REMEDIAL MATEMATIKA WAJIB KELAS XI

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Quizzes Created: 1 | Total Attempts: 127

| Attempts: 127

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Nilai minimum Kurva parabola dari fungsi kuadrat f (x) = x² – 8x adalah … .
- -13
- -14
- -15
- -16
- -17

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; &nbs p; Marcelinus Sinaga

Remedial Matematika Wajib Kelas Xi - Quiz

2.
- 6x +1 + c
- 2x³- x + c
- 2x³+ x - c
- 2x³+ x + c
- 3x³+ x + c
Correct Answer

A. 2x³+ x + c
3.
- 2x³ + x² + x + c
- 2x³ + x² + x - c
- 2x³ - x² + x + c
- 2x³ + x² + c
- 3x³ + x² + x + c
- 3x³ + x² + x + c
Correct Answer

A. 2x³ - x² + x + c
4.

Nilai maksimum kurva parabola dari fungsi kuadrat f(x) = 4x – x² adalah … .
- 3
- 4
- 5
- 6
- 7
Correct Answer

A. 4

Explanation

The maximum value of a parabola can be found by determining the vertex of the parabola. In this case, the given quadratic function f(x) = 4x - x^2 is in the form of f(x) = ax^2 + bx + c, where a = -1, b = 4, and c = 0. To find the x-coordinate of the vertex, we can use the formula x = -b/2a. Plugging in the values, we get x = -4/(2*(-1)) = -4/(-2) = 2. To find the y-coordinate of the vertex, we substitute x = 2 into the function: f(2) = 4(2) - (2^2) = 8 - 4 = 4. Therefore, the maximum value of the parabola is 4.

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5.

Interval x yang membuat kurva fungsi f (x) = x² + 6x – 4 tidak pernah turun adalah … .
- X ≤ - 5
- X ≤ - 4
- X ≥ - 3
- X ≥ - 4
- X ≥ 0
Correct Answer

A. X ≥ - 3

Explanation

The correct answer is x ≥ -3. This is because the equation f(x) = x^2 + 6x - 4 represents a quadratic function. The graph of a quadratic function is a parabola that opens upward if the coefficient of x^2 is positive. In this case, the coefficient of x^2 is 1, which is positive. When x ≥ -3, the function f(x) = x^2 + 6x - 4 will never decrease because the parabola opens upward. Therefore, the interval x ≥ -3 ensures that the curve of the function never decreases.

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6.
- 8 + c
- X + c
- 8x + c
- 9x + c
- 10x + c
Correct Answer

A. 8x + c
7.
- 5x + c
- 5x – c
Correct Answer

A.
8.
- 2x + 12y
- 2x - 12y – 13
- 2x + 12y + 13
- 2x + 12y – 13
- 2x + 12y + 13
Correct Answer

A. 2x + 12y – 13
9.

Garis singgung pada parabola y = x² – 4 yang tegak lurus pada garis y = x+ 3 memotong sumbu Y adalah … .
Correct Answer

A.

Explanation

The tangent line to the parabola y = x^2 - 4 that is perpendicular to the line y = x + 3 will intersect the y-axis at a certain point.

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10.

Gradien garis singgung pada kurva f (x) = x² +1 di titik (1,2) adalah … .
- -2
- -1
- 0
- 1
- 2
Correct Answer

A. 2

Explanation

The gradient of the tangent line at the point (1,2) on the curve f(x) = x^2 + 1 is 2. This means that the slope of the tangent line at that point is 2, indicating that the curve is steeply increasing at that point.

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11.
- 3x² + 8x
- 3x² + 8x + 2
- 3x² + 8x + 3
- 3x² + 8x + 4
- 3x² + 8x + 5
Correct Answer

A. 3x² + 8x + 5
12.

Nilai Optimum dari kurva Fungsi h(x) = x² – 4x + 6 adalah … .
- Maksimum = -2
- Maksimum = 2
- Minimum = 2
- Minimum = - 2
- Minimum = 0
Correct Answer

A. Minimum = 2

Explanation

The given function is a quadratic function in the form of h(x) = x^2 - 4x + 6. To find the optimum value, we need to find the vertex of the parabola. The vertex of a quadratic function in the form of ax^2 + bx + c can be found using the formula x = -b/2a. In this case, a = 1 and b = -4. Plugging these values into the formula, we get x = -(-4)/2(1) = 2. So, the x-coordinate of the vertex is 2. To find the corresponding y-coordinate, we substitute x = 2 into the function h(x) = x^2 - 4x + 6. h(2) = 2^2 - 4(2) + 6 = 4 - 8 + 6 = 2. Therefore, the minimum value of the function is 2.

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13.
- 2x+1
- 2x + 2
- 2x+ 4
- 4x +1
- 4x + 2
Correct Answer

A. 2x+1
14.

Interval yang membuat kurva fungsi f (x) = x² – 5x + 6 selalu naik adalah … .
- X > 0
- X > 12
- X > 1
- X > 32
- X > 52
Correct Answer

A. X > 52

Explanation

The correct answer is x > 52 because for any value of x greater than 52, the function f(x) = x^2 - 5x + 6 will always increase. This can be determined by analyzing the quadratic equation and observing that the coefficient of the x^2 term is positive, indicating an upward opening parabola. Therefore, the function will always have a positive slope and continue to rise as x increases beyond 52.

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15.

Nilai Gradien Garis singgung pada kurva y = f(x) = - x² + 3x + 1 pada titik yang berabsis x = -1 adalah … .
- 5
- 4
- 3
- 2
- 1
Correct Answer

A. 5

Explanation

The gradient of a tangent line to a curve represents the slope of the line at a specific point. In this case, the curve is represented by the equation y = -x^2 + 3x + 1. To find the gradient at x = -1, we need to find the derivative of the equation and substitute x = -1 into it. The derivative of -x^2 + 3x + 1 is -2x + 3. Substituting x = -1 into this equation gives us -2(-1) + 3 = 5. Therefore, the gradient of the tangent line at x = -1 is 5.

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16.

Interval x yang membuat kurva fungsi g (x) = 7 – 3x - x² tidak pernah Naik adalah … .
- X ≥ 3/2
- X ≥ - 3/2
- X ≤ - 3/2
- X ≤ 12
- X ≤ 32
Correct Answer

A. X ≥ - 3/2

Explanation

The given function is a quadratic function, g(x) = 7 - 3x - x^2. To find the interval where the function never increases, we need to find the values of x for which the derivative of the function is always negative. The derivative of g(x) is -3 - 2x. To find when the derivative is negative, we set -3 - 2x < 0 and solve for x. Simplifying the inequality, we get x > -3/2. Therefore, the interval x ≥ -3/2 is the correct answer.

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17.

Nilai stasioner Fungsi y = x³ – 3x² + 3x -2 adalah … .
- X = 0
- X = 1
- Y = 1
- Y = 0
- Y = -1
Correct Answer

A. X = 1

Explanation

The stationary value of a function occurs where the derivative is equal to zero. To find the stationary values of the function y = x^3 - 3x^2 + 3x - 2, we need to find the derivative and set it equal to zero. The derivative of the function is y' = 3x^2 - 6x + 3. Setting this equal to zero and solving for x, we get x = 1. Therefore, the stationary value of the function is x = 1.

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18.
- -1
- 0
- 1
- 0 atau 1
- -1 atau 1
Correct Answer

A. 0
19.
Correct Answer

A.
20.

Interval x yang membuat kurva fungsi g (x) = x² + 4x – 9 selalu turun adalah … .
- X > - 4
- X > - 2
- X < 0
- X < -2
- X < -4
Correct Answer

A. X < -4

Explanation

The correct answer is x < -4. This is because when we analyze the given function g(x) = x^2 + 4x - 9, we can see that the coefficient of the x^2 term is positive, indicating an upward opening parabola. Therefore, the curve of the function g(x) will be decreasing (or "always turun") when x is less than -4, as the values of x become more negative.

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Jul 22, 2024

Quiz Edited by
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Jun 09, 2020

Quiz Created by
Matkelasxiips1si

Remedial Matematika Wajib Kelas Xi

Nilai minimum Kurva parabola dari fungsi kuadrat f (x) = x2 – 8x adalah … .

Quiz Preview

Nilai maksimum kurva parabola dari fungsi kuadrat f(x) = 4x – x2 adalah … .

Interval x yang membuat kurva fungsi f (x) = x2 + 6x – 4 tidak pernah turun adalah … .

Garis singgung pada parabola y = x2 – 4 yang tegak lurus pada garis y = x+ 3 memotong sumbu Y adalah … .

Gradien garis singgung pada kurva f (x) = x2 +1 di titik (1,2) adalah … .

Nilai Optimum dari kurva Fungsi h(x) = x2 – 4x + 6 adalah … .

Interval yang membuat kurva fungsi f (x) = x2 – 5x + 6 selalu naik adalah … .

Nilai Gradien Garis singgung pada kurva y = f(x) = - x2 + 3x + 1 pada titik yang berabsis x = -1 adalah … .

Interval x yang membuat kurva fungsi g (x) = 7 – 3x - x2 tidak pernah Naik adalah … .

Nilai stasioner Fungsi y = x3 – 3x2 + 3x -2 adalah … .

Interval x yang membuat kurva fungsi g (x) = x2 + 4x – 9 selalu turun adalah … .

Nilai minimum Kurva parabola dari fungsi kuadrat f (x) = x² – 8x adalah … .

Nilai maksimum kurva parabola dari fungsi kuadrat f(x) = 4x – x² adalah … .

Interval x yang membuat kurva fungsi f (x) = x² + 6x – 4 tidak pernah turun adalah … .

Garis singgung pada parabola y = x² – 4 yang tegak lurus pada garis y = x+ 3 memotong sumbu Y adalah … .

Gradien garis singgung pada kurva f (x) = x² +1 di titik (1,2) adalah … .

Nilai Optimum dari kurva Fungsi h(x) = x² – 4x + 6 adalah … .

Interval yang membuat kurva fungsi f (x) = x² – 5x + 6 selalu naik adalah … .

Nilai Gradien Garis singgung pada kurva y = f(x) = - x² + 3x + 1 pada titik yang berabsis x = -1 adalah … .

Interval x yang membuat kurva fungsi g (x) = 7 – 3x - x² tidak pernah Naik adalah … .

Nilai stasioner Fungsi y = x³ – 3x² + 3x -2 adalah … .

Interval x yang membuat kurva fungsi g (x) = x² + 4x – 9 selalu turun adalah … .