada kurva f (x) = x2 +1 di titik (1,2) adalah … .

Nilai Gradien Garis singgung pada kurva y = f(x) = - x2 + 3x + 1 pada titik yang berabsis x = -1 adalah … .

Garis singgung pada parabola y = x2 – 4 yang tegak lurus pada garis y = x+ 3 memotong sumbu Y adalah … .

Nilai minimum Kurva parabola dari fungsi kuadrat f (x) = x² – 8x adalah … .

Nilai maksimum kurva parabola dari fungsi kuadrat f(x) = 4x – x² adalah … .

Nilai Optimum dari kurva Fungsi h(x) = x² – 4x + 6 adalah … .

Interval x yang membuat kurva fungsi g (x) = x² + 4x – 9 selalu turun adalah … .

Interval yang membuat kurva fungsi f (x) = x² – 5x + 6 selalu naik adalah … .

Interval x yang membuat kurva fungsi f (x) = x² + 6x – 4 tidak pernah turun adalah … .

Interval x yang membuat kurva fungsi g (x) = 7 – 3x - x² tidak pernah Naik adalah … .

Nilai stasioner Fungsi y = x³ – 3x² + 3x -2 adalah … .

Gradien garis singgung pada kurva f (x) = x² +1 di titik (1,2) adalah … .

Nilai Gradien Garis singgung pada kurva y = f(x) = - x² + 3x + 1 pada titik yang berabsis x = -1 adalah … .

Garis singgung pada parabola y = x² – 4 yang tegak lurus pada garis y = x+ 3 memotong sumbu Y adalah … .