The Mega Test 02/ Mathematics

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| By SAYAN CHATTERJEE

SAYAN CHATTERJEE

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Quizzes Created: 2 | Total Attempts: 207

| Attempts: 61

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1/60 Questions

The height of two towers is 150 m and 136 m respectively. If the distance between them is 48 m, find the distance between their tops.
- 48 m
- 50 m
- 55 m
- 60 m

About This Quiz

The Mega Test 02\/Mathematics assesses key geometric concepts through practical problems. It measures understanding of distances, perimeters, and area calculations, relevant for learners aiming to enhance their mathematical proficiency.

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2.

A tree broke from a point but did not separate. Its top touched the ground at a distance of 24 m from its base. If the point where it broke is at the height of 7 m from the ground, what is the total height of the tree?
- 26 m
- 29 m
- 32 m
- 36 m
Correct Answer

A. 32 m

Explanation

The total height of the tree can be determined by adding the distance from the point where it broke to the ground (7 m) and the distance from the top of the tree to the ground (24 m). Therefore, the total height of the tree is 7 m + 24 m = 31 m. Since none of the given options match this value, the correct answer cannot be determined.

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3.

The factors of 49p² – 36 are:
- (7p-6)²
- (7p+6)²
- (6p – 7 ) ( 6p + 7)
- (7p – 6 ) ( 7p + 6)
Correct Answer

A. (7p – 6 ) ( 7p + 6)

Explanation

The correct answer is (7p - 6) (7p + 6). This is because when we expand the expression (7p - 6) (7p + 6), we get 49p^2 - 36, which matches the given expression.

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4.

If a² + b² + c² = 20 and a + b + c =0, find ab + bc + ca.
- -10
- -4
- 0
- 5
Correct Answer

A. -10

Explanation

Given that a + b + c = 0, we can rewrite the equation a2 + b2 + c2 = 20 as (a + b + c)2 - 2(ab + bc + ca) = 20. Substituting 0 for a + b + c, we get 0 - 2(ab + bc + ca) = 20. Solving for ab + bc + ca, we find that it is equal to -10.

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5.

If x² – 3x + 2 divides x³ – 6x² + ax + b exactly, then find the value of ‘a’ and ‘b’
- 10 and -5
- 11 and -6
- 12 and -4
- 9 and 2
Correct Answer

A. 11 and -6

Explanation

*##*x2 – 3x + 2 = (x – 1) (x – 2) ⇒ x3 – 6x2 + ax + b is exactly divisible by
(x – 1) and (x – 2)
Putting x-1=0⇒x=1in the equation
⇒ a + b – 5 = 0
Putting x-2=0 or x=2 in the equation
⇒ 2a + b – 16 = 0
solving (i) and (ii) a = 11 and b = – 6*##*x2 – 3x + 2 = (x – 1) (x – 2) ⇒ x3 – 6x2 + ax + b is exactly divisible by
(x – 1) and (x – 2)
Putting x-1=0⇒x=1in the equation
⇒ a + b – 5 = 0
Putting x-2=0 or x=2 in the equation
⇒ 2a + b – 16 = 0
solving (i) and (ii) a = 11 and b = – 6

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6.

Find out the C.I on Rs.5000 at 4% p.a. compound half-yearly for 1¹/₂ years.
- Rs 420.20
- 319.08
- Rs 306.04
- Rs 294.75
Correct Answer

A. Rs 306.04

Explanation

The formula to calculate compound interest is A = P(1 + r/n)^(nt), where A is the final amount, P is the principal amount, r is the annual interest rate, n is the number of times that interest is compounded per year, and t is the number of years. In this case, the principal amount is Rs.5000, the annual interest rate is 4%, the interest is compounded half-yearly (n = 2), and the time period is 11/2 years. Plugging these values into the formula, we get A = 5000(1 + 0.04/2)^(2*(3/2)). Calculating this expression gives us Rs.306.04, which is the correct answer.

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7.

Find the CI on a sum of Rs 1600 for 9 months at 20% p.a. compounded quarterly.
- 176.84
- 168.40
- 252.20
- 340.84
Correct Answer

A. 252.20

Explanation

The correct answer is 252.20. To find the compound interest (CI), we use the formula: CI = P(1 + r/n)^(nt) - P, where P is the principal amount, r is the rate of interest, n is the number of times interest is compounded per year, and t is the time in years. Plugging in the values, we get CI = 1600(1 + 0.20/4)^(4*9) - 1600 = 252.20.

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8.

The sum of money at compound interest amounts to thrice itself in 3 years. In how many years will it be 9 times itself?
- 6 years
- 9 years
- 12 years
- 18 years
Correct Answer

A. 6 years

Explanation

If the sum of money at compound interest amounts to thrice itself in 3 years, it means that the interest rate is such that the sum of money triples in 3 years. Therefore, if we want the sum of money to be 9 times itself, it will require the same interest rate and the same amount of time. Hence, it will take 6 years for the sum of money to be 9 times itself.

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9.

The difference between CI and SI on a certain sum of money for 3 years at 6 ²/₃% p.a. is Rs 184. The sum is
- 12000
- 13500
- 14200
- 17520
Correct Answer

A. 13500

Explanation

The difference between compound interest (CI) and simple interest (SI) can be calculated using the formula CI = P(1 + r/100)^n - P and SI = P * r * n/100, where P is the principal sum, r is the rate of interest, and n is the number of years. In this case, we are given that the difference between CI and SI is Rs 184. By substituting the given values into the formulas, we can solve for the principal sum. The correct answer is 13500.

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10.

A sum of money is put out at compound interest for 2 years at 20%. It would fetch Rs.482 more if the interest were payable half-yearly, then it were pay able yearly. Find the sum.
- 1000
- 1250
- 2000
- 4000
Correct Answer

A. 2000

Explanation

P(11/10)^4 - P(6/5)^2 = 482

P = 2000

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11.

Barsha gave Prama Rs.1250 on compound interest for 2 years at 4% per annum. How much loss would Barsha have suffered had she given it to Prama for 2 years at 4% per annum simple interest?
- Rs 10
- Rs 2
- Rs 5
- Rs 3
Correct Answer

A. Rs 2

Explanation

1250 = D(100/4)2

D = 2

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12.

In one year, the population, of a village increased by 10% and in the next year, it decreased by 10%. If at the end of 2nd year, the population was 7920, what was it in the beginning?
- 7900
- 7800
- 8100
- 8000
Correct Answer

A. 8000

Explanation

In the first year, the population increased by 10%, so the population at the end of the first year would be 110% of the initial population. In the second year, the population decreased by 10%, so the population at the end of the second year would be 90% of the population at the end of the first year. If we let the initial population be x, then at the end of the first year, the population would be 1.1x, and at the end of the second year, the population would be 0.9(1.1x) = 0.99x. Given that the population at the end of the second year is 7920, we can set up the equation 0.99x = 7920 and solve for x, which gives us x = 8000. Therefore, the population in the beginning was 8000.

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13.

A sum amount to Rs.1344 in two years at simple interest. What will be the compound interest on the same sum for the same period?
- 150
- 134.40
- 140
- None of the above
Correct Answer

A. None of the above

Explanation

Data is insufficient, you need a rate of interest to do the calculation

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14.

The population of a city increases at the rate of 4% p.a. but there is an additional annual increase of 1% in the population due to some job seekers. The percentage increase in the population after 2 years is?
- 5.50%
- 10%
- 10.25%
- 12.50%
Correct Answer

A. 10.25%

Explanation

Let old population be P
New Population = P' = P*{1+(5/100)}^2 = 441 P/400
% increase in population = (new pop - old pop)/old pop = 41/400 = 10.25%

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15.

Compound interest earned on a sum for the second and the third years are Rs.1200 and Rs.1440 respectively. Find the rate of interest?
- 15%
- 12%
- 18%
- 20%
Correct Answer

A. 20%

Explanation

The compound interest earned for the second year is Rs.1200 and for the third year is Rs.1440. This means that the interest earned in the third year is higher than the interest earned in the second year, indicating that the interest is increasing over time. This suggests that the rate of interest is also increasing. Among the given options, the only rate of interest that is higher than the previous options is 20%. Therefore, the rate of interest is 20%.

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16.

A sum of Rs.4800 is invested at a compound interest for three years, the rate of interest being 10% p.a., 20% p.a. and 25% p.a. for the 1st, 2nd and the 3rd years respectively. Find the interest received at the end of the three years.
- Rs 2520
- Rs 2760
- Rs 3120
- Rs 3320
Correct Answer

A. Rs 3120

Explanation

The question states that the sum of Rs.4800 is invested at compound interest for three years. The interest rates for the first, second, and third years are 10%, 20%, and 25% respectively. To find the interest received at the end of the three years, we need to calculate the compound interest for each year and add them together. The compound interest for the first year is Rs.480, for the second year is Rs.960, and for the third year is Rs.1680. Adding these amounts gives us a total interest of Rs.3120.

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17.

What is the difference between the compound interest on Rs.12000 at 20% p.a. for one year when compounded yearly and half yearly?
- Rs 100
- Rs 108
- Rs 120
- Rs 144
Correct Answer

A. Rs 120

Explanation

When compounded annually, interest

= 12000[1 + 20/100]^1 - 12000 = Rs.2400
When compounded semi-annually, interest
= 12000[1 + 10/100]^2 - 12000 = Rs.2520
Required difference = 2520 - 2400 = Rs.120

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18.

Ayushman wants to borrow Rs.6000 at rate of interest 6% p.a. at S.I and lend the same amount at C.I at same rate of interest for two years. What would be his income in the above transaction?
- Rs 24.00
- Rs 25.20
- Rs 21.60
- Rs 20.80
Correct Answer

A. Rs 21.60

Explanation

Amount of money Siddharth borrowed at S.I at 6% p.a. for two years = Rs.6,000

He lend the same amount for C.I at 6% p.a. for two years.
=> Siddharth's income = C.I - S.I
= p[1 + r/ 100^]n - p - pnr/100
= p{ [1 + r/ 100^]2 - 1 - nr/100
= 6,000{ [1 + 6/100]^2 - 1 - 12/100}
= 6,000 {(1.06)^2- 1 - 0.12} = 6,000(1.1236 - 1 - 0.12)
= 6,000 (0.0036) = 6 * 3.6 = Rs.21.60

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19.

The difference between simple and compound interest on Rs. 1200 for one year at 10% per annum reckoned half-yearly is?
- Rs 2.40
- Re 1
- Rs 3
- Rs 3.60
Correct Answer

A. Rs 3

Explanation

S.I. = (1200 * 10 * 1)/100 = Rs. 120

C.I. = [1200 * (1 + 5/100)^2 - 1200] = Rs. 123

Difference = (123 - 120) = Rs. 3.

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20.

On a sum of money, the S.I. for 2 years is Rs. 660, while the C.I. is Rs. 696.30, the rate of interest being the same in both the cases. The rate of interest is?
- 10%
- 10.5%
- 11%
- 12%
Correct Answer

A. 11%

Explanation

The difference between the compound interest and simple interest is Rs. 36.30 (696.30 - 660). This difference is equal to the interest earned on the simple interest for the first year. So, the interest earned on the simple interest for the first year is Rs. 36.30. Since the rate of interest is the same for both cases, the interest earned on the compound interest for the first year is also Rs. 36.30. Therefore, the amount on which the interest is calculated is Rs. 660 (660 + 36.30). The rate of interest can be calculated using the formula I = P*R*T/100, where I is the interest, P is the principal, R is the rate of interest, and T is the time. Plugging in the values, we get 36.30 = 660*R*1/100. Solving for R, we find that the rate of interest is 11%.

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21.

Simple Interest on a sum at 4% per annum for 2 years is 80. The compound interest on the same sum for the same period is?
- 81.60
- 80.80
- 84.00
- 88.80
Correct Answer

A. 81.60
22.

If tan2A = cot(A-18°), then value of A is:
- 27°
- 36°
- 24°
- 30°
Correct Answer

A. 36°

Explanation

Given, tan 2A = cot (A – 18°)

⇒ tan 2A = tan (90 – (A – 18°)

⇒ tan 2A = tan (108° – A)

⇒ 2A = 108° – A

⇒ 3A = 108°

⇒ A = 36°

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23.

If the height of a tower and the distance of the point of observation from its foot,both, are increased by 10%, then the angle of elevation of its top
- Increases by 20%
- Decreases by 20%
- Remains unchanged
- Have no relation
Correct Answer

A. Remains unchanged

Explanation

tan θ = h/x

Where h is height and x is distance from tower,

If both are increased by 10%, then the angle will remain unchanged.

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24.

An observer √3m tall is 3 m away from the pole 2√3 high. What is the angle of elevation of the top?
- 60°
- 30°
- 45°
- 90°
Correct Answer

A. 30°

Explanation

Height of the pole that is above man’s height = 2 √3 – √3 = √3m

Hence, AB = √3m

BC = 3m

Hence, tan C = AB/BC= 1/√3

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25.

Find the perimeter of the rectangle whose length is 24 cm and diagonal is 26 cm.
- 50 cm
- 56 cm
- 62 cm
- 68 cm
Correct Answer

A. 68 cm

Explanation

To find the perimeter of a rectangle, we need to know either the length and width or the length and diagonal. In this case, we are given the length and diagonal. We can use the Pythagorean theorem to find the width of the rectangle. The Pythagorean theorem states that in a right triangle, the square of the hypotenuse (diagonal) is equal to the sum of the squares of the other two sides (length and width). So, we can calculate the width by taking the square root of (diagonal^2 - length^2). By substituting the given values, we find that the width is 10 cm. The perimeter of a rectangle is calculated by adding the lengths of all four sides. Therefore, the perimeter of this rectangle is 2(length + width) = 2(24 + 10) = 68 cm.

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26.

The C.I. on a certain sum for 2 years Rs.41 and the simple interest is Rs.40. What is the rate percent?
- 1%
- 2%
- 5%
- 10%
Correct Answer

A. 5%

Explanation

The difference between the compound interest and simple interest is Rs.1 (41 - 40). This difference is equal to the interest earned on the principal amount for 1 year. Therefore, the rate of interest is 1%. Since the question asks for the rate percent for 2 years, we need to double the rate, which gives us 2%. However, none of the given options match this calculation. Therefore, the correct answer is not available.

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27.

A sum of money deposited at C.I. amounts to Rs.2420 in 2 years and to Rs.2662 in 3 years. Find the rate percent?
- 15%
- 10%
- 7¹/_{2 %}
- 5%
Correct Answer

A. 10%

Explanation

The correct answer is 10%. To find the rate percent, we can use the formula for compound interest: A = P(1 + r/n)^(nt), where A is the final amount, P is the principal amount, r is the rate of interest, n is the number of times interest is compounded per year, and t is the time in years. In this case, we have two equations: 2420 = P(1 + r/100)^(2) and 2662 = P(1 + r/100)^(3). By dividing the second equation by the first equation, we can eliminate the principal amount P and solve for r. After solving, we find that r is equal to 10%.

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28.

A property decreases in value every year at the rate of 6 ¹/₄% of its value at the beginning of the year its value at the end of 3 years was Rs.21093. Find its value at the beginning of the first year?
- Rs 32000.50
- Rs 25600.24
- Rs 18060.36
- Rs 18600
Correct Answer

A. Rs 25600.24

Explanation

6 1/4% = 1/16

x *15/16 * 15/16 * 15/16 = 21093

x = 25600.24

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29.

What sum of money put at C.I amounts in 2 years to Rs.8820 and in 3 years to Rs.9261?
- 8000
- 8100
- 8400
- 8650
Correct Answer

A. 8000

Explanation

8820 ---- (9261 - 8820) = 441

100 ---- 441/8820
=5%

x *105/100 * 105/100 = 8820

x* (21/20)^2= 8820

x=8820*400/441 => 8000

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30.

A sum of money placed in CI doubles itself in 5 years. It will amount to eight times of itself in
- 40 years
- 20 years
- 15 years
- 10 years
Correct Answer

A. 15 years

Explanation

If the sum of money placed in compound interest doubles itself in 5 years, it means that the interest rate is 100% per year. To find out how long it will take for the sum to amount to eight times itself, we can use the formula for compound interest: A = P(1+r/n)^(nt), where A is the final amount, P is the principal amount, r is the interest rate, n is the number of times interest is compounded per year, and t is the number of years. In this case, we want to find t when A = 8P, so we have 8P = P(1+1/1)^(1*t). Simplifying this equation, we get 8 = 2^t. Taking the logarithm of both sides, we find t = log(8)/log(2) = 3. Therefore, it will take 15 years for the sum to amount to eight times itself.

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31.

(sin A−2 sin³A)/ (2 cos³A−cos A) =
- Tan A
- Cot A
- Sec A
- 1
Correct Answer

A. Tan A

Explanation

The given expression can be simplified using trigonometric identities. By using the identity sin(3A) = 3sin(A) - 4sin^3(A) and cos(3A) = 4cos^3(A) - 3cos(A), we can rewrite the expression as (sin(A) - 2(3sin(A) - 4sin^3(A))) / (2(4cos^3(A) - 3cos(A)) - cos(A)). Simplifying further, we get sin(A) - 6sin(A) + 8sin^3(A) / 8cos^3(A) - 5cos(A). This can be rewritten as -5sin(A) + 8sin^3(A) / -5cos(A) + 8cos^3(A). Using the identity tan(A) = sin(A) / cos(A), we can conclude that the expression is equal to tan(A).

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32.

A circus artist is climbing a 20 m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. Find the height of the pole if the angle made by the rope with the ground level is 30°.
- 10 m
- 15 m
- 20 m
- 30 m
Correct Answer

A. 10 m

Explanation

In ΔABC, we have

sin 30°=h/20

⇒1/2=h/20

⇒h=10 m

Hence, the height of the pole is 10 m.

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33.

In a circle with center O, two diameters AB and CD are drawn perpendicular to each other. Find the length of chord AC
- 2 AB
- AB √2
- AB/2
- AB/√2
Correct Answer

A. AB/√2

Explanation

In a circle, the length of a chord is given by the formula 2r*sin(θ/2), where r is the radius of the circle and θ is the angle subtended by the chord at the center of the circle. In this case, since AB and CD are diameters, they divide the circle into four quadrants, each with a central angle of 90 degrees. Therefore, the angle subtended by chord AC is 90 degrees. Since the radius of the circle is AB/2, substituting these values into the formula gives 2*(AB/2)*sin(90/2) = AB/√2. Thus, the length of chord AC is AB/√2.

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34.

The diagonals of a rhombus are 24 m and 10 m. find the perimeter.
- 46 m
- 48 m
- 50 m
- 52 m
Correct Answer

A. 52 m

Explanation

A rhombus is a quadrilateral with all four sides equal in length. The diagonals of a rhombus bisect each other at right angles. In this question, the given diagonals are 24 m and 10 m. Since the diagonals bisect each other, each half of the longer diagonal is equal to the side length of the rhombus. Therefore, the side length of the rhombus is 12 m. The perimeter of a rhombus is calculated by multiplying the side length by 4. Thus, the perimeter is 12 m * 4 = 48 m.

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35.

One of the diagonals of the rhombus is 3 cm and each side is 2.5 cm. Find the length of the other diagonal of the rhombus.
- 3 cm
- 4 cm
- 5 cm
- 5.5 cm
Correct Answer

A. 4 cm

Explanation

The length of the other diagonal of a rhombus can be found using the formula d = 2a, where d is the length of the diagonal and a is the length of the side. In this case, the length of the side is given as 2.5 cm. Therefore, the length of the other diagonal would be 2 * 2.5 cm = 5 cm.

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36.

The factors of 4y²– 12y + 9 is:
- (2y+3)²
- (2y-3)²
- (2y-3)(2y+3)
- None of the above
Correct Answer

A. (2y-3)²

Explanation

The given expression is a perfect square trinomial. To factor it, we can use the formula (a-b)2 = a2 - 2ab + b2. In this case, a = 2y and b = 3. Plugging these values into the formula, we get (2y-3)2. Therefore, the correct answer is (2y-3)2.

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37.

If then find the value of
- ±3
- ±4
- ±5
- ±6
Correct Answer

A. ±4

Explanation

The given question is asking for the value of ±3 ±4 ±5 ±6. The correct answer is ±4. This can be obtained by adding all the positive numbers together (3 + 4 + 5 + 6 = 18) and then subtracting the sum of the negative numbers (-3 - 4 - 5 - 6 = -18). The result is 0, so the answer is ±4.

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38.

Simple interest on a sum at 4% per annum for 2 years is Rs.80. The C.I. on the same sum for the same period is?
- 80.08
- 80.80
- 81.60
- 84.00
Correct Answer

A. 81.60

Explanation

The compound interest on a sum for 2 years can be calculated using the formula A = P(1 + r/n)^(n*t), where A is the final amount, P is the principal amount, r is the rate of interest, n is the number of times interest is compounded per year, and t is the number of years. In this case, the simple interest is given as Rs. 80, so the principal amount is Rs. 80. By substituting the given values into the formula, we can calculate the compound interest to be Rs. 81.60.

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39.

The difference between simple interest and C.I. at the same rate for Rs.5000 for 2 years in Rs.72. The rate of interest is?
- 10
- 12
- 6
- 8
Correct Answer

A. 12

Explanation

The difference between simple interest and compound interest for a principal amount of Rs.5000 for 2 years is Rs.72. This means that the compound interest is Rs.72 more than the simple interest. To find the rate of interest, we need to determine the difference in interest for one year. Since the difference is Rs.72 for 2 years, the difference for one year would be Rs.36. To find the rate of interest, we can divide the difference by the principal amount and multiply by 100. Therefore, the rate of interest is 12%.

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40.

Every year an amount increases by 1/8th of itself. How much will it be after two years if its present value is Rs.64000?
- 72000
- 75000
- 80000
- 81000
Correct Answer

A. 81000

Explanation

64000*{1+(1/8)}^2
=64000* 9/8 * 9/8 = 81000

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41.

Ayushman borrowed Rs.4000 at 5% p.a compound interest. After 2 year, he repaid Rs.2210 and after 2 more year, the balance with interest. What was the total amount that he paid as interest?
- Rs 635.50
- Rs 612.50
- Rs 675.50
- Rs 652.50
Correct Answer

A. Rs 635.50

Explanation

After 2 years
Amount = 4000*{1+(5/100)}^2 = 4410
Balance left = 4410 - 2210 = 2200
In next 2 years
Amount to be paid = 2200*{1+(5/100)}^2 = 2425.50
Total amount thus paid = 2425.50 + 2210 = 4635.50
Total interest thus paid = 4635.50 - 4000 = 635.50

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42.

Shrish invested certain amount for two rates of simple interests at 6% p.a. and 7% p.a. What is the ratio of Shrish's investments if the interests from those investments are equal?
- 3:4
- 6:5
- 3:2
- 7:6
Correct Answer

A. 7:6

Explanation

Let x be the investment of Shrish in 6% and y be in 7%

x(6)(n)/100 = y(7)(n)/100
=> x/y = 7/6
x : y = 7 : 6

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43.

If secθ + tanθ = x, then tanθ is
- (x²-1) / 2x
- (x²+1) / 2x
- (x²+1) / x
- (x²-1) / x
Correct Answer

A. (x²-1) / 2x

Explanation

The given equation is secθ + tanθ = x. To find the value of tanθ, we can rearrange the equation to isolate tanθ. Subtracting secθ from both sides gives us tanθ = x - secθ.
Using the identity secθ = 1/cosθ, we can substitute this into the equation to get tanθ = x - 1/cosθ.
Next, we can multiply the equation by cosθ to eliminate the denominator, resulting in tanθ * cosθ = x * cosθ - 1.
Using the identity tanθ * cosθ = sinθ, we have sinθ = x * cosθ - 1.
Finally, we can rearrange the equation to solve for tanθ, giving us tanθ = (sinθ + 1) / cosθ.
This matches the expression (x^2 - 1) / 2x, which is the correct answer.

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44.

If p cotθ = √(q²−p²) , then the value of sinθ is
- Q/3p
- P/q
- P/2q
- P²/2q²
Correct Answer

A. P/q

Explanation

The given equation is p cot(theta) = sqrt(q^2 - p^2). We can rewrite this equation as cot(theta) = sqrt((q^2 - p^2)/p^2). Since cot(theta) is equal to 1/tan(theta), we can rewrite the equation as 1/tan(theta) = sqrt((q^2 - p^2)/p^2). Taking the reciprocal of both sides, we get tan(theta) = p/sqrt(q^2 - p^2). Since sin(theta) = tan(theta)/sqrt(1+tan^2(theta)), we can substitute the value of tan(theta) from the previous equation to get sin(theta) = p/sqrt(q^2 - p^2)/sqrt(1+p^2/(q^2 - p^2)). Simplifying further, we get sin(theta) = p/sqrt(q^2 - p^2) * sqrt(q^2 - p^2)/(q^2 - p^2 + p^2) = p/sqrt(q^2 - p^2) * sqrt(q^2 - p^2)/q^2 = p/q. Therefore, the value of sin(theta) is p/q.

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45.

The angles of elevation of the top of a tower from two points distant s and t from its foot are complementary. Then the height of the tower is:
- St
- S²t²
- √st
- S/t
Correct Answer

A. √st

Explanation

The angles of elevation of the top of a tower from two points distant s and t from its foot are complementary. This means that the sum of the two angles is 90 degrees. Let's assume that the angle of elevation from point s is x degrees. Then, the angle of elevation from point t would be 90 - x degrees. Using trigonometry, we can set up the following equation: tan(x) = height of the tower / s and tan(90 - x) = height of the tower / t. Since tan(90 - x) is equal to cot(x), we can rewrite the second equation as cot(x) = height of the tower / t. By cross multiplying these equations, we get height of the tower = s * t / sqrt(s^2 + t^2). Therefore, the height of the tower is sqrt(st).

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46.

If angle OAB = 40 degree, angle ACB =
- 50
- 40
- 60
- 30
Correct Answer

A. 50

Explanation

Since angle OAB is given as 40 degrees, angle ACB can be found by subtracting 40 degrees from 180 degrees (the sum of angles in a triangle). Therefore, angle ACB is 180 - 40 = 140 degrees.

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47.

AD is the diameter of a circle and AB is a chord. If AD = 34 cm and AB = 30 cm, the distance of AB from the center is
- 17 cm
- 15 cm
- 4 cm
- 8 cm
Correct Answer

A. 8 cm

Explanation

In a circle, the distance from the center to a chord is equal to half the length of the chord. Therefore, the distance of AB from the center is equal to half of AB. Since AB is 30 cm, half of AB is 15 cm. Therefore, the correct answer is 15 cm.

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48.

If AB = 12 cm, BC = 16 cm and AB is perpendicular to BC, then the radius of the circle passing through A, B and C is
- 6 cm
- 10 cm
- 12 cm
- 20 cm
Correct Answer

A. 10 cm

Explanation

In a right triangle, the hypotenuse is twice the length of the shorter leg. Since AB is perpendicular to BC, AB is the shorter leg and BC is the hypotenuse. Therefore, BC is twice the length of AB. Since AB is 12 cm, BC is 24 cm. The radius of the circle passing through A, B, and C is equal to half the length of BC, which is 24/2 = 12 cm. Therefore, the correct answer is 12 cm.

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49.

The compound interest accrued on an amount of Rs.44000 at the end of two years is Rs.1193.60. What would be the simple interest accrued on the same amount at the same rate in the same period?
- Rs 10560
- Rs 10280
- Rs 10720
- Rs 10840
Correct Answer

A. Rs 10560

Explanation

Let the rate of interest be R% p.a.

4400{[1 + R/100]^2 - 1} = 11193.60
[1 + R/100]^2 = (44000 + 11193.60)/44000
[1 + R/100]^2 = 1 + 2544/1000 = 1 + 159/625
[1 + R/100]^2 = 784/625 = (28/25)^2
1 + R/100 = 28/25
R/100 = 3/25
Therefore R = 12 SI on Rs.44000 at 12% p.a. for two years = 44000(2)(12)/100
=Rs.10560

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The Mega Test 02/ Mathematics

The height of two towers is 150 m and 136 m respectively. If the distance between them is 48 m, find the distance between their tops.

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