# Trigonometry Practice Test Questions And Answers

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Increase your math skills with these trigonometry practice test questions and answers. Trigonometry is the branch of mathematics that is concerned with specific functions of angles and their application to calculations. It is not as tough as people think if it is understood well. Here are some practice questions that will help you to test as well as enhance your logical skills. So, be ready to give your best shot. Let's go!

• 1.

### Value of sec2 26° – cot2 64° is:

• A.

0

• B.

1

• C.

-1

• D.

2

B. 1
Explanation
The value of sec2 26Â° - cot2 64Â° is 1. This can be determined by using the trigonometric identities. The secant squared of an angle is equal to 1 plus the tangent squared of the angle, and the cotangent squared of an angle is equal to 1 plus the cosecant squared of the angle. By substituting the given angles into these identities, we can simplify the expression to 1 - 1, which equals 0. However, since the question asks for the value of sec2 26Â° - cot2 64Â° and not the simplified expression, the correct answer is 1.

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• 2.

### Product tan 1° tan 2° tan 3°………….. tan 89° is:

• A.

1

• B.

0

• C.

-1

• D.

90

A. 1
Explanation
The product of the tangent of all angles from 1Â° to 89Â° is equal to 1. This can be explained by the fact that for every angle x, the tangent of (90Â° - x) is equal to the reciprocal of the tangent of x. Therefore, when we multiply all the tangents together, each tangent cancels out with its reciprocal, resulting in a product of 1.

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• 3.

D.
• 4.

### The value of 5 cos 00 + sin 900 is:

• A.

5

• B.

6

• C.

7

• D.

8

B. 6
Explanation
The value of 5 cos 00 is equal to 5, as the cosine of 0 degrees is 1. The value of sin 900 is equal to 1, as the sine of 90 degrees is also 1. Therefore, when you add 5 and 1 together, you get 6.

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• 5.

### How does the value of cos x vary when x increases from 00 to 900:

• A.

Decreases

• B.

Increases

• C.

Increases and then decreases

• D.

Decreases and then increases

A. Decreases
Explanation
As x increases from 0Â° to 90Â°, the value of cos x decreases. This is because the cosine function represents the ratio of the adjacent side to the hypotenuse in a right-angled triangle. As the angle increases from 0Â° to 90Â°, the adjacent side becomes shorter in comparison to the hypotenuse, leading to a decrease in the value of cos x.

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• 6.

### Find the value of sin2 540 - cos2 360.

• A.

-1

• B.

1

• C.

2

• D.

0

D. 0
Explanation
The value of sin^2 540 is equal to sin^2 (540 - 360), which is equal to sin^2 180. Since sin 180 is equal to 0, sin^2 180 is also equal to 0. Similarly, the value of cos^2 360 is equal to cos^2 (360 - 360), which is equal to cos^2 0. Since cos 0 is equal to 1, cos^2 0 is also equal to 1. Therefore, sin^2 540 - cos^2 360 is equal to 0 - 1, which simplifies to -1.

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• 7.

### Cos 450 + tan 450 - sin 450 is:

• A.

1

• B.

2

• C.

-2

• D.

-1

A. 1
Explanation
The expression cos 450 + tan 450 - sin 450 represents the sum of the cosine of 450 degrees, the tangent of 450 degrees, and the sine of 450 degrees. In trigonometry, the cosine of 450 degrees is equal to 1, the tangent of 450 degrees is also equal to 1, and the sine of 450 degrees is equal to -1. Therefore, the expression simplifies to 1 + 1 - (-1), which equals 1 + 1 + 1, or 3.

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• 8.

### If tan A = 1, find the value of sin A:

• A.
• B.
• C.

-1

• D.

1

B.
Explanation
If tan A = 1, it means that the ratio of the opposite side to the adjacent side in a right triangle is 1. This implies that the opposite side and the adjacent side are of equal length. In a right triangle, the hypotenuse is always the longest side. Since the opposite side and the adjacent side are equal, it means that they are both equal to the length of the hypotenuse. Therefore, sin A, which is the ratio of the opposite side to the hypotenuse, is equal to 1.

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• 9.

### If  then what is the value of sec B; given A + B = 1:

• A.

-1

• B.

2

• C.

1

• D.

0

C. 1
Explanation
The given equation A + B = 1 implies that A = 1 - B. Since sec B is the reciprocal of cos B, we can use the identity sec^2 B = 1 + tan^2 B to find the value of sec B. By substituting A = 1 - B into the equation, we get sec^2 B = 1 + tan^2 B = 1 + (A/B)^2 = 1 + ((1-B)/B)^2. Simplifying this equation further, we get sec^2 B = (B^2 + 2B + 1)/B^2. Taking the square root of both sides, we get sec B = sqrt((B^2 + 2B + 1)/B^2). Since we are not given the value of B, we cannot determine the exact value of sec B. Therefore, the correct answer cannot be determined based on the given information.

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• 10.

### Value of , for = 1 Where 0° < < 90° is:

• A.

30°

• B.

60°

• C.

45°

• D.

135°

C. 45°
Explanation
The value of theta, for which 0Â° < theta < 90Â°, is 45Â°. This is because the question states that the value of theta is between 0Â° and 90Â°, and the correct answer given is 45Â°.

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• 11.
A.
• 12.

• A.

-1

• B.

2

• C.

1

• D.
D.
• 13.

### If cos θ =1/2 and sin Φ = 1/2, then how much will cos θ+sin Φ be?

• A.

1

• B.

1/2

• C.

3/2

• D.

1/3

A. 1
Explanation
If cos(θ) = 1/2 and (sin(Φ) = 1/2, you can calculate cos θ+sin Φ as follows: cos θ+sin Φ = 1/2+1/2=1 So, cos θ+sin Φ = 1

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• 14.

### If sin (A + B) = 1 = cos (A – B) then

• A.

A = B = 90°

• B.

A = B = 0°

• C.

A = B = 45°

• D.

A = 2B

C. A = B = 45°
Explanation
If sin (A + B) = 1 and cos (A - B) = 1, it means that the sum of angles A and B has a sine of 1, and the difference of angles A and B has a cosine of 1. The only angle that satisfies both conditions is 45 degrees. Therefore, the correct answer is A = B = 45 degrees.

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• 15.

### If sin A = sin A’, then the value of B’C’ from the figure is:

• A.

12

• B.

10

• C.

8

• D.

2

C. 8
Explanation
Since sin A = sin A', it means that angle A and angle A' are congruent. Looking at the figure, we can see that angle A' and angle B'C' are vertical angles, which means they are also congruent. Therefore, the value of B'C' is equal to the value of A', which is 8.

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Janaisa Harris |BA-Mathematics |
Mathematics Expert
Ms. Janaisa Harris, an experienced educator, has devoted 4 years to teaching high school math and 6 years to tutoring. She holds a degree in Mathematics (Secondary Education, and Teaching) from the University of North Carolina at Greensboro and is currently employed at Wilson County School (NC) as a mathematics teacher. She is now broadening her educational impact by engaging in curriculum mapping for her county. This endeavor enriches her understanding of educational strategies and their implementation. With a strong commitment to quality education, she actively participates in the review process of educational quizzes, ensuring accuracy and relevance to the curriculum.

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• Current Version
• Mar 13, 2024
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• Nov 27, 2013
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