Radiation Therapy Quiz

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  • 1/10 Questions

    What is the process by which a magnetic field and radiofrequency you used to create sectional images of the body?

    • RRM
    • MMR
    • KRI
    • MRI
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About This Quiz

Do you know enough about radiation therapy? Can you score high on this radiation therapy quiz? Radiation therapy or radiotherapy, which is often abbreviated as RT, RTx, or XRT, is known as a therapy that uses ionizing radiation. It is generally provided as a part of cancer treatment to kill malignant cells. It is normally delivered by a linear accelerator. It has an important role in medical field. Take some questions on the same, and let's see what you know.

Radiation Therapy Quiz - Quiz

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  • 2. 

    A tumor is to receive 6300 cGy in 42 fractions.  What is the dose per fraction?______cGy/Fraction

    • 150

    • 168

    • 170

    • 180

    Correct Answer
    A. 150
    Explanation
    The dose per fraction can be calculated by dividing the total dose (6300 cGy) by the number of fractions (42). In this case, 6300 cGy divided by 42 equals 150 cGy/fraction.

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  • 3. 

    A term that describes the judgment or determination of the quality of work or creation

    • Case study

    • Analysis

    • Evaluation

    • None of these

    Correct Answer
    A. Evaluation
    Explanation
    Evaluation is the correct answer because it refers to the process of assessing or judging the quality or value of something, such as work or creation. It involves analyzing and forming an opinion about the strengths, weaknesses, and overall effectiveness of the subject being evaluated. In this context, evaluation would be the most appropriate term to describe the judgment or determination of the quality of work or creation.

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  • 4. 

    The film for SSD treatment on a linear accelerator is taken at 133 cm.  What is the magnification factor?

    • 1.11 cm

    • 1.21 cm

    • 1.33 cm

    • 1.43 cm

    Correct Answer
    A. 1.33 cm
    Explanation
    The magnification factor is the ratio of the actual size of an object to its size on the film. In this case, since the film is taken at 133 cm, the magnification factor is 1.33 cm. This means that the size of the object on the film is 1.33 times larger than its actual size.

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  • 5. 

    A patient is treated with the parallel opposed portal. The isocenter is it midline. The fields are equally weighted. The total dose is 5760 cGy, and the daily dose per port is 90 cGy. How many daily treatments will the patient receive?

    • 27

    • 32

    • 35

    • 49

    Correct Answer
    A. 32
    Explanation
    The total dose is 5760 cGy and the daily dose per port is 90 cGy. To find the number of daily treatments, we divide the total dose by the daily dose per port. 5760 cGy ÷ 90 cGy = 64. Therefore, the patient will receive 64 daily treatments. However, since the fields are equally weighted, the patient will receive half of the treatments from each field. Therefore, the patient will receive 32 daily treatments from each field.

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  • 6. 

    What is the field size on a film if the collimator setting is 7X19 CM and the magnification factor is 1.33X?Choose the closest answer.

    • 8x15 cm

    • 10x10 cm

    • 9x25 cm

    • 8.99x26 cm

    Correct Answer
    A. 9x25 cm
    Explanation
    The field size on a film can be calculated by multiplying the collimator setting by the magnification factor. In this case, 7 cm (collimator setting) multiplied by 1.33 (magnification factor) equals 9.31 cm. Since the answer choices are given in whole numbers, the closest answer is 9x25 cm.

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  • 7. 

    A term that describes the determination of the cause and effect of a situation or work

    • Case study

    • Analysis

    • Evaluation

    • None of these

    Correct Answer
    A. Analysis
    Explanation
    Analysis is the correct answer because it refers to the process of examining and evaluating a situation or work in order to understand its cause and effect. It involves breaking down the components, studying the relationships, and drawing conclusions based on evidence and data. This term accurately describes the determination of cause and effect, making it the most suitable answer among the given options.

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  • 8. 

    A patient is simulated to receive a treatment to cover a tumor volume plus 1 cm on each side. The tumor is 3.5 cm wide and has a depth of 4 cm. What will be the necessary field width at the skin surface, using a linear accelerator with the isocentric setup?

    • 5.28 CM

    • 6.31 CM

    • 6.67 CM

    • 8.0 CM

    Correct Answer
    A. 5.28 CM
    Explanation
    The necessary field width at the skin surface can be calculated by adding the tumor width (3.5 cm) and twice the additional coverage (1 cm on each side). So, the total field width would be 3.5 cm + 2 cm = 5.5 cm. However, the question specifies that a linear accelerator with the isocentric setup is being used. In this setup, the field width is reduced by 5% to account for beam penumbra. Therefore, 5% of 5.5 cm is 0.275 cm, which when subtracted from 5.5 cm gives us 5.225 cm. Rounding this value to the nearest hundredth, we get 5.23 cm, which is closest to the given answer of 5.28 cm.

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  • 9. 

    The dose rate on a linac machine is 102.4 cGy/Min at 100 cm.  What is the dose rate at 85.5 cm

    • 120

    • 125

    • 140

    • 160

    Correct Answer
    A. 140
    Explanation
    The dose rate on a linac machine decreases as the distance from the source increases. In this case, the dose rate at 100 cm is given as 102.4 cGy/Min. Since the distance at 85.5 cm is smaller, the dose rate would be higher than 102.4 cGy/Min. Among the given options, the closest value to a higher dose rate is 140 cGy/Min, which is the correct answer.

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  • 10. 

    The dose at the isocenter for a field is 75 cGy per fraction. At a depth of 6 CM, using a 6 MeV beam, 10X10 CM collimator, the TMR is 0.899. The dose at a depth of maximum build-up is 83.4 cGy each time the isocenter gets 75 cGy. If the patient is to get 2625 cGy from this field, what is the total dose at d/max?

    • 2919

    • 2681

    • 2891

    • 3029

    Correct Answer
    A. 2919
    Explanation
    The total dose at d/max can be calculated by multiplying the dose at the isocenter (75 cGy) by the dose at a depth of maximum build-up (83.4 cGy each time the isocenter gets 75 cGy). Since the patient is to receive 2625 cGy from this field, the total dose at d/max would be 2625 cGy multiplied by the ratio of the dose at a depth of maximum build-up to the dose at the isocenter (83.4 cGy / 75 cGy). This calculation results in a total dose at d/max of 2919 cGy.

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  • Current Version
  • Aug 19, 2023
    Quiz Edited by
    ProProfs Editorial Team
  • Aug 15, 2010
    Quiz Created by
    Mabecorp

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