A3/A4/A6/B4/B6 - HW 1.3
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A runner's position is 40 m at time t = 0 s. If he runs at a constant pace of 1.5 m/s, what will his position be at t = 45s? (Hint: Draw a graph to help!)
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67.5 meters
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107.5 meters
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40 meters
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106.5 meters
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This quiz, titled 'A3\/A4\/A6\/B4\/B6 - HW 1.3', assesses understanding of kinematics, focusing on constant velocity motion. Students calculate positions at different times, analyze velocity, and apply linear motion equations. It's designed to enhance problem-solving skills in physics.
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- 2.
A runner's position is 20 m at time t = 0 s. If he runs at a constant pace of 0.5 m/s, what will his position be at t = 45s? (Hint: Draw a graph to help!)
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20 meters
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40.5 meters
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42.5 meters
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22.5 meters
Correct Answer
A. 42.5 metersExplanation
The runner's position at time t=0s is given as 20m. Since the runner is running at a constant pace of 0.5m/s, we can calculate his position at t=45s by multiplying the pace by the time. Therefore, the runner will have covered a distance of 0.5m/s * 45s = 22.5m. Adding this distance to the initial position of 20m, we get the final position of 42.5m.Rate this question:
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- 3.
Use the data below to answer the following question: Is the velocity of the object constant? If so, what is the object's velocity? Time (s) Position (m) 0.0 30 1.0 40 2.0 50 3.0 60 4.0 70 5.0 80
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Yes; +50 m/sec
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Yes; +30 m/sec
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Yes; + 10 m/sec
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Yes; +16 m/sec
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No
Correct Answer
A. Yes; + 10 m/secExplanation
The velocity of the object is constant because the position increases by the same amount (10 meters) every second. Therefore, the object's velocity is +10 m/sec.Rate this question:
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- 4.
Use the data below to answer the following question: What is the starting position of the object? Time (s) Position (m) 0.0 30 1.0 40 2.0 50 3.0 60 4.0 70 5.0 80
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0 meters
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+30 meters
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+15 meters
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-30 meters
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+80 meters
Correct Answer
A. +30 metersExplanation
The starting position of the object is +30 meters. This is because at time 0.0 seconds, the object's position is recorded as 30 meters.Rate this question:
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- 5.
Use the data below to answer the following question: Write an equation for the objects position over time. Time (s) Position (m) 0.0 30 1.0 40 2.0 50 3.0 60 4.0 70 5.0 80
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X = (+10 m/sec) (t) - 30 m
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X = (-10 m/sec) (t) + 30 m
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X = (-10 m/sec) (t) - 30 m
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X = (+10 m/sec) (t) + 30 m
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X = (10 m/sec) (t) + 30 m
Correct Answer
A. X = (+10 m/sec) (t) + 30 mExplanation
The equation X = (+10 m/sec) (t) + 30 m represents the objects position over time. The equation shows that the position of the object is determined by multiplying the time (t) by the velocity (+10 m/sec) and adding the initial position (+30 m). This equation suggests that the object is moving in a positive direction with a constant velocity of 10 m/sec.Rate this question:
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- 6.
Use the data below to answer the following question: Use your equation to solve for the objects position at time 15.0 s Time (s) Position (m) 0.0 30 1.0 40 2.0 50 3.0 60 4.0 70 5.0 80
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+150 m
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+180 m
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-150 m
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- 180 m
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0 m
Correct Answer
A. +180 mExplanation
The correct answer is +180 m. This can be determined by using the equation that relates time and position. By examining the data, we can see that the position increases by 10 m every second. Therefore, at time 15.0 s, the position would have increased by 10 m for each second, resulting in a total increase of 150 m. However, since the initial position was 30 m, we need to add this value as well, resulting in a final position of +180 m.Rate this question:
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- 7.
Use the graph below to answer questions 7-11 #7: What interval had the greatest velocity?
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2-5 sec
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5-7 sec
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7-12 sec
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12-14
Correct Answer
A. 5-7 secExplanation
The interval from 5-7 seconds had the greatest velocity. This can be determined by looking at the graph and observing that the slope of the line during this interval is steeper compared to the other intervals. A steeper slope indicates a higher velocity.Rate this question:
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- 8.
Use the graph below to answer questions 7-11 #8: What interval had the most negative velocity?
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2-5 sec
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5-7 sec
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7-12 sec
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12-14
Correct Answer
A. 12-14Explanation
The interval from 12 to 14 seconds had the most negative velocity. This can be determined by looking at the graph and identifying the portion where the line representing velocity is at its lowest point. During this interval, the velocity is decreasing at the fastest rate, indicating a negative velocity.Rate this question:
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- 9.
Use the graph below to answer questions 7-11 #9: Describe the motion of the vehicle at 10 seconds?
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The vehicle is at a constant positive velocity and moving.
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The vehicle is at a constant negative velocity and moving.
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The vehicle is at a constant velocity and not moving.
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The vehicle is continually increasing in velocity.
Correct Answer
A. The vehicle is at a constant velocity and not moving.Explanation
At 10 seconds, the graph shows that the position of the vehicle remains constant, indicating that it is not moving. Additionally, the velocity of the vehicle is zero, as there is no change in the position over time. Therefore, the correct answer is that the vehicle is at a constant velocity and not moving.Rate this question:
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- 10.
Use the graph below to answer questions 7-11 #10: Describe the motion of the vehicle at 10 seconds?
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The vehicle is at a constant positive velocity and moving.
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The vehicle is at a constant negative velocity and moving.
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The vehicle is at a constant velocity and not moving.
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The vehicle is continually increasing in velocity.
Correct Answer
A. The vehicle is at a constant velocity and not moving.Explanation
The graph shows a horizontal line at the 10-second mark, indicating that the position of the vehicle does not change over time. This means that the vehicle is not moving. Additionally, since the line is horizontal, the velocity of the vehicle is constant, meaning it is not increasing or decreasing. Therefore, the correct answer is that the vehicle is at a constant velocity and not moving.Rate this question:
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- 11.
Use the graph below to answer questions 7-11 #11: Describe the motion of the vehicle at 2-5 seconds
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Velocity = +1 m/sec, traveling in the positive direction
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Velocity = -1 m/sec, traveling in the positive direction
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Velocity = +1 m/sec, traveling in the negative direction
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Velocity = -1 m/sec, traveling in the negative direction
Correct Answer
A. Velocity = -1 m/sec, traveling in the negative directionExplanation
The graph shows a decreasing slope from 2 to 5 seconds, indicating a negative velocity. Since the velocity is -1 m/sec, it means that the vehicle is moving in the negative direction. Therefore, the correct answer is "Velocity = -1 m/sec, traveling in the negative direction."Rate this question:
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- 12.
Is this graph possible? Can it describe the motion for one vehicle in a single trial? Choose the best answer below.
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No, a vehicle can't be in the same position at the same value.
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No, a vehicle can't have different positions attached to different time values.
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Yes, a vehicle is able to have two positions at one time value
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Yes, a vehicle can have multiple positions (one or more) at one time value.
Correct Answer
A. No, a vehicle can't be in the same position at the same value.Explanation
This answer is correct because according to the question, it is not possible for a vehicle to be in the same position at the same time value. This violates the basic principles of motion where an object can only have one position at a given time. Therefore, this graph cannot describe the motion of a vehicle in a single trial.Rate this question:
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- 13.
Use the following for questions 13-15 What happens when the lines above cross?
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CMV1 and CMV2 crash
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CMV1 and CMV2 have the same velocity
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CMV1 and CMV2 are at the same position from the origin
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CMV1 and CMV2 have moved the same total position
Correct Answer
A. CMV1 and CMV2 crashExplanation
When the lines above cross, CMV1 and CMV2 crash.Rate this question:
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- 14.
Use the following for questions 13-15 Which CMV has moved more position overall from 0-15 seconds?
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CMV1
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CMV2
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CMV1 and CMV2 are same
Correct Answer
A. CMV2Explanation
CMV2 has moved more positions overall from 0-15 seconds compared to CMV1.Rate this question:
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- 15.
Use the following for questions 13-15 Which answer best supports your response in #14
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CMV2 is moving in the negative direction, and CMV1 is moving positive, so it has traveled further.
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CMV2 has changed more position over this time period than CMV1
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CMV1 has changed more position over this time period than CMV2
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CMV1 and CMV2 change the same amount of position
Correct Answer
A. CMV2 has changed more position over this time period than CMV1Explanation
The given answer suggests that CMV2 has changed more position over the time period compared to CMV1. This means that CMV2 has traveled a greater distance or has experienced a greater displacement than CMV1.Rate this question:
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.png "Use the following for questions 13-15
What happens when the lines above cross?")
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Mar 21, 2023Quiz Edited by
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Sep 24, 2013Quiz Created by
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