Chemically speaking, molarity is the concentration of a solution expressed as the number of moles of solute per liter solution. Do you know how to calculate this chemical measure? Below we look at the molarity of Sodium Chloride solution.
1/2
1/128
1/7
1/32
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15g
150g
1500g
0.15g
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15g
150g
1500g
0.15g
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2
8
5
32
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True
False
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1/2
1/8
1/5
1/32
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2
128
7
32
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0.001mL reagent and 0.999mL diluent
Make a 10 fold compound dilution with each tube 1/10 as concentrated as the last tube. Two tubes are needed - #1 and #2 . Tube #1 contains 1ml reagent and 9ml diluent. tube two contains 1ml of dilution from tube #1 and 9ml diluent. tube #2 now contains 10mL of 1/1000 dilution of reagent
Make a 10 fold compound diution with each tube 1/10 as concentrated as the last tube. Three tubes are needed.tube #1 ,#2 and #3 . tube #1 contains 1ml reagent and 9ml diluent. Tube two contains 1ml of dilution from tube #1 and 9ml diluent. tube #3 contains 1ml of dilution from tube #2 and 9ml diluent. tube #3 now contains 10mL of 1/1000 dilution of reagent
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1g
10g
1000g
0.1g
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17.4g
174g
1740g
5.9g
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17.4g
1.74g
1740g
5.9g
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0.01g
1g
100g
0.1g
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0.001mL reagent and 0.999mL diluent
Make a 10 fold compound dilution with each tube 1/10 as concentrated as the last tube. Two tubes are needed - #1 and #2 . Tube #1 contains 1ml reagent and 9ml diluent. tube two contains 1ml of dilution from tube #1 and 9ml diluent. tube #2 now contains 10mL of 1/100 dilution of reagent
Make a 10 fold compound diution with each tube 1/10 as concentrated as the last tube. Three tubes are needed.tube #1 ,#2 and #3 . tube #1 contains 1ml reagent and 9ml diluent. Tube two contains 1ml of dilution from tube #1 and 9ml diluent. tube #3 contains 1ml of dilution from tube #2 and 9ml diluent. tube #3 now contains 10mL of 1/100 dilution of reagent
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15g
150g
1500g
0.15g
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