Solving Algebraic Word Problems

  • CCSS.Math.Content.HSA
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| By Tbutler2013
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1) 4a + 1 = 13 Solve for a.

Explanation

On the actual test, watch out for positive and negative charges. And if time allows you, check your answer.

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About This Quiz
Word Problems Quizzes & Trivia

This quiz titled 'Solving Algebraic Word Problems' assesses skills in solving linear equations and understanding algebraic expressions. It includes problems on solving for unknown variables and determining dimensions from given perimeters, enhancing algebraic problem-solving abilities.

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2) 9 = 5 + 4r Solve for r.

Explanation

9 = 5 + 4r
4 = 4r
1 = r

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3) Solve this equation 4s - 13 = 51

Explanation

By solving the equation 4s - 13 = 51, we want to find the value of s that satisfies the equation. To isolate the variable s, we add 13 to both sides of the equation, resulting in 4s = 64. Then, we divide both sides by 4 to solve for s, giving us s = 16. Therefore, the correct answer is S = 16.

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4) 2x + 23 = 49

Explanation

The given equation states that 2 times x, plus 23, equals 49. To find the value of x that satisfies this equation, we need to isolate x on one side of the equation. By subtracting 23 from both sides, we get 2x = 26. Dividing both sides by 2, we find that x = 13. Therefore, the correct answer is x = 13.

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5) Chose the first step you would do in the following equation. 24 - x = -16

Explanation

In order to isolate the variable x, the first step would be to get rid of the -24 on the left side of the equation. Subtracting 24 from both sides would cancel out the -24 on the left side, leaving us with -x = -40.

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6) To mail a first class letter, the U.S. Postal Service charges are $.34 for the first ounce and $.21 for each additional ounce. It costs $1.18 to mail your letter. How many ounces does your letter weigh?

Explanation

To calculate the cost of mailing the letter, we need to subtract the initial charge of $0.34 from the total cost of $1.18. This leaves us with $0.84, which represents the additional cost for the extra weight of the letter. Since each additional ounce costs $0.21, we can divide $0.84 by $0.21 to find the number of additional ounces. The result is 4, indicating that the letter weighs 4 additional ounces. Therefore, the total weight of the letter is 4 ounces.

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7) Chose the following answer that is correct.

Explanation

A) 2n + 3n + 2 = -41

5n + 2 = -41

5n = -43

n = -8.6

The given solution n = 8.6 is incorrect.

B) 4(2a + 2) - 17 = 15

8a + 8 - 17 = 15

8a - 9 = 15

8a = 24

a = 3

The given solution a = 3 is correct.

C) -w + 4(w + 3) = -12

w + 4w + 12 = -12

3w + 12 = -12

3w = -24

w = -8

The given solution w = 0 is incorrect.

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4a + 1 = 13 Solve for a.
9 = 5 + 4r Solve for r.
Solve this equation 4s - 13 = 51
2x + 23 = 49
Chose the first step you would do in the following equation. ...
To mail a first class letter, the U.S. Postal Service charges are $.34...
Chose the following answer that is correct.
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