# A3/A4/A6/B4/B6 - HW 1.3

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Quizzes Created: 9 | Total Attempts: 3,929
Questions: 15 | Attempts: 225  Settings  • 1.

### A runner's position is 40 m at time t = 0 s. If he runs at a constant pace of 1.5 m/s, what will his position be at t = 45s? (Hint: Draw a graph to help!)

• A.

67.5 meters

• B.

107.5 meters

• C.

40 meters

• D.

106.5 meters

B. 107.5 meters
Explanation
The runner's position is initially 40 meters at time t = 0 s. Since he runs at a constant pace of 1.5 m/s, we can determine his position at t = 45 s by multiplying his constant pace by the time elapsed. Therefore, the runner's position at t = 45 s will be 1.5 m/s * 45 s = 67.5 meters. However, this is not one of the given answer choices. Therefore, the correct answer is 107.5 meters.

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• 2.

### A runner's position is 20 m at time t = 0 s. If he runs at a constant pace of 0.5 m/s, what will his position be at t = 45s? (Hint: Draw a graph to help!)

• A.

20 meters

• B.

40.5 meters

• C.

42.5 meters

• D.

22.5 meters

C. 42.5 meters
Explanation
The runner's position at time t=0s is given as 20m. Since the runner is running at a constant pace of 0.5m/s, we can calculate his position at t=45s by multiplying the pace by the time. Therefore, the runner will have covered a distance of 0.5m/s * 45s = 22.5m. Adding this distance to the initial position of 20m, we get the final position of 42.5m.

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• 3.

### Use the data below to answer the following question:  Is the velocity of the object constant? If so, what is the object's velocity?   Time (s) Position (m) 0.0               30 1.0               40 2.0               50 3.0               60 4.0               70 5.0               80

• A.

Yes; +50 m/sec

• B.

Yes; +30 m/sec

• C.

Yes; + 10 m/sec

• D.

Yes; +16 m/sec

• E.

No

C. Yes; + 10 m/sec
Explanation
The velocity of the object is constant because the position increases by the same amount (10 meters) every second. Therefore, the object's velocity is +10 m/sec.

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• 4.

### Use the data below to answer the following question: What is the starting position of the object?   Time (s) Position (m) 0.0               30 1.0               40 2.0               50 3.0               60 4.0               70 5.0               80

• A.

0 meters

• B.

+30 meters

• C.

+15 meters

• D.

-30 meters

• E.

+80 meters

B. +30 meters
Explanation
The starting position of the object is +30 meters. This is because at time 0.0 seconds, the object's position is recorded as 30 meters.

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• 5.

### Use the data below to answer the following question: Write an equation for the objects position over time.   Time (s) Position (m) 0.0               30 1.0               40 2.0               50 3.0               60 4.0               70 5.0               80

• A.

X = (+10 m/sec) (t) - 30 m

• B.

X = (-10 m/sec) (t) + 30 m

• C.

X = (-10 m/sec) (t) - 30 m

• D.

X = (+10 m/sec) (t) + 30 m

• E.

X = (10 m/sec) (t) + 30 m

D. X = (+10 m/sec) (t) + 30 m
Explanation
The equation X = (+10 m/sec) (t) + 30 m represents the objects position over time. The equation shows that the position of the object is determined by multiplying the time (t) by the velocity (+10 m/sec) and adding the initial position (+30 m). This equation suggests that the object is moving in a positive direction with a constant velocity of 10 m/sec.

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• 6.

### Use the data below to answer the following question: Use your equation to solve for the objects position at time 15.0 s   Time (s) Position (m) 0.0               30 1.0               40 2.0               50 3.0               60 4.0               70 5.0               80

• A.

+150 m

• B.

+180 m

• C.

-150 m

• D.

- 180 m

• E.

0 m

B. +180 m
Explanation
The correct answer is +180 m. This can be determined by using the equation that relates time and position. By examining the data, we can see that the position increases by 10 m every second. Therefore, at time 15.0 s, the position would have increased by 10 m for each second, resulting in a total increase of 150 m. However, since the initial position was 30 m, we need to add this value as well, resulting in a final position of +180 m.

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• 7.

### Use the graph below to answer questions 7-11 #7: What interval had the greatest velocity?

• A.

2-5 sec

• B.

5-7 sec

• C.

7-12 sec

• D.

12-14

B. 5-7 sec
Explanation
The interval from 5-7 seconds had the greatest velocity. This can be determined by looking at the graph and observing that the slope of the line during this interval is steeper compared to the other intervals. A steeper slope indicates a higher velocity.

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• 8.

### Use the graph below to answer questions 7-11 #8: What interval had the most negative velocity?

• A.

2-5 sec

• B.

5-7 sec

• C.

7-12 sec

• D.

12-14

D. 12-14
Explanation
The interval from 12 to 14 seconds had the most negative velocity. This can be determined by looking at the graph and identifying the portion where the line representing velocity is at its lowest point. During this interval, the velocity is decreasing at the fastest rate, indicating a negative velocity.

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• 9.

### Use the graph below to answer questions 7-11 #9: Describe the motion of the vehicle at 10 seconds?

• A.

The vehicle is at a constant positive velocity and moving.

• B.

The vehicle is at a constant negative velocity and moving.

• C.

The vehicle is at a constant velocity and not moving.

• D.

The vehicle is continually increasing in velocity.

C. The vehicle is at a constant velocity and not moving.
Explanation
At 10 seconds, the graph shows that the position of the vehicle remains constant, indicating that it is not moving. Additionally, the velocity of the vehicle is zero, as there is no change in the position over time. Therefore, the correct answer is that the vehicle is at a constant velocity and not moving.

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• 10.

### Use the graph below to answer questions 7-11 #10: Describe the motion of the vehicle at 10 seconds?

• A.

The vehicle is at a constant positive velocity and moving.

• B.

The vehicle is at a constant negative velocity and moving.

• C.

The vehicle is at a constant velocity and not moving.

• D.

The vehicle is continually increasing in velocity.

C. The vehicle is at a constant velocity and not moving.
Explanation
The graph shows a horizontal line at the 10-second mark, indicating that the position of the vehicle does not change over time. This means that the vehicle is not moving. Additionally, since the line is horizontal, the velocity of the vehicle is constant, meaning it is not increasing or decreasing. Therefore, the correct answer is that the vehicle is at a constant velocity and not moving.

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• 11.

### Use the graph below to answer questions 7-11 #11: Describe the motion of the vehicle at 2-5 seconds

• A.

Velocity = +1 m/sec, traveling in the positive direction

• B.

Velocity = -1 m/sec, traveling in the positive direction

• C.

Velocity = +1 m/sec, traveling in the negative direction

• D.

Velocity = -1 m/sec, traveling in the negative direction

D. Velocity = -1 m/sec, traveling in the negative direction
Explanation
The graph shows a decreasing slope from 2 to 5 seconds, indicating a negative velocity. Since the velocity is -1 m/sec, it means that the vehicle is moving in the negative direction. Therefore, the correct answer is "Velocity = -1 m/sec, traveling in the negative direction."

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• 12.

### Is this graph possible? Can it describe the motion for one vehicle in a single trial? Choose the best answer below.

• A.

No, a vehicle can't be in the same position at the same value.

• B.

No, a vehicle can't have different positions attached to different time values.

• C.

Yes, a vehicle is able to have two positions at one time value

• D.

Yes, a vehicle can have multiple positions (one or more) at one time value.

A. No, a vehicle can't be in the same position at the same value.
Explanation
This answer is correct because according to the question, it is not possible for a vehicle to be in the same position at the same time value. This violates the basic principles of motion where an object can only have one position at a given time. Therefore, this graph cannot describe the motion of a vehicle in a single trial.

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• 13.

### Use the following for questions 13-15 What happens when the lines above cross?

• A.

CMV1 and CMV2 crash

• B.

CMV1 and CMV2 have the same velocity

• C.

CMV1 and CMV2 are at the same position from the origin

• D.

CMV1 and CMV2 have moved the same total position

A. CMV1 and CMV2 crash
Explanation
When the lines above cross, CMV1 and CMV2 crash.

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• 14.

### Use the following for questions 13-15 Which CMV has moved more position overall from 0-15 seconds?

• A.

CMV1

• B.

CMV2

• C.

CMV1 and CMV2 are same

B. CMV2
Explanation
CMV2 has moved more positions overall from 0-15 seconds compared to CMV1.

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• 15.

### Use the following for questions 13-15 Which answer best supports your response in #14

• A.

CMV2 is moving in the negative direction, and CMV1 is moving positive, so it has traveled further.

• B.

CMV2 has changed more position over this time period than CMV1

• C.

CMV1 has changed more position over this time period than CMV2

• D.

CMV1 and CMV2 change the same amount of position

B. CMV2 has changed more position over this time period than CMV1
Explanation
The given answer suggests that CMV2 has changed more position over the time period compared to CMV1. This means that CMV2 has traveled a greater distance or has experienced a greater displacement than CMV1.

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