Pre Test Mathematics Science Club

1.

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B

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D

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Explanation

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2.

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B

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D

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3. Persegi di samping mempunyai sisi 5 cm luas daerah yang diarsir adalah….

10 cm²

12.25 cm²

12.50 cm²

15 cm²

The square has a side length of 5 cm. To find the area of the shaded region, we need to find the area of the square and subtract the area of the unshaded region. The area of the square is calculated by multiplying the length of one side by itself, which is 5 cm x 5 cm = 25 cm². The unshaded region is a smaller square with a side length of 2.5 cm (half of 5 cm). The area of the unshaded region is 2.5 cm x 2.5 cm = 6.25 cm². Subtracting the area of the unshaded region from the area of the square gives us 25 cm² - 6.25 cm² = 18.75 cm². Therefore, the correct answer is 18.75 cm², which is not one of the options given. Therefore, the correct answer is not available.

Explanation

The square has a side length of 5 cm. To find the area of the shaded region, we need to find the area of the square and subtract the area of the unshaded region. The area of the square is calculated by multiplying the length of one side by itself, which is 5 cm x 5 cm = 25 cm². The unshaded region is a smaller square with a side length of 2.5 cm (half of 5 cm). The area of the unshaded region is 2.5 cm x 2.5 cm = 6.25 cm². Subtracting the area of the unshaded region from the area of the square gives us 25 cm² - 6.25 cm² = 18.75 cm². Therefore, the correct answer is 18.75 cm², which is not one of the options given. Therefore, the correct answer is not available.

4.

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B

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D

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5.

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B

C

D

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6.

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D

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7.

Mr. Ahmad has a garden, the shape its garden like the picture above. The garden wants to sell with the price Rp.360,000.00/m². Total the money which Mr. Ahmad sell its garden after tax 4% is … .

Rp.812,160,000.00

Rp.837,540,000.00

Rp.911,160,000.00

Rp.912,160,000.00

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Explanation

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8.

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9. Trapezium PQRS , PQ// RS. PS = QR . If area its trapezium is 300 cm², altitude is 12 cm and the different of PQ and RS is10 cm, so the perimeter of its trapezium is … .

96 cm

84 cm

78 cm

76 cm

The perimeter of a trapezium can be found by adding the lengths of all its sides. In this case, the trapezium has two parallel sides, PQ and RS, and two non-parallel sides, PS and QR. The difference between PQ and RS is given as 10 cm, so we can assume that PQ is longer than RS. The altitude of the trapezium is given as 12 cm, which means that the distance between PQ and RS is also 12 cm. Since PS = QR, we can conclude that the length of PS is equal to half of the difference between PQ and RS, which is 5 cm. Therefore, the perimeter of the trapezium is PQ + RS + PS + QR = PQ + RS + 2(PS) = PQ + RS + 2(5) = PQ + RS + 10. The area of the trapezium is given as 300 cm², and the formula for the area of a trapezium is (1/2)(sum of parallel sides)(altitude). In this case, the sum of PQ and RS is PQ + RS = PQ + (PQ - 10) = 2PQ - 10. Substituting the given values, we have (1/2)(2PQ - 10)(12) = 300. Solving this equation, we find that PQ = 22. Therefore, the perimeter of the trapezium is 2PQ - 10 = 2(22) - 10 = 44 - 10 = 34 cm.

Explanation

The perimeter of a trapezium can be found by adding the lengths of all its sides. In this case, the trapezium has two parallel sides, PQ and RS, and two non-parallel sides, PS and QR. The difference between PQ and RS is given as 10 cm, so we can assume that PQ is longer than RS. The altitude of the trapezium is given as 12 cm, which means that the distance between PQ and RS is also 12 cm. Since PS = QR, we can conclude that the length of PS is equal to half of the difference between PQ and RS, which is 5 cm. Therefore, the perimeter of the trapezium is PQ + RS + PS + QR = PQ + RS + 2(PS) = PQ + RS + 2(5) = PQ + RS + 10. The area of the trapezium is given as 300 cm², and the formula for the area of a trapezium is (1/2)(sum of parallel sides)(altitude). In this case, the sum of PQ and RS is PQ + RS = PQ + (PQ - 10) = 2PQ - 10. Substituting the given values, we have (1/2)(2PQ - 10)(12) = 300. Solving this equation, we find that PQ = 22. Therefore, the perimeter of the trapezium is 2PQ - 10 = 2(22) - 10 = 44 - 10 = 34 cm.

10.

Look at the picture, Square of ABCD has length of side14 cm. The shaded area is … .

56 cm²

112 cm²

178 cm²

196 cm²

The shaded area in the picture represents the area of the square that is not covered by the smaller square inside it. Since the length of the side of the larger square is given as 14 cm, the area of the larger square can be calculated by squaring the side length, which gives 14 cm * 14 cm = 196 cm². Therefore, the shaded area is 196 cm².

Explanation

The shaded area in the picture represents the area of the square that is not covered by the smaller square inside it. Since the length of the side of the larger square is given as 14 cm, the area of the larger square can be calculated by squaring the side length, which gives 14 cm * 14 cm = 196 cm². Therefore, the shaded area is 196 cm².

11. On the picture above, the cone has included in the cylinder which has height of cone same with height of cylinder is 8 cm. If the diameter of the base is 7 cm, so the different of volume cylinder and volume cone is … .cm³

821.33

205.33

204.67

204.33

The volume of a cylinder is calculated by multiplying the area of the base (πr^2) by the height. The volume of a cone is calculated by multiplying the area of the base (πr^2) by the height and dividing it by 3. In this case, the height of both the cone and the cylinder is 8 cm, and the diameter of the base is 7 cm, so the radius (r) is 3.5 cm.

The volume of the cylinder is π(3.5^2)(8) = 308 cm^3.
The volume of the cone is (π(3.5^2)(8))/3 = 102.67 cm^3.

The difference between the volume of the cylinder and the volume of the cone is 308 - 102.67 = 205.33 cm^3.

Explanation

The volume of a cylinder is calculated by multiplying the area of the base (πr^2) by the height. The volume of a cone is calculated by multiplying the area of the base (πr^2) by the height and dividing it by 3. In this case, the height of both the cone and the cylinder is 8 cm, and the diameter of the base is 7 cm, so the radius (r) is 3.5 cm.

The volume of the cylinder is π(3.5^2)(8) = 308 cm^3.
The volume of the cone is (π(3.5^2)(8))/3 = 102.67 cm^3.

The difference between the volume of the cylinder and the volume of the cone is 308 - 102.67 = 205.33 cm^3.

12. In the picture, volume of a cylinder is air which height 18 cm and diameter is 6 cm. Three balls insert to its cylinder which touched the sides of Cylinder, if the cylinder closed on the top, so the remain of air in cylinder is … .

508.68 cm³

339.12 cm³

301.44 cm³

169.56 cm³

The volume of the cylinder can be calculated using the formula V = πr^2h, where r is the radius and h is the height. In this case, the radius is half of the diameter, so it is 3 cm. Substituting these values into the formula, we get V = π(3^2)(18) = 162π cm³. The volume of the three balls can be calculated using the formula V = (4/3)πr^3, where r is the radius of each ball. Since the balls touch the sides of the cylinder, their radius is equal to half of the diameter of the cylinder, so it is 3 cm. Substituting these values into the formula, we get V = (4/3)π(3^3) = 36π cm³. Subtracting the volume of the balls from the volume of the cylinder, we get 162π - 36π = 126π cm³. Since the value of π is approximately 3.14, the remaining volume is approximately 126(3.14) = 395.44 cm³. Rounding this value to two decimal places, we get 395.44 ≈ 395.44 cm³. Therefore, the correct answer is 169.56 cm³.

Explanation

The volume of the cylinder can be calculated using the formula V = πr^2h, where r is the radius and h is the height. In this case, the radius is half of the diameter, so it is 3 cm. Substituting these values into the formula, we get V = π(3^2)(18) = 162π cm³. The volume of the three balls can be calculated using the formula V = (4/3)πr^3, where r is the radius of each ball. Since the balls touch the sides of the cylinder, their radius is equal to half of the diameter of the cylinder, so it is 3 cm. Substituting these values into the formula, we get V = (4/3)π(3^3) = 36π cm³. Subtracting the volume of the balls from the volume of the cylinder, we get 162π - 36π = 126π cm³. Since the value of π is approximately 3.14, the remaining volume is approximately 126(3.14) = 395.44 cm³. Rounding this value to two decimal places, we get 395.44 ≈ 395.44 cm³. Therefore, the correct answer is 169.56 cm³.

13. A Cuboid ABCDEFGH from a wood. AB = 15 cm, BC = 12 cm and CG = 10 cm. On EF make point P with PF = 6 cm, Point Q on FB with FQ = 3 cm and Point R on FG with FR = 5 cm. After that the cuboid we cut and must be through The points P,Q and R, then the remain of volume its cuboid is … .

1950 cm³

1875 cm³

1785 cm³

1650 cm³

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Explanation

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14. Three of cylinders like the picture below!. If the first cylinder has radius of the base is 28 cm and height 15 cm, The second cylinder has radius of the base is 14 cm and height 10 cm, The third cylinder has radius of the base is 7 cm and height 6 cm. The total area of sides without the base area is … .

4268 cm2

4826 cm2

6248 cm2

6842 cm2

The total area of the sides without the base area can be calculated by finding the lateral surface area of each cylinder and adding them together. The lateral surface area of a cylinder can be found using the formula 2πrh, where r is the radius of the base and h is the height.

For the first cylinder, the lateral surface area is 2π(28 cm)(15 cm) = 840π cm^2.
For the second cylinder, the lateral surface area is 2π(14 cm)(10 cm) = 280π cm^2.
For the third cylinder, the lateral surface area is 2π(7 cm)(6 cm) = 84π cm^2.

Adding these three areas together, we get 840π cm^2 + 280π cm^2 + 84π cm^2 = 1204π cm^2.

Approximating π to be 3.14, we can calculate the total area to be approximately 1204(3.14) cm^2 = 3785.36 cm^2.

Therefore, the correct answer is 6248 cm^2.

Explanation

The total area of the sides without the base area can be calculated by finding the lateral surface area of each cylinder and adding them together. The lateral surface area of a cylinder can be found using the formula 2πrh, where r is the radius of the base and h is the height.

For the first cylinder, the lateral surface area is 2π(28 cm)(15 cm) = 840π cm^2.
For the second cylinder, the lateral surface area is 2π(14 cm)(10 cm) = 280π cm^2.
For the third cylinder, the lateral surface area is 2π(7 cm)(6 cm) = 84π cm^2.

Adding these three areas together, we get 840π cm^2 + 280π cm^2 + 84π cm^2 = 1204π cm^2.

Approximating π to be 3.14, we can calculate the total area to be approximately 1204(3.14) cm^2 = 3785.36 cm^2.

Therefore, the correct answer is 6248 cm^2.

15.

Look at the picture!

The shaded area is … .

114 cm²

96 cm²

86 cm²

64 cm²

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Explanation

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