Molecular Geometry And Hybridization Quiz #2
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In order to produce sp hybrid orbitals, __________ s atomic orbitals(s) and ___________ p atomic orbital(s) must be mixed.
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One, two
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One, three
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One, one
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Two, two
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Two, three
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Molecular Geometry and Hybridization Quiz #2 assesses understanding of hybrid orbitals, bond angles, and pi\/sigma bond counts in organic molecules. It tests key concepts crucial for students in chemistry, enhancing their grasp of molecular structures and bonding.
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- 2.
The angles between sp orbitals are __________.
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45
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180
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90
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109.5
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120
Correct Answer
A. 120Explanation
The angles between sp orbitals are 120. In sp hybridization, one s orbital and one p orbital combine to form two sp hybrid orbitals. These orbitals are arranged in a trigonal planar geometry, with an angle of 120 degrees between them. This arrangement allows for maximum overlap and bonding with other atoms or orbitals.Rate this question:
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- 3.
There are ____________ sigma bonds and ___________ pi bonds in the H--CC--H molecule.
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Three, two
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Three, four
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Four, three
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Two, three
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Five, zero
Correct Answer
A. Three, twoExplanation
In the H--CC--H molecule, there are three sigma bonds and two pi bonds. Sigma bonds are formed by the overlap of atomic orbitals along the bonding axis, while pi bonds are formed by the sideways overlap of p orbitals. Since there are two carbon atoms connected by a double bond (CC), there is one sigma bond and one pi bond between them. Additionally, each carbon atom is bonded to a hydrogen atom (H--C and C--H), resulting in two sigma bonds. Therefore, the molecule has three sigma bonds and two pi bonds.Rate this question:
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- 4.
The total number of pi bonds in the H--CC--CC--CN molecule is _______.
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3
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4
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6
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9
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12
Correct Answer
A. 6Explanation
In the given molecule, H--CC--CC--CN, there are three carbon-carbon double bonds (CC) and one carbon-nitrogen triple bond (CN). Each double bond consists of one pi bond, and each triple bond consists of two pi bonds. Therefore, the total number of pi bonds in the molecule is 3 (from the double bonds) + 2 (from the triple bond) = 5.Rate this question:
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- 5.
The O--C--O bond angle in the CO ion is approximately ___________.
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90
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109.5
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120
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180
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60
Correct Answer
A. 120Explanation
The O--C--O bond angle in the CO ion is approximately 120 degrees. This is because the CO ion has a linear molecular geometry, meaning that the two oxygen atoms are directly opposite each other with the carbon atom in the middle. In a linear molecular geometry, the bond angle is always 180 degrees, but since the CO ion has a charge, it experiences electron-electron repulsion which pushes the oxygen atoms slightly closer together, resulting in a bond angle of approximately 120 degrees.Rate this question:
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- 6.
The central iodine atom in the ICl ion has _________ nonbonded electron pairs and ___________ bonded electron pairs in its valence shell.
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Two, two
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Three, four
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One, three
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Three, two
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Two, four
Correct Answer
A. Two, fourExplanation
The central iodine atom in the ICl ion has two nonbonded electron pairs and four bonded electron pairs in its valence shell.Rate this question:
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- 7.
The central Xe atom in the XeF molecule has ________ unbonded electron pairs and __________ bonded electron pairs in its valence shell.
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One, four
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Two, four
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Four, zero
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Four, one
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Four, two
Correct Answer
A. Two, fourExplanation
The central Xe atom in the XeF molecule has two unbonded electron pairs and four bonded electron pairs in its valence shell. This means that there are two pairs of electrons that are not involved in any chemical bonds and four pairs of electrons that are shared with other atoms in the molecule.Rate this question:
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- 8.
An electron domain consists of ____________. a) a nonbonding pair of electrons b) a single bond c) a multiple bond
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A only
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B only
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C only
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A, b, and c
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B and c
Correct Answer
A. A, b, and cExplanation
An electron domain consists of a nonbonding pair of electrons, a single bond, and a multiple bond. This means that it can include any of these three types of electron configurations.Rate this question:
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- 9.
According to VSEPR theory, if there are three electron domains on a central atom, they will be arranged such that the angles between the domains are _____________.
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90
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180
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109.5
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360
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120
Correct Answer
A. 120Explanation
According to VSEPR theory, if there are three electron domains on a central atom, they will be arranged such that the angles between the domains are 120 degrees. This is because when there are three electron domains, they will arrange themselves in a trigonal planar geometry, with each domain pointing towards the corners of an equilateral triangle. The angles between the domains in this arrangement are 120 degrees.Rate this question:
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- 10.
The electron-domain geometry and the molecular geometry of a molecule of the general formula AB are _________.
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Never the same
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Always the same
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Sometimes the same
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Not related
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Mirror images of one another
Correct Answer
A. Sometimes the sameExplanation
The electron-domain geometry and the molecular geometry of a molecule of the general formula AB can be sometimes the same. This means that in certain cases, the arrangement of the electron domains around the central atom can result in the same overall molecular shape. However, it is important to note that this is not always the case, as there are instances where the electron-domain geometry and molecular geometry can differ.Rate this question:
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Current Version
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Mar 20, 2023Quiz Edited by
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Nov 12, 2014Quiz Created by
Ashley Vickers
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