Quadratic Graphs And Equations
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Solve. 8x2 + 10x + 3 = 0
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X = -8 and -4
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X = -2 and -6
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X = -1.5 and -0.167
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X = -0.75 and -0.5
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This quiz on Quadratic Graphs and Equations assesses understanding of solving quadratic equations and properties of their graphs. Learners solve various quadratic equations and explore graph transformations, enhancing their algebraic skills and comprehension of parabolic shapes.
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- 2.
Solve. 1x2 + 12x + 32 = 0
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X = -8 and -4
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X = -2 and -6
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X = -1.5 and -0.167
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X = -0.75 and -0.5
Correct Answer
A. X = -8 and -4Explanation
The equation is a quadratic equation in the form of ax^2 + bx + c = 0. By factoring or using the quadratic formula, we can find the values of x that satisfy the equation. In this case, the equation can be factored as (x + 8)(x + 4) = 0, which gives us x = -8 and x = -4 as the solutions.Rate this question:
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- 3.
Solve. 16x2 + 20x = 0
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X = 0 and 1.25
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X = 0 and -5
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X = 0 and -1.25
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X = -1.25
Correct Answer
A. X = 0 and -1.25Explanation
The given equation is a quadratic equation in the form of ax^2 + bx + c = 0. To solve this equation, we can use the quadratic formula: x = (-b ± √(b^2 - 4ac)) / 2a. In this case, a = 16, b = 20, and c = 0. Plugging these values into the quadratic formula, we get x = (-20 ± √(20^2 - 4(16)(0))) / (2(16)). Simplifying further, we have x = (-20 ± √(400)) / 32. This gives us two possible solutions: x = (-20 + 20) / 32 = 0 and x = (-20 - 20) / 32 = -1.25. Therefore, the correct answer is x = 0 and -1.25.Rate this question:
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- 4.
Which best describes the graph of a quadratic function?
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A line.
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A parabola
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A v-shape.
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A circle
Correct Answer
A. A parabolaExplanation
A quadratic function is a polynomial function of degree 2. Its graph is a parabola, which is a U-shaped curve. The shape of the parabola can vary depending on the coefficients of the quadratic function, but it always has a symmetric form. The graph of a quadratic function can open upwards or downwards, depending on the leading coefficient. Therefore, the correct answer is a parabola.Rate this question:
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- 5.
How do you change the concavity of the graph of a quadratic function written in standard form?
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Change the value of a to its opposite.
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Change the value of b to its opposite.
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Change the value of c to its opposite.
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Take the square root of both sides.
Correct Answer
A. Change the value of a to its opposite.Explanation
To change the concavity of the graph of a quadratic function written in standard form, you need to change the value of a to its opposite. The coefficient of the x^2 term, represented by a, determines whether the graph opens upwards or downwards. If a is positive, the graph opens upwards and has a concave shape. If a is negative, the graph opens downwards and has a concave shape. Thus, changing the value of a to its opposite will change the concavity of the graph.Rate this question:
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- 6.
Subtracting 7 from y=x2+2x will move the graph how?
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Left 7.
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Right 7.
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Up 7.
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Down 7.
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None of these.
Correct Answer
A. Down 7.Explanation
When we subtract 7 from the equation y = x^2 + 2x, it means that we are subtracting 7 from the y-coordinate of each point on the graph. This will result in the entire graph being shifted downwards by 7 units. Therefore, the correct answer is Down 7.Rate this question:
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- 7.
To make the graph y=x2+4x+7 grow faster (more narrow) I could do the following:
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Change a to 1/2.
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Change a to -1.
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Change a to 3.
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Change c to 10.
Correct Answer
A. Change a to 3.Explanation
By changing the value of "a" to 3 in the equation y=x^2+4x+7, we are increasing the coefficient of the x^2 term. This will cause the parabola to become steeper and narrower, resulting in a faster growth rate. Increasing the value of "a" will make the graph more concentrated around the vertex, making it grow faster.Rate this question:
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- 8.
Can the graph of a quadratic function ever have three x-intercepts?
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Yes.
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No.
Correct Answer
A. No.Explanation
The graph of a quadratic function can never have three x-intercepts because a quadratic function is a polynomial of degree 2, which means it can have at most two x-intercepts. This is because a quadratic equation can be factored into two linear factors, resulting in two solutions for x. Therefore, the correct answer is no.Rate this question:
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- 9.
Quadratic functions have a line of symmetry. True or False?
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True.
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False.
Correct Answer
A. True.Explanation
Quadratic functions have a line of symmetry because they are symmetric about the vertical line passing through the vertex of the parabola. This means that if a point (x, y) lies on the graph of the quadratic function, then the point (-x, y) will also lie on the graph. This line of symmetry divides the parabola into two equal halves.Rate this question:
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- 10.
The graph of y=x2 has a
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Maximum
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Minimum
Correct Answer
A. MinimumExplanation
The graph of y=x^2 is a parabola that opens upwards. Since the coefficient of the x^2 term is positive, the parabola is concave up and has a minimum point. This minimum point represents the lowest value of the function and is located at the vertex of the parabola. Therefore, the correct answer is minimum.Rate this question:
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- 11.
Solve. x2 - 100 = 0
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X =10
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X = 50
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X = 50 and -50
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X = 10 and -10
Correct Answer
A. X = 10 and -10Explanation
The given equation is a quadratic equation in the form of x^2 - 100 = 0. To solve this equation, we can factorize it as (x - 10)(x + 10) = 0. This means that either (x - 10) = 0 or (x + 10) = 0. Solving these two equations separately, we find that x = 10 and x = -10. Therefore, the correct answer is x = 10 and -10.Rate this question:
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- 12.
Use the discriminant to find the number of real solutions. 2x2 + 5x + 7 = 0
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0
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1
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2
Correct Answer
A. 0Explanation
The given quadratic equation is in the form ax^2 + bx + c = 0. The discriminant, denoted by Δ, is calculated as b^2 - 4ac. If Δ is greater than 0, the equation has two distinct real solutions. If Δ is equal to 0, the equation has one real solution. If Δ is less than 0, the equation has no real solutions. In this case, the discriminant is 5^2 - 4(2)(7) = 25 - 56 = -31. Since the discriminant is negative, there are no real solutions to the equation.Rate this question:
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- 13.
Solve. x2 - 3x - 2 = 0
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X =10 and -7
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X is approximately 3.56 and -0.56
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X is approximately 5.06 and -0.94
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No real solutions
Correct Answer
A. X is approximately 3.56 and -0.56Explanation
The given equation is a quadratic equation, which can be solved by factoring, completing the square, or using the quadratic formula. In this case, the equation does not factor easily, so we can use the quadratic formula. The quadratic formula states that for an equation of the form ax^2 + bx + c = 0, the solutions for x are given by x = (-b ± √(b^2 - 4ac)) / (2a). In this equation, a = 1, b = -3, and c = -2. Plugging in these values into the quadratic formula, we get x = (-(-3) ± √((-3)^2 - 4(1)(-2))) / (2(1)). Simplifying further, x = (3 ± √(9 + 8)) / 2, which becomes x = (3 ± √17) / 2. Therefore, the solutions for x are approximately 3.56 and -0.56.Rate this question:
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- 14.
Find the roots of y = x2 + 2x - 24
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(0,6) and (0,-4)
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(6,0) and (-4,0)
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(0,-6) and (0,4)
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(-6,0) and (4,0)
Correct Answer
A. (-6,0) and (4,0)Explanation
The answer (-6,0) and (4,0) suggests that the roots of the equation y = x^2 + 2x - 24 are x = -6 and x = 4. This means that when x is equal to -6 or 4, the equation will be satisfied and y will be equal to 0. Therefore, the points (-6,0) and (4,0) lie on the graph of the equation.Rate this question:
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- 15.
Identify the vertex of y = 2x2 + 12x + 3
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(-3, -15)
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(-3, -51)
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(-6, 3)
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(-6, -141)
Correct Answer
A. (-3, -15)Explanation
The vertex of a quadratic function in the form y = ax^2 + bx + c is given by the coordinates (-b/2a, f(-b/2a)), where f(x) represents the function. In this case, the quadratic function is y = 2x^2 + 12x + 3. By comparing the equation to the standard form, we can see that a = 2, b = 12, and c = 3. Plugging these values into the formula, we get (-12/(2*2), f(-12/(2*2))) = (-3, f(-3)). To find f(-3), we substitute x = -3 into the equation: f(-3) = 2(-3)^2 + 12(-3) + 3 = -15. Therefore, the vertex is (-3, -15).Rate this question:
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Current Version
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Mar 20, 2023Quiz Edited by
ProProfs Editorial Team -
Apr 23, 2014Quiz Created by
Latshawfive
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