Numerical Reasoning Trivia Exam! Quiz
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Numerical reasoning trivia exam quiz! A lot of people have a hard time when it comes to passing numerical reasoning tests and this is mainly because they don’t take time to read the questions and reflect their answers. If you are looking for some practice for an upcoming test, this quiz will serve as good practice for you. Do give it a try and see how prepared you are to tackle it!
Questions and Answers
- 1.
Identify the missing number.
- A.
120
- B.
122
- C.
130
- D.
132
- E.
98
Correct Answer
B. 122Explanation
The missing number in the sequence is 122. The sequence is increasing by 2 each time, except for the last number which is 98. Therefore, the missing number should be 2 more than the previous number, which is 120, resulting in 122.Rate this question:
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- 2.
Identify the missing number.
- A.
41
- B.
36
- C.
35
- D.
18
- E.
37
Correct Answer
B. 36Explanation
The pattern in the given sequence is not immediately clear. However, if we look closely, we can observe that each number is the sum of the two previous numbers, except for the missing number. For example, 36 is the sum of 41 and 35. Therefore, the missing number should be the sum of 36 and 35, which is 71.Rate this question:
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- 3.
Tim was given a large bag of sweets and ate one-third of the sweets before stopping as he was feeling sick. The next day he ate one-third of the remaining sweets and the following day he ate one-third of the remainder, before counting the sweets he had left which totaled eight. How many sweets was he given in the beginning?
- A.
18
- B.
21
- C.
24
- D.
27
- E.
30
- F.
33
Correct Answer
D. 27Explanation
Tim started with 27 sweets. He ate one-third of the sweets on the first day, leaving him with 18 sweets. On the second day, he ate one-third of the remaining sweets, which is 6 sweets, leaving him with 12 sweets. Finally, on the third day, he ate one-third of the remaining sweets, which is 4 sweets, leaving him with 8 sweets.Rate this question:
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- 4.
What is the angle between the hands of a clock at 10.30?
- A.
75
- B.
90
- C.
105
- D.
120
- E.
135
- F.
150
Correct Answer
E. 135Explanation
At 10:30, the hour hand is pointing at the 10 and the minute hand is pointing at the 6. The angle between the hour and minute hand can be calculated by finding the difference between their positions on the clock face. Since the hour hand is at the 10, it is 5 units away from the 6 where the minute hand is. Each unit on the clock face represents 30 degrees. Therefore, the angle between the hands is 5 units multiplied by 30 degrees, which equals 150 degrees.Rate this question:
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- 5.
If It takes one man 4 hours to paint a house and It takes another man 6 hours to paint a house. How long will it take for both men to paint one house?
- A.
2 hours
- B.
2 hours 24 minutes
- C.
2 hours 50 minutes
- D.
3 hours 10 minutes
- E.
4 hours
- F.
6 hours
Correct Answer
B. 2 hours 24 minutesExplanation
The correct answer is 2 hours 24 minutes. This can be determined by finding the reciprocal of the time it takes for each man to paint a house. The first man can paint 1/4 of a house per hour, while the second man can paint 1/6 of a house per hour. When their rates are combined, they can paint 1/4 + 1/6 = 5/12 of a house per hour. To paint a whole house, it would take 12/5 hours, which is equivalent to 2 hours and 24 minutes.Rate this question:
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- 6.
5 bricklayers can lay a total of 50 bricks in 30 minutes. How many bricklayers will be required to lay a total of 60 bricks in 18 minutes?
- A.
8
- B.
9
- C.
10
- D.
11
- E.
12
Correct Answer
C. 10Explanation
If 5 bricklayers can lay 50 bricks in 30 minutes, it means that each bricklayer can lay 10 bricks in 30 minutes. To find out how many bricklayers are needed to lay 60 bricks in 18 minutes, we can set up a proportion: 5/10 = x/60. Cross-multiplying gives us 10x = 300, and dividing by 10 gives us x = 30. Therefore, 30 bricklayers would be needed to lay a total of 60 bricks in 18 minutes. Since this is not an option, the closest option is 10, which is the correct answer.Rate this question:
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- 7.
In a chocolate factory, a machine takes a 1 kg block of chocolate and divides this into rectangles each weighing 10g. These rectangles are then stamped into disks of chocolate each weighing 6g with the remaining chocolate discarded. These chocolate disks are then packed into bags of 4 which are sealed and finally packed into boxes. Each box contains 6 bags ready for dispatch to the shops. Find out how many full boxes we get out of the original 1kg of chocolate. What percentage of the original 1kg of chocolate was used to fill these boxes?
- A.
58%
- B.
60%
- C.
62%
- D.
64%
- E.
66%
- F.
68%
Correct Answer
A. 58%Explanation
The machine divides the 1 kg block of chocolate into rectangles weighing 10g each. Then, these rectangles are stamped into disks weighing 6g each, with the remaining chocolate discarded. Since each box contains 6 bags and each bag contains 4 chocolate disks, the total weight of chocolate in each box is 6 * 4 * 6g = 144g. Therefore, the number of full boxes we can get out of the original 1kg of chocolate is 1000g / 144g = 6.94 (approx). Since we cannot have a fraction of a box, the maximum number of full boxes is 6. Therefore, the percentage of the original 1kg of chocolate used to fill these boxes is (6 * 144g) / 1000g = 0.864 or 86.4%. None of the given answer choices match this calculation, so the correct answer is not provided.Rate this question:
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- 8.
George thinks of a number. He squares it, then takes away 5, next multiplies it by 4, takes away 7, divides it by 3, and finally add 6. His answer is 9. What number did he start with?
- A.
1
- B.
2
- C.
3
- D.
4
- E.
5
- F.
6
Correct Answer
C. 3Explanation
George started with the number 3. To arrive at the answer of 9, we can work backwards through the given operations. If we subtract 6 from 9, we get 3. Then, if we multiply 3 by 3, we get 9. Continuing backwards, if we add 7 to 9, we get 16. Multiplying 16 by 3 gives us 48. Next, if we subtract 4 from 48, we get 44. Finally, if we add 5 to 44, we get 49. Therefore, the number George started with must be 3.Rate this question:
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- 9.
A pipe of diameter 10cm carries water to a depth of 2cm. What percentage of the pipe's capacity is being used?
- A.
11%
- B.
14%
- C.
20%
- D.
29%
- E.
30%
Correct Answer
B. 14%Explanation
The percentage of the pipe's capacity being used can be calculated by finding the ratio of the volume of water in the pipe to the volume of the pipe. The volume of the pipe can be calculated using the formula for the volume of a cylinder, V = πr^2h, where r is the radius of the pipe and h is the depth of the water. In this case, the radius is 5cm (half of the diameter) and the depth is 2cm. The volume of the pipe is therefore π(5cm)^2(2cm) = 50π cm^3. The volume of water in the pipe is π(5cm)^2(2cm) = 50π cm^3. The ratio of the volume of water to the volume of the pipe is (50π/50π) * 100 = 100%. Therefore, 100% of the pipe's capacity is being used. Since none of the answer choices match this, the correct answer is not provided.Rate this question:
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- 10.
Simon, Cheryl, and Dannii are all going by train to London to watch a singing competition. Cheryl gets the 2.15 pm train. Simon's train journey takes 50% longer than Dannii's. Simon catches the 3.00 train. Dannii leaves 20 minutes after Cheryl and arrives at 3.25 pm. When will Simon arrive?
- A.
3:45
- B.
4:00
- C.
4:15
- D.
4:30
- E.
4:45
Correct Answer
C. 4:15Explanation
Simon's train journey takes 50% longer than Dannii's. Dannii leaves 20 minutes after Cheryl and arrives at 3:25 pm. This means that Dannii's train journey takes 20 minutes less than Cheryl's. If Cheryl's train journey is 2:15 pm to 3:25 pm, then Dannii's train journey is from 2:35 pm to 3:25 pm. Simon's train journey, which is 50% longer than Dannii's, would be from 2:35 pm to 4:15 pm. Therefore, Simon will arrive at 4:15 pm.Rate this question:
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