A Quiz On Mobile Communication! Trivia
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Power-limited region is when
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Bandwidth utilization factor is less than 1
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Bandwidth utilization factor is greater than 1
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About This Quiz
Explore the fundamentals of mobile communication with this trivia quiz! Assess your understanding of channel capacity, signal to noise ratios, MIMO technology, and the impact of interference in radio links. Ideal for learners and professionals in telecommunications.
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- 2.
Bandwidth-limited region is when
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Bandwidth utilization factor is greater than 1
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Bandwidth utilization factor is less than 1
Correct Answer
A. Bandwidth utilization factor is greater than 1Explanation
The bandwidth utilization factor represents the ratio of the actual bandwidth utilized to the maximum available bandwidth. When the bandwidth utilization factor is greater than 1, it means that the actual bandwidth being used exceeds the maximum available bandwidth. This indicates that the system or network is operating beyond its capacity and experiencing congestion or overload.Rate this question:
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- 3.
The most efficient method to increase the channel capacity operates in a power-limited region is
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Increase signal to noise ratio at the receiver
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Use MIMO at the receiver and the transmitter
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Increase the channel bandwidth
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Increase the transmitter power
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Use multiple antennas at the receiver side (receiver antenna diversity)
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Use multiple antennas at the transmitter side (beam focusing)
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Reduce the noise power at the receiver (use advanced receiver RF design)
Correct Answer(s)
A. Increase signal to noise ratio at the receiver
A. Increase the transmitter power
A. Use multiple antennas at the receiver side (receiver antenna diversity)
A. Use multiple antennas at the transmitter side (beam focusing)
A. Reduce the noise power at the receiver (use advanced receiver RF design)Explanation
The most efficient method to increase the channel capacity in a power-limited region is by increasing the signal to noise ratio at the receiver. This improves the quality of the received signal, allowing for more data to be transmitted over the channel. Additionally, increasing the transmitter power can also help to improve the signal strength and overcome any noise or interference. Using multiple antennas at both the receiver and transmitter sides can provide diversity and beam focusing, which can further enhance the signal quality and increase the channel capacity. Finally, reducing the noise power at the receiver through advanced receiver RF design can help to improve the signal-to-noise ratio and increase the channel capacity.Rate this question:
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- 4.
The most efficient method to increase the channel capacity operates in a bandwidth-limited region is
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Increase signal to noise ratio at the receiver
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Use MIMO at the receiver and the transmitter
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Increase the channel bandwidth
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Increase the transmitter power
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Use multiple antennas at the receiver side (receiver antenna diversity)
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Use multiple antennas at the transmitter side (beam focusing)
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Reduce the noise power at the receiver (use advanced receiver RF design)
Correct Answer(s)
A. Use MIMO at the receiver and the transmitter
A. Increase the channel bandwidthExplanation
The most efficient method to increase the channel capacity in a bandwidth-limited region is by using MIMO (Multiple-Input Multiple-Output) at both the receiver and the transmitter. MIMO technology utilizes multiple antennas to transmit and receive multiple streams of data simultaneously, thus increasing the overall capacity of the channel. Additionally, increasing the channel bandwidth also helps to enhance the capacity by allowing more data to be transmitted at a given time. Therefore, combining MIMO with an increased channel bandwidth is the most effective approach to maximize the channel capacity in a bandwidth-limited region.Rate this question:
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- 5.
Interference is the dominant source of radio-link impairment in mobile communications.
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True
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False
Correct Answer
A. TrueExplanation
Interference refers to the presence of unwanted signals that can disrupt the transmission of the desired signal in mobile communications. It can occur due to various factors such as other nearby devices operating on the same frequency, atmospheric conditions, or physical obstacles. In mobile communications, interference is a common issue that can degrade the quality and reliability of the radio link. Therefore, it is accurate to say that interference is the dominant source of radio-link impairment in mobile communications, making the answer "True."Rate this question:
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- 6.
Radio link bandwidth utilization factor is defined as the transmitted data rate divided by the available channel bandwidth
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True
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False
Correct Answer
A. TrueExplanation
The explanation for the given correct answer is that radio link bandwidth utilization factor is indeed defined as the transmitted data rate divided by the available channel bandwidth. This means that it calculates how efficiently the available channel bandwidth is being used to transmit data.Rate this question:
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- 7.
Combining 16QAM or 64QAM with channel coding may produce less bit-error probability, compared to QPSK.
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True
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False
Correct Answer
A. TrueExplanation
Combining 16QAM or 64QAM with channel coding can result in a lower bit-error probability compared to QPSK. This is because 16QAM and 64QAM allow for higher data rates by transmitting more bits per symbol, but they are also more susceptible to noise and interference. By using channel coding techniques, errors can be detected and corrected, improving the overall reliability of the transmission. Therefore, it is true that combining 16QAM or 64QAM with channel coding can reduce the bit-error probability.Rate this question:
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- 8.
16QAM or 64QAM uses more bandwidth and produces less bit-error probability compared to QPSK.
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True
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False
Correct Answer
A. FalseExplanation
16QAM or 64QAM does not use more bandwidth compared to QPSK. In fact, these higher order modulation schemes use the same bandwidth as QPSK. However, they are capable of transmitting more bits per symbol, which increases the data rate. Additionally, the bit-error probability of 16QAM or 64QAM is generally higher compared to QPSK due to the increased complexity of the modulation scheme. Therefore, the statement that 16QAM or 64QAM uses more bandwidth and produces less bit-error probability compared to QPSK is false.Rate this question:
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- 9.
The modulation scheme that has the highest variations in instantaneous transmit power is
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64QAM
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QPSK
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16QAM
Correct Answer
A. 64QAMExplanation
64QAM has the highest variations in instantaneous transmit power because it uses a higher number of amplitude and phase combinations to represent data compared to QPSK and 16QAM. This means that the signal in 64QAM can have more distinct levels, resulting in a wider range of power levels being transmitted. As a result, the instantaneous transmit power can vary more significantly in 64QAM compared to the other modulation schemes.Rate this question:
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- 10.
Even though the large variations in instantaneous transmit power for higher-order modulation schemes, the transmit power amplifier can operate with 100% efficiency.
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True
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False
Correct Answer
A. FalseExplanation
The statement is false because even though higher-order modulation schemes may have large variations in instantaneous transmit power, the transmit power amplifier cannot operate with 100% efficiency. Transmit power amplifiers typically have some level of inefficiency due to factors such as non-linearities and power dissipation, which prevent them from achieving perfect efficiency.Rate this question:
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- 11.
The higher-order modulation schemes are more suitable for the downlink compared to the uplink due to variations in instantaneous transmit power.
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True
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False
Correct Answer
A. TrueExplanation
Higher-order modulation schemes require higher signal-to-noise ratio (SNR) for reliable transmission. In the downlink, the base station has more power and can transmit signals with higher SNR to the user devices. This allows for the use of higher-order modulation schemes in the downlink, resulting in higher data rates. However, in the uplink, user devices have limited transmit power, which may not be sufficient to support higher-order modulation schemes. Therefore, the statement that higher-order modulation schemes are more suitable for the downlink compared to the uplink is true.Rate this question:
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- 12.
In order to provide high data rates as efficiently as possible in terms of required signal-to-noise ratio, the transmission bandwidth should be at least of the same order as the data rates to be provided (bandwidth utilization factor =1).
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True
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False
Correct Answer
A. TrueExplanation
To provide high data rates efficiently, the transmission bandwidth should be at least of the same order as the data rates. This means that the bandwidth utilization factor should be 1, indicating that the entire bandwidth is being used effectively to transmit the data. If the bandwidth is lower than the data rates, it may result in a lower signal-to-noise ratio, leading to decreased efficiency and slower data transmission. Therefore, the statement is true.Rate this question:
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- 13.
Time dispersion
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Time dispersion occurs when the transmitted signal propagates to the receiver via multiple paths with different delays.
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Is the time required for a data symbol to propagate from the base station to the terminal mobile
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Is the delay of a radio packet
Correct Answer
A. Time dispersion occurs when the transmitted signal propagates to the receiver via multiple paths with different delays.Explanation
The correct answer is time dispersion occurs when the transmitted signal propagates to the receiver via multiple paths with different delays. This means that when a signal is transmitted, it can take different paths to reach the receiver, and each path may have a different delay. This can result in the signal arriving at different times, causing dispersion.Rate this question:
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- 14.
Frequency selectivity
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Is the frequency response of a channel that suffers of a time dispersion problem
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Is the Doppler dispersion
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Is the bandwidth of the channel that is selected in frequency division multiplexing
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None of the above
Correct Answer
A. Is the frequency response of a channel that suffers of a time dispersion problemExplanation
Frequency selectivity refers to the ability of a channel to selectively transmit or attenuate certain frequencies. In the given answer, it states that frequency selectivity is the frequency response of a channel that suffers from a time dispersion problem. This means that the channel's frequency response is affected by a delay or spreading of the signal over time, causing distortion in the transmitted signal. Therefore, the correct answer implies that frequency selectivity is related to the channel's response to time dispersion issues.Rate this question:
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- 15.
It is easier to design equalizers for wider bandwidth channels than narrower bandwidth channels?
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True
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False
Correct Answer
A. FalseExplanation
False. It is actually easier to design equalizers for narrower bandwidth channels than wider bandwidth channels. This is because narrower bandwidth channels have fewer frequencies to equalize, making the design process less complex. In wider bandwidth channels, there are more frequencies that need to be equalized, which can be more challenging and require more advanced techniques.Rate this question:
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- 16.
The bandwidth of a WCDMA signal is
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5 MHz
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1 MHz
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15 MHz
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10 MHz
Correct Answer
A. 5 MHzExplanation
The bandwidth of a WCDMA signal is 5 MHz. WCDMA stands for Wideband Code Division Multiple Access, which is a wireless communication technology used in 3G mobile networks. It uses a spread spectrum technique to allow multiple users to share the same frequency band. The 5 MHz bandwidth refers to the range of frequencies that can be used for transmitting and receiving data in a WCDMA system. This bandwidth allows for high data rates and supports simultaneous voice and data transmission.Rate this question:
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- 17.
The reasons for using OFDM in 4G systems are
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Better performance against time dispersion
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Better performance against frequency selectivity
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The design for an equalizer is easier for bandwidths larger than 5 MHz
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It can perform well even at the edge of a cell
Correct Answer(s)
A. Better performance against time dispersion
A. Better performance against frequency selectivity
A. The design for an equalizer is easier for bandwidths larger than 5 MHz
A. It can perform well even at the edge of a cellExplanation
OFDM (Orthogonal Frequency Division Multiplexing) is used in 4G systems for several reasons. Firstly, it provides better performance against time dispersion, which refers to the spreading of a signal over time due to multipath propagation. OFDM divides the signal into multiple subcarriers, allowing it to combat the effects of time dispersion. Secondly, OFDM also offers better performance against frequency selectivity, which is the variation of signal strength at different frequencies. By using multiple subcarriers, OFDM can mitigate the effects of frequency selectivity. Additionally, the design for an equalizer is easier for bandwidths larger than 5 MHz in OFDM, making it a practical choice for 4G systems. Lastly, OFDM can perform well even at the edge of a cell, ensuring reliable and consistent connectivity throughout the coverage area.Rate this question:
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- 18.
One of the main reasons for using multi-carrier for transmitting high data rates is to avoid the frequency selectivity problem.
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True
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False
Correct Answer
A. TrueExplanation
Multi-carrier modulation is a technique used to transmit high data rates by dividing the available frequency spectrum into multiple subcarriers. Each subcarrier carries a smaller portion of the total data, allowing for efficient transmission of high data rates. One of the advantages of multi-carrier modulation is its ability to combat frequency selectivity. Frequency selectivity refers to the variation in channel characteristics across different frequency components. By using multiple subcarriers, multi-carrier modulation can mitigate the effects of frequency selectivity, ensuring reliable transmission of high data rates. Therefore, the statement that using multi-carrier helps to avoid the frequency selectivity problem is true.Rate this question:
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- 19.
WCDMA/HSPA uses
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Multicarrier transmission
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One carrier transmission
Correct Answer
A. Multicarrier transmissionExplanation
WCDMA/HSPA uses multicarrier transmission. This means that it uses multiple carriers or frequencies to transmit data simultaneously. This allows for increased capacity and higher data rates. By dividing the available spectrum into multiple smaller carriers, WCDMA/HSPA can efficiently utilize the spectrum and accommodate multiple users at the same time. This technique is commonly used in modern cellular networks to provide high-speed data services.Rate this question:
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Current Version
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Mar 21, 2023Quiz Edited by
ProProfs Editorial Team -
Oct 04, 2013Quiz Created by
Gdeisat
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